Edit - Selecting an image on Instagram is not working on my chrome extension
EDIT #2
I've just tried selecting every div
element on the website as each image is contained in a div
. So, I used querySelectorAll
followed with an if
statement. The if
statement checks the div
and makes sure the image (class: FFVAD
) is actually inside of the div
before proceeding. But it's not working, it's now throwing a getElementsByClassName is not a function
error.
My content script:
console.log('injected')
window.onload = function() {
var imagediv = document.querySelectorAll('div')
console.log('selected elements')
var i;
for (i = 0; i < imagediv.length; i++) {
imagediv[i].addEventListener('mouseover', function(el){
if (el.getElementsByClassName('FFVAD').length > 0) { //if the image with the class FFVAD is in the div
el.target.style.border = "7px solid red" //change the certain div's color
}
})
}
}
PREVIOUS QUESTION
I am developing a chrome extension which injects a javascript-written script into Instagram. I am trying to get the src of each image displayed on the users profile.
I have tried using document.querySelectorAll('img')
to get every image element, but that isn't working. So, I took a peek in the developer console and noticed each image has a class called FFVAD
. So, I used document.getElementsByClassName('FFVAD')
(reference here). I also noticed each image has a div
element as their parent. So, I tried doing this with my code:
My content script:
console.log('injected')
var image = document.getElementsByClassName('FFVAD') // instagram sets all
their images as the class FFVAD, as I looked in the inspect element window
console.log('selected elements')
while(image.length > 0){ //for every image
image[0].parentNode.addEventListener("mouseover", function (event) { //when the image's parent is hovered
event.style.border = "2px solid red";
});
image[0].parentNode.addEventListener("mouseout", function (event) { //when the image's parent isn't hovered
event.style.border = "none";
});
image[0].parentNode.addEventListener("click", function(event){ //when the image's parent is clicked
var child = event.childNodes; //get the image in the image's div
console.log(child[1].src) //log the src of the image
});
}
My exensions manifest:
{
"manifest_version": 2,
"name": "Testing",
"description": "Test extension",
"version": "0.0.1",
"author": "tester123",
"icons":{
"16": "icon.png",
"48": "icon2.png",
"128": "icon3.png"
},
"content_scripts": [{
"all_frames": false,
"js": ["imgselect.js"],
"matches": [ "https://*.instagram.com/*"],
"run_at": "document_end"
}],
"browser_action": {
"default_icon": "icon.png",
"default_popup": "popup.html"
},
"permissions": [
"tabs"
]
}
I used parentNode
to get the parent of the image. I expect to see a red border around the image's div parent when it's hovered and seeing the src of the image in the console but I'm not seeing results. Any help will be appreciated, thank you!
javascript dom google-chrome-extension content-script
|
show 1 more comment
EDIT #2
I've just tried selecting every div
element on the website as each image is contained in a div
. So, I used querySelectorAll
followed with an if
statement. The if
statement checks the div
and makes sure the image (class: FFVAD
) is actually inside of the div
before proceeding. But it's not working, it's now throwing a getElementsByClassName is not a function
error.
My content script:
console.log('injected')
window.onload = function() {
var imagediv = document.querySelectorAll('div')
console.log('selected elements')
var i;
for (i = 0; i < imagediv.length; i++) {
imagediv[i].addEventListener('mouseover', function(el){
if (el.getElementsByClassName('FFVAD').length > 0) { //if the image with the class FFVAD is in the div
el.target.style.border = "7px solid red" //change the certain div's color
}
})
}
}
PREVIOUS QUESTION
I am developing a chrome extension which injects a javascript-written script into Instagram. I am trying to get the src of each image displayed on the users profile.
