Define Rank Javascript/Jquery












2















I try to define the rank cars from most expensive to least expensive, using javascript, but I don’t know how to make it the rank.



For now, I am still using the data object array.



<script>
var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

console.log(cars);
</script>




So I Hope get output like this:



[{mobil : "Kijang Inova", "price" : 300, rank : 1},
{mobil : "Expander, "price" :200, rank : 2},
{mobil : "Nissan, "price" : 180, rank : 3}]









share|improve this question




















  • 1





    Possible duplicate of Sorting arrays in javascript by object key value

    – Dmitry
    Jan 1 at 7:08
















2















I try to define the rank cars from most expensive to least expensive, using javascript, but I don’t know how to make it the rank.



For now, I am still using the data object array.



<script>
var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

console.log(cars);
</script>




So I Hope get output like this:



[{mobil : "Kijang Inova", "price" : 300, rank : 1},
{mobil : "Expander, "price" :200, rank : 2},
{mobil : "Nissan, "price" : 180, rank : 3}]









share|improve this question




















  • 1





    Possible duplicate of Sorting arrays in javascript by object key value

    – Dmitry
    Jan 1 at 7:08














2












2








2








I try to define the rank cars from most expensive to least expensive, using javascript, but I don’t know how to make it the rank.



For now, I am still using the data object array.



<script>
var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

console.log(cars);
</script>




So I Hope get output like this:



[{mobil : "Kijang Inova", "price" : 300, rank : 1},
{mobil : "Expander, "price" :200, rank : 2},
{mobil : "Nissan, "price" : 180, rank : 3}]









share|improve this question
















I try to define the rank cars from most expensive to least expensive, using javascript, but I don’t know how to make it the rank.



For now, I am still using the data object array.



<script>
var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

console.log(cars);
</script>




So I Hope get output like this:



[{mobil : "Kijang Inova", "price" : 300, rank : 1},
{mobil : "Expander, "price" :200, rank : 2},
{mobil : "Nissan, "price" : 180, rank : 3}]






javascript sorting






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edited Jan 1 at 10:56









Lloyd Nicholson

300110




300110










asked Jan 1 at 7:01









kayum imankayum iman

1913




1913








  • 1





    Possible duplicate of Sorting arrays in javascript by object key value

    – Dmitry
    Jan 1 at 7:08














  • 1





    Possible duplicate of Sorting arrays in javascript by object key value

    – Dmitry
    Jan 1 at 7:08








1




1





Possible duplicate of Sorting arrays in javascript by object key value

– Dmitry
Jan 1 at 7:08





Possible duplicate of Sorting arrays in javascript by object key value

– Dmitry
Jan 1 at 7:08












1 Answer
1






active

oldest

votes


















1














You could do this






var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);








share|improve this answer
























  • its work...amazing, great...thanks verry much :D

    – kayum iman
    Jan 1 at 7:46













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You could do this






var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);








share|improve this answer
























  • its work...amazing, great...thanks verry much :D

    – kayum iman
    Jan 1 at 7:46


















1














You could do this






var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);








share|improve this answer
























  • its work...amazing, great...thanks verry much :D

    – kayum iman
    Jan 1 at 7:46
















1












1








1







You could do this






var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);








share|improve this answer













You could do this






var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);








var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);





var cars = ;
cars.push({"mobil" : "Kijang Inova", "price" : 300});
cars.push({"mobil" : "Nissan", "price" : 180});
cars.push({"mobil" : "Expander", "price" : 200});

let rank = 1;

cars.sort((a,b) => {
return b['price'] - a['price']
});
cars.forEach(car => {
car.rank = rank;
rank ++;
});
console.log(cars);






share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 1 at 7:30









ibn_Abubakreibn_Abubakre

775




775













  • its work...amazing, great...thanks verry much :D

    – kayum iman
    Jan 1 at 7:46





















  • its work...amazing, great...thanks verry much :D

    – kayum iman
    Jan 1 at 7:46



















its work...amazing, great...thanks verry much :D

– kayum iman
Jan 1 at 7:46







its work...amazing, great...thanks verry much :D

– kayum iman
Jan 1 at 7:46






















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