Apache TIKA detects wrong content type
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I am using spring JAX-RS to upload file as a multipart form-data. I have inputstream object as an argument. I get my text file when I copy this input stream to disk.
but when I try to detect content type of this Input stream, I get Content Type as application/octet-stream.
My code is
Tika tika = new Tika();
String contentType = tika.detect(in);
in is my InputStream object and I am getting content type as application/octet-stream.
As a test I also tested the same file with tika desktop, and i got the right content type text/plain.
spring jax-rs apache-tika
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
add a comment |
I am using spring JAX-RS to upload file as a multipart form-data. I have inputstream object as an argument. I get my text file when I copy this input stream to disk.
but when I try to detect content type of this Input stream, I get Content Type as application/octet-stream.
My code is
Tika tika = new Tika();
String contentType = tika.detect(in);
in is my InputStream object and I am getting content type as application/octet-stream.
As a test I also tested the same file with tika desktop, and i got the right content type text/plain.
spring jax-rs apache-tika
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
add a comment |
I am using spring JAX-RS to upload file as a multipart form-data. I have inputstream object as an argument. I get my text file when I copy this input stream to disk.
but when I try to detect content type of this Input stream, I get Content Type as application/octet-stream.
My code is
Tika tika = new Tika();
String contentType = tika.detect(in);
in is my InputStream object and I am getting content type as application/octet-stream.
As a test I also tested the same file with tika desktop, and i got the right content type text/plain.
spring jax-rs apache-tika
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
I am using spring JAX-RS to upload file as a multipart form-data. I have inputstream object as an argument. I get my text file when I copy this input stream to disk.
but when I try to detect content type of this Input stream, I get Content Type as application/octet-stream.
My code is
Tika tika = new Tika();
String contentType = tika.detect(in);
in is my InputStream object and I am getting content type as application/octet-stream.
As a test I also tested the same file with tika desktop, and i got the right content type text/plain.
spring jax-rs apache-tika
spring jax-rs apache-tika
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
asked Jan 4 at 14:36
Jafar AliJafar Ali
677830
677830
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Detecting a text file as a text file is actually hard...there are no magic bytes. Tika relies on the filename (file suffix) if it is provided. If you run detect on a File or if you pass in the file name detect(InputStream is, String filename) or if you pass in the file name in the Metadata object (metadata.set(Metadata.RESOURCE_NAME_KEY, fileName)), you'll get the correct results.
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Detecting a text file as a text file is actually hard...there are no magic bytes. Tika relies on the filename (file suffix) if it is provided. If you run detect on a File or if you pass in the file name detect(InputStream is, String filename) or if you pass in the file name in the Metadata object (metadata.set(Metadata.RESOURCE_NAME_KEY, fileName)), you'll get the correct results.
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
add a comment |
Detecting a text file as a text file is actually hard...there are no magic bytes. Tika relies on the filename (file suffix) if it is provided. If you run detect on a File or if you pass in the file name detect(InputStream is, String filename) or if you pass in the file name in the Metadata object (metadata.set(Metadata.RESOURCE_NAME_KEY, fileName)), you'll get the correct results.
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
add a comment |
Detecting a text file as a text file is actually hard...there are no magic bytes. Tika relies on the filename (file suffix) if it is provided. If you run detect on a File or if you pass in the file name detect(InputStream is, String filename) or if you pass in the file name in the Metadata object (metadata.set(Metadata.RESOURCE_NAME_KEY, fileName)), you'll get the correct results.
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
Detecting a text file as a text file is actually hard...there are no magic bytes. Tika relies on the filename (file suffix) if it is provided. If you run detect on a File or if you pass in the file name detect(InputStream is, String filename) or if you pass in the file name in the Metadata object (metadata.set(Metadata.RESOURCE_NAME_KEY, fileName)), you'll get the correct results.
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
answered Jan 8 at 17:52
Tim AllisonTim Allison
40126
40126
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
add a comment |
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
even the filename doesn't have any clue of the format. file extension is .xyz
– Jafar Ali
Jan 9 at 13:57
add a comment |
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