How to wake Pic32 from sleep mode?












0















I am trying to keep PIC32 in sleep mode on boot up. And when the power button is pressed the Pic32 should exit the sleep mode and wake up.



I am able to put PIC32 in sleep mode but I am not sure how I can trigger it to wake up on button press.
Is it possible if I can trigger an interrupt whenever the user presses the power button and thus wake the PIC32?
I am using microchip harmony framework and am quite new to this can someone please suggest how I can achieve this?



To put PIC32 I am using the PowerEnterMode function of harmony. To wake up PIC32 I have tried using the watch dog timer following the sample project provided with microchip harmony but couldn't get it to work.
I also read that I can use external interrupt to set it up but I don't know how to set it up.



I have added my code below.



void APP_Initialize ( void )
{
DRV_ADC_Open();
DRV_ADC_Start();
PLIB_ADC_Enable(ADC_ID_1);

SPIHandle = DRV_SPI_Open(DRV_SPI_INDEX_0, DRV_IO_INTENT_READWRITE );
DelayMs(100);
SYS_DEVCON_PowerModeEnter(SYS_POWER_MODE_IDLE);

appData.state = APP_STATE_POWER_UP;
}

void APP_Tasks (void)
{
switch ( appData.state )
{
case APP_STATE_POWER_UP:
{
uint8_t pwrButton;
pwrButton = PWR_BTNStateGet() ;
if (npwrButton == 0) // If button is pressed
{
PwrButtonDebounce += 1; // Increment the pressed timer
DelayMs(10);
} else
{
PwrButtonDebounce = 0; // Clear the Debounce Timer
}
if (PwrButtonDebounce == MAX_DEBOUNCE) // Debounced....
{
// Here Wake up routine on button press
appData.state = APP_STATE_INIT;
}
}
}


I expect that whenever I press the power button the Pic32 should come in the APP_STATE_POWER_UP state and on debounce go in the initialization state but It never comes in this state.
Can someone suggest how I can set this up?










share|improve this question





























    0















    I am trying to keep PIC32 in sleep mode on boot up. And when the power button is pressed the Pic32 should exit the sleep mode and wake up.



    I am able to put PIC32 in sleep mode but I am not sure how I can trigger it to wake up on button press.
    Is it possible if I can trigger an interrupt whenever the user presses the power button and thus wake the PIC32?
    I am using microchip harmony framework and am quite new to this can someone please suggest how I can achieve this?



    To put PIC32 I am using the PowerEnterMode function of harmony. To wake up PIC32 I have tried using the watch dog timer following the sample project provided with microchip harmony but couldn't get it to work.
    I also read that I can use external interrupt to set it up but I don't know how to set it up.



    I have added my code below.



    void APP_Initialize ( void )
    {
    DRV_ADC_Open();
    DRV_ADC_Start();
    PLIB_ADC_Enable(ADC_ID_1);

    SPIHandle = DRV_SPI_Open(DRV_SPI_INDEX_0, DRV_IO_INTENT_READWRITE );
    DelayMs(100);
    SYS_DEVCON_PowerModeEnter(SYS_POWER_MODE_IDLE);

    appData.state = APP_STATE_POWER_UP;
    }

    void APP_Tasks (void)
    {
    switch ( appData.state )
    {
    case APP_STATE_POWER_UP:
    {
    uint8_t pwrButton;
    pwrButton = PWR_BTNStateGet() ;
    if (npwrButton == 0) // If button is pressed
    {
    PwrButtonDebounce += 1; // Increment the pressed timer
    DelayMs(10);
    } else
    {
    PwrButtonDebounce = 0; // Clear the Debounce Timer
    }
    if (PwrButtonDebounce == MAX_DEBOUNCE) // Debounced....
    {
    // Here Wake up routine on button press
    appData.state = APP_STATE_INIT;
    }
    }
    }


    I expect that whenever I press the power button the Pic32 should come in the APP_STATE_POWER_UP state and on debounce go in the initialization state but It never comes in this state.
    Can someone suggest how I can set this up?










    share|improve this question



























      0












      0








      0








      I am trying to keep PIC32 in sleep mode on boot up. And when the power button is pressed the Pic32 should exit the sleep mode and wake up.



      I am able to put PIC32 in sleep mode but I am not sure how I can trigger it to wake up on button press.
      Is it possible if I can trigger an interrupt whenever the user presses the power button and thus wake the PIC32?
      I am using microchip harmony framework and am quite new to this can someone please suggest how I can achieve this?



      To put PIC32 I am using the PowerEnterMode function of harmony. To wake up PIC32 I have tried using the watch dog timer following the sample project provided with microchip harmony but couldn't get it to work.
      I also read that I can use external interrupt to set it up but I don't know how to set it up.



