Sending multipart/formdata with jQuery.ajax












505















I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files') but how is it possible to send this Data to the server? The resulting array ($_POST) on the serverside php-script is 0 (NULL) when using the file-input.



I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).



This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.



I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.



My code for now is:



$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});









share|improve this question

























  • Sadly using FormData object doesn't works on IE<10.

    – Alejandro García Iglesias
    May 13 '13 at 16:52











  • @GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.

    – yuxhuang
    Jul 12 '13 at 4:09











  • Possible duplicate.

    – Raphael Schweikert
    Mar 26 '14 at 13:19






  • 3





    You can use $(':file') to select all input files. It's just a bit simpler.

    – Shahar
    Aug 20 '15 at 12:03











  • @RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.

    – Ryan P
    Apr 10 '17 at 23:48
















505















I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files') but how is it possible to send this Data to the server? The resulting array ($_POST) on the serverside php-script is 0 (NULL) when using the file-input.



I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).



This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.



I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.



My code for now is:



$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});









share|improve this question

























  • Sadly using FormData object doesn't works on IE<10.

    – Alejandro García Iglesias
    May 13 '13 at 16:52











  • @GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.

    – yuxhuang
    Jul 12 '13 at 4:09











  • Possible duplicate.

    – Raphael Schweikert
    Mar 26 '14 at 13:19






  • 3





    You can use $(':file') to select all input files. It's just a bit simpler.

    – Shahar
    Aug 20 '15 at 12:03











  • @RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.

    – Ryan P
    Apr 10 '17 at 23:48














505












505








505


277






I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files') but how is it possible to send this Data to the server? The resulting array ($_POST) on the serverside php-script is 0 (NULL) when using the file-input.



I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).



This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.



I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.



My code for now is:



$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});









share|improve this question
















I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files') but how is it possible to send this Data to the server? The resulting array ($_POST) on the serverside php-script is 0 (NULL) when using the file-input.



I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).



This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.



I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.



My code for now is:



$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});






jquery ajax file-upload multipartform-data form-data






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 13 '16 at 16:17









Adexe Rivera

343510




343510










asked Mar 22 '11 at 13:52









zokuzoku

2,86131421




2,86131421













  • Sadly using FormData object doesn't works on IE<10.

    – Alejandro García Iglesias
    May 13 '13 at 16:52











  • @GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.

    – yuxhuang
    Jul 12 '13 at 4:09











  • Possible duplicate.

    – Raphael Schweikert
    Mar 26 '14 at 13:19






  • 3





    You can use $(':file') to select all input files. It's just a bit simpler.

    – Shahar
    Aug 20 '15 at 12:03











  • @RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.

    – Ryan P
    Apr 10 '17 at 23:48



















  • Sadly using FormData object doesn't works on IE<10.

    – Alejandro García Iglesias
    May 13 '13 at 16:52











  • @GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.

    – yuxhuang
    Jul 12 '13 at 4:09











  • Possible duplicate.

    – Raphael Schweikert
    Mar 26 '14 at 13:19






  • 3





    You can use $(':file') to select all input files. It's just a bit simpler.

    – Shahar
    Aug 20 '15 at 12:03











  • @RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.

    – Ryan P
    Apr 10 '17 at 23:48

















Sadly using FormData object doesn't works on IE<10.

– Alejandro García Iglesias
May 13 '13 at 16:52





Sadly using FormData object doesn't works on IE<10.

– Alejandro García Iglesias
May 13 '13 at 16:52













@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.

– yuxhuang
Jul 12 '13 at 4:09





@GarciaWebDev supposedly you can use a polyfill with Flash to support the same API. Check out github.com/Modernizr/Modernizr/wiki/… for more info.

– yuxhuang
Jul 12 '13 at 4:09













Possible duplicate.

– Raphael Schweikert
Mar 26 '14 at 13:19





Possible duplicate.

– Raphael Schweikert
Mar 26 '14 at 13:19




3




3





You can use $(':file') to select all input files. It's just a bit simpler.

– Shahar
Aug 20 '15 at 12:03





You can use $(':file') to select all input files. It's just a bit simpler.

– Shahar
Aug 20 '15 at 12:03













@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.

– Ryan P
Apr 10 '17 at 23:48





@RameshwarVyevhare That answer was posted five years after this question was answered. Please don't troll similar questions just to promote your own answers.

– Ryan P
Apr 10 '17 at 23:48












12 Answers
12






active

oldest

votes


















814














Starting with Safari 5/Firefox 4, it’s easiest to use the FormData class:



var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});


So now you have a FormData object, ready to be sent along with the XMLHttpRequest.



jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});


It’s imperative that you set the contentType option to false, forcing jQuery not to add a Content-Type header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData flag set to false, otherwise, jQuery will try to convert your FormData into a string, which will fail.



You may now retrieve the file in PHP using:



$_FILES['file-0']


(There is only one file, file-0, unless you specified the multiple attribute on your file input, in which case, the numbers will increment with each file.)



Using the FormData emulation for older browsers



var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);


Create FormData from an existing form



Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:



var data = new FormData(jQuery('form')[0]);


Use a PHP native array instead of a counter



Just name your file elements the same and end the name in brackets:



jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file', file);
});


$_FILES['file'] will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.






share|improve this answer





















  • 2





    Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

    – Raphael Schweikert
    Aug 24 '11 at 8:01








  • 12





    So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

    – Raphael Schweikert
    Apr 19 '12 at 9:44






  • 3





    This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

    – Timmmm
    Apr 6 '13 at 20:43






  • 4





    @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

    – Raphael Schweikert
    Apr 7 '13 at 8:57






  • 5





    @RoyiNamir It’s only documented in code, I’m afraid.

    – Raphael Schweikert
    Jan 6 '14 at 18:30



















46














Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES, regardless of whether you use JavaScript to submit.



HTML form:



<form enctype="multipart/form-data" action="/test.php" 
method="post" class="putImages">
<input name="media" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>


PHP produces this $_FILES, when submitted without JavaScript:



Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)

[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)

[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)

[error] => Array
(
[0] => 0
[1] => 0
)

[size] => Array
(
[0] => 258004
[1] => 127884
)

)

)


If you do progressive enhancement, using Raphael's JS to submit the files...



var data = new FormData($('input[name^="media"]'));     
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});

$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});


... this is what PHP's $_FILES array looks like, after using that JavaScript to submit:



Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)

[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)

)


That's a nice array, and actually what some people transform $_FILES into, but I find it's useful to work with the same $_FILES, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:



// match anything not a [ or ]
regexp = /^[^[]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );

// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});


(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)



That code does two things.




