Bar chart is not grouped properly in chartjs
0
I tried to create a multi bar chart using chartjs.But jobType and jobCount is not displayed according to the each companyName.
Here is the table
Here is the php file(CompanySeletion.php):
<?php
header('Content-Type:application/json');
define('DB_HOST','127.0.0.1');
define('DB_USERNAME','root');
define('DB_PASSWORD','');
define('DB_NAME','newmanpower');
$mysqli =new mysqli(DB_HOST,DB_USERNAME,DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: ".$mysqli->error);
}
//$selected = $_GET['Month'];
$selected=3;
$query = sprintf("SELECT jobType,jobCount,comName FROM graphview group by jobType,comName");
$result= $mysqli->query($query);
$data =array();
foreach ($result as $row){
$data= $row;
}
$result->close();
$mysqli->close();
print json_encode($data);
?>
Here is the JS file(testingbutton.js):
$(document).ready(function(){
$.ajax({
url: "http://localhost/chartjs/CompanySeletion.php",
method: "GET",
success: function (data) {
console.log(data);
var jobType = ;
var jobCount = ;
var comName=;
var chartColors = {
green: 'rgb(70, 214, 8)',
red: 'rgb(242, 26, 2)'
};
for (var i in data)
{
jobType.push( data[i].jobType);
jobCount.push(data[i].jobCount);
comName.push(data[i].comName);
}
var ctx = document.getElementById("mycanvas").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: jobType,
datasets: [{
label: comName[0],
data: jobCount(comName[0]),
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
{
label: comName[1],
data: jobCount ,
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
]
},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
var colorChangeValue = 1;
var dataset = myChart.data.datasets[0];
var dataset = myChart.data.datasets[1];
for (var i = 0; i < dataset.data.length; i++) {
if (dataset.data[i] > colorChangeValue) {
dataset.backgroundColor[i] = chartColors.green;
}
else {
dataset.backgroundColor[i] = chartColors.red;
}
}
myChart.update();
},
error: function (data) {
console.log(data);
}
});
});
Here is the HTML file:
<!DOCTYPE html>
<html>
<head>
<script src="jquery-3.0.0.js"></script>
<script src="jquery-ui.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="https://code.jquery.com/color/jquery.color-2.1.2.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.2.1/Chart.bundle.js"></script>
<link rel="stylesheet" href="stylesheet.css">
<style type="text/css">
#chart-container {
width: 640px;
heigth: auto;
}
</style>
<title>Job Progress</title>
</head>
<body>
<canvas height='75' width='200' id="mycanvas"></canvas>
<!-- javascript -->
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/Chart.min.js"></script>
<script type="text/javascript" src="js/testingbutton.js"></script>
</body>
</html>
Here is the received output according to the above code samples:
In the above graph, it shows same job type twice.Can anyone suggest a solution for that?
javascript php html json chart.js
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
add a comment |
0
I tried to create a multi bar chart using chartjs.But jobType and jobCount is not displayed according to the each companyName.
