Regular expression for exact match of a string












100















I want to match two passwords with regular expression. for example i have two inputs "123456" and "1234567" then the result should be not match(false). And when i have entered "123456" and "123456" then the result should be match(true).



I couldn't make the expression. Can any one help me plz.






regex







share|improve this question




















  • 7





    Why do you want regex in this case? Checking for (exact) equality should really be done without regex.

    – Bart Kiers
    Apr 22 '11 at 6:26











  • Because we look up how to replace text in a Bash script and get an answer that involves Perl and regex.

    – sudo
    Aug 1 '15 at 19:11











  • having the same issue a better solution ^(123456) will give the results that you want

    – sdx11
    Dec 21 '16 at 17:48
















100















I want to match two passwords with regular expression. for example i have two inputs "123456" and "1234567" then the result should be not match(false). And when i have entered "123456" and "123456" then the result should be match(true).



I couldn't make the expression. Can any one help me plz.






regex







share|improve this question




















  • 7





    Why do you want regex in this case? Checking for (exact) equality should really be done without regex.

    – Bart Kiers
    Apr 22 '11 at 6:26











  • Because we look up how to replace text in a Bash script and get an answer that involves Perl and regex.

    – sudo
    Aug 1 '15 at 19:11











  • having the same issue a better solution ^(123456) will give the results that you want

    – sdx11
    Dec 21 '16 at 17:48














100












100








100


23






I want to match two passwords with regular expression. for example i have two inputs "123456" and "1234567" then the result should be not match(false). And when i have entered "123456" and "123456" then the result should be match(true).



I couldn't make the expression. Can any one help me plz.






regex







share|improve this question
















I want to match two passwords with regular expression. for example i have two inputs "123456" and "1234567" then the result should be not match(false). And when i have entered "123456" and "123456" then the result should be match(true).



I couldn't make the expression. Can any one help me plz.






regex




regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jul 27 '18 at 7:20









Wiktor Stribiżew

318k16139221




318k16139221










asked Apr 22 '11 at 6:24









ChirayuChirayu

1,59262244




1,59262244








  • 7





    Why do you want regex in this case? Checking for (exact) equality should really be done without regex.

    – Bart Kiers
    Apr 22 '11 at 6:26











  • Because we look up how to replace text in a Bash script and get an answer that involves Perl and regex.

    – sudo
    Aug 1 '15 at 19:11











  • having the same issue a better solution ^(123456) will give the results that you want

    – sdx11
    Dec 21 '16 at 17:48














  • 7





    Why do you want regex in this case? Checking for (exact) equality should really be done without regex.

    – Bart Kiers
    Apr 22 '11 at 6:26











  • Because we look up how to replace text in a Bash script and get an answer that involves Perl and regex.

    – sudo
    Aug 1 '15 at 19:11











  • having the same issue a better solution ^(123456) will give the results that you want

    – sdx11
    Dec 21 '16 at 17:48








7




7





Why do you want regex in this case? Checking for (exact) equality should really be done without regex.

– Bart Kiers
Apr 22 '11 at 6:26





Why do you want regex in this case? Checking for (exact) equality should really be done without regex.

– Bart Kiers
Apr 22 '11 at 6:26













Because we look up how to replace text in a Bash script and get an answer that involves Perl and regex.

– sudo
Aug 1 '15 at 19:11





Because we look up how to replace text in a Bash script and get an answer that involves Perl and regex.

– sudo
Aug 1 '15 at 19:11













having the same issue a better solution ^(123456) will give the results that you want

– sdx11
Dec 21 '16 at 17:48





having the same issue a better solution ^(123456) will give the results that you want

– sdx11
Dec 21 '16 at 17:48












5 Answers
5






active

oldest

votes


















126














if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:



/^123456$/


in perl the test for matching the password would be something like



print "MATCH_OK" if ($input_pass=~/^123456$/);


EDIT:



bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way



as a second thought, you may want to consider a safer authentication mechanism :)






share|improve this answer


























  • FYI: for me only ^123456$ works in the tester linked below.

    – Tilo
    Nov 6 '13 at 17:43











  • Thanks for the anchors, I knew that but completely didn't think about it :)

    – vikingsteve
    Dec 2 '15 at 11:47



















100














In malfaux's answer '^' and '$' has been used to detect the beginning and the end of the text.

These are usually used to detect the beginning and the end of a line.
However this may be the correct way in this case.
But if you wish to match an exact word the more elegant way is to use 'b'. In this case following pattern will match the exact phrase'123456'.