  1. Retrieves the input name attribute automatically, making the HTML more maintainable. Now, as long as form has the class putImages, everything else is taken care of automatically. That is, the input need not have any special name.

  2. The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.


With these changes, submitting with JavaScript now produces precisely the same $_FILES array as submitting with simple HTML.






share|improve this answer


























  • Had the same issue with Safari. Thanks for the hint!

    – medoingthings
    Aug 4 '18 at 12:42



















44














Look at my code, it does the job for me



$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );





share|improve this answer

































    44














    I just built this function based on some info I read.



    Use it like using .serialize(), instead just put .serializefiles();.

    Working here in my tests.



    //USAGE: $("#form").serializefiles();
    (function($) {
    $.fn.serializefiles = function() {
    var obj = $(this);
    /* ADD FILE TO PARAM AJAX */
    var formData = new FormData();
    $.each($(obj).find("input[type='file']"), function(i, tag) {
    $.each($(tag)[0].files, function(i, file) {
    formData.append(tag.name, file);
    });
    });
    var params = $(obj).serializeArray();
    $.each(params, function (i, val) {
    formData.append(val.name, val.value);
    });
    return formData;
    };
    })(jQuery);





    share|improve this answer





















    • 2





      I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

      – Fallenreaper
      Sep 19 '12 at 15:09






    • 1





      that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

      – SchurigH
      Nov 19 '13 at 21:53













    • that was tricky (y) :D loved it

      – sarath
      May 18 '15 at 10:30



















    23














    If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.



    $('#my-form').submit( function(e) {
    e.preventDefault();

    var data = new FormData(this); // <-- 'this' is your form element

    $.ajax({
    url: '/my_URL/',
    data: data,
    cache: false,
    contentType: false,
    processData: false,
    type: 'POST',
    success: function(data){
    ...





    share|improve this answer































      6














      Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.



      I also wanted to use jQuery's on() method so I could avoid using .ready().



      That got me to this:
      (replace formSelector with your jQuery selector)



      $(document).on('submit', formSelecter, function( e ) {
      e.preventDefault();
      $.ajax( {
      url: $(this).attr('action'),
      type: 'POST',
      data: new FormData( this ),
      processData: false,
      contentType: false
      }).done(function( data ) {
      //do stuff with the data you got back.
      });

      });





      share|improve this answer

































        1














        The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.



        Mozilla Dev has a nice page on manipulating FormData objects.



        So, add an empty form somewhere in your page, specifying the enctype:



        <form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>


        Then, create FormData object as:



        var data = new FormData($("#fileinfo"));


        and proceed as in Raphael's code.






        share|improve this answer


























        • I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

          – glyph
          Mar 1 '13 at 21:17





















        0














        One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.



        For example, I was posting to http://server.com/context?param=x



        In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)



        During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.






        share|improve this answer































          0














          Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).



          Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript






          share|improve this answer































            0














            All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:



            formData.append(val.name, val.value);






            share|improve this answer































              0














              Nova days you not need even jQuery:) fetch API support table



              let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})





              share|improve this answer
























              • In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                – Omar Tariq
                Nov 9 '18 at 15:00













              • @OmarTariq yes I have a similar link in my answer))

                – Alex Nikulin
                Nov 11 '18 at 14:11











              • Oops. How can I miss that :-|

                – Omar Tariq
                Nov 12 '18 at 12:01



















              -1















              1. get form object by jquery-> $("#id")[0]

              2. data = new FormData($("#id")[0]);

              3. ok,data is your want






              share|improve this answer


























              • $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                – Mohammad-Hossein Jamali
                May 29 '15 at 6:47










              protected by Community Nov 1 '13 at 21:44



              Thank you for your interest in this question.
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              12 Answers
              12






              active

              oldest

              votes








              12 Answers
              12






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              814














              Starting with Safari 5/Firefox 4, it’s easiest to use the FormData class:



              var data = new FormData();
              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file-'+i, file);
              });


              So now you have a FormData object, ready to be sent along with the XMLHttpRequest.



              jQuery.ajax({
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              });


              It’s imperative that you set the contentType option to false, forcing jQuery not to add a Content-Type header for you, otherwise, the boundary string will be missing from it.
              Also, you must leave the processData flag set to false, otherwise, jQuery will try to convert your FormData into a string, which will fail.



              You may now retrieve the file in PHP using:



              $_FILES['file-0']


              (There is only one file, file-0, unless you specified the multiple attribute on your file input, in which case, the numbers will increment with each file.)



              Using the FormData emulation for older browsers



              var opts = {
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              };
              if(data.fake) {
              // Make sure no text encoding stuff is done by xhr
              opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
              opts.contentType = "multipart/form-data; boundary="+data.boundary;
              opts.data = data.toString();
              }
              jQuery.ajax(opts);


              Create FormData from an existing form



              Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:



              var data = new FormData(jQuery('form')[0]);


              Use a PHP native array instead of a counter



              Just name your file elements the same and end the name in brackets:



              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file', file);
              });


              $_FILES['file'] will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.






              share|improve this answer





















              • 2





                Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

                – Raphael Schweikert
                Aug 24 '11 at 8:01








              • 12





                So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

                – Raphael Schweikert
                Apr 19 '12 at 9:44






              • 3





                This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

                – Timmmm
                Apr 6 '13 at 20:43






              • 4





                @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

                – Raphael Schweikert
                Apr 7 '13 at 8:57






              • 5





                @RoyiNamir It’s only documented in code, I’m afraid.

                – Raphael Schweikert
                Jan 6 '14 at 18:30
















              814














              Starting with Safari 5/Firefox 4, it’s easiest to use the FormData class:



              var data = new FormData();
              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file-'+i, file);
              });


              So now you have a FormData object, ready to be sent along with the XMLHttpRequest.



              jQuery.ajax({
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              });


              It’s imperative that you set the contentType option to false, forcing jQuery not to add a Content-Type header for you, otherwise, the boundary string will be missing from it.
              Also, you must leave the processData flag set to false, otherwise, jQuery will try to convert your FormData into a string, which will fail.



