Sending multipart/formdata with jQuery.ajax
I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files')
but how is it possible to send this Data to the server? The resulting array ($_POST
) on the serverside php-script is 0 (NULL
) when using the file-input.
I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).
This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.
I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.
My code for now is:
$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
jquery ajax file-upload multipartform-data form-data
|
show 1 more comment
I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files')
but how is it possible to send this Data to the server? The resulting array ($_POST
) on the serverside php-script is 0 (NULL
) when using the file-input.
I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).
This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.
I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.
My code for now is:
$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
jquery ajax file-upload multipartform-data form-data
Sadly using FormData object doesn't works on IE<10.
– Alejandro García Iglesias
May 13 '13 at 16:52
@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.
– yuxhuang
Jul 12 '13 at 4:09
Possible duplicate.
– Raphael Schweikert
Mar 26 '14 at 13:19
3
You can use$(':file')
to select all input files. It's just a bit simpler.
– Shahar
Aug 20 '15 at 12:03
@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.
– Ryan P
Apr 10 '17 at 23:48
|
show 1 more comment
I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files')
but how is it possible to send this Data to the server? The resulting array ($_POST
) on the serverside php-script is 0 (NULL
) when using the file-input.
I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).
This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.
I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.
My code for now is:
$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
jquery ajax file-upload multipartform-data form-data
I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files')
but how is it possible to send this Data to the server? The resulting array ($_POST
) on the serverside php-script is 0 (NULL
) when using the file-input.
I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).
This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.
I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.
My code for now is:
$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
jquery ajax file-upload multipartform-data form-data
jquery ajax file-upload multipartform-data form-data
edited Dec 13 '16 at 16:17
Adexe Rivera
343510
343510
asked Mar 22 '11 at 13:52
zokuzoku
2,86131421
2,86131421
Sadly using FormData object doesn't works on IE<10.
– Alejandro García Iglesias
May 13 '13 at 16:52
@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.
– yuxhuang
Jul 12 '13 at 4:09
Possible duplicate.
– Raphael Schweikert
Mar 26 '14 at 13:19
3
You can use$(':file')
to select all input files. It's just a bit simpler.
– Shahar
Aug 20 '15 at 12:03
@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.
– Ryan P
Apr 10 '17 at 23:48
|
show 1 more comment
Sadly using FormData object doesn't works on IE<10.
– Alejandro García Iglesias
May 13 '13 at 16:52
@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.
– yuxhuang
Jul 12 '13 at 4:09
Possible duplicate.
– Raphael Schweikert
Mar 26 '14 at 13:19
3
You can use$(':file')
to select all input files. It's just a bit simpler.
– Shahar
Aug 20 '15 at 12:03
@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.
– Ryan P
Apr 10 '17 at 23:48
Sadly using FormData object doesn't works on IE<10.
– Alejandro García Iglesias
May 13 '13 at 16:52
Sadly using FormData object doesn't works on IE<10.
– Alejandro García Iglesias
May 13 '13 at 16:52
@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.
– yuxhuang
Jul 12 '13 at 4:09
@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.
– yuxhuang
Jul 12 '13 at 4:09
Possible duplicate.
– Raphael Schweikert
Mar 26 '14 at 13:19
Possible duplicate.
– Raphael Schweikert
Mar 26 '14 at 13:19
3
3
You can use
$(':file')
to select all input files. It's just a bit simpler.– Shahar
Aug 20 '15 at 12:03
You can use
$(':file')
to select all input files. It's just a bit simpler.– Shahar
Aug 20 '15 at 12:03
@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.
– Ryan P
Apr 10 '17 at 23:48
@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.
– Ryan P
Apr 10 '17 at 23:48
|
show 1 more comment
12 Answers
12
active
oldest
votes
Starting with Safari 5/Firefox 4, it’s easiest to use the FormData
class:
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
So now you have a FormData
object, ready to be sent along with the XMLHttpRequest.
jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});
It’s imperative that you set the contentType
option to false
, forcing jQuery not to add a Content-Type
header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData
flag set to false, otherwise, jQuery will try to convert your FormData
into a string, which will fail.
You may now retrieve the file in PHP using:
$_FILES['file-0']
(There is only one file, file-0
, unless you specified the multiple
attribute on your file input, in which case, the numbers will increment with each file.)