I have tried using document.querySelectorAll('img')
to get every image element, but that isn't working. So, I took a peek in the developer console and noticed each image has a class called FFVAD
. So, I used document.getElementsByClassName('FFVAD')
(reference here). I also noticed each image has a div
element as their parent. So, I tried doing this with my code:
My content script:
console.log('injected')
var image = document.getElementsByClassName('FFVAD') // instagram sets all
their images as the class FFVAD, as I looked in the inspect element window
console.log('selected elements')
while(image.length > 0){ //for every image
image[0].parentNode.addEventListener("mouseover", function (event) { //when the image's parent is hovered
event.style.border = "2px solid red";
});
image[0].parentNode.addEventListener("mouseout", function (event) { //when the image's parent isn't hovered
event.style.border = "none";
});
image[0].parentNode.addEventListener("click", function(event){ //when the image's parent is clicked
var child = event.childNodes; //get the image in the image's div
console.log(child[1].src) //log the src of the image
});
}
My exensions manifest:
{
"manifest_version": 2,
"name": "Testing",
"description": "Test extension",
"version": "0.0.1",
"author": "tester123",
"icons":{
"16": "icon.png",
"48": "icon2.png",
"128": "icon3.png"
},
"content_scripts": [{
"all_frames": false,
"js": ["imgselect.js"],
"matches": [ "https://*.instagram.com/*"],
"run_at": "document_end"
}],
"browser_action": {
"default_icon": "icon.png",
"default_popup": "popup.html"
},
"permissions": [
"tabs"
]
}
I used parentNode
to get the parent of the image. I expect to see a red border around the image's div parent when it's hovered and seeing the src of the image in the console but I'm not seeing results. Any help will be appreciated, thank you!
javascript dom google-chrome-extension content-script
Is it giving you any errors?
– Charlie Fish
Dec 28 '18 at 0:08
@CharlieFish It's not giving me any errors
– johnboy13
Dec 28 '18 at 0:08
Try add the event listener in this wayimage[0].addEventListener
and then changeevent.style.border = "2px solid red";
intoevent.target.style.border = "2px solid red";
And you should do a for loop to change all the element on the image object. Something like(for i=0; i<image.length; i++)
image[i].addEventListener
– Mattia
Dec 28 '18 at 0:26
@Mattia I just updated my question with new code that I've tried.
– johnboy13
Dec 28 '18 at 0:43
@johnboy13 jsfiddle.net/2L9cmyto/13
– Mattia
Dec 28 '18 at 1:46
|
show 1 more comment
EDIT #2
I've just tried selecting every div
element on the website as each image is contained in a div
. So, I used querySelectorAll
followed with an if
statement. The if
statement checks the div
and makes sure the image (class: FFVAD
) is actually inside of the div
before proceeding. But it's not working, it's now throwing a getElementsByClassName is not a function
error.
My content script:
console.log('injected')
window.onload = function() {
var imagediv = document.querySelectorAll('div')
console.log('selected elements')
var i;
for (i = 0; i < imagediv.length; i++) {
imagediv[i].addEventListener('mouseover', function(el){
if (el.getElementsByClassName('FFVAD').length > 0) { //if the image with the class FFVAD is in the div
el.target.style.border = "7px solid red" //change the certain div's color
}
})
}
}
PREVIOUS QUESTION
I am developing a chrome extension which injects a javascript-written script into Instagram. I am trying to get the src of each image displayed on the users profile.