              You may now retrieve the file in PHP using:



              $_FILES['file-0']


              (There is only one file, file-0, unless you specified the multiple attribute on your file input, in which case, the numbers will increment with each file.)



              Using the FormData emulation for older browsers



              var opts = {
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              };
              if(data.fake) {
              // Make sure no text encoding stuff is done by xhr
              opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
              opts.contentType = "multipart/form-data; boundary="+data.boundary;
              opts.data = data.toString();
              }
              jQuery.ajax(opts);


              Create FormData from an existing form



              Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:



              var data = new FormData(jQuery('form')[0]);


              Use a PHP native array instead of a counter



              Just name your file elements the same and end the name in brackets:



              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file', file);
              });


              $_FILES['file'] will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.






              share|improve this answer





















              • 2





                Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

                – Raphael Schweikert
                Aug 24 '11 at 8:01








              • 12





                So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

                – Raphael Schweikert
                Apr 19 '12 at 9:44






              • 3





                This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

                – Timmmm
                Apr 6 '13 at 20:43






              • 4





                @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

                – Raphael Schweikert
                Apr 7 '13 at 8:57






              • 5





                @RoyiNamir It’s only documented in code, I’m afraid.

                – Raphael Schweikert
                Jan 6 '14 at 18:30














              814












              814








              814







              Starting with Safari 5/Firefox 4, it’s easiest to use the FormData class:



              var data = new FormData();
              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file-'+i, file);
              });


              So now you have a FormData object, ready to be sent along with the XMLHttpRequest.



              jQuery.ajax({
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              });


              It’s imperative that you set the contentType option to false, forcing jQuery not to add a Content-Type header for you, otherwise, the boundary string will be missing from it.
              Also, you must leave the processData flag set to false, otherwise, jQuery will try to convert your FormData into a string, which will fail.



              You may now retrieve the file in PHP using:



              $_FILES['file-0']


              (There is only one file, file-0, unless you specified the multiple attribute on your file input, in which case, the numbers will increment with each file.)



              Using the FormData emulation for older browsers



              var opts = {
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              };
              if(data.fake) {
              // Make sure no text encoding stuff is done by xhr
              opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
              opts.contentType = "multipart/form-data; boundary="+data.boundary;
              opts.data = data.toString();
              }
              jQuery.ajax(opts);


              Create FormData from an existing form



              Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:



              var data = new FormData(jQuery('form')[0]);


              Use a PHP native array instead of a counter



              Just name your file elements the same and end the name in brackets:



              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file', file);
              });


              $_FILES['file'] will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.






              share|improve this answer















              Starting with Safari 5/Firefox 4, it’s easiest to use the FormData class:



              var data = new FormData();
              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file-'+i, file);
              });


              So now you have a FormData object, ready to be sent along with the XMLHttpRequest.



              jQuery.ajax({
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              });


              It’s imperative that you set the contentType option to false, forcing jQuery not to add a Content-Type header for you, otherwise, the boundary string will be missing from it.
              Also, you must leave the processData flag set to false, otherwise, jQuery will try to convert your FormData into a string, which will fail.



              You may now retrieve the file in PHP using:



              $_FILES['file-0']


              (There is only one file, file-0, unless you specified the multiple attribute on your file input, in which case, the numbers will increment with each file.)



              Using the FormData emulation for older browsers



              var opts = {
              url: 'php/upload.php',
              data: data,
              cache: false,
              contentType: false,
              processData: false,
              method: 'POST',
              type: 'POST', // For jQuery < 1.9
              success: function(data){
              alert(data);
              }
              };
              if(data.fake) {
              // Make sure no text encoding stuff is done by xhr
              opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
              opts.contentType = "multipart/form-data; boundary="+data.boundary;
              opts.data = data.toString();
              }
              jQuery.ajax(opts);


              Create FormData from an existing form



              Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:



              var data = new FormData(jQuery('form')[0]);


              Use a PHP native array instead of a counter



              Just name your file elements the same and end the name in brackets:



              jQuery.each(jQuery('#file')[0].files, function(i, file) {
              data.append('file', file);
              });


              $_FILES['file'] will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Oct 5 '17 at 20:13

























              answered May 12 '11 at 9:36









              Raphael SchweikertRaphael Schweikert

              15.1k54862




              15.1k54862








              • 2





                Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

                – Raphael Schweikert
                Aug 24 '11 at 8:01








              • 12





                So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

                – Raphael Schweikert
                Apr 19 '12 at 9:44






              • 3





                This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

                – Timmmm
                Apr 6 '13 at 20:43






              • 4





                @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

                – Raphael Schweikert
                Apr 7 '13 at 8:57






              • 5





                @RoyiNamir It’s only documented in code, I’m afraid.

                – Raphael Schweikert
                Jan 6 '14 at 18:30














              • 2





                Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

                – Raphael Schweikert
                Aug 24 '11 at 8:01








              • 12





                So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

                – Raphael Schweikert
                Apr 19 '12 at 9:44






              • 3





                This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

                – Timmmm
                Apr 6 '13 at 20:43






              • 4





                @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

                – Raphael Schweikert
                Apr 7 '13 at 8:57






              • 5





                @RoyiNamir It’s only documented in code, I’m afraid.

                – Raphael Schweikert
                Jan 6 '14 at 18:30








              2




              2





              Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

              – Raphael Schweikert
              Aug 24 '11 at 8:01







              Also, there is a FormData emulation which will make porting this solution to older browsers quite simple. All you have to do is to check for data.fake and set the contentType property manually as well as overriding xhr to use sendAsBinary().

              – Raphael Schweikert
              Aug 24 '11 at 8:01






              12




              12





              So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

              – Raphael Schweikert
              Apr 19 '12 at 9:44





              So you’re neither using jQuery nor the FormData class and you’re asking me in the context of a question specific to jQuery and an answer specific to using FormData? I’m sorry but I don’t think I can help you there…

              – Raphael Schweikert
              Apr 19 '12 at 9:44




              3




              3





              This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

              – Timmmm
              Apr 6 '13 at 20:43





              This uses application/x-www-form-urlencoded. Is there a way to use multipart/form-data instead?