      I have added my code below.



      void APP_Initialize ( void )
      {
      DRV_ADC_Open();
      DRV_ADC_Start();
      PLIB_ADC_Enable(ADC_ID_1);

      SPIHandle = DRV_SPI_Open(DRV_SPI_INDEX_0, DRV_IO_INTENT_READWRITE );
      DelayMs(100);
      SYS_DEVCON_PowerModeEnter(SYS_POWER_MODE_IDLE);

      appData.state = APP_STATE_POWER_UP;
      }

      void APP_Tasks (void)
      {
      switch ( appData.state )
      {
      case APP_STATE_POWER_UP:
      {
      uint8_t pwrButton;
      pwrButton = PWR_BTNStateGet() ;
      if (npwrButton == 0) // If button is pressed
      {
      PwrButtonDebounce += 1; // Increment the pressed timer
      DelayMs(10);
      } else
      {
      PwrButtonDebounce = 0; // Clear the Debounce Timer
      }
      if (PwrButtonDebounce == MAX_DEBOUNCE) // Debounced....
      {
      // Here Wake up routine on button press
      appData.state = APP_STATE_INIT;
      }
      }
      }


      I expect that whenever I press the power button the Pic32 should come in the APP_STATE_POWER_UP state and on debounce go in the initialization state but It never comes in this state.
      Can someone suggest how I can set this up?










      share|improve this question
















      I am trying to keep PIC32 in sleep mode on boot up. And when the power button is pressed the Pic32 should exit the sleep mode and wake up.



      I am able to put PIC32 in sleep mode but I am not sure how I can trigger it to wake up on button press.
      Is it possible if I can trigger an interrupt whenever the user presses the power button and thus wake the PIC32?
      I am using microchip harmony framework and am quite new to this can someone please suggest how I can achieve this?



      To put PIC32 I am using the PowerEnterMode function of harmony. To wake up PIC32 I have tried using the watch dog timer following the sample project provided with microchip harmony but couldn't get it to work.
      I also read that I can use external interrupt to set it up but I don't know how to set it up.



      I have added my code below.



      void APP_Initialize ( void )
      {
      DRV_ADC_Open();
      DRV_ADC_Start();
      PLIB_ADC_Enable(ADC_ID_1);

      SPIHandle = DRV_SPI_Open(DRV_SPI_INDEX_0, DRV_IO_INTENT_READWRITE );
      DelayMs(100);
      SYS_DEVCON_PowerModeEnter(SYS_POWER_MODE_IDLE);

      appData.state = APP_STATE_POWER_UP;
      }

      void APP_Tasks (void)
      {
      switch ( appData.state )
      {
      case APP_STATE_POWER_UP:
      {
      uint8_t pwrButton;
      pwrButton = PWR_BTNStateGet() ;
      if (npwrButton == 0) // If button is pressed
      {
      PwrButtonDebounce += 1; // Increment the pressed timer
      DelayMs(10);
      } else
      {
      PwrButtonDebounce = 0; // Clear the Debounce Timer
      }
      if (PwrButtonDebounce == MAX_DEBOUNCE) // Debounced....
      {
      // Here Wake up routine on button press
      appData.state = APP_STATE_INIT;
      }
      }
      }


      I expect that whenever I press the power button the Pic32 should come in the APP_STATE_POWER_UP state and on debounce go in the initialization state but It never comes in this state.
      Can someone suggest how I can set this up?







      c mplab pic32






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      edited Jan 2 at 11:58









      Mike

      2,0071621




      2,0071621










      asked Dec 28 '18 at 12:49









      abdullahabdullah

      63




      63
























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          0














          You should use Change Notification interrupt.



          Enable the CN interrupt on the pin that you have your button and it will wake your device when pressed.






          share|improve this answer























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            1 Answer
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            1 Answer
            1






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            active

            oldest

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            0














            You should use Change Notification interrupt.



            Enable the CN interrupt on the pin that you have your button and it will wake your device when pressed.






            share|improve this answer




























              0














              You should use Change Notification interrupt.



              Enable the CN interrupt on the pin that you have your button and it will wake your device when pressed.






              share|improve this answer


























                0












                0








                0







                You should use Change Notification interrupt.



                Enable the CN interrupt on the pin that you have your button and it will wake your device when pressed.






                share|improve this answer













                You should use Change Notification interrupt.



                Enable the CN interrupt on the pin that you have your button and it will wake your device when pressed.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Jan 5 at 11:40









                DamienDamien

                788316




                788316






























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