JAVA: Iterating vertical object values in a collection to horizontal object values












0















I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:



List<BookFormat> book= new ArrayList<BookFormat>();

book.add(1,A,A0);
book.add(1,A,A1);
book.add(1,A,A2);
book.add(2,B,A1);
book.add(2,B,A2);
book.add(3,C,A4);
book.add(4,D,A0);
book.add(4,D,A2);
book.add(4,D,A3);


Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.



class BookFormatNew{
String BookID,
String BookSeries,
String A0,
String A1,
String A2,
String A3,
String A4}


where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.



The expected output result should be something like this



List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();

bookNew.add(1,A,T,T,T,F,F);
bookNew.add(2,B,F,T,T,F,F);
bookNew.add(3,C,F,F,F,F,T);
bookNew.add(4,D,T,F,T,T,F);


How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?



Thanks for taking out your time!










share|improve this question





























    0















    I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:



    List<BookFormat> book= new ArrayList<BookFormat>();

    book.add(1,A,A0);
    book.add(1,A,A1);
    book.add(1,A,A2);
    book.add(2,B,A1);
    book.add(2,B,A2);
    book.add(3,C,A4);
    book.add(4,D,A0);
    book.add(4,D,A2);
    book.add(4,D,A3);


    Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.



    class BookFormatNew{
    String BookID,
    String BookSeries,
    String A0,
    String A1,
    String A2,
    String A3,
    String A4}


    where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.



    The expected output result should be something like this



    List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();

    bookNew.add(1,A,T,T,T,F,F);
    bookNew.add(2,B,F,T,T,F,F);
    bookNew.add(3,C,F,F,F,F,T);
    bookNew.add(4,D,T,F,T,T,F);


    How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?



    Thanks for taking out your time!










    share|improve this question



























      0












      0








      0








      I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:



      List<BookFormat> book= new ArrayList<BookFormat>();

      book.add(1,A,A0);
      book.add(1,A,A1);
      book.add(1,A,A2);
      book.add(2,B,A1);
      book.add(2,B,A2);
      book.add(3,C,A4);
      book.add(4,D,A0);
      book.add(4,D,A2);
      book.add(4,D,A3);


      Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.



      class BookFormatNew{
      String BookID,
      String BookSeries,
      String A0,
      String A1,
      String A2,
      String A3,
      String A4}


      where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.



      The expected output result should be something like this



      List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();

      bookNew.add(1,A,T,T,T,F,F);
      bookNew.add(2,B,F,T,T,F,F);
      bookNew.add(3,C,F,F,F,F,T);
      bookNew.add(4,D,T,F,T,T,F);


      How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?



      Thanks for taking out your time!










      share|improve this question
















      I have a list of an object with 3 items that accepts BookID, bookseries, and Format as shown below:



      List<BookFormat> book= new ArrayList<BookFormat>();

      book.add(1,A,A0);
      book.add(1,A,A1);
      book.add(1,A,A2);
      book.add(2,B,A1);
      book.add(2,B,A2);
      book.add(3,C,A4);
      book.add(4,D,A0);
      book.add(4,D,A2);
      book.add(4,D,A3);


      Now I'm trying to sort it on the horizontal basis on the "BookID" on which I have created another new class object "BookFormatNew" that returns true or false if the specified "Format" is available or not.



      class BookFormatNew{
      String BookID,
      String BookSeries,
      String A0,
      String A1,
      String A2,
      String A3,
      String A4}


      where A0, A1, A2, A3, and A4 takes up "T" if the value is available or "F" if not.



      The expected output result should be something like this



      List<BookFormatNew> bookNew= new ArrayList<BookFormatNew>();

      bookNew.add(1,A,T,T,T,F,F);
      bookNew.add(2,B,F,T,T,F,F);
      bookNew.add(3,C,F,F,F,F,T);
      bookNew.add(4,D,T,F,T,T,F);


      How to iterate the vertical values for the BookFormat in order to get an output which is the NewBookFormat as horizontal values?



      Thanks for taking out your time!







      java android arrays






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Dec 31 '18 at 7:10









      Nagesh Katna

      409516




      409516










      asked Dec 31 '18 at 6:46









      Hussain Abdul MajeedHussain Abdul Majeed

      33




      33
























          1 Answer
          1






          active

          oldest

          votes


















          0














          You can use Map while iterating vertical list.