              – Timmmm
              Apr 6 '13 at 20:43




              4




              4





              @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

              – Raphael Schweikert
              Apr 7 '13 at 8:57





              @Timmmm No, it uses multipart/form-data. Using application/x-www-form-urlencoded would not work.

              – Raphael Schweikert
              Apr 7 '13 at 8:57




              5




              5





              @RoyiNamir It’s only documented in code, I’m afraid.

              – Raphael Schweikert
              Jan 6 '14 at 18:30





              @RoyiNamir It’s only documented in code, I’m afraid.

              – Raphael Schweikert
              Jan 6 '14 at 18:30













              46














              Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES, regardless of whether you use JavaScript to submit.



              HTML form:



              <form enctype="multipart/form-data" action="/test.php" 
              method="post" class="putImages">
              <input name="media" type="file" multiple/>
              <input class="button" type="submit" alt="Upload" value="Upload" />
              </form>


              PHP produces this $_FILES, when submitted without JavaScript:



              Array
              (
              [media] => Array
              (
              [name] => Array
              (
              [0] => Galata_Tower.jpg
              [1] => 518f.jpg
              )

              [type] => Array
              (
              [0] => image/jpeg
              [1] => image/jpeg
              )

              [tmp_name] => Array
              (
              [0] => /tmp/phpIQaOYo
              [1] => /tmp/phpJQaOYo
              )

              [error] => Array
              (
              [0] => 0
              [1] => 0
              )

              [size] => Array
              (
              [0] => 258004
              [1] => 127884
              )

              )

              )


              If you do progressive enhancement, using Raphael's JS to submit the files...



              var data = new FormData($('input[name^="media"]'));     
              jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
              data.append(i, file);
              });

              $.ajax({
              type: ppiFormMethod,
              data: data,
              url: ppiFormActionURL,
              cache: false,
              contentType: false,
              processData: false,
              success: function(data){
              alert(data);
              }
              });


              ... this is what PHP's $_FILES array looks like, after using that JavaScript to submit:



              Array
              (
              [0] => Array
              (
              [name] => Galata_Tower.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpAQaOYo
              [error] => 0
              [size] => 258004
              )

              [1] => Array
              (
              [name] => 518f.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpBQaOYo
              [error] => 0
              [size] => 127884
              )

              )


              That's a nice array, and actually what some people transform $_FILES into, but I find it's useful to work with the same $_FILES, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:



              // match anything not a [ or ]
              regexp = /^[^[]]+/;
              var fileInput = $('.putImages input[type="file"]');
              var fileInputName = regexp.exec( fileInput.attr('name') );

              // make files available
              var data = new FormData();
              jQuery.each($(fileInput)[0].files, function(i, file) {
              data.append(fileInputName+'['+i+']', file);
              });


              (14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)



              That code does two things.




              1. Retrieves the input name attribute automatically, making the HTML more maintainable. Now, as long as form has the class putImages, everything else is taken care of automatically. That is, the input need not have any special name.

              2. The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.


              With these changes, submitting with JavaScript now produces precisely the same $_FILES array as submitting with simple HTML.






              share|improve this answer


























              • Had the same issue with Safari. Thanks for the hint!

                – medoingthings
                Aug 4 '18 at 12:42
















              46














              Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES, regardless of whether you use JavaScript to submit.



              HTML form:



              <form enctype="multipart/form-data" action="/test.php" 
              method="post" class="putImages">
              <input name="media" type="file" multiple/>
              <input class="button" type="submit" alt="Upload" value="Upload" />
              </form>


              PHP produces this $_FILES, when submitted without JavaScript:



              Array
              (
              [media] => Array
              (
              [name] => Array
              (
              [0] => Galata_Tower.jpg
              [1] => 518f.jpg
              )

              [type] => Array
              (
              [0] => image/jpeg
              [1] => image/jpeg
              )

              [tmp_name] => Array
              (
              [0] => /tmp/phpIQaOYo
              [1] => /tmp/phpJQaOYo
              )

              [error] => Array
              (
              [0] => 0
              [1] => 0
              )

              [size] => Array
              (
              [0] => 258004
              [1] => 127884
              )

              )

              )


              If you do progressive enhancement, using Raphael's JS to submit the files...



              var data = new FormData($('input[name^="media"]'));     
              jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
              data.append(i, file);
              });

              $.ajax({
              type: ppiFormMethod,
              data: data,
              url: ppiFormActionURL,
              cache: false,
              contentType: false,
              processData: false,
              success: function(data){
              alert(data);
              }
              });


              ... this is what PHP's $_FILES array looks like, after using that JavaScript to submit:



              Array
              (
              [0] => Array
              (
              [name] => Galata_Tower.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpAQaOYo
              [error] => 0
              [size] => 258004
              )

              [1] => Array
              (
              [name] => 518f.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpBQaOYo
              [error] => 0
              [size] => 127884
              )

              )


              That's a nice array, and actually what some people transform $_FILES into, but I find it's useful to work with the same $_FILES, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:



              // match anything not a [ or ]
              regexp = /^[^[]]+/;
              var fileInput = $('.putImages input[type="file"]');
              var fileInputName = regexp.exec( fileInput.attr('name') );

              // make files available
              var data = new FormData();
              jQuery.each($(fileInput)[0].files, function(i, file) {
              data.append(fileInputName+'['+i+']', file);
              });


              (14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)



              That code does two things.




              1. Retrieves the input name attribute automatically, making the HTML more maintainable. Now, as long as form has the class putImages, everything else is taken care of automatically. That is, the input need not have any special name.

              2. The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.


              With these changes, submitting with JavaScript now produces precisely the same $_FILES array as submitting with simple HTML.






              share|improve this answer


























              • Had the same issue with Safari. Thanks for the hint!

                – medoingthings
                Aug 4 '18 at 12:42














              46












              46








              46







              Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES, regardless of whether you use JavaScript to submit.