I have tried using document.querySelectorAll('img')
to get every image element, but that isn't working. So, I took a peek in the developer console and noticed each image has a class called FFVAD
. So, I used document.getElementsByClassName('FFVAD')
(reference here). I also noticed each image has a div
element as their parent. So, I tried doing this with my code:
My content script:
console.log('injected')
var image = document.getElementsByClassName('FFVAD') // instagram sets all
their images as the class FFVAD, as I looked in the inspect element window
console.log('selected elements')
while(image.length > 0){ //for every image
image[0].parentNode.addEventListener("mouseover", function (event) { //when the image's parent is hovered
event.style.border = "2px solid red";
});
image[0].parentNode.addEventListener("mouseout", function (event) { //when the image's parent isn't hovered
event.style.border = "none";
});
image[0].parentNode.addEventListener("click", function(event){ //when the image's parent is clicked
var child = event.childNodes; //get the image in the image's div
console.log(child[1].src) //log the src of the image
});
}
My exensions manifest:
{
"manifest_version": 2,
"name": "Testing",
"description": "Test extension",
"version": "0.0.1",
"author": "tester123",
"icons":{
"16": "icon.png",
"48": "icon2.png",
"128": "icon3.png"
},
"content_scripts": [{
"all_frames": false,
"js": ["imgselect.js"],
"matches": [ "https://*.instagram.com/*"],
"run_at": "document_end"
}],
"browser_action": {
"default_icon": "icon.png",
"default_popup": "popup.html"
},
"permissions": [
"tabs"
]
}
I used parentNode
to get the parent of the image. I expect to see a red border around the image's div parent when it's hovered and seeing the src of the image in the console but I'm not seeing results. Any help will be appreciated, thank you!
javascript dom google-chrome-extension content-script
EDIT #2
I've just tried selecting every div
element on the website as each image is contained in a div
. So, I used querySelectorAll
followed with an if
statement. The if
statement checks the div
and makes sure the image (class: FFVAD
) is actually inside of the div
before proceeding. But it's not working, it's now throwing a getElementsByClassName is not a function
error.
My content script:
console.log('injected')
window.onload = function() {
var imagediv = document.querySelectorAll('div')
console.log('selected elements')
var i;
for (i = 0; i < imagediv.length; i++) {
imagediv[i].addEventListener('mouseover', function(el){
if (el.getElementsByClassName('FFVAD').length > 0) { //if the image with the class FFVAD is in the div
el.target.style.border = "7px solid red" //change the certain div's color
}
})
}
}
PREVIOUS QUESTION
I am developing a chrome extension which injects a javascript-written script into Instagram. I am trying to get the src of each image displayed on the users profile.
I have tried using document.querySelectorAll('img')
to get every image element, but that isn't working. So, I took a peek in the developer console and noticed each image has a class called FFVAD
. So, I used document.getElementsByClassName('FFVAD')
(reference here). I also noticed each image has a div
element as their parent. So, I tried doing this with my code:
My content script:
console.log('injected')
var image = document.getElementsByClassName('FFVAD') // instagram sets all
their images as the class FFVAD, as I looked in the inspect element window
console.log('selected elements')
while(image.length > 0){ //for every image
image[0].parentNode.addEventListener("mouseover", function (event) { //when the image's parent is hovered
event.style.border = "2px solid red";
});
image[0].parentNode.addEventListener("mouseout", function (event) { //when the image's parent isn't hovered
event.style.border = "none";
});
image[0].parentNode.addEventListener("click", function(event){ //when the image's parent is clicked
var child = event.childNodes; //get the image in the image's div
console.log(child[1].src) //log the src of the image
});
}
My exensions manifest:
{
"manifest_version": 2,
"name": "Testing",
"description": "Test extension",
"version": "0.0.1",
"author": "tester123",
"icons":{
"16": "icon.png",
"48": "icon2.png",
"128": "icon3.png"
},
"content_scripts": [{
"all_frames": false,
"js": ["imgselect.js"],
"matches": [ "https://*.instagram.com/*"],
"run_at": "document_end"
}],
"browser_action": {
"default_icon": "icon.png",
"default_popup": "popup.html"
},
"permissions": [
"tabs"
]
}
I used parentNode
to get the parent of the image. I expect to see a red border around the image's div parent when it's hovered and seeing the src of the image in the console but I'm not seeing results. Any help will be appreciated, thank you!
javascript dom google-chrome-extension content-script
javascript dom google-chrome-extension content-script
edited Dec 28 '18 at 2:12
asked Dec 28 '18 at 0:03
johnboy13
316
316
Is it giving you any errors?
