get the context of a created canvas with JQuery












-1















I'm trying to use this methods ( http://jsfiddle.net/erickzanardo/RHZL6/ ) to create a canvas with createElement and then draw on it, but since I'm using JQuery the canvas so created deosn't have a class function getContext("2d"), but it seems to work on the last jsfiddle.
My code is as follow :



 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
var map_rendered = document.createElement("map");
map_rendered.heigt = 100 ; map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");


the error I get is :



TypeError: map_rendered.getContext is not a function


Do you have a way to solve it, or any other method to create a pre-rendered map, my aim is then to display a subsection of this map in a smaller canvas.
Thanks.










share|improve this question




















  • 4





    map_rendered is a <map> element. You must use a <canvas> element if you hope .getContext('2d'); to succeed.

    – enhzflep
    Dec 28 '18 at 12:27






  • 1





    Also this has nothing to do with jQuery.

    – Mark Baijens
    Dec 28 '18 at 12:29
















-1















I'm trying to use this methods ( http://jsfiddle.net/erickzanardo/RHZL6/ ) to create a canvas with createElement and then draw on it, but since I'm using JQuery the canvas so created deosn't have a class function getContext("2d"), but it seems to work on the last jsfiddle.
My code is as follow :



 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
var map_rendered = document.createElement("map");
map_rendered.heigt = 100 ; map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");


the error I get is :



TypeError: map_rendered.getContext is not a function


Do you have a way to solve it, or any other method to create a pre-rendered map, my aim is then to display a subsection of this map in a smaller canvas.
Thanks.










share|improve this question




















  • 4





    map_rendered is a <map> element. You must use a <canvas> element if you hope .getContext('2d'); to succeed.

    – enhzflep
    Dec 28 '18 at 12:27






  • 1





    Also this has nothing to do with jQuery.

    – Mark Baijens
    Dec 28 '18 at 12:29














-1












-1








-1








I'm trying to use this methods ( http://jsfiddle.net/erickzanardo/RHZL6/ ) to create a canvas with createElement and then draw on it, but since I'm using JQuery the canvas so created deosn't have a class function getContext("2d"), but it seems to work on the last jsfiddle.
My code is as follow :



 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
var map_rendered = document.createElement("map");
map_rendered.heigt = 100 ; map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");


the error I get is :



TypeError: map_rendered.getContext is not a function


Do you have a way to solve it, or any other method to create a pre-rendered map, my aim is then to display a subsection of this map in a smaller canvas.
Thanks.










share|improve this question
















I'm trying to use this methods ( http://jsfiddle.net/erickzanardo/RHZL6/ ) to create a canvas with createElement and then draw on it, but since I'm using JQuery the canvas so created deosn't have a class function getContext("2d"), but it seems to work on the last jsfiddle.
My code is as follow :



 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
var map_rendered = document.createElement("map");
map_rendered.heigt = 100 ; map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");


the error I get is :



TypeError: map_rendered.getContext is not a function


Do you have a way to solve it, or any other method to create a pre-rendered map, my aim is then to display a subsection of this map in a smaller canvas.
Thanks.







javascript html canvas createelement






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share|improve this question













share|improve this question




share|improve this question








edited Dec 28 '18 at 13:09









Kaiido

39.7k45899




39.7k45899










asked Dec 28 '18 at 12:24









fraglothfragloth

42




42








  • 4





    map_rendered is a <map> element. You must use a <canvas> element if you hope .getContext('2d'); to succeed.

    – enhzflep
    Dec 28 '18 at 12:27






  • 1





    Also this has nothing to do with jQuery.

    – Mark Baijens
    Dec 28 '18 at 12:29














  • 4





    map_rendered is a <map> element. You must use a <canvas> element if you hope .getContext('2d'); to succeed.

    – enhzflep
    Dec 28 '18 at 12:27






  • 1





    Also this has nothing to do with jQuery.

    – Mark Baijens
    Dec 28 '18 at 12:29








4




4





map_rendered is a <map> element. You must use a <canvas> element if you hope .getContext('2d'); to succeed.

– enhzflep
Dec 28 '18 at 12:27





map_rendered is a <map> element. You must use a <canvas> element if you hope .getContext('2d'); to succeed.

– enhzflep
Dec 28 '18 at 12:27




1




1





Also this has nothing to do with jQuery.

– Mark Baijens
Dec 28 '18 at 12:29





Also this has nothing to do with jQuery.

– Mark Baijens
Dec 28 '18 at 12:29












1 Answer
1






active

oldest

votes


















3














change "map" to "canvas", and error will gone






  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>








share|improve this answer
























  • thank you very much, I thought we could give an arbitrary name in the function createElement.

    – fragloth
    Dec 28 '18 at 13:42











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1 Answer
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1 Answer
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active

oldest

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oldest

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3














change "map" to "canvas", and error will gone






  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>








share|improve this answer
























  • thank you very much, I thought we could give an arbitrary name in the function createElement.

    – fragloth
    Dec 28 '18 at 13:42
















3














change "map" to "canvas", and error will gone






  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>








share|improve this answer
























  • thank you very much, I thought we could give an arbitrary name in the function createElement.

    – fragloth
    Dec 28 '18 at 13:42














3












3








3







change "map" to "canvas", and error will gone






  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>








share|improve this answer













change "map" to "canvas", and error will gone






  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>








  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>





  var map_rendered = document.createElement("canvas");
map_rendered.heigt = 100 ;
map_rendered.width = 100 ;
var map_rendered_ctx = map_rendered.getContext("2d");

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>






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share|improve this answer



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answered Dec 28 '18 at 12:28









Vadim HulevichVadim Hulevich

4867




4867













  • thank you very much, I thought we could give an arbitrary name in the function createElement.

    – fragloth
    Dec 28 '18 at 13:42



















  • thank you very much, I thought we could give an arbitrary name in the function createElement.

    – fragloth
    Dec 28 '18 at 13:42

















thank you very much, I thought we could give an arbitrary name in the function createElement.

– fragloth
Dec 28 '18 at 13:42





thank you very much, I thought we could give an arbitrary name in the function createElement.

– fragloth
Dec 28 '18 at 13:42


















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