              HTML form:



              <form enctype="multipart/form-data" action="/test.php" 
              method="post" class="putImages">
              <input name="media" type="file" multiple/>
              <input class="button" type="submit" alt="Upload" value="Upload" />
              </form>


              PHP produces this $_FILES, when submitted without JavaScript:



              Array
              (
              [media] => Array
              (
              [name] => Array
              (
              [0] => Galata_Tower.jpg
              [1] => 518f.jpg
              )

              [type] => Array
              (
              [0] => image/jpeg
              [1] => image/jpeg
              )

              [tmp_name] => Array
              (
              [0] => /tmp/phpIQaOYo
              [1] => /tmp/phpJQaOYo
              )

              [error] => Array
              (
              [0] => 0
              [1] => 0
              )

              [size] => Array
              (
              [0] => 258004
              [1] => 127884
              )

              )

              )


              If you do progressive enhancement, using Raphael's JS to submit the files...



              var data = new FormData($('input[name^="media"]'));     
              jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
              data.append(i, file);
              });

              $.ajax({
              type: ppiFormMethod,
              data: data,
              url: ppiFormActionURL,
              cache: false,
              contentType: false,
              processData: false,
              success: function(data){
              alert(data);
              }
              });


              ... this is what PHP's $_FILES array looks like, after using that JavaScript to submit:



              Array
              (
              [0] => Array
              (
              [name] => Galata_Tower.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpAQaOYo
              [error] => 0
              [size] => 258004
              )

              [1] => Array
              (
              [name] => 518f.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpBQaOYo
              [error] => 0
              [size] => 127884
              )

              )


              That's a nice array, and actually what some people transform $_FILES into, but I find it's useful to work with the same $_FILES, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:



              // match anything not a [ or ]
              regexp = /^[^[]]+/;
              var fileInput = $('.putImages input[type="file"]');
              var fileInputName = regexp.exec( fileInput.attr('name') );

              // make files available
              var data = new FormData();
              jQuery.each($(fileInput)[0].files, function(i, file) {
              data.append(fileInputName+'['+i+']', file);
              });


              (14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)



              That code does two things.




              1. Retrieves the input name attribute automatically, making the HTML more maintainable. Now, as long as form has the class putImages, everything else is taken care of automatically. That is, the input need not have any special name.

              2. The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.


              With these changes, submitting with JavaScript now produces precisely the same $_FILES array as submitting with simple HTML.






              share|improve this answer















              Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES, regardless of whether you use JavaScript to submit.



              HTML form:



              <form enctype="multipart/form-data" action="/test.php" 
              method="post" class="putImages">
              <input name="media" type="file" multiple/>
              <input class="button" type="submit" alt="Upload" value="Upload" />
              </form>


              PHP produces this $_FILES, when submitted without JavaScript:



              Array
              (
              [media] => Array
              (
              [name] => Array
              (
              [0] => Galata_Tower.jpg
              [1] => 518f.jpg
              )

              [type] => Array
              (
              [0] => image/jpeg
              [1] => image/jpeg
              )

              [tmp_name] => Array
              (
              [0] => /tmp/phpIQaOYo
              [1] => /tmp/phpJQaOYo
              )

              [error] => Array
              (
              [0] => 0
              [1] => 0
              )

              [size] => Array
              (
              [0] => 258004
              [1] => 127884
              )

              )

              )


              If you do progressive enhancement, using Raphael's JS to submit the files...



              var data = new FormData($('input[name^="media"]'));     
              jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
              data.append(i, file);
              });

              $.ajax({
              type: ppiFormMethod,
              data: data,
              url: ppiFormActionURL,
              cache: false,
              contentType: false,
              processData: false,
              success: function(data){
              alert(data);
              }
              });


              ... this is what PHP's $_FILES array looks like, after using that JavaScript to submit:



              Array
              (
              [0] => Array
              (
              [name] => Galata_Tower.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpAQaOYo
              [error] => 0
              [size] => 258004
              )

              [1] => Array
              (
              [name] => 518f.jpg
              [type] => image/jpeg
              [tmp_name] => /tmp/phpBQaOYo
              [error] => 0
              [size] => 127884
              )

              )


              That's a nice array, and actually what some people transform $_FILES into, but I find it's useful to work with the same $_FILES, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:



              // match anything not a [ or ]
              regexp = /^[^[]]+/;
              var fileInput = $('.putImages input[type="file"]');
              var fileInputName = regexp.exec( fileInput.attr('name') );

              // make files available
              var data = new FormData();
              jQuery.each($(fileInput)[0].files, function(i, file) {
              data.append(fileInputName+'['+i+']', file);
              });


              (14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)



              That code does two things.




              1. Retrieves the input name attribute automatically, making the HTML more maintainable. Now, as long as form has the class putImages, everything else is taken care of automatically. That is, the input need not have any special name.

              2. The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.


              With these changes, submitting with JavaScript now produces precisely the same $_FILES array as submitting with simple HTML.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Apr 14 '17 at 17:00

























              answered Jan 10 '12 at 0:56









              ajmicekajmicek

              66656




              66656













              • Had the same issue with Safari. Thanks for the hint!

                – medoingthings
                Aug 4 '18 at 12:42



















              • Had the same issue with Safari. Thanks for the hint!

                – medoingthings
                Aug 4 '18 at 12:42

















              Had the same issue with Safari. Thanks for the hint!

              – medoingthings
              Aug 4 '18 at 12:42





              Had the same issue with Safari. Thanks for the hint!

              – medoingthings
              Aug 4 '18 at 12:42











              44














              Look at my code, it does the job for me



              $( '#formId' )
              .submit( function( e ) {
              $.ajax( {
              url: 'FormSubmitUrl',
              type: 'POST',
              data: new FormData( this ),
              processData: false,
              contentType: false
              } );
              e.preventDefault();
              } );





              share|improve this answer






























                44














                Look at my code, it does the job for me



                $( '#formId' )
                .submit( function( e ) {
                $.ajax( {
                url: 'FormSubmitUrl',
                type: 'POST',
                data: new FormData( this ),
                processData: false,
                contentType: false
                } );
                e.preventDefault();
                } );





                share|improve this answer




























                  44












                  44








                  44







                  Look at my code, it does the job for me



                  $( '#formId' )
                  .submit( function( e ) {
                  $.ajax( {
                  url: 'FormSubmitUrl',
                  type: 'POST',
                  data: new FormData( this ),
                  processData: false,
                  contentType: false
                  } );
                  e.preventDefault();
                  } );





                  share|improve this answer















                  Look at my code, it does the job for me



                  $( '#formId' )
                  .submit( function( e ) {
                  $.ajax( {
                  url: 'FormSubmitUrl',
                  type: 'POST',
                  data: new FormData( this ),
                  processData: false,
                  contentType: false
                  } );
                  e.preventDefault();
                  } );






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 4 '14 at 5:06

























                  answered Aug 30 '14 at 6:49









                  Asad MalikAsad Malik

                  1,25111519




                  1,25111519























                      44














                      I just built this function based on some info I read.