          HashMap<Integer, BookFormatNew> map = new HashMap<>();
          for(BookFormat b: book){
          BookFormatNew bfn = map.get(b.getBookId());
          if(bfn == null){
          // Create new EntryPair and add
          BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
          map.put(b.getBookId(), bfn_new);
          bfn = map.get(b.getBookId());
          }
          if(b.getFormat().equals("A0"){
          bfn.setA0("T");
          }
          else if(b.getFormat().equals("A1"){
          bfn.setA1("T");
          }
          else if(b.getFormat().equals("A2"){
          bfn.setA2("T");
          }
          else if(b.getFormat().equals("A3"){
          bfn.setA3("T");
          }
          else if(b.getFormat().equals("A4"){
          bfn.setA4("T");
          }

          map.put(b.getBookId(),bfn); // Puts updated T,F set
          }


          Then iterate through the map and add it to new horizontal list if necessary or use the map itself.






          share|improve this answer


























          • What is bfn_new here?

            – Hussain Abdul Majeed
            Dec 31 '18 at 8:32











          • New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

            – okcomputer_kid
            Dec 31 '18 at 8:36













          • How do you create one?

            – Hussain Abdul Majeed
            Dec 31 '18 at 9:16











          • I have updated answer with complete code. That gives you required hashmap

            – okcomputer_kid
            Dec 31 '18 at 9:33











          • Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

            – Hussain Abdul Majeed
            Dec 31 '18 at 10:22











          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53984447%2fjava-iterating-vertical-object-values-in-a-collection-to-horizontal-object-valu%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          You can use Map while iterating vertical list.



          HashMap<Integer, BookFormatNew> map = new HashMap<>();
          for(BookFormat b: book){
          BookFormatNew bfn = map.get(b.getBookId());
          if(bfn == null){
          // Create new EntryPair and add
          BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
          map.put(b.getBookId(), bfn_new);
          bfn = map.get(b.getBookId());
          }
          if(b.getFormat().equals("A0"){
          bfn.setA0("T");
          }
          else if(b.getFormat().equals("A1"){
          bfn.setA1("T");
          }
          else if(b.getFormat().equals("A2"){
          bfn.setA2("T");
          }
          else if(b.getFormat().equals("A3"){
          bfn.setA3("T");
          }
          else if(b.getFormat().equals("A4"){
          bfn.setA4("T");
          }

          map.put(b.getBookId(),bfn); // Puts updated T,F set
          }


          Then iterate through the map and add it to new horizontal list if necessary or use the map itself.






          share|improve this answer


























          • What is bfn_new here?

            – Hussain Abdul Majeed
            Dec 31 '18 at 8:32











          • New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

            – okcomputer_kid
            Dec 31 '18 at 8:36













          • How do you create one?

            – Hussain Abdul Majeed
            Dec 31 '18 at 9:16











          • I have updated answer with complete code. That gives you required hashmap

            – okcomputer_kid
            Dec 31 '18 at 9:33











          • Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

            – Hussain Abdul Majeed
            Dec 31 '18 at 10:22
















          0














          You can use Map while iterating vertical list.



          HashMap<Integer, BookFormatNew> map = new HashMap<>();
          for(BookFormat b: book){
          BookFormatNew bfn = map.get(b.getBookId());
          if(bfn == null){
          // Create new EntryPair and add
          BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
          map.put(b.getBookId(), bfn_new);
          bfn = map.get(b.getBookId());
          }
          if(b.getFormat().equals("A0"){
          bfn.setA0("T");
          }
          else if(b.getFormat().equals("A1"){
          bfn.setA1("T");
          }
          else if(b.getFormat().equals("A2"){
          bfn.setA2("T");
          }
          else if(b.getFormat().equals("A3"){
          bfn.setA3("T");
          }
          else if(b.getFormat().equals("A4"){
          bfn.setA4("T");
          }

          map.put(b.getBookId(),bfn); // Puts updated T,F set
          }


          Then iterate through the map and add it to new horizontal list if necessary or use the map itself.






          share|improve this answer


























          • What is bfn_new here?

            – Hussain Abdul Majeed
            Dec 31 '18 at 8:32











          • New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

            – okcomputer_kid
            Dec 31 '18 at 8:36













          • How do you create one?

            – Hussain Abdul Majeed
            Dec 31 '18 at 9:16











          • I have updated answer with complete code. That gives you required hashmap

            – okcomputer_kid
            Dec 31 '18 at 9:33











          • Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

            – Hussain Abdul Majeed
            Dec 31 '18 at 10:22














          0












          0








          0







          You can use Map while iterating vertical list.