Using the FormData emulation for older browsers
var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);
Create FormData from an existing form
Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:
var data = new FormData(jQuery('form')[0]);
Use a PHP native array instead of a counter
Just name your file elements the same and end the name in brackets:
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file', file);
});
$_FILES['file']
will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.
2
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check fordata.fake
and set thecontentType
property manually as well as overriding xhr to usesendAsBinary()
.
– Raphael Schweikert
Aug 24 '11 at 8:01
12
So you’re neither usingjQuery
nor theFormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…
– Raphael Schweikert
Apr 19 '12 at 9:44
3
This usesapplication/x-www-form-urlencoded
. Is there a way to usemultipart/form-data
instead?
– Timmmm
Apr 6 '13 at 20:43
4
@Timmmm No, it usesmultipart/form-data
. Usingapplication/x-www-form-urlencoded
would not work.
– Raphael Schweikert
Apr 7 '13 at 8:57
5
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
|
show 23 more comments
Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES
, regardless of whether you use JavaScript to submit.
HTML form:
<form enctype="multipart/form-data" action="/test.php"
method="post" class="putImages">
<input name="media" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>
PHP produces this $_FILES
, when submitted without JavaScript:
Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)
[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)
[error] => Array
(
[0] => 0
[1] => 0
)
[size] => Array
(
[0] => 258004
[1] => 127884
)
)
)
If you do progressive enhancement, using Raphael's JS to submit the files...
var data = new FormData($('input[name^="media"]'));
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});
$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});
... this is what PHP's $_FILES
array looks like, after using that JavaScript to submit:
Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)
[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)
)
That's a nice array, and actually what some people transform $_FILES
into, but I find it's useful to work with the same $_FILES
, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:
// match anything not a [ or ]
regexp = /^[^[]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );
// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});
(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)
That code does two things.
- Retrieves the
input
name attribute automatically, making the HTML more maintainable. Now, as long asform
has the class putImages, everything else is taken care of automatically. That is, theinput
need not have any special name. - The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.
With these changes, submitting with JavaScript now produces precisely the same $_FILES
array as submitting with simple HTML.
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
add a comment |
Look at my code, it does the job for me
$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );
add a comment |
I just built this function based on some info I read.
Use it like using .serialize()
, instead just put .serializefiles();
.
Working here in my tests.
//USAGE: $("#form").serializefiles();
(function($) {
$.fn.serializefiles = function() {
var obj = $(this);
/* ADD FILE TO PARAM AJAX */
var formData = new FormData();
$.each($(obj).find("input[type='file']"), function(i, tag) {
$.each($(tag)[0].files, function(i, file) {
formData.append(tag.name, file);
});
});
var params = $(obj).serializeArray();
$.each(params, function (i, val) {
formData.append(val.name, val.value);
});
return formData;
};
})(jQuery);
2
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
1
that works for me just fine. getting data withvar data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable:form.parse(req, function(err, fields, files){
thank you for that code snippet :)
– SchurigH
Nov 19 '13 at 21:53
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
add a comment |
If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.
$('#my-form').submit( function(e) {
e.preventDefault();
var data = new FormData(this); // <-- 'this' is your form element
$.ajax({
url: '/my_URL/',
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
...
add a comment |
Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.
I also wanted to use jQuery's on() method so I could avoid using .ready().
That got me to this:
(replace formSelector with your jQuery selector)
$(document).on('submit', formSelecter, function( e ) {
e.preventDefault();
$.ajax( {
url: $(this).attr('action'),
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
}).done(function( data ) {
//do stuff with the data you got back.
});
});
add a comment |
The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.
Mozilla Dev has a nice page on manipulating FormData objects.
So, add an empty form somewhere in your page, specifying the enctype:
<form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>
Then, create FormData object as:
var data = new FormData($("#fileinfo"));
and proceed as in Raphael's code.
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
add a comment |
One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.
For example, I was posting to http://server.com/context?param=x
In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)
During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.
add a comment |
Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).
Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript
add a comment |
All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:
formData.append(val.name, val.value);
add a comment |
Nova days you not need even jQuery:) fetch API support table
let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})
In the context of file upload viafetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…
– Omar Tariq
Nov 9 '18 at 15:00
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
Oops. How can I miss that:-|
– Omar Tariq
Nov 12 '18 at 12:01
add a comment |
- get form object by jquery-> $("#id")[0]
- data = new FormData($("#id")[0]);
- ok,data is your want
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
add a comment |
protected by Community♦ Nov 1 '13 at 21:44
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12 Answers
12
active
oldest
votes
12 Answers
12
active
oldest
votes
active
oldest
votes
active
oldest
votes
Starting with Safari 5/Firefox 4, it’s easiest to use the FormData
class:
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
So now you have a FormData
object, ready to be sent along with the XMLHttpRequest.
jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});
It’s imperative that you set the contentType
option to false
, forcing jQuery not to add a Content-Type
header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData
flag set to false, otherwise, jQuery will try to convert your FormData
into a string, which will fail.
You may now retrieve the file in PHP using:
$_FILES['file-0']
(There is only one file, file-0
, unless you specified the multiple
attribute on your file input, in which case, the numbers will increment with each file.)
Using the FormData emulation for older browsers
var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);
Create FormData from an existing form
Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:
var data = new FormData(jQuery('form')[0]);
Use a PHP native array instead of a counter
Just name your file elements the same and end the name in brackets:
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file', file);
});
$_FILES['file']
will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.
2
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check fordata.fake
and set thecontentType
property manually as well as overriding xhr to usesendAsBinary()
.
– Raphael Schweikert
Aug 24 '11 at 8:01
12
So you’re neither usingjQuery
nor theFormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…
– Raphael Schweikert
Apr 19 '12 at 9:44
3
This usesapplication/x-www-form-urlencoded
. Is there a way to usemultipart/form-data
instead?
– Timmmm
Apr 6 '13 at 20:43
4
@Timmmm No, it usesmultipart/form-data
. Usingapplication/x-www-form-urlencoded
would not work.
– Raphael Schweikert
Apr 7 '13 at 8:57
5
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
|
show 23 more comments
Starting with Safari 5/Firefox 4, it’s easiest to use the FormData
class:
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
So now you have a FormData
object, ready to be sent along with the XMLHttpRequest.
jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});
It’s imperative that you set the contentType
option to false
, forcing jQuery not to add a Content-Type
header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData
flag set to false, otherwise, jQuery will try to convert your FormData
into a string, which will fail.
You may now retrieve the file in PHP using:
$_FILES['file-0']
(There is only one file, file-0
, unless you specified the multiple
attribute on your file input, in which case, the numbers will increment with each file.)
Using the FormData emulation for older browsers
var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);
Create FormData from an existing form
Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:
var data = new FormData(jQuery('form')[0]);
Use a PHP native array instead of a counter
Just name your file elements the same and end the name in brackets:
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file', file);
});
$_FILES['file']
will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.
2
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check fordata.fake
and set thecontentType
property manually as well as overriding xhr to usesendAsBinary()
.
– Raphael Schweikert
Aug 24 '11 at 8:01
12
So you’re neither usingjQuery
nor theFormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…
– Raphael Schweikert
Apr 19 '12 at 9:44
3
This usesapplication/x-www-form-urlencoded
. Is there a way to usemultipart/form-data
instead?
– Timmmm
Apr 6 '13 at 20:43
4
@Timmmm No, it usesmultipart/form-data
. Usingapplication/x-www-form-urlencoded
would not work.
– Raphael Schweikert
Apr 7 '13 at 8:57
5
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
|
show 23 more comments
Starting with Safari 5/Firefox 4, it’s easiest to use the FormData
class:
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
So now you have a FormData
object, ready to be sent along with the XMLHttpRequest.
jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});
It’s imperative that you set the contentType
option to false
, forcing jQuery not to add a Content-Type
header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData
flag set to false, otherwise, jQuery will try to convert your FormData
into a string, which will fail.
You may now retrieve the file in PHP using:
$_FILES['file-0']
(There is only one file, file-0
, unless you specified the multiple
attribute on your file input, in which case, the numbers will increment with each file.)
Using the FormData emulation for older browsers
var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);
Create FormData from an existing form
Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:
var data = new FormData(jQuery('form')[0]);
Use a PHP native array instead of a counter
Just name your file elements the same and end the name in brackets:
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file', file);
});
$_FILES['file']
will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.
