Drop rows in data frame only if values in two columns are reversed and all other values identical












0














I am working with the iris dataset, and manipulating it as follows to get a species, feature1, feature2, value data frame:



gatherpairs <- function(data, ..., 
xkey = '.xkey', xvalue = '.xvalue',
ykey = '.ykey', yvalue = '.yvalue',
na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
vars <- quos(...)
xkey <- enquo(xkey)
xvalue <- enquo(xvalue)
ykey <- enquo(ykey)
yvalue <- enquo(yvalue)

data %>% {
cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
na.rm = na.rm, convert = convert, factor_key = factor_key),
select(., !!!vars))
} %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
filter(!(.xkey == .ykey)) %>%
mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
arrange(var)
}

test = iris %>%
gatherpairs(sapply(colnames(iris[, -ncol(iris)]), eval))


This was taken from https://stackoverflow.com/a/47731111/8315659



What this does is give me that data frame with all combinations of feature1 and feature2, but I want to remove duplicates where it is just the reverse being shown. For example, Petal.Length vs Petal.Width is the same as Petal.Width vs Petal.Length. But if there are two rows with identical values for Petal.Length vs Petal.Width, I do not want to drop that row. Therefore, just dropping rows where all values are identical except that .xkey and .ykey are reversed is what I would want to do. Essentially, this is just to recreate the bottom triangle of the ggplot matrix shown in the above linked answer.



How can this be done?
Jack










share|improve this question





























    0














    I am working with the iris dataset, and manipulating it as follows to get a species, feature1, feature2, value data frame:



    gatherpairs <- function(data, ..., 
    xkey = '.xkey', xvalue = '.xvalue',
    ykey = '.ykey', yvalue = '.yvalue',
    na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
    vars <- quos(...)
    xkey <- enquo(xkey)
    xvalue <- enquo(xvalue)
    ykey <- enquo(ykey)
    yvalue <- enquo(yvalue)

    data %>% {
    cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
    na.rm = na.rm, convert = convert, factor_key = factor_key),
    select(., !!!vars))
    } %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
    na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
    filter(!(.xkey == .ykey)) %>%
    mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
    arrange(var)
    }

    test = iris %>%
    gatherpairs(sapply(colnames(iris[, -ncol(iris)]), eval))


    This was taken from https://stackoverflow.com/a/47731111/8315659



    What this does is give me that data frame with all combinations of feature1 and feature2, but I want to remove duplicates where it is just the reverse being shown. For example, Petal.Length vs Petal.Width is the same as Petal.Width vs Petal.Length. But if there are two rows with identical values for Petal.Length vs Petal.Width, I do not want to drop that row. Therefore, just dropping rows where all values are identical except that .xkey and .ykey are reversed is what I would want to do. Essentially, this is just to recreate the bottom triangle of the ggplot matrix shown in the above linked answer.



    How can this be done?
    Jack










    share|improve this question



























      0












      0








      0







      I am working with the iris dataset, and manipulating it as follows to get a species, feature1, feature2, value data frame:



      gatherpairs <- function(data, ..., 
      xkey = '.xkey', xvalue = '.xvalue',
      ykey = '.ykey', yvalue = '.yvalue',
      na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
      vars <- quos(...)
      xkey <- enquo(xkey)
      xvalue <- enquo(xvalue)
      ykey <- enquo(ykey)
      yvalue <- enquo(yvalue)

      data %>% {
      cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
      na.rm = na.rm, convert = convert, factor_key = factor_key),
      select(., !!!vars))
      } %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
      na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
      filter(!(.xkey == .ykey)) %>%
      mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
      arrange(var)
      }

      test = iris %>%
      gatherpairs(sapply(colnames(iris[, -ncol(iris)]), eval))


      This was taken from https://stackoverflow.com/a/47731111/8315659



      What this does is give me that data frame with all combinations of feature1 and feature2, but I want to remove duplicates where it is just the reverse being shown. For example, Petal.Length vs Petal.Width is the same as Petal.Width vs Petal.Length. But if there are two rows with identical values for Petal.Length vs Petal.Width, I do not want to drop that row. Therefore, just dropping rows where all values are identical except that .xkey and .ykey are reversed is what I would want to do. Essentially, this is just to recreate the bottom triangle of the ggplot matrix shown in the above linked answer.



      How can this be done?
      Jack










      share|improve this question















      I am working with the iris dataset, and manipulating it as follows to get a species, feature1, feature2, value data frame:



      gatherpairs <- function(data, ..., 
      xkey = '.xkey', xvalue = '.xvalue',
      ykey = '.ykey', yvalue = '.yvalue',
      na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
      vars <- quos(...)
      xkey <- enquo(xkey)
      xvalue <- enquo(xvalue)
      ykey <- enquo(ykey)
      yvalue <- enquo(yvalue)

      data %>% {
      cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
      na.rm = na.rm, convert = convert, factor_key = factor_key),
      select(., !!!vars))
      } %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
      na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
      filter(!(.xkey == .ykey)) %>%
      mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
      arrange(var)
      }

      test = iris %>%
      gatherpairs(sapply(colnames(iris[, -ncol(iris)]), eval))


      This was taken from https://stackoverflow.com/a/47731111/8315659



      What this does is give me that data frame with all combinations of feature1 and feature2, but I want to remove duplicates where it is just the reverse being shown. For example, Petal.Length vs Petal.Width is the same as Petal.Width vs Petal.Length. But if there are two rows with identical values for Petal.Length vs Petal.Width, I do not want to drop that row. Therefore, just dropping rows where all values are identical except that .xkey and .ykey are reversed is what I would want to do. Essentially, this is just to recreate the bottom triangle of the ggplot matrix shown in the above linked answer.