                      Use it like using .serialize(), instead just put .serializefiles();.

                      Working here in my tests.



                      //USAGE: $("#form").serializefiles();
                      (function($) {
                      $.fn.serializefiles = function() {
                      var obj = $(this);
                      /* ADD FILE TO PARAM AJAX */
                      var formData = new FormData();
                      $.each($(obj).find("input[type='file']"), function(i, tag) {
                      $.each($(tag)[0].files, function(i, file) {
                      formData.append(tag.name, file);
                      });
                      });
                      var params = $(obj).serializeArray();
                      $.each(params, function (i, val) {
                      formData.append(val.name, val.value);
                      });
                      return formData;
                      };
                      })(jQuery);





                      share|improve this answer





















                      • 2





                        I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

                        – Fallenreaper
                        Sep 19 '12 at 15:09






                      • 1





                        that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

                        – SchurigH
                        Nov 19 '13 at 21:53













                      • that was tricky (y) :D loved it

                        – sarath
                        May 18 '15 at 10:30
















                      44














                      I just built this function based on some info I read.



                      Use it like using .serialize(), instead just put .serializefiles();.

                      Working here in my tests.



                      //USAGE: $("#form").serializefiles();
                      (function($) {
                      $.fn.serializefiles = function() {
                      var obj = $(this);
                      /* ADD FILE TO PARAM AJAX */
                      var formData = new FormData();
                      $.each($(obj).find("input[type='file']"), function(i, tag) {
                      $.each($(tag)[0].files, function(i, file) {
                      formData.append(tag.name, file);
                      });
                      });
                      var params = $(obj).serializeArray();
                      $.each(params, function (i, val) {
                      formData.append(val.name, val.value);
                      });
                      return formData;
                      };
                      })(jQuery);





                      share|improve this answer





















                      • 2





                        I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

                        – Fallenreaper
                        Sep 19 '12 at 15:09






                      • 1





                        that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

                        – SchurigH
                        Nov 19 '13 at 21:53













                      • that was tricky (y) :D loved it

                        – sarath
                        May 18 '15 at 10:30














                      44












                      44








                      44







                      I just built this function based on some info I read.



                      Use it like using .serialize(), instead just put .serializefiles();.

                      Working here in my tests.



                      //USAGE: $("#form").serializefiles();
                      (function($) {
                      $.fn.serializefiles = function() {
                      var obj = $(this);
                      /* ADD FILE TO PARAM AJAX */
                      var formData = new FormData();
                      $.each($(obj).find("input[type='file']"), function(i, tag) {
                      $.each($(tag)[0].files, function(i, file) {
                      formData.append(tag.name, file);
                      });
                      });
                      var params = $(obj).serializeArray();
                      $.each(params, function (i, val) {
                      formData.append(val.name, val.value);
                      });
                      return formData;
                      };
                      })(jQuery);





                      share|improve this answer















                      I just built this function based on some info I read.



                      Use it like using .serialize(), instead just put .serializefiles();.

                      Working here in my tests.



                      //USAGE: $("#form").serializefiles();
                      (function($) {
                      $.fn.serializefiles = function() {
                      var obj = $(this);
                      /* ADD FILE TO PARAM AJAX */
                      var formData = new FormData();
                      $.each($(obj).find("input[type='file']"), function(i, tag) {
                      $.each($(tag)[0].files, function(i, file) {
                      formData.append(tag.name, file);
                      });
                      });
                      var params = $(obj).serializeArray();
                      $.each(params, function (i, val) {
                      formData.append(val.name, val.value);
                      });
                      return formData;
                      };
                      })(jQuery);






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Oct 10 '18 at 17:01









                      Tod Birdsall

                      7,91922834




                      7,91922834










                      answered Sep 14 '12 at 14:33









                      evandro777evandro777

                      54144




                      54144








                      • 2





                        I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

                        – Fallenreaper
                        Sep 19 '12 at 15:09






                      • 1





                        that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

                        – SchurigH
                        Nov 19 '13 at 21:53













                      • that was tricky (y) :D loved it

                        – sarath
                        May 18 '15 at 10:30














                      • 2





                        I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

                        – Fallenreaper
                        Sep 19 '12 at 15:09






                      • 1





                        that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

                        – SchurigH
                        Nov 19 '13 at 21:53













                      • that was tricky (y) :D loved it

                        – sarath
                        May 18 '15 at 10:30








                      2




                      2





                      I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

                      – Fallenreaper
                      Sep 19 '12 at 15:09





                      I was trying to get this working, but it seemed to not recognize serializefiles() as a function, despite this definition going at the top of the page.

                      – Fallenreaper
                      Sep 19 '12 at 15:09




                      1




                      1





                      that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

                      – SchurigH
                      Nov 19 '13 at 21:53







                      that works for me just fine. getting data with var data = $("#avatar-form").serializefiles(); sending this via ajax data parameter and analysing with express formidable: form.parse(req, function(err, fields, files){ thank you for that code snippet :)

                      – SchurigH
                      Nov 19 '13 at 21:53















                      that was tricky (y) :D loved it

                      – sarath
                      May 18 '15 at 10:30





                      that was tricky (y) :D loved it

                      – sarath
                      May 18 '15 at 10:30











                      23














                      If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.



                      $('#my-form').submit( function(e) {
                      e.preventDefault();

                      var data = new FormData(this); // <-- 'this' is your form element

                      $.ajax({
                      url: '/my_URL/',
                      data: data,
                      cache: false,
                      contentType: false,
                      processData: false,
                      type: 'POST',
                      success: function(data){
                      ...





                      share|improve this answer




























                        23














                        If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.



                        $('#my-form').submit( function(e) {
                        e.preventDefault();

                        var data = new FormData(this); // <-- 'this' is your form element

                        $.ajax({
                        url: '/my_URL/',
                        data: data,
                        cache: false,
                        contentType: false,
                        processData: false,
                        type: 'POST',
                        success: function(data){
                        ...





                        share|improve this answer


























                          23












                          23








                          23







                          If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.



