GraphQL “Cannot return null for non-nullable”
Trying to make my first graphQL server, here's what I have written so far.
https://gist.github.com/tharakabimal/7f2947e805e69f67af2b633268db0406
Following error pops up on GraphQL when I try to filter the users by username.
Error on GraphQL
The error occurs in the users field in UserQueriesQL.js.
Is there anything wrong the way I pass arguments on the resolve functions?
user: {
type: UserType,
args: {
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
},
resolve: function(parentValue, args) {
return User.find( args ).exec();
}
javascript node.js express graphql
edited Jan 1 at 12:06
AndrewL64
10.1k41846
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
add a comment |
Trying to make my first graphQL server, here's what I have written so far.
https://gist.github.com/tharakabimal/7f2947e805e69f67af2b633268db0406
Following error pops up on GraphQL when I try to filter the users by username.
Error on GraphQL
The error occurs in the users field in UserQueriesQL.js.
Is there anything wrong the way I pass arguments on the resolve functions?
user: {
type: UserType,
args: {
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
},
resolve: function(parentValue, args) {
return User.find( args ).exec();
}
javascript node.js express graphql
edited Jan 1 at 12:06
AndrewL64
10.1k41846
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
The error means you are returningnull, but withtype: new GraphQLNonNull(GraphQLString)you declared that there may never be returnednullfor the username. Either return something else thannull, or declare the type astype: new GraphQLString()
– marktani
Feb 23 '17 at 13:49
add a comment |
Trying to make my first graphQL server, here's what I have written so far.
https://gist.github.com/tharakabimal/7f2947e805e69f67af2b633268db0406
Following error pops up on GraphQL when I try to filter the users by username.
Error on GraphQL
The error occurs in the users field in UserQueriesQL.js.
Is there anything wrong the way I pass arguments on the resolve functions?
user: {
type: UserType,
args: {
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
},
resolve: function(parentValue, args) {
return User.find( args ).exec();
}
javascript node.js express graphql
edited Jan 1 at 12:06
AndrewL64
10.1k41846
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
Trying to make my first graphQL server, here's what I have written so far.
https://gist.github.com/tharakabimal/7f2947e805e69f67af2b633268db0406
Following error pops up on GraphQL when I try to filter the users by username.
Error on GraphQL
The error occurs in the users field in UserQueriesQL.js.
Is there anything wrong the way I pass arguments on the resolve functions?
user: {
type: UserType,
args: {
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
},
resolve: function(parentValue, args) {
return User.find( args ).exec();
}
javascript node.js express graphql
javascript node.js express graphql
edited Jan 1 at 12:06
AndrewL64
10.1k41846
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
edited Jan 1 at 12:06
AndrewL64
10.1k41846
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
edited Jan 1 at 12:06
AndrewL64
10.1k41846
edited Jan 1 at 12:06
AndrewL64
10.1k41846
edited Jan 1 at 12:06
AndrewL64
10.1k41846
10.1k41846
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
asked Feb 23 '17 at 6:58
King JulianKing Julian
64124
64124
The error means you are returningnull, but withtype: new GraphQLNonNull(GraphQLString)you declared that there may never be returnednullfor the username. Either return something else thannull, or declare the type astype: new GraphQLString()
– marktani
Feb 23 '17 at 13:49
add a comment |
The error means you are returningnull, but withtype: new GraphQLNonNull(GraphQLString)you declared that there may never be returnednullfor the username. Either return something else thannull, or declare the type astype: new GraphQLString()
– marktani
Feb 23 '17 at 13:49
The error means you are returning
null, but with type: new GraphQLNonNull(GraphQLString) you declared that there may never be returned null for the username. Either return something else than null, or declare the type as type: new GraphQLString()– marktani
Feb 23 '17 at 13:49
The error means you are returning
null, but with type: new GraphQLNonNull(GraphQLString) you declared that there may never be returned null for the username. Either return something else than null, or declare the type as type: new GraphQLString()– marktani
Feb 23 '17 at 13:49
add a comment |
1 Answer
1
active
oldest
votes
user: {
type: UserType,
args: {
username: { type: new GraphQLNonNull(GraphQLString) }
},
resolve: function(parentValue, args) {
return User.find( args ).exec(); // User.find({username: 'some name'}).exec();
// will work as matches your mongoose schema
}
Previously, in the args you are providing an an object with nested object username so,
args: { // this won't match your mongoose schema field as it's nested object
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
}
so when the user queries and provides args then
your args would be { username: { name: 'abcd' } }
// args = {username: {name: 'abcd'}}
and resolve() is executing User.find({username: {name: 'abcd'}}).exec();
/* searching for username{} object, but
your mongoose schema is username: String */
which doesn't match your database fields, which will always return an empty array ,also which will not match your GraphQL field type, as it is GraphQLNonNull
after viewing the gist the problem is with rootquery
the problem is with rootquery
let RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: () => ({
users: { type:UserQueries.users, resolve: UserQueries.users }
user: { type: UserQueries.user, resolve: UserQueries.user }
})
});
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
so do you have usernameJohninuserscollection, put a gist and snapshot of the database
– p0k8_
Feb 23 '17 at 10:58
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
|
show 1 more comment
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
user: {
type: UserType,
args: {
username: { type: new GraphQLNonNull(GraphQLString) }
},
resolve: function(parentValue, args) {
return User.find( args ).exec(); // User.find({username: 'some name'}).exec();
// will work as matches your mongoose schema
}
Previously, in the args you are providing an an object with nested object username so,
args: { // this won't match your mongoose schema field as it's nested object
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
}
so when the user queries and provides args then
your args would be { username: { name: 'abcd' } }