Starting with Safari 5/Firefox 4, it’s easiest to use the FormData
class:
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
So now you have a FormData
object, ready to be sent along with the XMLHttpRequest.
jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});
It’s imperative that you set the contentType
option to false
, forcing jQuery not to add a Content-Type
header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData
flag set to false, otherwise, jQuery will try to convert your FormData
into a string, which will fail.
You may now retrieve the file in PHP using:
$_FILES['file-0']
(There is only one file, file-0
, unless you specified the multiple
attribute on your file input, in which case, the numbers will increment with each file.)
Using the FormData emulation for older browsers
var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);
Create FormData from an existing form
Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:
var data = new FormData(jQuery('form')[0]);
Use a PHP native array instead of a counter
Just name your file elements the same and end the name in brackets:
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file', file);
});
$_FILES['file']
will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.
edited Oct 5 '17 at 20:13
answered May 12 '11 at 9:36
Raphael SchweikertRaphael Schweikert
15.1k54862
15.1k54862
2
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check fordata.fake
and set thecontentType
property manually as well as overriding xhr to usesendAsBinary()
.
– Raphael Schweikert
Aug 24 '11 at 8:01
12
So you’re neither usingjQuery
nor theFormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…
– Raphael Schweikert
Apr 19 '12 at 9:44
3
This usesapplication/x-www-form-urlencoded
. Is there a way to usemultipart/form-data
instead?
– Timmmm
Apr 6 '13 at 20:43
4
@Timmmm No, it usesmultipart/form-data
. Usingapplication/x-www-form-urlencoded
would not work.
– Raphael Schweikert
Apr 7 '13 at 8:57
5
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
|
show 23 more comments
2
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check fordata.fake
and set thecontentType
property manually as well as overriding xhr to usesendAsBinary()
.
– Raphael Schweikert
Aug 24 '11 at 8:01
12
So you’re neither usingjQuery
nor theFormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…
– Raphael Schweikert
Apr 19 '12 at 9:44
3
This usesapplication/x-www-form-urlencoded
. Is there a way to usemultipart/form-data
instead?
– Timmmm
Apr 6 '13 at 20:43
4
@Timmmm No, it usesmultipart/form-data
. Usingapplication/x-www-form-urlencoded
would not work.
– Raphael Schweikert
Apr 7 '13 at 8:57
5
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
2
2
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for
data.fake
and set the contentType
property manually as well as overriding xhr to use sendAsBinary()
.– Raphael Schweikert
Aug 24 '11 at 8:01
Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for
data.fake
and set the contentType
property manually as well as overriding xhr to use sendAsBinary()
.– Raphael Schweikert
Aug 24 '11 at 8:01
12
12
So you’re neither using
jQuery
nor the FormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…– Raphael Schweikert
Apr 19 '12 at 9:44
So you’re neither using
jQuery
nor the FormData
class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…– Raphael Schweikert
Apr 19 '12 at 9:44
3
3
This uses
application/x-www-form-urlencoded
. Is there a way to use multipart/form-data
instead?– Timmmm
Apr 6 '13 at 20:43
This uses
application/x-www-form-urlencoded
. Is there a way to use multipart/form-data
instead?– Timmmm
Apr 6 '13 at 20:43
4
4
@Timmmm No, it uses
multipart/form-data
. Using application/x-www-form-urlencoded
would not work.– Raphael Schweikert
Apr 7 '13 at 8:57
@Timmmm No, it uses
multipart/form-data
. Using application/x-www-form-urlencoded
would not work.– Raphael Schweikert
Apr 7 '13 at 8:57
5
5
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
@RoyiNamir It’s only documented in code, I’m afraid.
– Raphael Schweikert
Jan 6 '14 at 18:30
|
show 23 more comments
Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES
, regardless of whether you use JavaScript to submit.
