JAVA: Iterating vertical object values in a collection to horizontal object values
0
I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:
List<BookFormat> book= new ArrayList<BookFormat>();
book.add(1,A,A0);
book.add(1,A,A1);
book.add(1,A,A2);
book.add(2,B,A1);
book.add(2,B,A2);
book.add(3,C,A4);
book.add(4,D,A0);
book.add(4,D,A2);
book.add(4,D,A3);
Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.
class BookFormatNew{
String BookID,
String BookSeries,
String A0,
String A1,
String A2,
String A3,
String A4}
where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.
The expected output result should be something like this
List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();
bookNew.add(1,A,T,T,T,F,F);
bookNew.add(2,B,F,T,T,F,F);
bookNew.add(3,C,F,F,F,F,T);
bookNew.add(4,D,T,F,T,T,F);
How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?
Thanks for taking out your time!
java
android arrays edited Dec 31 '18 at 7:10
Nagesh Katna
409516
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
add a comment |
0
I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:
List<BookFormat> book= new ArrayList<BookFormat>();
book.add(1,A,A0);
book.add(1,A,A1);
book.add(1,A,A2);
book.add(2,B,A1);
book.add(2,B,A2);
book.add(3,C,A4);
book.add(4,D,A0);
book.add(4,D,A2);
book.add(4,D,A3);
Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.
class BookFormatNew{
String BookID,
String BookSeries,
String A0,
String A1,
String A2,
String A3,
String A4}
where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.
The expected output result should be something like this
List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();
bookNew.add(1,A,T,T,T,F,F);
bookNew.add(2,B,F,T,T,F,F);
bookNew.add(3,C,F,F,F,F,T);
bookNew.add(4,D,T,F,T,T,F);
How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?
Thanks for taking out your time!
java
android arrays edited Dec 31 '18 at 7:10
Nagesh Katna
409516
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
add a comment |
0
0
0
I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:
List<BookFormat> book= new ArrayList<BookFormat>();
book.add(1,A,A0);
book.add(1,A,A1);
book.add(1,A,A2);
book.add(2,B,A1);
book.add(2,B,A2);
book.add(3,C,A4);
book.add(4,D,A0);
book.add(4,D,A2);
book.add(4,D,A3);
Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.
class BookFormatNew{
String BookID,
String BookSeries,
String A0,
String A1,
String A2,
String A3,
String A4}
where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.
The expected output result should be something like this
List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();
bookNew.add(1,A,T,T,T,F,F);
bookNew.add(2,B,F,T,T,F,F);
bookNew.add(3,C,F,F,F,F,T);
bookNew.add(4,D,T,F,T,T,F);
How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?
Thanks for taking out your time!
java
android arrays edited Dec 31 '18 at 7:10
Nagesh Katna
409516
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:
List<BookFormat> book= new ArrayList<BookFormat>();
book.add(1,A,A0);
book.add(1,A,A1);
book.add(1,A,A2);
book.add(2,B,A1);
book.add(2,B,A2);
book.add(3,C,A4);
book.add(4,D,A0);
book.add(4,D,A2);
book.add(4,D,A3);
Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.
class BookFormatNew{
String BookID,
String BookSeries,
String A0,
String A1,
String A2,
String A3,
String A4}
where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.
The expected output result should be something like this
List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();
bookNew.add(1,A,T,T,T,F,F);
bookNew.add(2,B,F,T,T,F,F);
bookNew.add(3,C,F,F,F,F,T);
bookNew.add(4,D,T,F,T,T,F);
How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?
Thanks for taking out your time!
java
android arrays java
android arrays edited Dec 31 '18 at 7:10
Nagesh Katna
409516
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
edited Dec 31 '18 at 7:10
Nagesh Katna
409516
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
edited Dec 31 '18 at 7:10
Nagesh Katna
409516
edited Dec 31 '18 at 7:10
Nagesh Katna
409516
edited Dec 31 '18 at 7:10
Nagesh Katna
409516
409516
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
asked Dec 31 '18 at 6:46
Hussain Abdul MajeedHussain Abdul Majeed
33
33
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
You can use Map while iterating vertical list.
HashMap<Integer, BookFormatNew> map = new HashMap<>();
for(BookFormat b: book){
BookFormatNew bfn = map.get(b.getBookId());
if(bfn == null){
// Create new EntryPair and add
BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
map.put(b.getBookId(), bfn_new);
bfn = map.get(b.getBookId());
}
if(b.getFormat().equals("A0"){
bfn.setA0("T");
}
else if(b.getFormat().equals("A1"){
bfn.setA1("T");
}
else if(b.getFormat().equals("A2"){
bfn.setA2("T");
}
else if(b.getFormat().equals("A3"){
bfn.setA3("T");
}
else if(b.getFormat().equals("A4"){
bfn.setA4("T");
}
map.put(b.getBookId(),bfn); // Puts updated T,F set
}
Then iterate through the map and add it to new horizontal list if necessary or use the map itself.
