Variable based AWK partly string match (if column/word partly matches)
This question comes from this other.
Case scenario for my Linux shell script:
$ cat test.txt
C1 C2 C3
1 a snow
2 b snowman
snow c sowman
Searching for lines with third field containing "snow" works OK:
$ awk '$3 ~/snow/' test.txt
1 a snow
2 b snowman
But I need to do it by using variables:
$ word="snow"
$ echo $word
snow
$ awk -v variable="snow" '$3 ~/variable/' test.txt
$ awk -v variable="$word" '$3 ~/variable/' test.txt
$
As can be seen, there are no results.
How could I perform AWK search variable-based?
regex awk syntax
edited Jan 1 at 7:20
Cyrus
46.1k43878
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
add a comment |
This question comes from this other.
Case scenario for my Linux shell script:
$ cat test.txt
C1 C2 C3
1 a snow
2 b snowman
snow c sowman
Searching for lines with third field containing "snow" works OK:
$ awk '$3 ~/snow/' test.txt
1 a snow
2 b snowman
But I need to do it by using variables:
$ word="snow"
$ echo $word
snow
$ awk -v variable="snow" '$3 ~/variable/' test.txt
$ awk -v variable="$word" '$3 ~/variable/' test.txt
$
As can be seen, there are no results.
How could I perform AWK search variable-based?
regex awk syntax
edited Jan 1 at 7:20
Cyrus
46.1k43878
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
add a comment |
This question comes from this other.
Case scenario for my Linux shell script:
$ cat test.txt
C1 C2 C3
1 a snow
2 b snowman
snow c sowman
Searching for lines with third field containing "snow" works OK:
$ awk '$3 ~/snow/' test.txt
1 a snow
2 b snowman
But I need to do it by using variables:
$ word="snow"
$ echo $word
snow
$ awk -v variable="snow" '$3 ~/variable/' test.txt
$ awk -v variable="$word" '$3 ~/variable/' test.txt
$
As can be seen, there are no results.
How could I perform AWK search variable-based?
regex awk syntax
edited Jan 1 at 7:20
Cyrus
46.1k43878
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
This question comes from this other.
Case scenario for my Linux shell script:
$ cat test.txt
C1 C2 C3
1 a snow
2 b snowman
snow c sowman
Searching for lines with third field containing "snow" works OK:
$ awk '$3 ~/snow/' test.txt
1 a snow
2 b snowman
But I need to do it by using variables:
$ word="snow"
$ echo $word
snow
$ awk -v variable="snow" '$3 ~/variable/' test.txt
$ awk -v variable="$word" '$3 ~/variable/' test.txt
$
As can be seen, there are no results.
How could I perform AWK search variable-based?
regex awk syntax
regex awk syntax
edited Jan 1 at 7:20
Cyrus
46.1k43878
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
edited Jan 1 at 7:20
Cyrus
46.1k43878
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
edited Jan 1 at 7:20
Cyrus
46.1k43878
edited Jan 1 at 7:20
Cyrus
46.1k43878
edited Jan 1 at 7:20
Cyrus
46.1k43878
46.1k43878
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
asked Jan 1 at 2:03
Sopalajo de ArrierezSopalajo de Arrierez
1,59822035
1,59822035
add a comment |
add a comment |
1 Answer
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You should change $3 ~/variable/ TO $3 ~ variable since a /../ contains regexp not variables. So in your case it will try to search "a string" named variable NOT "a variable" named variable.
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
1
Yes,/.../is a regex literal. If the pattern is stored in a variable, you don't use the slashes.
– glenn jackman
Jan 1 at 3:20
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
You should change $3 ~/variable/ TO $3 ~ variable since a /../ contains regexp not variables. So in your case it will try to search "a string" named variable NOT "a variable" named variable.
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
1
Yes,/.../is a regex literal. If the pattern is stored in a variable, you don't use the slashes.
– glenn jackman
Jan 1 at 3:20
add a comment |
You should change $3 ~/variable/ TO $3 ~ variable since a /../ contains regexp not variables. So in your case it will try to search "a string" named variable NOT "a variable" named variable.
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
1
Yes,/.../is a regex literal. If the pattern is stored in a variable, you don't use the slashes.
– glenn jackman
Jan 1 at 3:20
add a comment |
You should change $3 ~/variable/ TO $3 ~ variable since a /../ contains regexp not variables. So in your case it will try to search "a string" named variable NOT "a variable" named variable.
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
You should change $3 ~/variable/ TO $3 ~ variable since a /../ contains regexp not variables. So in your case it will try to search "a string" named variable NOT "a variable" named variable.
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
edited Jan 1 at 4:49
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
answered Jan 1 at 2:06
RavinderSingh13RavinderSingh13
28k41638
28k41638
1
Yes,/.../is a regex literal. If the pattern is stored in a variable, you don't use the slashes.
– glenn jackman
Jan 1 at 3:20
add a comment |
1
Yes,/.../is a regex literal. If the pattern is stored in a variable, you don't use the slashes.
– glenn jackman
Jan 1 at 3:20
1
1
Yes,
/.../ is a regex literal. If the pattern is stored in a variable, you don't use the slashes.– glenn jackman
Jan 1 at 3:20
Yes,
/.../ is a regex literal. If the pattern is stored in a variable, you don't use the slashes.– glenn jackman
Jan 1 at 3:20
add a comment |
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