HTML form:
<form enctype="multipart/form-data" action="/test.php"
method="post" class="putImages">
<input name="media" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>
PHP produces this $_FILES
, when submitted without JavaScript:
Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)
[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)
[error] => Array
(
[0] => 0
[1] => 0
)
[size] => Array
(
[0] => 258004
[1] => 127884
)
)
)
If you do progressive enhancement, using Raphael's JS to submit the files...
var data = new FormData($('input[name^="media"]'));
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});
$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});
... this is what PHP's $_FILES
array looks like, after using that JavaScript to submit:
Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)
[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)
)
That's a nice array, and actually what some people transform $_FILES
into, but I find it's useful to work with the same $_FILES
, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:
// match anything not a [ or ]
regexp = /^[^[]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );
// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});
(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)
That code does two things.
- Retrieves the
input
name attribute automatically, making the HTML more maintainable. Now, as long asform
has the class putImages, everything else is taken care of automatically. That is, theinput
need not have any special name. - The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.
With these changes, submitting with JavaScript now produces precisely the same $_FILES
array as submitting with simple HTML.
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
add a comment |
Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES
, regardless of whether you use JavaScript to submit.
HTML form:
<form enctype="multipart/form-data" action="/test.php"
method="post" class="putImages">
<input name="media" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>
PHP produces this $_FILES
, when submitted without JavaScript:
Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)
[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)
[error] => Array
(
[0] => 0
[1] => 0
)
[size] => Array
(
[0] => 258004
[1] => 127884
)
)
)
If you do progressive enhancement, using Raphael's JS to submit the files...
var data = new FormData($('input[name^="media"]'));
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});
$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});
... this is what PHP's $_FILES
array looks like, after using that JavaScript to submit:
Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)
[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)
)
That's a nice array, and actually what some people transform $_FILES
into, but I find it's useful to work with the same $_FILES
, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:
// match anything not a [ or ]
regexp = /^[^[]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );
// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});
(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)
That code does two things.
- Retrieves the
input
name attribute automatically, making the HTML more maintainable. Now, as long asform
has the class putImages, everything else is taken care of automatically. That is, theinput
need not have any special name. - The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.
With these changes, submitting with JavaScript now produces precisely the same $_FILES
array as submitting with simple HTML.
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
add a comment |
Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES
, regardless of whether you use JavaScript to submit.
HTML form:
<form enctype="multipart/form-data" action="/test.php"
method="post" class="putImages">
<input name="media" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>
PHP produces this $_FILES
, when submitted without JavaScript:
Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)
[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)
[error] => Array
(
[0] => 0
[1] => 0
)
[size] => Array
(
[0] => 258004
[1] => 127884
)
)
)
If you do progressive enhancement, using Raphael's JS to submit the files...
var data = new FormData($('input[name^="media"]'));
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});
$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});
... this is what PHP's $_FILES
array looks like, after using that JavaScript to submit:
Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)
[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)
)
That's a nice array, and actually what some people transform $_FILES
into, but I find it's useful to work with the same $_FILES
, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:
// match anything not a [ or ]
regexp = /^[^[]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );
// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});
(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)
That code does two things.
- Retrieves the
input
name attribute automatically, making the HTML more maintainable. Now, as long asform
has the class putImages, everything else is taken care of automatically. That is, theinput
need not have any special name. - The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.
With these changes, submitting with JavaScript now produces precisely the same $_FILES
array as submitting with simple HTML.
Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES
, regardless of whether you use JavaScript to submit.
HTML form:
<form enctype="multipart/form-data" action="/test.php"
method="post" class="putImages">
<input name="media" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>
PHP produces this $_FILES
, when submitted without JavaScript:
Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)
[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)
[error] => Array
(
[0] => 0
[1] => 0
)
[size] => Array
(
[0] => 258004
[1] => 127884
)
)
)
If you do progressive enhancement, using Raphael's JS to submit the files...
var data = new FormData($('input[name^="media"]'));
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});
$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});
... this is what PHP's $_FILES
array looks like, after using that JavaScript to submit:
Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)
[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)
)
That's a nice array, and actually what some people transform $_FILES
into, but I find it's useful to work with the same $_FILES
, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:
// match anything not a [ or ]
regexp = /^[^[]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );
// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});
(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)
That code does two things.
- Retrieves the
input
name attribute automatically, making the HTML more maintainable. Now, as long asform
has the class putImages, everything else is taken care of automatically. That is, theinput
need not have any special name. - The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.