Here is the table
Here is the php file(CompanySeletion.php):
<?php
header('Content-Type:application/json');
define('DB_HOST','127.0.0.1');
define('DB_USERNAME','root');
define('DB_PASSWORD','');
define('DB_NAME','newmanpower');
$mysqli =new mysqli(DB_HOST,DB_USERNAME,DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: ".$mysqli->error);
}
//$selected = $_GET['Month'];
$selected=3;
$query = sprintf("SELECT jobType,jobCount,comName FROM graphview group by jobType,comName");
$result= $mysqli->query($query);
$data =array();
foreach ($result as $row){
$data= $row;
}
$result->close();
$mysqli->close();
print json_encode($data);
?>
Here is the JS file(testingbutton.js):
$(document).ready(function(){
$.ajax({
url: "http://localhost/chartjs/CompanySeletion.php",
method: "GET",
success: function (data) {
console.log(data);
var jobType = ;
var jobCount = ;
var comName=;
var chartColors = {
green: 'rgb(70, 214, 8)',
red: 'rgb(242, 26, 2)'
};
for (var i in data)
{
jobType.push( data[i].jobType);
jobCount.push(data[i].jobCount);
comName.push(data[i].comName);
}
var ctx = document.getElementById("mycanvas").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: jobType,
datasets: [{
label: comName[0],
data: jobCount(comName[0]),
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
{
label: comName[1],
data: jobCount ,
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
]
},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
var colorChangeValue = 1;
var dataset = myChart.data.datasets[0];
var dataset = myChart.data.datasets[1];
for (var i = 0; i < dataset.data.length; i++) {
if (dataset.data[i] > colorChangeValue) {
dataset.backgroundColor[i] = chartColors.green;
}
else {
dataset.backgroundColor[i] = chartColors.red;
}
}
myChart.update();
},
error: function (data) {
console.log(data);
}
});
});
Here is the HTML file:
<!DOCTYPE html>
<html>
<head>
<script src="jquery-3.0.0.js"></script>
<script src="jquery-ui.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="https://code.jquery.com/color/jquery.color-2.1.2.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.2.1/Chart.bundle.js"></script>
<link rel="stylesheet" href="stylesheet.css">
<style type="text/css">
#chart-container {
width: 640px;
heigth: auto;
}
</style>
<title>Job Progress</title>
</head>
<body>
<canvas height='75' width='200' id="mycanvas"></canvas>
<!-- javascript -->
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/Chart.min.js"></script>
<script type="text/javascript" src="js/testingbutton.js"></script>
</body>
</html>
Here is the received output according to the above code samples:
In the above graph, it shows same job type twice.Can anyone suggest a solution for that?
javascript php html json chart.js
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
add a comment |
0
0
0
I tried to create a multi bar chart using chartjs.But jobType and jobCount is not displayed according to the each companyName.
Here is the table
Here is the php file(CompanySeletion.php):
<?php
header('Content-Type:application/json');
define('DB_HOST','127.0.0.1');
define('DB_USERNAME','root');
define('DB_PASSWORD','');
define('DB_NAME','newmanpower');
$mysqli =new mysqli(DB_HOST,DB_USERNAME,DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: ".$mysqli->error);
}
//$selected = $_GET['Month'];
$selected=3;
$query = sprintf("SELECT jobType,jobCount,comName FROM graphview group by jobType,comName");
$result= $mysqli->query($query);
$data =array();
foreach ($result as $row){
$data= $row;
}
$result->close();
$mysqli->close();
print json_encode($data);
?>
Here is the JS file(testingbutton.js):
$(document).ready(function(){
$.ajax({
url: "http://localhost/chartjs/CompanySeletion.php",
method: "GET",
success: function (data) {
console.log(data);
var jobType = ;
var jobCount = ;
var comName=;
var chartColors = {
green: 'rgb(70, 214, 8)',
red: 'rgb(242, 26, 2)'
};
for (var i in data)
{
jobType.push( data[i].jobType);
jobCount.push(data[i].jobCount);
comName.push(data[i].comName);
}
var ctx = document.getElementById("mycanvas").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: jobType,
datasets: [{
label: comName[0],
data: jobCount(comName[0]),
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
{
label: comName[1],
data: jobCount ,
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
]
},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
var colorChangeValue = 1;
var dataset = myChart.data.datasets[0];
var dataset = myChart.data.datasets[1];
for (var i = 0; i < dataset.data.length; i++) {
if (dataset.data[i] > colorChangeValue) {
dataset.backgroundColor[i] = chartColors.green;
}
else {
dataset.backgroundColor[i] = chartColors.red;
}
}
myChart.update();
},
error: function (data) {
console.log(data);
}
});
});
Here is the HTML file:
<!DOCTYPE html>
<html>
<head>
<script src="jquery-3.0.0.js"></script>
<script src="jquery-ui.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="https://code.jquery.com/color/jquery.color-2.1.2.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.2.1/Chart.bundle.js"></script>
<link rel="stylesheet" href="stylesheet.css">
<style type="text/css">
#chart-container {
width: 640px;
heigth: auto;
}
</style>
<title>Job Progress</title>
</head>
<body>
<canvas height='75' width='200' id="mycanvas"></canvas>
<!-- javascript -->
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/Chart.min.js"></script>
<script type="text/javascript" src="js/testingbutton.js"></script>
</body>
</html>
Here is the received output according to the above code samples:
In the above graph, it shows same job type twice.Can anyone suggest a solution for that?
javascript php html json chart.js
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
I tried to create a multi bar chart using chartjs.But jobType and jobCount is not displayed according to the each companyName.