                          $('#my-form').submit( function(e) {
                          e.preventDefault();

                          var data = new FormData(this); // <-- 'this' is your form element

                          $.ajax({
                          url: '/my_URL/',
                          data: data,
                          cache: false,
                          contentType: false,
                          processData: false,
                          type: 'POST',
                          success: function(data){
                          ...





                          share|improve this answer













                          If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.



                          $('#my-form').submit( function(e) {
                          e.preventDefault();

                          var data = new FormData(this); // <-- 'this' is your form element

                          $.ajax({
                          url: '/my_URL/',
                          data: data,
                          cache: false,
                          contentType: false,
                          processData: false,
                          type: 'POST',
                          success: function(data){
                          ...






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Jun 2 '14 at 17:43









                          Devin VenableDevin Venable

                          47135




                          47135























                              6














                              Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.



                              I also wanted to use jQuery's on() method so I could avoid using .ready().



                              That got me to this:
                              (replace formSelector with your jQuery selector)



                              $(document).on('submit', formSelecter, function( e ) {
                              e.preventDefault();
                              $.ajax( {
                              url: $(this).attr('action'),
                              type: 'POST',
                              data: new FormData( this ),
                              processData: false,
                              contentType: false
                              }).done(function( data ) {
                              //do stuff with the data you got back.
                              });

                              });





                              share|improve this answer






























                                6














                                Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.



                                I also wanted to use jQuery's on() method so I could avoid using .ready().



                                That got me to this:
                                (replace formSelector with your jQuery selector)



                                $(document).on('submit', formSelecter, function( e ) {
                                e.preventDefault();
                                $.ajax( {
                                url: $(this).attr('action'),
                                type: 'POST',
                                data: new FormData( this ),
                                processData: false,
                                contentType: false
                                }).done(function( data ) {
                                //do stuff with the data you got back.
                                });

                                });





                                share|improve this answer




























                                  6












                                  6








                                  6







                                  Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.



                                  I also wanted to use jQuery's on() method so I could avoid using .ready().



                                  That got me to this:
                                  (replace formSelector with your jQuery selector)



                                  $(document).on('submit', formSelecter, function( e ) {
                                  e.preventDefault();
                                  $.ajax( {
                                  url: $(this).attr('action'),
                                  type: 'POST',
                                  data: new FormData( this ),
                                  processData: false,
                                  contentType: false
                                  }).done(function( data ) {
                                  //do stuff with the data you got back.
                                  });

                                  });





                                  share|improve this answer















                                  Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.



                                  I also wanted to use jQuery's on() method so I could avoid using .ready().



                                  That got me to this:
                                  (replace formSelector with your jQuery selector)



                                  $(document).on('submit', formSelecter, function( e ) {
                                  e.preventDefault();
                                  $.ajax( {
                                  url: $(this).attr('action'),
                                  type: 'POST',
                                  data: new FormData( this ),
                                  processData: false,
                                  contentType: false
                                  }).done(function( data ) {
                                  //do stuff with the data you got back.
                                  });

                                  });






                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited May 23 '17 at 12:34









                                  Community

                                  11




                                  11










                                  answered Jun 15 '16 at 16:54









                                  Karl HenselinKarl Henselin

                                  8321012




                                  8321012























                                      1














                                      The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.



                                      Mozilla Dev has a nice page on manipulating FormData objects.



                                      So, add an empty form somewhere in your page, specifying the enctype:



                                      <form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>


                                      Then, create FormData object as:



                                      var data = new FormData($("#fileinfo"));


                                      and proceed as in Raphael's code.






                                      share|improve this answer


























                                      • I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

                                        – glyph
                                        Mar 1 '13 at 21:17


















                                      1














                                      The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.



                                      Mozilla Dev has a nice page on manipulating FormData objects.



                                      So, add an empty form somewhere in your page, specifying the enctype:



                                      <form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>


                                      Then, create FormData object as:



                                      var data = new FormData($("#fileinfo"));


                                      and proceed as in Raphael's code.






                                      share|improve this answer


























                                      • I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

                                        – glyph
                                        Mar 1 '13 at 21:17
















                                      1












                                      1








                                      1







                                      The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.



                                      Mozilla Dev has a nice page on manipulating FormData objects.



                                      So, add an empty form somewhere in your page, specifying the enctype:



                                      <form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>


                                      Then, create FormData object as:



                                      var data = new FormData($("#fileinfo"));


                                      and proceed as in Raphael's code.






                                      share|improve this answer















                                      The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.



                                      Mozilla Dev has a nice page on manipulating FormData objects.



                                      So, add an empty form somewhere in your page, specifying the enctype:



                                      <form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>


                                      Then, create FormData object as:



                                      var data = new FormData($("#fileinfo"));


                                      and proceed as in Raphael's code.







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited May 23 '17 at 12:34









                                      Community

                                      11




                                      11










                                      answered Feb 22 '13 at 0:24









                                      topkaratopkara

                                      688615




                                      688615













                                      • I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

                                        – glyph
                                        Mar 1 '13 at 21:17





















                                      • I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

                                        – glyph
                                        Mar 1 '13 at 21:17



















                                      I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

                                      – glyph
                                      Mar 1 '13 at 21:17







                                      I had a problem with my jquery ajax uploads silently hanging in Safari and ended up doing a browser conditional $('form-name').submit() for Safari instead of the ajax upload that works in IE9 and FF18. Probably not an ideal solution for multi-uploads but I was doing this for a single file into an iframe from a jquery dialog so it worked ok.

                                      – glyph
                                      Mar 1 '13 at 21:17













                                      0














                                      One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.



                                      For example, I was posting to http://server.com/context?param=x



                                      In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)



                                      During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.






                                      share|improve this answer




























                                        0














                                        One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.



                                        For example, I was posting to http://server.com/context?param=x



                                        In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)



                                        During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.






                                        share|improve this answer


























                                          0












                                          0








                                          0







                                          One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.



                                          For example, I was posting to http://server.com/context?param=x



                                          In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)



                                          During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.






                                          share|improve this answer













                                          One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.



                                          For example, I was posting to http://server.com/context?param=x



                                          In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)



                                          During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.







                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered Mar 17 '16 at 22:07









                                          jamesjames

                                          32045




                                          32045























                                              0














                                              Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).