With these changes, submitting with JavaScript now produces precisely the same $_FILES
array as submitting with simple HTML.
edited Apr 14 '17 at 17:00
answered Jan 10 '12 at 0:56
ajmicekajmicek
66656
66656
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
add a comment |
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
Had the same issue with Safari. Thanks for the hint!
– medoingthings
Aug 4 '18 at 12:42
add a comment |
Look at my code, it does the job for me
$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );
add a comment |
Look at my code, it does the job for me
$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );
add a comment |
Look at my code, it does the job for me
$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );
Look at my code, it does the job for me
$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );
edited Nov 4 '14 at 5:06
answered Aug 30 '14 at 6:49
Asad MalikAsad Malik
1,25111519
1,25111519
add a comment |
add a comment |
I just built this function based on some info I read.
Use it like using .serialize()
, instead just put .serializefiles();
.
Working here in my tests.
//USAGE: $("#form").serializefiles();
(function($) {
$.fn.serializefiles = function() {
var obj = $(this);
/* ADD FILE TO PARAM AJAX */
var formData = new FormData();
$.each($(obj).find("input[type='file']"), function(i, tag) {
$.each($(tag)[0].files, function(i, file) {
formData.append(tag.name, file);
});
});
var params = $(obj).serializeArray();
$.each(params, function (i, val) {
formData.append(val.name, val.value);
});
return formData;
};
})(jQuery);
2
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
1
that works for me just fine. getting data withvar data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable:form.parse(req, function(err, fields, files){
thank you for that code snippet :)
– SchurigH
Nov 19 '13 at 21:53
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
add a comment |
I just built this function based on some info I read.
Use it like using .serialize()
, instead just put .serializefiles();
.
Working here in my tests.
//USAGE: $("#form").serializefiles();
(function($) {
$.fn.serializefiles = function() {
var obj = $(this);
/* ADD FILE TO PARAM AJAX */
var formData = new FormData();
$.each($(obj).find("input[type='file']"), function(i, tag) {
$.each($(tag)[0].files, function(i, file) {
formData.append(tag.name, file);
});
});
var params = $(obj).serializeArray();
$.each(params, function (i, val) {
formData.append(val.name, val.value);
});
return formData;
};
})(jQuery);
2
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
1
that works for me just fine. getting data withvar data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable:form.parse(req, function(err, fields, files){
thank you for that code snippet :)
– SchurigH
Nov 19 '13 at 21:53
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
add a comment |
I just built this function based on some info I read.
Use it like using .serialize()
, instead just put .serializefiles();
.
Working here in my tests.
//USAGE: $("#form").serializefiles();
(function($) {
$.fn.serializefiles = function() {
var obj = $(this);
/* ADD FILE TO PARAM AJAX */
var formData = new FormData();
$.each($(obj).find("input[type='file']"), function(i, tag) {
$.each($(tag)[0].files, function(i, file) {
formData.append(tag.name, file);
});
});
var params = $(obj).serializeArray();
$.each(params, function (i, val) {
formData.append(val.name, val.value);
});
return formData;
};
})(jQuery);
I just built this function based on some info I read.
Use it like using .serialize()
, instead just put .serializefiles();
.
Working here in my tests.
//USAGE: $("#form").serializefiles();
(function($) {
$.fn.serializefiles = function() {
var obj = $(this);
/* ADD FILE TO PARAM AJAX */
var formData = new FormData();
$.each($(obj).find("input[type='file']"), function(i, tag) {
$.each($(tag)[0].files, function(i, file) {
formData.append(tag.name, file);
});
});
var params = $(obj).serializeArray();
$.each(params, function (i, val) {
formData.append(val.name, val.value);
});
return formData;
};
})(jQuery);
edited Oct 10 '18 at 17:01
Tod Birdsall
7,91922834
7,91922834
answered Sep 14 '12 at 14:33
evandro777evandro777
54144
54144
2
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
1
that works for me just fine. getting data withvar data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable:form.parse(req, function(err, fields, files){
thank you for that code snippet :)
– SchurigH
Nov 19 '13 at 21:53
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
add a comment |
2
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
1
that works for me just fine. getting data withvar data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable:form.parse(req, function(err, fields, files){
thank you for that code snippet :)
– SchurigH
Nov 19 '13 at 21:53
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
2
2
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.
