How to merge array of objects with same key












-2















I have one array with multiple object,want to merge them by same keys without losing their values.



I try some of answer in stakoverflow but none of them help me.i want to do this with map/reduce but i don't know how can i retrieve key name of every object to check them.



let rows = [
{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },
{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },
{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },
{ parag: { text: "sample test" } },
{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },
{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },
{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }
];


i want this result:



let rows = [
{
row1: [
{ val: "row1-val1" },
{ val: "row1-val2" },
{ val: "row1-val3" },
{ val: "row1-val4" },
{ val: "row1-val5" },
{ val: "row1-val6" }
]
},
{ parag: { text: "sample test" } },
{
row2: [
{ val: "row2-val1" },
{ val: "row2-val2" },
{ val: "row2-val3" },
{ val: "row2-val4" },
{ val: "row2-val5" },
{ val: "row2-val6" }
]
}
];









share|improve this question























  • The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

    – CertainPerformance
    Jan 1 at 7:08
















-2















I have one array with multiple object,want to merge them by same keys without losing their values.



I try some of answer in stakoverflow but none of them help me.i want to do this with map/reduce but i don't know how can i retrieve key name of every object to check them.



let rows = [
{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },
{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },
{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },
{ parag: { text: "sample test" } },
{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },
{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },
{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }
];


i want this result:



let rows = [
{
row1: [
{ val: "row1-val1" },
{ val: "row1-val2" },
{ val: "row1-val3" },
{ val: "row1-val4" },
{ val: "row1-val5" },
{ val: "row1-val6" }
]
},
{ parag: { text: "sample test" } },
{
row2: [
{ val: "row2-val1" },
{ val: "row2-val2" },
{ val: "row2-val3" },
{ val: "row2-val4" },
{ val: "row2-val5" },
{ val: "row2-val6" }
]
}
];









share|improve this question























  • The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

    – CertainPerformance
    Jan 1 at 7:08














-2












-2








-2


1






I have one array with multiple object,want to merge them by same keys without losing their values.



I try some of answer in stakoverflow but none of them help me.i want to do this with map/reduce but i don't know how can i retrieve key name of every object to check them.



let rows = [
{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },
{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },
{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },
{ parag: { text: "sample test" } },
{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },
{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },
{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }
];


i want this result:



let rows = [
{
row1: [
{ val: "row1-val1" },
{ val: "row1-val2" },
{ val: "row1-val3" },
{ val: "row1-val4" },
{ val: "row1-val5" },
{ val: "row1-val6" }
]
},
{ parag: { text: "sample test" } },
{
row2: [
{ val: "row2-val1" },
{ val: "row2-val2" },
{ val: "row2-val3" },
{ val: "row2-val4" },
{ val: "row2-val5" },
{ val: "row2-val6" }
]
}
];









share|improve this question














I have one array with multiple object,want to merge them by same keys without losing their values.



I try some of answer in stakoverflow but none of them help me.i want to do this with map/reduce but i don't know how can i retrieve key name of every object to check them.



let rows = [
{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },
{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },
{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },
{ parag: { text: "sample test" } },
{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },
{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },
{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }
];


i want this result:



let rows = [
{
row1: [
{ val: "row1-val1" },
{ val: "row1-val2" },
{ val: "row1-val3" },
{ val: "row1-val4" },
{ val: "row1-val5" },
{ val: "row1-val6" }
]
},
{ parag: { text: "sample test" } },
{
row2: [
{ val: "row2-val1" },
{ val: "row2-val2" },
{ val: "row2-val3" },
{ val: "row2-val4" },
{ val: "row2-val5" },
{ val: "row2-val6" }
]
}
];






javascript






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asked Jan 1 at 7:00









FarbodKainFarbodKain

457




457













  • The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

    – CertainPerformance
    Jan 1 at 7:08



















  • The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

    – CertainPerformance
    Jan 1 at 7:08

















The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Jan 1 at 7:08





The posted question does not appear to include any attempt at all to solve the problem. StackOverflow expects you to try to solve your own problem first, as your attempts help us to better understand what you want. Please edit the question to show what you've tried, so as to illustrate a specific roadblock you're running into a Minimal, Complete, and Verifiable example. For more information, please see How to Ask and take the tour.

– CertainPerformance
Jan 1 at 7:08












1 Answer
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1














You can do it with help of reduce






let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

let op = rows.reduce((o,c)=>{
let key = Object.keys(c)[0];
if(o[key]){
o[key].push(...c[key]);
} else {
o[key] = c[key];
}
return o;
},{})

console.log(op)








share|improve this answer























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    You can do it with help of reduce






    let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

    let op = rows.reduce((o,c)=>{
    let key = Object.keys(c)[0];
    if(o[key]){
    o[key].push(...c[key]);
    } else {
    o[key] = c[key];
    }
    return o;
    },{})

    console.log(op)








    share|improve this answer




























      1














      You can do it with help of reduce






      let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

      let op = rows.reduce((o,c)=>{
      let key = Object.keys(c)[0];
      if(o[key]){
      o[key].push(...c[key]);
      } else {
      o[key] = c[key];
      }
      return o;
      },{})

      console.log(op)








      share|improve this answer


























        1












        1








        1







        You can do it with help of reduce






        let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

        let op = rows.reduce((o,c)=>{
        let key = Object.keys(c)[0];
        if(o[key]){
        o[key].push(...c[key]);
        } else {
        o[key] = c[key];
        }
        return o;
        },{})

        console.log(op)








        share|improve this answer













        You can do it with help of reduce






        let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

        let op = rows.reduce((o,c)=>{
        let key = Object.keys(c)[0];
        if(o[key]){
        o[key].push(...c[key]);
        } else {
        o[key] = c[key];
        }
        return o;
        },{})

        console.log(op)








        let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

        let op = rows.reduce((o,c)=>{
        let key = Object.keys(c)[0];
        if(o[key]){
        o[key].push(...c[key]);
        } else {
        o[key] = c[key];
        }
        return o;
        },{})

        console.log(op)





        let rows = [{ row1: [{ val: "row1-val1" }, { val: "row1-val2" }] },{ row1: [{ val: "row1-val3" }, { val: "row1-val4" }] },{ row1: [{ val: "row1-val5" }, { val: "row1-val6" }] },{ parag: { text: "sample test" } },{ row2: [{ val: "row2-val1" }, { val: "row2-val2" }] },{ row2: [{ val: "row2-val3" }, { val: "row2-val4" }] },{ row2: [{ val: "row2-val5" }, { val: "row2-val6" }] }];

        let op = rows.reduce((o,c)=>{
        let key = Object.keys(c)[0];
        if(o[key]){
        o[key].push(...c[key]);
        } else {
        o[key] = c[key];
        }
        return o;
        },{})

        console.log(op)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 1 at 7:19









        Code ManiacCode Maniac

        6,8311326




        6,8311326
































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