/b123456b/







share|improve this answer


























  • Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

    – prageeth
    Sep 29 '13 at 3:16








  • 1





    If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

    – prageeth
    Jan 2 '14 at 5:03






  • 17





    Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

    – 0x1mason
    Jan 2 '14 at 17:53








  • 2





    You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

    – 0x1mason
    Jan 7 '14 at 14:45








  • 1





    @0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

    – twknab
    Feb 11 '17 at 11:26





















25














(?<![wd])abc(?![wd])


this makes sure that your match is not preceded by some character, number, or underscore and is not followed immediately by character or number, or underscore



so it will match "abc" in "abc", "abc.", "abc ", but not "4abc", nor "abcde"






share|improve this answer



















  • 1





    The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

    – Alan Moore
    Apr 17 '14 at 2:54



















5














A more straight forward way is to check for equality



if string1 == string2

  puts "match"

else

  puts "not match"

end


however, if you really want to stick to regular expression, 



string1 =~ /^123456$/





share|improve this answer
























  • @Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

    – Antwan
    Mar 30 '14 at 0:45



















2














You may also try appending a space at the start and end of keyword: /s+123456s+/i.






share|improve this answer


























  • I was not able to get this method to work using s via: regex101.com

    – twknab
    Feb 11 '17 at 11:29











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5 Answers
5






active

oldest

votes








5 Answers
5






active

oldest

votes









active

oldest

votes






active

oldest

votes









126














if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:



/^123456$/


in perl the test for matching the password would be something like



print "MATCH_OK" if ($input_pass=~/^123456$/);


EDIT:



bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way



as a second thought, you may want to consider a safer authentication mechanism :)






share|improve this answer


























  • FYI: for me only ^123456$ works in the tester linked below.

    – Tilo
    Nov 6 '13 at 17:43











  • Thanks for the anchors, I knew that but completely didn't think about it :)

    – vikingsteve
    Dec 2 '15 at 11:47
















126














if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:



/^123456$/


in perl the test for matching the password would be something like



print "MATCH_OK" if ($input_pass=~/^123456$/);


EDIT:



bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way



as a second thought, you may want to consider a safer authentication mechanism :)






share|improve this answer


























  • FYI: for me only ^123456$ works in the tester linked below.

    – Tilo
    Nov 6 '13 at 17:43











  • Thanks for the anchors, I knew that but completely didn't think about it :)

    – vikingsteve
    Dec 2 '15 at 11:47














126












126








126







if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:



/^123456$/


in perl the test for matching the password would be something like



print "MATCH_OK" if ($input_pass=~/^123456$/);


EDIT:



bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way



as a second thought, you may want to consider a safer authentication mechanism :)






share|improve this answer















if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:



/^123456$/


in perl the test for matching the password would be something like



print "MATCH_OK" if ($input_pass=~/^123456$/);


EDIT:



bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way



as a second thought, you may want to consider a safer authentication mechanism :)







share|improve this answer














share|improve this answer



share|improve this answer








edited May 23 '17 at 12:34









Community♦

11




11










answered Apr 22 '11 at 6:29









user237419user237419

5,74432435




5,74432435













  • FYI: for me only ^123456$ works in the tester linked below.

    – Tilo
    Nov 6 '13 at 17:43











  • Thanks for the anchors, I knew that but completely didn't think about it :)

    – vikingsteve
    Dec 2 '15 at 11:47



















  • FYI: for me only ^123456$ works in the tester linked below.

    – Tilo
    Nov 6 '13 at 17:43











  • Thanks for the anchors, I knew that but completely didn't think about it :)

    – vikingsteve
    Dec 2 '15 at 11:47

















FYI: for me only ^123456$ works in the tester linked below.

– Tilo
Nov 6 '13 at 17:43





FYI: for me only ^123456$ works in the tester linked below.

– Tilo
Nov 6 '13 at 17:43













Thanks for the anchors, I knew that but completely didn't think about it :)

– vikingsteve
Dec 2 '15 at 11:47





Thanks for the anchors, I knew that but completely didn't think about it :)

– vikingsteve
Dec 2 '15 at 11:47













100














In malfaux's answer '^' and '$' has been used to detect the beginning and the end of the text.

These are usually used to detect the beginning and the end of a line.
However this may be the correct way in this case.
But if you wish to match an exact word the more elegant way is to use 'b'. In this case following pattern will match the exact phrase'123456'.