– Fallenreaper
Sep 19 '12 at 15:09
1
1
that works for me just fine. getting data with
var data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){
thank you for that code snippet :)– SchurigH
Nov 19 '13 at 21:53
that works for me just fine. getting data with
var data = $("#avatar-form").serializefiles();
sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){
thank you for that code snippet :)– SchurigH
Nov 19 '13 at 21:53
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
that was tricky (y) :D loved it
– sarath
May 18 '15 at 10:30
add a comment |
If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.
$('#my-form').submit( function(e) {
e.preventDefault();
var data = new FormData(this); // <-- 'this' is your form element
$.ajax({
url: '/my_URL/',
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
...
add a comment |
If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.
$('#my-form').submit( function(e) {
e.preventDefault();
var data = new FormData(this); // <-- 'this' is your form element
$.ajax({
url: '/my_URL/',
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
...
add a comment |
If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.
$('#my-form').submit( function(e) {
e.preventDefault();
var data = new FormData(this); // <-- 'this' is your form element
$.ajax({
url: '/my_URL/',
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
...
If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.
$('#my-form').submit( function(e) {
e.preventDefault();
var data = new FormData(this); // <-- 'this' is your form element
$.ajax({
url: '/my_URL/',
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
...
answered Jun 2 '14 at 17:43
Devin VenableDevin Venable
47135
47135
add a comment |
add a comment |
Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.
I also wanted to use jQuery's on() method so I could avoid using .ready().
That got me to this:
(replace formSelector with your jQuery selector)
$(document).on('submit', formSelecter, function( e ) {
e.preventDefault();
$.ajax( {
url: $(this).attr('action'),
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
}).done(function( data ) {
//do stuff with the data you got back.
});
});
add a comment |
Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.
I also wanted to use jQuery's on() method so I could avoid using .ready().
That got me to this:
(replace formSelector with your jQuery selector)
$(document).on('submit', formSelecter, function( e ) {
e.preventDefault();
$.ajax( {
url: $(this).attr('action'),
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
}).done(function( data ) {
//do stuff with the data you got back.
});
});
add a comment |
Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.
I also wanted to use jQuery's on() method so I could avoid using .ready().
That got me to this:
(replace formSelector with your jQuery selector)
$(document).on('submit', formSelecter, function( e ) {
e.preventDefault();
$.ajax( {
url: $(this).attr('action'),
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
}).done(function( data ) {
//do stuff with the data you got back.
});
});
Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.
I also wanted to use jQuery's on() method so I could avoid using .ready().
That got me to this:
(replace formSelector with your jQuery selector)
$(document).on('submit', formSelecter, function( e ) {
e.preventDefault();
$.ajax( {
url: $(this).attr('action'),
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
}).done(function( data ) {
//do stuff with the data you got back.
});
});
edited May 23 '17 at 12:34
Community♦
11
11
answered Jun 15 '16 at 16:54
Karl HenselinKarl Henselin
8321012
8321012
add a comment |
add a comment |
The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.
Mozilla Dev has a nice page on manipulating FormData objects.
So, add an empty form somewhere in your page, specifying the enctype:
<form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>
Then, create FormData object as:
var data = new FormData($("#fileinfo"));
and proceed as in Raphael's code.
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
add a comment |
The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.
Mozilla Dev has a nice page on manipulating FormData objects.
So, add an empty form somewhere in your page, specifying the enctype:
<form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>
Then, create FormData object as:
var data = new FormData($("#fileinfo"));
and proceed as in Raphael's code.
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
add a comment |
The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.
Mozilla Dev has a nice page on manipulating FormData objects.
So, add an empty form somewhere in your page, specifying the enctype:
<form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>
Then, create FormData object as:
var data = new FormData($("#fileinfo"));
and proceed as in Raphael's code.
The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.
Mozilla Dev has a nice page on manipulating FormData objects.
So, add an empty form somewhere in your page, specifying the enctype:
<form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>
Then, create FormData object as:
var data = new FormData($("#fileinfo"));
and proceed as in Raphael's code.
edited May 23 '17 at 12:34
Community♦
11
11
answered Feb 22 '13 at 0:24
topkaratopkara
688615
688615
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
add a comment |
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.