// args = {username: {name: 'abcd'}}
and resolve() is executing User.find({username: {name: 'abcd'}}).exec();
/* searching for username{} object, but
your mongoose schema is username: String */
which doesn't match your database fields, which will always return an empty array ,also which will not match your GraphQL field type, as it is GraphQLNonNull
after viewing the gist the problem is with rootquery
the problem is with rootquery
let RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: () => ({
users: { type:UserQueries.users, resolve: UserQueries.users }
user: { type: UserQueries.user, resolve: UserQueries.user }
})
});
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
so do you have usernameJohninuserscollection, put a gist and snapshot of the database
– p0k8_
Feb 23 '17 at 10:58
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
|
show 1 more comment
user: {
type: UserType,
args: {
username: { type: new GraphQLNonNull(GraphQLString) }
},
resolve: function(parentValue, args) {
return User.find( args ).exec(); // User.find({username: 'some name'}).exec();
// will work as matches your mongoose schema
}
Previously, in the args you are providing an an object with nested object username so,
args: { // this won't match your mongoose schema field as it's nested object
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
}
so when the user queries and provides args then
your args would be { username: { name: 'abcd' } }
// args = {username: {name: 'abcd'}}
and resolve() is executing User.find({username: {name: 'abcd'}}).exec();
/* searching for username{} object, but
your mongoose schema is username: String */
which doesn't match your database fields, which will always return an empty array ,also which will not match your GraphQL field type, as it is GraphQLNonNull
after viewing the gist the problem is with rootquery
the problem is with rootquery
let RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: () => ({
users: { type:UserQueries.users, resolve: UserQueries.users }
user: { type: UserQueries.user, resolve: UserQueries.user }
})
});
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
so do you have usernameJohninuserscollection, put a gist and snapshot of the database
– p0k8_
Feb 23 '17 at 10:58
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
|
show 1 more comment
user: {
type: UserType,
args: {
username: { type: new GraphQLNonNull(GraphQLString) }
},
resolve: function(parentValue, args) {
return User.find( args ).exec(); // User.find({username: 'some name'}).exec();
// will work as matches your mongoose schema
}
Previously, in the args you are providing an an object with nested object username so,
args: { // this won't match your mongoose schema field as it's nested object
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
}
so when the user queries and provides args then
your args would be { username: { name: 'abcd' } }
// args = {username: {name: 'abcd'}}
and resolve() is executing User.find({username: {name: 'abcd'}}).exec();
/* searching for username{} object, but
your mongoose schema is username: String */
which doesn't match your database fields, which will always return an empty array ,also which will not match your GraphQL field type, as it is GraphQLNonNull
after viewing the gist the problem is with rootquery
the problem is with rootquery
let RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: () => ({
users: { type:UserQueries.users, resolve: UserQueries.users }
user: { type: UserQueries.user, resolve: UserQueries.user }
})
});
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
user: {
type: UserType,
args: {
username: { type: new GraphQLNonNull(GraphQLString) }
},
resolve: function(parentValue, args) {
return User.find( args ).exec(); // User.find({username: 'some name'}).exec();
// will work as matches your mongoose schema
}
Previously, in the args you are providing an an object with nested object username so,
args: { // this won't match your mongoose schema field as it's nested object
username: {
name: 'username',
type: new GraphQLNonNull(GraphQLString)
}
}
so when the user queries and provides args then
your args would be { username: { name: 'abcd' } }
// args = {username: {name: 'abcd'}}
and resolve() is executing User.find({username: {name: 'abcd'}}).exec();
/* searching for username{} object, but
your mongoose schema is username: String */
which doesn't match your database fields, which will always return an empty array ,also which will not match your GraphQL field type, as it is GraphQLNonNull
after viewing the gist the problem is with rootquery
the problem is with rootquery
let RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: () => ({
users: { type:UserQueries.users, resolve: UserQueries.users }
user: { type: UserQueries.user, resolve: UserQueries.user }
})
});
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
edited Feb 23 '17 at 11:30
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
answered Feb 23 '17 at 7:05
p0k8_p0k8_
4,19142133
4,19142133
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
so do you have usernameJohninuserscollection, put a gist and snapshot of the database
– p0k8_
Feb 23 '17 at 10:58
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
|
show 1 more comment
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
so do you have usernameJohninuserscollection, put a gist and snapshot of the database
– p0k8_
Feb 23 '17 at 10:58
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
I did the suggested changes, but still having the issue gist.github.com/tharakabimal/c84ff21d6a6aa898cb3ccc02757867df
– King Julian
Feb 23 '17 at 10:35
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
have you entered the username in the args
– p0k8_
Feb 23 '17 at 10:37
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
Yes gist.github.com/tharakabimal/1883dcb50322456fe81d37e9abc22daa
– King Julian
Feb 23 '17 at 10:55
so do you have username
John in users collection, put a gist and snapshot of the database– p0k8_
Feb 23 '17 at 10:58
so do you have username
John in users collection, put a gist and snapshot of the database– p0k8_
Feb 23 '17 at 10:58
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
Here are the 3 users I have in my mongoDB gist.github.com/tharakabimal/cdd58e7534fef268801142eb7ce4266c
– King Julian
Feb 23 '17 at 11:09
|
show 1 more comment
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The error means you are returning
null, but withtype: new GraphQLNonNull(GraphQLString)you declared that there may never be returnednullfor the username. Either return something else thannull, or declare the type astype: new GraphQLString()– marktani
Feb 23 '17 at 13:49