          HashMap<Integer, BookFormatNew> map = new HashMap<>();
          for(BookFormat b: book){
          BookFormatNew bfn = map.get(b.getBookId());
          if(bfn == null){
          // Create new EntryPair and add
          BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
          map.put(b.getBookId(), bfn_new);
          bfn = map.get(b.getBookId());
          }
          if(b.getFormat().equals("A0"){
          bfn.setA0("T");
          }
          else if(b.getFormat().equals("A1"){
          bfn.setA1("T");
          }
          else if(b.getFormat().equals("A2"){
          bfn.setA2("T");
          }
          else if(b.getFormat().equals("A3"){
          bfn.setA3("T");
          }
          else if(b.getFormat().equals("A4"){
          bfn.setA4("T");
          }

          map.put(b.getBookId(),bfn); // Puts updated T,F set
          }


          Then iterate through the map and add it to new horizontal list if necessary or use the map itself.






          share|improve this answer















          You can use Map while iterating vertical list.



          HashMap<Integer, BookFormatNew> map = new HashMap<>();
          for(BookFormat b: book){
          BookFormatNew bfn = map.get(b.getBookId());
          if(bfn == null){
          // Create new EntryPair and add
          BookFormatNew bfn_new = new BookFormatNew(b.getBookId(), b.getBookSeries(), "F","F","F","F","F");
          map.put(b.getBookId(), bfn_new);
          bfn = map.get(b.getBookId());
          }
          if(b.getFormat().equals("A0"){
          bfn.setA0("T");
          }
          else if(b.getFormat().equals("A1"){
          bfn.setA1("T");
          }
          else if(b.getFormat().equals("A2"){
          bfn.setA2("T");
          }
          else if(b.getFormat().equals("A3"){
          bfn.setA3("T");
          }
          else if(b.getFormat().equals("A4"){
          bfn.setA4("T");
          }

          map.put(b.getBookId(),bfn); // Puts updated T,F set
          }


          Then iterate through the map and add it to new horizontal list if necessary or use the map itself.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Dec 31 '18 at 10:23

























          answered Dec 31 '18 at 7:22









          okcomputer_kidokcomputer_kid

          33839




          33839













          • What is bfn_new here?

            – Hussain Abdul Majeed
            Dec 31 '18 at 8:32











          • New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

            – okcomputer_kid
            Dec 31 '18 at 8:36













          • How do you create one?

            – Hussain Abdul Majeed
            Dec 31 '18 at 9:16











          • I have updated answer with complete code. That gives you required hashmap

            – okcomputer_kid
            Dec 31 '18 at 9:33











          • Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

            – Hussain Abdul Majeed
            Dec 31 '18 at 10:22



















          • What is bfn_new here?

            – Hussain Abdul Majeed
            Dec 31 '18 at 8:32











          • New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

            – okcomputer_kid
            Dec 31 '18 at 8:36













          • How do you create one?

            – Hussain Abdul Majeed
            Dec 31 '18 at 9:16











          • I have updated answer with complete code. That gives you required hashmap

            – okcomputer_kid
            Dec 31 '18 at 9:33











          • Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

            – Hussain Abdul Majeed
            Dec 31 '18 at 10:22

















          What is bfn_new here?

          – Hussain Abdul Majeed
          Dec 31 '18 at 8:32





          What is bfn_new here?

          – Hussain Abdul Majeed
          Dec 31 '18 at 8:32













          New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

          – okcomputer_kid
          Dec 31 '18 at 8:36







          New BookFormatNew Object. Since corresponding BookFormatNew doesn't exist yet in Map, create one and put it to map.

          – okcomputer_kid
          Dec 31 '18 at 8:36















          How do you create one?

          – Hussain Abdul Majeed
          Dec 31 '18 at 9:16





          How do you create one?

          – Hussain Abdul Majeed
          Dec 31 '18 at 9:16













          I have updated answer with complete code. That gives you required hashmap

          – okcomputer_kid
          Dec 31 '18 at 9:33





          I have updated answer with complete code. That gives you required hashmap

          – okcomputer_kid
          Dec 31 '18 at 9:33













          Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

          – Hussain Abdul Majeed
          Dec 31 '18 at 10:22





          Is this line "map.add(b.getBookId(), bfn_new);" supposed to be "map.put(b.getBookId(), bfn_new);"as HashMap doesnt have .add?

          – Hussain Abdul Majeed
          Dec 31 '18 at 10:22


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53984447%2fjava-iterating-vertical-object-values-in-a-collection-to-horizontal-object-valu%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Monofisismo

          Angular Downloading a file using contenturl with Basic Authentication

          Olmecas