– glyph
Mar 1 '13 at 21:17
add a comment |
One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.
For example, I was posting to http://server.com/context?param=x
In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)
During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.
add a comment |
One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.
For example, I was posting to http://server.com/context?param=x
In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)
During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.
add a comment |
One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.
For example, I was posting to http://server.com/context?param=x
In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)
During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.
One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.
For example, I was posting to http://server.com/context?param=x
In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)
During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.
answered Mar 17 '16 at 22:07
jamesjames
32045
32045
add a comment |
add a comment |
Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).
Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript
add a comment |
Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).
Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript
add a comment |
Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).
Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript
Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).
Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript
answered Feb 8 '18 at 10:42
sudipsudip
1,9092128
1,9092128
add a comment |
add a comment |
All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:
formData.append(val.name, val.value);
add a comment |
All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:
formData.append(val.name, val.value);
add a comment |
All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:
formData.append(val.name, val.value);
All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:
formData.append(val.name, val.value);
answered Mar 8 '18 at 13:47
szatti1489szatti1489
802311
802311
add a comment |
add a comment |
Nova days you not need even jQuery:) fetch API support table
let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})
In the context of file upload viafetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…
– Omar Tariq
Nov 9 '18 at 15:00
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
Oops. How can I miss that:-|
– Omar Tariq
Nov 12 '18 at 12:01
add a comment |
Nova days you not need even jQuery:) fetch API support table
let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})
In the context of file upload viafetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…
– Omar Tariq
Nov 9 '18 at 15:00
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
Oops. How can I miss that:-|
– Omar Tariq
Nov 12 '18 at 12:01
add a comment |
Nova days you not need even jQuery:) fetch API support table
let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})
Nova days you not need even jQuery:) fetch API support table
let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})
answered Oct 29 '18 at 11:26
Alex NikulinAlex Nikulin
3,75112125
3,75112125
In the context of file upload viafetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…
– Omar Tariq
Nov 9 '18 at 15:00
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
Oops. How can I miss that:-|
– Omar Tariq
Nov 12 '18 at 12:01
add a comment |
In the context of file upload viafetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…
– Omar Tariq
Nov 9 '18 at 15:00
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
Oops. How can I miss that:-|
– Omar Tariq
Nov 12 '18 at 12:01
In the context of file upload via
fetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…– Omar Tariq
Nov 9 '18 at 15:00
In the context of file upload via
fetch
please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…– Omar Tariq
Nov 9 '18 at 15:00
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
@OmarTariq yes I have a similar link in my answer))
– Alex Nikulin
Nov 11 '18 at 14:11
Oops. How can I miss that
:-|
– Omar Tariq
Nov 12 '18 at 12:01
Oops. How can I miss that
:-|
– Omar Tariq
Nov 12 '18 at 12:01
add a comment |
- get form object by jquery-> $("#id")[0]
- data = new FormData($("#id")[0]);
- ok,data is your want
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
add a comment |
- get form object by jquery-> $("#id")[0]
- data = new FormData($("#id")[0]);
- ok,data is your want
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
add a comment |
- get form object by jquery-> $("#id")[0]
- data = new FormData($("#id")[0]);
- ok,data is your want
- get form object by jquery-> $("#id")[0]
- data = new FormData($("#id")[0]);
- ok,data is your want
edited Jul 18 '13 at 10:11
Azik Abdullah
6,6251263111
6,6251263111
answered Jul 18 '13 at 9:54
user1909226user1909226
17
17
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
add a comment |
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
$("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?
– Mohammad-Hossein Jamali
May 29 '15 at 6:47
add a comment |
protected by Community♦ Nov 1 '13 at 21:44
Thank you for your interest in this question.
Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).
Would you like to answer one of these unanswered questions instead?
Sadly using FormData object doesn't works on IE<10.
– Alejandro García Iglesias
May 13 '13 at 16:52
@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.
– yuxhuang
Jul 12 '13 at 4:09
Possible duplicate.
– Raphael Schweikert
Mar 26 '14 at 13:19
3
You can use
$(':file')
to select all input files. It's just a bit simpler.– Shahar
Aug 20 '15 at 12:03
@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.
– Ryan P
Apr 10 '17 at 23:48