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
|
show 7 more comments
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1 Answer
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1 Answer
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0
You can use Map while iterating vertical list.
HashMap<Integer, BookFormatNew> map = new HashMap<>();
for(BookFormat b: book){
BookFormatNew bfn = map.get(b.getBookId());
if(bfn == null){
// Create new EntryPair and add
BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
map.put(b.getBookId(), bfn_new);
bfn = map.get(b.getBookId());
}
if(b.getFormat().equals("A0"){
bfn.setA0("T");
}
else if(b.getFormat().equals("A1"){
bfn.setA1("T");
}
else if(b.getFormat().equals("A2"){
bfn.setA2("T");
}
else if(b.getFormat().equals("A3"){
bfn.setA3("T");
}
else if(b.getFormat().equals("A4"){
bfn.setA4("T");
}
map.put(b.getBookId(),bfn); // Puts updated T,F set
}
Then iterate through the map and add it to new horizontal list if necessary or use the map itself.
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
|
show 7 more comments
0
You can use Map while iterating vertical list.
HashMap<Integer, BookFormatNew> map = new HashMap<>();
for(BookFormat b: book){
BookFormatNew bfn = map.get(b.getBookId());
if(bfn == null){
// Create new EntryPair and add
BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
map.put(b.getBookId(), bfn_new);
bfn = map.get(b.getBookId());
}
if(b.getFormat().equals("A0"){
bfn.setA0("T");
}
else if(b.getFormat().equals("A1"){
bfn.setA1("T");
}
else if(b.getFormat().equals("A2"){
bfn.setA2("T");
}
else if(b.getFormat().equals("A3"){
bfn.setA3("T");
}
else if(b.getFormat().equals("A4"){
bfn.setA4("T");
}
map.put(b.getBookId(),bfn); // Puts updated T,F set
}
Then iterate through the map and add it to new horizontal list if necessary or use the map itself.
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
|
show 7 more comments
0
0
0
You can use Map while iterating vertical list.
HashMap<Integer, BookFormatNew> map = new HashMap<>();
for(BookFormat b: book){
BookFormatNew bfn = map.get(b.getBookId());
if(bfn == null){
// Create new EntryPair and add
BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
map.put(b.getBookId(), bfn_new);
bfn = map.get(b.getBookId());
}
if(b.getFormat().equals("A0"){
bfn.setA0("T");
}
else if(b.getFormat().equals("A1"){
bfn.setA1("T");
}
else if(b.getFormat().equals("A2"){
bfn.setA2("T");
}
else if(b.getFormat().equals("A3"){
bfn.setA3("T");
}
else if(b.getFormat().equals("A4"){
bfn.setA4("T");
}
map.put(b.getBookId(),bfn); // Puts updated T,F set
}
Then iterate through the map and add it to new horizontal list if necessary or use the map itself.
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
You can use Map while iterating vertical list.
HashMap<Integer, BookFormatNew> map = new HashMap<>();
for(BookFormat b: book){
BookFormatNew bfn = map.get(b.getBookId());
if(bfn == null){
// Create new EntryPair and add
BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
map.put(b.getBookId(), bfn_new);
bfn = map.get(b.getBookId());
}
if(b.getFormat().equals("A0"){
bfn.setA0("T");
}
else if(b.getFormat().equals("A1"){
bfn.setA1("T");
}
else if(b.getFormat().equals("A2"){
bfn.setA2("T");
}
else if(b.getFormat().equals("A3"){
bfn.setA3("T");
}
else if(b.getFormat().equals("A4"){
bfn.setA4("T");
}
map.put(b.getBookId(),bfn); // Puts updated T,F set
}
Then iterate through the map and add it to new horizontal list if necessary or use the map itself.
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
edited Dec 31 '18 at 10:23
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
answered Dec 31 '18 at 7:22
okcomputer_kidokcomputer_kid
33839
33839
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
|
show 7 more comments
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
What is bfn_new here?
– Hussain Abdul Majeed
Dec 31 '18 at 8:32
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.
– okcomputer_kid
Dec 31 '18 at 8:36
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
How do you create one?
– Hussain Abdul Majeed
Dec 31 '18 at 9:16
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
I have updated answer with complete code. That gives you required hashmap
– okcomputer_kid
Dec 31 '18 at 9:33
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?
– Hussain Abdul Majeed
Dec 31 '18 at 10:22
|
show 7 more comments
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