– Charlie Fish
Dec 28 '18 at 0:08
@CharlieFish It's not giving me any errors
– johnboy13
Dec 28 '18 at 0:08
Try add the event listener in this wayimage[0].addEventListener
and then changeevent.style.border = "2px solid red";
intoevent.target.style.border = "2px solid red";
And you should do a for loop to change all the element on the image object. Something like(for i=0; i<image.length; i++)
image[i].addEventListener
– Mattia
Dec 28 '18 at 0:26
@Mattia I just updated my question with new code that I've tried.
– johnboy13
Dec 28 '18 at 0:43
@johnboy13 jsfiddle.net/2L9cmyto/13
– Mattia
Dec 28 '18 at 1:46
|
show 1 more comment
Is it giving you any errors?
– Charlie Fish
Dec 28 '18 at 0:08
@CharlieFish It's not giving me any errors
– johnboy13
Dec 28 '18 at 0:08
Try add the event listener in this wayimage[0].addEventListener
and then changeevent.style.border = "2px solid red";
intoevent.target.style.border = "2px solid red";
And you should do a for loop to change all the element on the image object. Something like(for i=0; i<image.length; i++)
image[i].addEventListener
– Mattia
Dec 28 '18 at 0:26
@Mattia I just updated my question with new code that I've tried.
– johnboy13
Dec 28 '18 at 0:43
@johnboy13 jsfiddle.net/2L9cmyto/13
– Mattia
Dec 28 '18 at 1:46
Is it giving you any errors?
– Charlie Fish
Dec 28 '18 at 0:08
Is it giving you any errors?
– Charlie Fish
Dec 28 '18 at 0:08
@CharlieFish It's not giving me any errors
– johnboy13
Dec 28 '18 at 0:08
@CharlieFish It's not giving me any errors
– johnboy13
Dec 28 '18 at 0:08
Try add the event listener in this way
image[0].addEventListener
and then change event.style.border = "2px solid red";
into event.target.style.border = "2px solid red";
And you should do a for loop to change all the element on the image object. Something like (for i=0; i<image.length; i++)
image[i].addEventListener
– Mattia
Dec 28 '18 at 0:26
Try add the event listener in this way
image[0].addEventListener
and then change event.style.border = "2px solid red";
into event.target.style.border = "2px solid red";
And you should do a for loop to change all the element on the image object. Something like (for i=0; i<image.length; i++)
image[i].addEventListener
– Mattia
Dec 28 '18 at 0:26
@Mattia I just updated my question with new code that I've tried.
– johnboy13
Dec 28 '18 at 0:43
@Mattia I just updated my question with new code that I've tried.
– johnboy13
Dec 28 '18 at 0:43
@johnboy13 jsfiddle.net/2L9cmyto/13
– Mattia
Dec 28 '18 at 1:46
@johnboy13 jsfiddle.net/2L9cmyto/13
– Mattia
Dec 28 '18 at 1:46
|
show 1 more comment
1 Answer
1
active
oldest
votes
This worked for me!
I looked deeper into the developer console and realized every image on Instagram is inside of multiple divs, so I put together this code that highlights the main div that contains the image, and it works perfectly!
console.log('injected')
function show(e) {
console.log("post found")
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "5px solid red"
}
}
}
function hide(e){
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "none"
}
}
}
setInterval(function(){
var imagediv = document.getElementsByClassName('KL4Bh')
var i;
for (i = 0; i < imagediv.length; i++) {
var parent = imagediv[i].parentNode
var secondparent = parent.parentNode
var thirdparent = secondparent.parentNode
var children = parent.children
if (children.length > 1){
children[1].remove()
thirdparent.addEventListener('mouseover', show)
thirdparent.addEventListener('mouseout', hide)
}
}
},1000)
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This worked for me!