Here is the table
Here is the php file(CompanySeletion.php):
<?php
header('Content-Type:application/json');
define('DB_HOST','127.0.0.1');
define('DB_USERNAME','root');
define('DB_PASSWORD','');
define('DB_NAME','newmanpower');
$mysqli =new mysqli(DB_HOST,DB_USERNAME,DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: ".$mysqli->error);
}
//$selected = $_GET['Month'];
$selected=3;
$query = sprintf("SELECT jobType,jobCount,comName FROM graphview group by jobType,comName");
$result= $mysqli->query($query);
$data =array();
foreach ($result as $row){
$data= $row;
}
$result->close();
$mysqli->close();
print json_encode($data);
?>
Here is the JS file(testingbutton.js):
$(document).ready(function(){
$.ajax({
url: "http://localhost/chartjs/CompanySeletion.php",
method: "GET",
success: function (data) {
console.log(data);
var jobType = ;
var jobCount = ;
var comName=;
var chartColors = {
green: 'rgb(70, 214, 8)',
red: 'rgb(242, 26, 2)'
};
for (var i in data)
{
jobType.push( data[i].jobType);
jobCount.push(data[i].jobCount);
comName.push(data[i].comName);
}
var ctx = document.getElementById("mycanvas").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: jobType,
datasets: [{
label: comName[0],
data: jobCount(comName[0]),
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
{
label: comName[1],
data: jobCount ,
backgroundColor: ,
borderColor: ,
borderWidth: 1
},
]
},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
var colorChangeValue = 1;
var dataset = myChart.data.datasets[0];
var dataset = myChart.data.datasets[1];
for (var i = 0; i < dataset.data.length; i++) {
if (dataset.data[i] > colorChangeValue) {
dataset.backgroundColor[i] = chartColors.green;
}
else {
dataset.backgroundColor[i] = chartColors.red;
}
}
myChart.update();
},
error: function (data) {
console.log(data);
}
});
});
Here is the HTML file:
<!DOCTYPE html>
<html>
<head>
<script src="jquery-3.0.0.js"></script>
<script src="jquery-ui.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="https://code.jquery.com/color/jquery.color-2.1.2.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.2.1/Chart.bundle.js"></script>
<link rel="stylesheet" href="stylesheet.css">
<style type="text/css">
#chart-container {
width: 640px;
heigth: auto;
}
</style>
<title>Job Progress</title>
</head>
<body>
<canvas height='75' width='200' id="mycanvas"></canvas>
<!-- javascript -->
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/Chart.min.js"></script>
<script type="text/javascript" src="js/testingbutton.js"></script>
</body>
</html>
Here is the received output according to the above code samples:
In the above graph, it shows same job type twice.Can anyone suggest a solution for that?