                                              Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript






                                              share|improve this answer




























                                                0














                                                Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).



                                                Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript






                                                share|improve this answer


























                                                  0












                                                  0








                                                  0







                                                  Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).



                                                  Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript






                                                  share|improve this answer













                                                  Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).



                                                  Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript







                                                  share|improve this answer












                                                  share|improve this answer



                                                  share|improve this answer










                                                  answered Feb 8 '18 at 10:42









                                                  sudipsudip

                                                  1,9092128




                                                  1,9092128























                                                      0














                                                      All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:



                                                      formData.append(val.name, val.value);






                                                      share|improve this answer




























                                                        0














                                                        All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:



                                                        formData.append(val.name, val.value);






                                                        share|improve this answer


























                                                          0












                                                          0








                                                          0







                                                          All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:



                                                          formData.append(val.name, val.value);






                                                          share|improve this answer













                                                          All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:



                                                          formData.append(val.name, val.value);







                                                          share|improve this answer












                                                          share|improve this answer



                                                          share|improve this answer










                                                          answered Mar 8 '18 at 13:47









                                                          szatti1489szatti1489

                                                          802311




                                                          802311























                                                              0














                                                              Nova days you not need even jQuery:) fetch API support table



                                                              let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})





                                                              share|improve this answer
























                                                              • In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                                                                – Omar Tariq
                                                                Nov 9 '18 at 15:00













                                                              • @OmarTariq yes I have a similar link in my answer))

                                                                – Alex Nikulin
                                                                Nov 11 '18 at 14:11











                                                              • Oops. How can I miss that :-|

                                                                – Omar Tariq
                                                                Nov 12 '18 at 12:01
















                                                              0














                                                              Nova days you not need even jQuery:) fetch API support table



                                                              let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})





                                                              share|improve this answer
























                                                              • In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                                                                – Omar Tariq
                                                                Nov 9 '18 at 15:00













                                                              • @OmarTariq yes I have a similar link in my answer))

                                                                – Alex Nikulin
                                                                Nov 11 '18 at 14:11











                                                              • Oops. How can I miss that :-|

                                                                – Omar Tariq
                                                                Nov 12 '18 at 12:01














                                                              0












                                                              0








                                                              0







                                                              Nova days you not need even jQuery:) fetch API support table



                                                              let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})





                                                              share|improve this answer













                                                              Nova days you not need even jQuery:) fetch API support table



                                                              let result = fetch('url', {method: 'POST', body: new FormData(documemt.querySelector("#form"))})






                                                              share|improve this answer












                                                              share|improve this answer



                                                              share|improve this answer










                                                              answered Oct 29 '18 at 11:26









                                                              Alex NikulinAlex Nikulin

                                                              3,75112125




                                                              3,75112125













                                                              • In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                                                                – Omar Tariq
                                                                Nov 9 '18 at 15:00













                                                              • @OmarTariq yes I have a similar link in my answer))

                                                                – Alex Nikulin
                                                                Nov 11 '18 at 14:11











                                                              • Oops. How can I miss that :-|

                                                                – Omar Tariq
                                                                Nov 12 '18 at 12:01



















                                                              • In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                                                                – Omar Tariq
                                                                Nov 9 '18 at 15:00













                                                              • @OmarTariq yes I have a similar link in my answer))

                                                                – Alex Nikulin
                                                                Nov 11 '18 at 14:11











                                                              • Oops. How can I miss that :-|

                                                                – Omar Tariq
                                                                Nov 12 '18 at 12:01

















                                                              In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                                                              – Omar Tariq
                                                              Nov 9 '18 at 15:00







                                                              In the context of file upload via fetch please see compatibility: developer.mozilla.org/en-US/docs/Web/API/…

                                                              – Omar Tariq
                                                              Nov 9 '18 at 15:00















                                                              @OmarTariq yes I have a similar link in my answer))

                                                              – Alex Nikulin
                                                              Nov 11 '18 at 14:11





                                                              @OmarTariq yes I have a similar link in my answer))

                                                              – Alex Nikulin
                                                              Nov 11 '18 at 14:11













                                                              Oops. How can I miss that :-|

                                                              – Omar Tariq
                                                              Nov 12 '18 at 12:01





                                                              Oops. How can I miss that :-|

                                                              – Omar Tariq
                                                              Nov 12 '18 at 12:01











                                                              -1















                                                              1. get form object by jquery-> $("#id")[0]

                                                              2. data = new FormData($("#id")[0]);

                                                              3. ok,data is your want






                                                              share|improve this answer


























                                                              • $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                                                                – Mohammad-Hossein Jamali
                                                                May 29 '15 at 6:47
















                                                              -1















                                                              1. get form object by jquery-> $("#id")[0]

                                                              2. data = new FormData($("#id")[0]);

                                                              3. ok,data is your want






                                                              share|improve this answer


























                                                              • $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                                                                – Mohammad-Hossein Jamali
                                                                May 29 '15 at 6:47














                                                              -1












                                                              -1








                                                              -1








                                                              1. get form object by jquery-> $("#id")[0]

                                                              2. data = new FormData($("#id")[0]);

                                                              3. ok,data is your want






                                                              share|improve this answer
















                                                              1. get form object by jquery-> $("#id")[0]

                                                              2. data = new FormData($("#id")[0]);

                                                              3. ok,data is your want







                                                              share|improve this answer














                                                              share|improve this answer



                                                              share|improve this answer








                                                              edited Jul 18 '13 at 10:11









                                                              Azik Abdullah

                                                              6,6251263111




                                                              6,6251263111










                                                              answered Jul 18 '13 at 9:54









                                                              user1909226user1909226

                                                              17




                                                              17













                                                              • $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                                                                – Mohammad-Hossein Jamali
                                                                May 29 '15 at 6:47



















                                                              • $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                                                                – Mohammad-Hossein Jamali
                                                                May 29 '15 at 6:47

















                                                              $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                                                              – Mohammad-Hossein Jamali
                                                              May 29 '15 at 6:47





                                                              $("#id")[0] returns first none empty <input type="file" /> of the form, how do you submit entire form including all <input type="file" /> of it?

                                                              – Mohammad-Hossein Jamali
                                                              May 29 '15 at 6:47





                                                              protected by Community Nov 1 '13 at 21:44



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