I looked deeper into the developer console and realized every image on Instagram is inside of multiple divs, so I put together this code that highlights the main div that contains the image, and it works perfectly!
console.log('injected')
function show(e) {
console.log("post found")
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "5px solid red"
}
}
}
function hide(e){
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "none"
}
}
}
setInterval(function(){
var imagediv = document.getElementsByClassName('KL4Bh')
var i;
for (i = 0; i < imagediv.length; i++) {
var parent = imagediv[i].parentNode
var secondparent = parent.parentNode
var thirdparent = secondparent.parentNode
var children = parent.children
if (children.length > 1){
children[1].remove()
thirdparent.addEventListener('mouseover', show)
thirdparent.addEventListener('mouseout', hide)
}
}
},1000)
add a comment |
This worked for me!
I looked deeper into the developer console and realized every image on Instagram is inside of multiple divs, so I put together this code that highlights the main div that contains the image, and it works perfectly!
console.log('injected')
function show(e) {
console.log("post found")
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "5px solid red"
}
}
}
function hide(e){
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "none"
}
}
}
setInterval(function(){
var imagediv = document.getElementsByClassName('KL4Bh')
var i;
for (i = 0; i < imagediv.length; i++) {
var parent = imagediv[i].parentNode
var secondparent = parent.parentNode
var thirdparent = secondparent.parentNode
var children = parent.children
if (children.length > 1){
children[1].remove()
thirdparent.addEventListener('mouseover', show)
thirdparent.addEventListener('mouseout', hide)
}
}
},1000)
add a comment |
This worked for me!
I looked deeper into the developer console and realized every image on Instagram is inside of multiple divs, so I put together this code that highlights the main div that contains the image, and it works perfectly!
console.log('injected')
function show(e) {
console.log("post found")
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "5px solid red"
}
}
}
function hide(e){
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "none"
}
}
}
setInterval(function(){
var imagediv = document.getElementsByClassName('KL4Bh')
var i;
for (i = 0; i < imagediv.length; i++) {
var parent = imagediv[i].parentNode
var secondparent = parent.parentNode
var thirdparent = secondparent.parentNode
var children = parent.children
if (children.length > 1){
children[1].remove()
thirdparent.addEventListener('mouseover', show)
thirdparent.addEventListener('mouseout', hide)
}
}
},1000)
This worked for me!
I looked deeper into the developer console and realized every image on Instagram is inside of multiple divs, so I put together this code that highlights the main div that contains the image, and it works perfectly!
console.log('injected')
function show(e) {
console.log("post found")
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "5px solid red"
}
}
}
function hide(e){
var img = this.getElementsByTagName('img')
for (i = 0; i <img.length; i++){
if (img[i].className == "FFVAD"){
console.log(img[i].src)
this.style.border = "none"
}
}
}
setInterval(function(){
var imagediv = document.getElementsByClassName('KL4Bh')
var i;
for (i = 0; i < imagediv.length; i++) {
var parent = imagediv[i].parentNode
var secondparent = parent.parentNode
var thirdparent = secondparent.parentNode
var children = parent.children
if (children.length > 1){
children[1].remove()
thirdparent.addEventListener('mouseover', show)
thirdparent.addEventListener('mouseout', hide)
}
}
},1000)
answered Dec 28 '18 at 3:10
johnboy13
316
316
add a comment |
add a comment |
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Is it giving you any errors?
– Charlie Fish
Dec 28 '18 at 0:08
@CharlieFish It's not giving me any errors
– johnboy13
Dec 28 '18 at 0:08
Try add the event listener in this way
image[0].addEventListener
and then changeevent.style.border = "2px solid red";
intoevent.target.style.border = "2px solid red";
And you should do a for loop to change all the element on the image object. Something like(for i=0; i<image.length; i++)
image[i].addEventListener
– Mattia
Dec 28 '18 at 0:26
@Mattia I just updated my question with new code that I've tried.
– johnboy13
Dec 28 '18 at 0:43
@johnboy13 jsfiddle.net/2L9cmyto/13
– Mattia
Dec 28 '18 at 1:46