Aggregate query for count for pivot table without using join












0















I have following MySQL query that I am using in laravel for getting pivot table counts.



select tracks.*, track_play_counts.track_id, count(track_play_counts.id) as track_play
from tracks
join track_play_counts on tracks.id = track_play_counts.track_id
group by track_id
order by track_play ;


it is taking too much time about 20 sec for larger amount of data. How can i reduce it?



I have already tried withCount() but it is used as filter query also so I can not use withCount here.



Is the way from that I can select particular field like track_play without using join? I realize that because of joining it is taking too much response time.










share|improve this question

























  • Have you indexed the foreign key??

    – Shibon
    Dec 31 '18 at 6:46











  • yes, i already indexed foreign key. what can be the other reason for it?

    – unknown
    Dec 31 '18 at 6:56













  • See meta.stackoverflow.com/questions/333952/…. In addition, questions about query performance always require the EXPLAIN for the given query.

    – Strawberry
    Dec 31 '18 at 9:05











  • Sample schema for what i want sqlfiddle.com/#!9/bac61a/5

    – unknown
    Dec 31 '18 at 9:45













  • Usually indexing is the solution. Everything of course depends on what is "larger amount of data" exactly.

    – James Z
    Dec 31 '18 at 11:45
















0















I have following MySQL query that I am using in laravel for getting pivot table counts.



select tracks.*, track_play_counts.track_id, count(track_play_counts.id) as track_play
from tracks
join track_play_counts on tracks.id = track_play_counts.track_id
group by track_id
order by track_play ;


it is taking too much time about 20 sec for larger amount of data. How can i reduce it?



I have already tried withCount() but it is used as filter query also so I can not use withCount here.



Is the way from that I can select particular field like track_play without using join? I realize that because of joining it is taking too much response time.










share|improve this question

























  • Have you indexed the foreign key??

    – Shibon
    Dec 31 '18 at 6:46











  • yes, i already indexed foreign key. what can be the other reason for it?

    – unknown
    Dec 31 '18 at 6:56













  • See meta.stackoverflow.com/questions/333952/…. In addition, questions about query performance always require the EXPLAIN for the given query.

    – Strawberry
    Dec 31 '18 at 9:05











  • Sample schema for what i want sqlfiddle.com/#!9/bac61a/5

    – unknown
    Dec 31 '18 at 9:45













  • Usually indexing is the solution. Everything of course depends on what is "larger amount of data" exactly.

    – James Z
    Dec 31 '18 at 11:45














0












0








0








I have following MySQL query that I am using in laravel for getting pivot table counts.



select tracks.*, track_play_counts.track_id, count(track_play_counts.id) as track_play
from tracks
join track_play_counts on tracks.id = track_play_counts.track_id
group by track_id
order by track_play ;


it is taking too much time about 20 sec for larger amount of data. How can i reduce it?



I have already tried withCount() but it is used as filter query also so I can not use withCount here.



Is the way from that I can select particular field like track_play without using join? I realize that because of joining it is taking too much response time.










share|improve this question
















I have following MySQL query that I am using in laravel for getting pivot table counts.



select tracks.*, track_play_counts.track_id, count(track_play_counts.id) as track_play
from tracks
join track_play_counts on tracks.id = track_play_counts.track_id
group by track_id
order by track_play ;


it is taking too much time about 20 sec for larger amount of data. How can i reduce it?



I have already tried withCount() but it is used as filter query also so I can not use withCount here.



Is the way from that I can select particular field like track_play without using join? I realize that because of joining it is taking too much response time.







php mysql laravel laravel-5.6






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 31 '18 at 11:43









James Z

11.2k71935




11.2k71935










asked Dec 31 '18 at 6:37









unknownunknown

207




207













  • Have you indexed the foreign key??

    – Shibon
    Dec 31 '18 at 6:46











  • yes, i already indexed foreign key. what can be the other reason for it?

    – unknown
    Dec 31 '18 at 6:56













  • See meta.stackoverflow.com/questions/333952/…. In addition, questions about query performance always require the EXPLAIN for the given query.

    – Strawberry
    Dec 31 '18 at 9:05











  • Sample schema for what i want sqlfiddle.com/#!9/bac61a/5

    – unknown
    Dec 31 '18 at 9:45













  • Usually indexing is the solution. Everything of course depends on what is "larger amount of data" exactly.

    – James Z
    Dec 31 '18 at 11:45



















  • Have you indexed the foreign key??

    – Shibon
    Dec 31 '18 at 6:46











  • yes, i already indexed foreign key. what can be the other reason for it?

    – unknown
    Dec 31 '18 at 6:56













  • See meta.stackoverflow.com/questions/333952/…. In addition, questions about query performance always require the EXPLAIN for the given query.

    – Strawberry
    Dec 31 '18 at 9:05











  • Sample schema for what i want sqlfiddle.com/#!9/bac61a/5

    – unknown
    Dec 31 '18 at 9:45













  • Usually indexing is the solution. Everything of course depends on what is "larger amount of data" exactly.

    – James Z
    Dec 31 '18 at 11:45

















Have you indexed the foreign key??

– Shibon
Dec 31 '18 at 6:46





Have you indexed the foreign key??

– Shibon
Dec 31 '18 at 6:46













yes, i already indexed foreign key. what can be the other reason for it?

– unknown
Dec 31 '18 at 6:56







yes, i already indexed foreign key. what can be the other reason for it?

– unknown
Dec 31 '18 at 6:56















See meta.stackoverflow.com/questions/333952/…. In addition, questions about query performance always require the EXPLAIN for the given query.

– Strawberry
Dec 31 '18 at 9:05





See meta.stackoverflow.com/questions/333952/…. In addition, questions about query performance always require the EXPLAIN for the given query.

– Strawberry
Dec 31 '18 at 9:05













Sample schema for what i want sqlfiddle.com/#!9/bac61a/5

– unknown
Dec 31 '18 at 9:45







Sample schema for what i want sqlfiddle.com/#!9/bac61a/5

– unknown
Dec 31 '18 at 9:45















Usually indexing is the solution. Everything of course depends on what is "larger amount of data" exactly.

– James Z
Dec 31 '18 at 11:45





Usually indexing is the solution. Everything of course depends on what is "larger amount of data" exactly.

– James Z
Dec 31 '18 at 11:45












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