/b123456b/







share|improve this answer


























  • Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

    – prageeth
    Sep 29 '13 at 3:16








  • 1





    If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

    – prageeth
    Jan 2 '14 at 5:03






  • 17





    Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

    – 0x1mason
    Jan 2 '14 at 17:53








  • 2





    You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

    – 0x1mason
    Jan 7 '14 at 14:45








  • 1





    @0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

    – twknab
    Feb 11 '17 at 11:26


















100














In malfaux's answer '^' and '$' has been used to detect the beginning and the end of the text.

These are usually used to detect the beginning and the end of a line.
However this may be the correct way in this case.
But if you wish to match an exact word the more elegant way is to use 'b'. In this case following pattern will match the exact phrase'123456'.




/b123456b/







share|improve this answer


























  • Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

    – prageeth
    Sep 29 '13 at 3:16








  • 1





    If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

    – prageeth
    Jan 2 '14 at 5:03






  • 17





    Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

    – 0x1mason
    Jan 2 '14 at 17:53








  • 2





    You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

    – 0x1mason
    Jan 7 '14 at 14:45








  • 1





    @0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

    – twknab
    Feb 11 '17 at 11:26
















100












100








100







In malfaux's answer '^' and '$' has been used to detect the beginning and the end of the text.

These are usually used to detect the beginning and the end of a line.
However this may be the correct way in this case.
But if you wish to match an exact word the more elegant way is to use 'b'. In this case following pattern will match the exact phrase'123456'.




/b123456b/







share|improve this answer















In malfaux's answer '^' and '$' has been used to detect the beginning and the end of the text.

These are usually used to detect the beginning and the end of a line.
However this may be the correct way in this case.
But if you wish to match an exact word the more elegant way is to use 'b'. In this case following pattern will match the exact phrase'123456'.




/b123456b/








share|improve this answer














share|improve this answer



share|improve this answer








edited Oct 17 '13 at 8:17

























answered Oct 25 '12 at 9:41









prageethprageeth

5,20063459




5,20063459













  • Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

    – prageeth
    Sep 29 '13 at 3:16








  • 1





    If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

    – prageeth
    Jan 2 '14 at 5:03






  • 17





    Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

    – 0x1mason
    Jan 2 '14 at 17:53








  • 2





    You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

    – 0x1mason
    Jan 7 '14 at 14:45








  • 1





    @0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

    – twknab
    Feb 11 '17 at 11:26





















  • Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

    – prageeth
    Sep 29 '13 at 3:16








  • 1





    If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

    – prageeth
    Jan 2 '14 at 5:03






  • 17





    Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

    – 0x1mason
    Jan 2 '14 at 17:53








  • 2





    You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

    – 0x1mason
    Jan 7 '14 at 14:45








  • 1





    @0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

    – twknab
    Feb 11 '17 at 11:26



















Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

– prageeth
Sep 29 '13 at 3:16







Are you sure that it works in that way? ;) Please use a regex tester like this. Use "show match" button and you will see why it matches. BTW remember '.' is a special char and good to escape it. (and good to think twice before down voting :D ).

– prageeth
Sep 29 '13 at 3:16






1




1





If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

– prageeth
Jan 2 '14 at 5:03





If you think my answer is misleading or wrong, you still can post your own answer(as other people do) or place a comment under my post explaining your suggestion.

– prageeth
Jan 2 '14 at 5:03




17




17





Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

– 0x1mason
Jan 2 '14 at 17:53







Your answer is misleading and will cause many people serious problems. E.g., using your approach bhttp://www.foo.comb will match http://www.bar.com/?http://www.foo.com, which is most definitely not an exact match, as requested in the OP. This will cause serious problems for people working with URLs or passwords (which, again, is what the OP requested) that contain non-word characters. You should clarify your answer so others are not led astray.

– 0x1mason
Jan 2 '14 at 17:53






2




2





You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

– 0x1mason
Jan 7 '14 at 14:45







You'll have to explain. '.' is a red herring. bhttp://www.foo.comb still produces a match for http://www.bar.com/?http://www.foo.com. That's not what the OP wants.