      How can this be done?
      Jack







      r dplyr tidyr






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Dec 27 '18 at 17:45









      PoGibas

      15.5k134175




      15.5k134175










      asked Dec 27 '18 at 15:50









      Jack Arnestad

      837211




      837211
























          1 Answer
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          0














          I think this could be accomplished using the first part of the source code, which performs a single gathering operation. Using the iris example, this will produce 600 rows of output, one for each of the 150 rows x 4 columns in iris.



          gatherpairs <- function(data, ..., 
          xkey = '.xkey', xvalue = '.xvalue',
          ykey = '.ykey', yvalue = '.yvalue',
          na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
          vars <- quos(...)
          xkey <- enquo(xkey)
          xvalue <- enquo(xvalue)
          ykey <- enquo(ykey)
          yvalue <- enquo(yvalue)

          data %>% {
          cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
          na.rm = na.rm, convert = convert, factor_key = factor_key),
          select(., !!!vars))
          } # %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
          # na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
          # filter(!(.xkey == .ykey)) %>%
          # mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
          # arrange(var)
          }





          share|improve this answer





















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            1 Answer
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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            I think this could be accomplished using the first part of the source code, which performs a single gathering operation. Using the iris example, this will produce 600 rows of output, one for each of the 150 rows x 4 columns in iris.



            gatherpairs <- function(data, ..., 
            xkey = '.xkey', xvalue = '.xvalue',
            ykey = '.ykey', yvalue = '.yvalue',
            na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
            vars <- quos(...)
            xkey <- enquo(xkey)
            xvalue <- enquo(xvalue)
            ykey <- enquo(ykey)
            yvalue <- enquo(yvalue)

            data %>% {
            cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
            na.rm = na.rm, convert = convert, factor_key = factor_key),
            select(., !!!vars))
            } # %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
            # na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
            # filter(!(.xkey == .ykey)) %>%
            # mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
            # arrange(var)
            }





            share|improve this answer


























              0














              I think this could be accomplished using the first part of the source code, which performs a single gathering operation. Using the iris example, this will produce 600 rows of output, one for each of the 150 rows x 4 columns in iris.



              gatherpairs <- function(data, ..., 
              xkey = '.xkey', xvalue = '.xvalue',
              ykey = '.ykey', yvalue = '.yvalue',
              na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
              vars <- quos(...)
              xkey <- enquo(xkey)
              xvalue <- enquo(xvalue)
              ykey <- enquo(ykey)
              yvalue <- enquo(yvalue)

              data %>% {
              cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
              na.rm = na.rm, convert = convert, factor_key = factor_key),
              select(., !!!vars))
              } # %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
              # na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
              # filter(!(.xkey == .ykey)) %>%
              # mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
              # arrange(var)
              }





              share|improve this answer
























                0












                0








                0






                I think this could be accomplished using the first part of the source code, which performs a single gathering operation. Using the iris example, this will produce 600 rows of output, one for each of the 150 rows x 4 columns in iris.



                gatherpairs <- function(data, ..., 
                xkey = '.xkey', xvalue = '.xvalue',
                ykey = '.ykey', yvalue = '.yvalue',
                na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
                vars <- quos(...)
                xkey <- enquo(xkey)
                xvalue <- enquo(xvalue)
                ykey <- enquo(ykey)
                yvalue <- enquo(yvalue)

                data %>% {
                cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
                na.rm = na.rm, convert = convert, factor_key = factor_key),
                select(., !!!vars))
                } # %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
                # na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
                # filter(!(.xkey == .ykey)) %>%
                # mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
                # arrange(var)
                }





                share|improve this answer












                I think this could be accomplished using the first part of the source code, which performs a single gathering operation. Using the iris example, this will produce 600 rows of output, one for each of the 150 rows x 4 columns in iris.



                gatherpairs <- function(data, ..., 
                xkey = '.xkey', xvalue = '.xvalue',
                ykey = '.ykey', yvalue = '.yvalue',
                na.rm = FALSE, convert = FALSE, factor_key = FALSE) {
                vars <- quos(...)
                xkey <- enquo(xkey)
                xvalue <- enquo(xvalue)
                ykey <- enquo(ykey)
                yvalue <- enquo(yvalue)

                data %>% {
                cbind(gather(., key = !!xkey, value = !!xvalue, !!!vars,
                na.rm = na.rm, convert = convert, factor_key = factor_key),
                select(., !!!vars))
                } # %>% gather(., key = !!ykey, value = !!yvalue, !!!vars,
                # na.rm = na.rm, convert = convert, factor_key = factor_key)%>%
                # filter(!(.xkey == .ykey)) %>%
                # mutate(var = apply(.[, c(".xkey", ".ykey")], 1, function(x) paste(sort(x), collapse = ""))) %>%
                # arrange(var)
                }






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Dec 28 '18 at 0:08









                Jon Spring

                5,2331625




                5,2331625






























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