javascript php html json chart.js
javascript php html json chart.js
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
edited Jan 1 at 7:13
Pasindu Senarath
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
asked Jan 1 at 7:02
Pasindu SenarathPasindu Senarath
117116
117116
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
You should pass the data in the below way to get the desired output. All the items which need to be showed in x-axis should be passed in the labels array, then each dataset i.e. "Pearson" and "srinath" should be passed as a separate dataset with data as corresponding values for the x-axis. Fiddle -> http://jsfiddle.net/Lzo5g01n/25/
var ctx = document.getElementById("myChart").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["CPI", "Cutting", "Ironing", "Mending"],
datasets: [{
label: 'Pearson',
data: [1, 1, 0, 1],
backgroundColor: 'rgba(255, 99, 132, 0.2)',
borderColor: 'rgba(255,99,132,1)',
borderWidth: 1
},{
label: 'srinath',
data: [1, 0, 1, 0],
backgroundColor: 'rgba(54, 162, 235, 0.2)',
borderColor: 'rgba(54, 162, 235, 1)',
borderWidth: 1
}
]},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
1
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You should pass the data in the below way to get the desired output. All the items which need to be showed in x-axis should be passed in the labels array, then each dataset i.e. "Pearson" and "srinath" should be passed as a separate dataset with data as corresponding values for the x-axis. Fiddle -> http://jsfiddle.net/Lzo5g01n/25/
var ctx = document.getElementById("myChart").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["CPI", "Cutting", "Ironing", "Mending"],
datasets: [{
label: 'Pearson',
data: [1, 1, 0, 1],
backgroundColor: 'rgba(255, 99, 132, 0.2)',
borderColor: 'rgba(255,99,132,1)',
borderWidth: 1
},{
label: 'srinath',
data: [1, 0, 1, 0],
backgroundColor: 'rgba(54, 162, 235, 0.2)',
borderColor: 'rgba(54, 162, 235, 1)',
borderWidth: 1
}
]},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
1
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
add a comment |
1
You should pass the data in the below way to get the desired output. All the items which need to be showed in x-axis should be passed in the labels array, then each dataset i.e. "Pearson" and "srinath" should be passed as a separate dataset with data as corresponding values for the x-axis. Fiddle -> http://jsfiddle.net/Lzo5g01n/25/
var ctx = document.getElementById("myChart").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["CPI", "Cutting", "Ironing", "Mending"],
datasets: [{
label: 'Pearson',
data: [1, 1, 0, 1],
backgroundColor: 'rgba(255, 99, 132, 0.2)',
borderColor: 'rgba(255,99,132,1)',
borderWidth: 1
},{
label: 'srinath',
data: [1, 0, 1, 0],
backgroundColor: 'rgba(54, 162, 235, 0.2)',
borderColor: 'rgba(54, 162, 235, 1)',
borderWidth: 1
}
]},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
1
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
add a comment |
1
1
1
You should pass the data in the below way to get the desired output. All the items which need to be showed in x-axis should be passed in the labels array, then each dataset i.e. "Pearson" and "srinath" should be passed as a separate dataset with data as corresponding values for the x-axis. Fiddle -> http://jsfiddle.net/Lzo5g01n/25/
var ctx = document.getElementById("myChart").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["CPI", "Cutting", "Ironing", "Mending"],
datasets: [{
label: 'Pearson',
data: [1, 1, 0, 1],
backgroundColor: 'rgba(255, 99, 132, 0.2)',
borderColor: 'rgba(255,99,132,1)',
borderWidth: 1
},{
label: 'srinath',
data: [1, 0, 1, 0],
backgroundColor: 'rgba(54, 162, 235, 0.2)',
borderColor: 'rgba(54, 162, 235, 1)',
borderWidth: 1
}
]},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
You should pass the data in the below way to get the desired output. All the items which need to be showed in x-axis should be passed in the labels array, then each dataset i.e. "Pearson" and "srinath" should be passed as a separate dataset with data as corresponding values for the x-axis. Fiddle -> http://jsfiddle.net/Lzo5g01n/25/
var ctx = document.getElementById("myChart").getContext('2d');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["CPI", "Cutting", "Ironing", "Mending"],
datasets: [{
label: 'Pearson',
data: [1, 1, 0, 1],
backgroundColor: 'rgba(255, 99, 132, 0.2)',
borderColor: 'rgba(255,99,132,1)',
borderWidth: 1
},{
label: 'srinath',
data: [1, 0, 1, 0],
backgroundColor: 'rgba(54, 162, 235, 0.2)',
borderColor: 'rgba(54, 162, 235, 1)',
borderWidth: 1
}
]},
options: {
scales: {
yAxes: [{
ticks: {
beginAtZero:true
}
}]
}
}
});
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
answered Jan 2 at 11:27
Kunal KhivensaraKunal Khivensara
629413
629413
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
1
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
add a comment |
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
1
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
i want it using array. you just hard coded data to the array.what if i change the data in database? :(
– Pasindu Senarath
Jan 2 at 15:12
1
1
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
It shows how the data should be passed to get the desired result, you need to have a business logic that will parse the data from the SQL server in the above-said format.
– Kunal Khivensara
Jan 3 at 3:23
add a comment |
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