– 0x1mason
Jan 7 '14 at 14:45






1




1





@0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

– twknab
Feb 11 '17 at 11:26







@0x1mason is correct that bhttp://www.foo.comb will match http://www.foo.com=?http://www.foo.com along with the URL as is. The first response, using the ^ (beginning) and $ (end) is the best method via these testers: regex101.com and regexr.com (the tester included in a link below is not very user friendly, these are much better)

– twknab
Feb 11 '17 at 11:26













25














(?<![wd])abc(?![wd])


this makes sure that your match is not preceded by some character, number, or underscore and is not followed immediately by character or number, or underscore



so it will match "abc" in "abc", "abc.", "abc ", but not "4abc", nor "abcde"






share|improve this answer



















  • 1





    The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

    – Alan Moore
    Apr 17 '14 at 2:54
















25














(?<![wd])abc(?![wd])


this makes sure that your match is not preceded by some character, number, or underscore and is not followed immediately by character or number, or underscore



so it will match "abc" in "abc", "abc.", "abc ", but not "4abc", nor "abcde"






share|improve this answer



















  • 1





    The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

    – Alan Moore
    Apr 17 '14 at 2:54














25












25








25







(?<![wd])abc(?![wd])


this makes sure that your match is not preceded by some character, number, or underscore and is not followed immediately by character or number, or underscore



so it will match "abc" in "abc", "abc.", "abc ", but not "4abc", nor "abcde"






share|improve this answer













(?<![wd])abc(?![wd])


this makes sure that your match is not preceded by some character, number, or underscore and is not followed immediately by character or number, or underscore



so it will match "abc" in "abc", "abc.", "abc ", but not "4abc", nor "abcde"







share|improve this answer












share|improve this answer



share|improve this answer










answered Apr 16 '14 at 19:01









AednaAedna

44145




44145








  • 1





    The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

    – Alan Moore
    Apr 17 '14 at 2:54














  • 1





    The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

    – Alan Moore
    Apr 17 '14 at 2:54








1




1





The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

– Alan Moore
Apr 17 '14 at 2:54





The title of the question is misleading; he's trying to make sure two whole strings are exactly the same. Also, w matches digits as well as letters, so [wd] is redundant.

– Alan Moore
Apr 17 '14 at 2:54











5














A more straight forward way is to check for equality



if string1 == string2

  puts "match"

else

  puts "not match"

end


however, if you really want to stick to regular expression, 



string1 =~ /^123456$/





share|improve this answer
























  • @Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

    – Antwan
    Mar 30 '14 at 0:45
















5














A more straight forward way is to check for equality



if string1 == string2

  puts "match"

else

  puts "not match"

end


however, if you really want to stick to regular expression, 



string1 =~ /^123456$/





share|improve this answer
























  • @Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

    – Antwan
    Mar 30 '14 at 0:45














5












5








5







A more straight forward way is to check for equality



if string1 == string2

  puts "match"

else

  puts "not match"

end


however, if you really want to stick to regular expression, 



string1 =~ /^123456$/





share|improve this answer













A more straight forward way is to check for equality



if string1 == string2

  puts "match"

else

  puts "not match"

end


however, if you really want to stick to regular expression, 



string1 =~ /^123456$/






share|improve this answer












share|improve this answer



share|improve this answer










answered Apr 22 '11 at 6:33









kurumikurumi

20k33344




20k33344













  • @Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

    – Antwan
    Mar 30 '14 at 0:45



















  • @Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

    – Antwan
    Mar 30 '14 at 0:45

















@Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

– Antwan
Mar 30 '14 at 0:45





@Kurumi I'm trying to make java code that search for specific word in txt file and i want to use regx so could i use that pattern /^myword$/ with String.match(/^myword$/ ) to search for the word in that txt?

– Antwan
Mar 30 '14 at 0:45











2














You may also try appending a space at the start and end of keyword: /s+123456s+/i.






share|improve this answer


























  • I was not able to get this method to work using s via: regex101.com

    – twknab
    Feb 11 '17 at 11:29
















2














You may also try appending a space at the start and end of keyword: /s+123456s+/i.






share|improve this answer


























  • I was not able to get this method to work using s via: regex101.com

    – twknab
    Feb 11 '17 at 11:29














2












2








2







You may also try appending a space at the start and end of keyword: /s+123456s+/i.






share|improve this answer















You may also try appending a space at the start and end of keyword: /s+123456s+/i.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 7 '11 at 13:17









Benoit Garret

12.5k35261




12.5k35261










answered Nov 7 '11 at 11:36









Bhushan LodhaBhushan Lodha

3,86164884




3,86164884













  • I was not able to get this method to work using s via: regex101.com

    – twknab
    Feb 11 '17 at 11:29



















  • I was not able to get this method to work using s via: regex101.com

    – twknab
    Feb 11 '17 at 11:29

















I was not able to get this method to work using s via: regex101.com

– twknab
Feb 11 '17 at 11:29





I was not able to get this method to work using s via: regex101.com

– twknab
Feb 11 '17 at 11:29


















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