sort Key of JSONArray
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0
I have a json Array like this :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
]
How can i Organize my json to have somethign like that :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos2": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos4": "free"
}
]
Because i need to have 'pos' in progressive order
I hope someone will understand my problem, and tell me how can i can resolve this..
I have already search and not found the same problem than me..
Thanks a lot
javascript json
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
add a comment |
0
I have a json Array like this :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
]
How can i Organize my json to have somethign like that :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos2": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos4": "free"
}
]
Because i need to have 'pos' in progressive order
I hope someone will understand my problem, and tell me how can i can resolve this..
I have already search and not found the same problem than me..
Thanks a lot
javascript json
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
keys are not intended to work like that, it is possible and I will help you if that's what you want, but let me ask you first. Can't you just add a key with name: "id": 0, "id": 1, etc? otherwise we will have to strip the digits from the object.key which isn't very beautiful :P
– joelgullander
Jan 4 at 0:50
Your objects should have a common name for the identifier property.
– Tiny Giant
Jan 4 at 0:51
I know that these keys are not beautiful, but in my program it make like that... I will try to change it :x
– Mathieu d.o
Jan 4 at 0:54
add a comment |
0
0
0
I have a json Array like this :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
]
How can i Organize my json to have somethign like that :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos2": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos4": "free"
}
]
Because i need to have 'pos' in progressive order
I hope someone will understand my problem, and tell me how can i can resolve this..
I have already search and not found the same problem than me..
Thanks a lot
javascript json
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
I have a json Array like this :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
]
How can i Organize my json to have somethign like that :
[
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos2": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos4": "free"
}
]
Because i need to have 'pos' in progressive order
I hope someone will understand my problem, and tell me how can i can resolve this..
I have already search and not found the same problem than me..
Thanks a lot
javascript json
javascript json
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
asked Jan 4 at 0:45
Mathieu d.oMathieu d.o
505
505
keys are not intended to work like that, it is possible and I will help you if that's what you want, but let me ask you first. Can't you just add a key with name: "id": 0, "id": 1, etc? otherwise we will have to strip the digits from the object.key which isn't very beautiful :P
– joelgullander
Jan 4 at 0:50
Your objects should have a common name for the identifier property.
– Tiny Giant
Jan 4 at 0:51
I know that these keys are not beautiful, but in my program it make like that... I will try to change it :x
– Mathieu d.o
Jan 4 at 0:54
add a comment |
keys are not intended to work like that, it is possible and I will help you if that's what you want, but let me ask you first. Can't you just add a key with name: "id": 0, "id": 1, etc? otherwise we will have to strip the digits from the object.key which isn't very beautiful :P
– joelgullander
Jan 4 at 0:50
Your objects should have a common name for the identifier property.
– Tiny Giant
Jan 4 at 0:51
I know that these keys are not beautiful, but in my program it make like that... I will try to change it :x
– Mathieu d.o
Jan 4 at 0:54
keys are not intended to work like that, it is possible and I will help you if that's what you want, but let me ask you first. Can't you just add a key with name: "id": 0, "id": 1, etc? otherwise we will have to strip the digits from the object.key which isn't very beautiful :P
– joelgullander
Jan 4 at 0:50
keys are not intended to work like that, it is possible and I will help you if that's what you want, but let me ask you first. Can't you just add a key with name: "id": 0, "id": 1, etc? otherwise we will have to strip the digits from the object.key which isn't very beautiful :P
– joelgullander
Jan 4 at 0:50
Your objects should have a common name for the identifier property.
– Tiny Giant
Jan 4 at 0:51
Your objects should have a common name for the identifier property.
– Tiny Giant
Jan 4 at 0:51
I know that these keys are not beautiful, but in my program it make like that... I will try to change it :x
– Mathieu d.o
Jan 4 at 0:54
I know that these keys are not beautiful, but in my program it make like that... I will try to change it :x
– Mathieu d.o
Jan 4 at 0:54
add a comment |
5 Answers
5
active
oldest
votes
0
A bit late to the party but I don't think the other answers are producing the output you want, i.e. you want to retain the current array order and replace the current pos[num] property of the object in the array with 'pos' + (idx + 1):
const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
add a comment |
0
Assuming that the first property of the object is what you want to sort by, something as simplistic as this should work:
var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
Look at the required output again.
– Andy
Jan 4 at 0:58
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
add a comment |
0
This will provide you with the output you want. It uses the following JS methods/syntax:
mapObject.keys()includes- Template literals
const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);answered Jan 4 at 1:21
AndyAndy
30.4k73565
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
add a comment |
-1
If the name is consistently pos[num] this will work.
let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
add a comment |
-1
let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
A bit late to the party but I don't think the other answers are producing the output you want, i.e. you want to retain the current array order and replace the current pos[num] property of the object in the array with 'pos' + (idx + 1):
const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
add a comment |
0
A bit late to the party but I don't think the other answers are producing the output you want, i.e. you want to retain the current array order and replace the current pos[num] property of the object in the array with 'pos' + (idx + 1):
const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
add a comment |
0
0
0
A bit late to the party but I don't think the other answers are producing the output you want, i.e. you want to retain the current array order and replace the current pos[num] property of the object in the array with 'pos' + (idx + 1):
const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
A bit late to the party but I don't think the other answers are producing the output you want, i.e. you want to retain the current array order and replace the current pos[num] property of the object in the array with 'pos' + (idx + 1):
const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)const input = [ { "pos1": "Batterie de préchauffage", "attributes": [ { "disconnect": "false", "disconnectBis": "false" } ] }, { "pos4": "Batterie haute température", "attributes": [ { "test": "true", "testBis": "false" } ] }, { "pos3": "free" }, { "pos2": "free" } ]
const output = input.map((o, idx) => {
const id = Object.keys(o).find(id => /^pos/.test(id));
if (id !== `pos${idx + 1}`) {
o[`pos${idx + 1}`] = o[id];
delete o[id];
}
return o;
});
console.log(output)answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
answered Jan 4 at 1:15
ic3b3rgic3b3rg
10.9k42045
10.9k42045
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
add a comment |
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json
– Mathieu d.o
Jan 4 at 2:41
add a comment |
0
Assuming that the first property of the object is what you want to sort by, something as simplistic as this should work:
var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
Look at the required output again.
– Andy
Jan 4 at 0:58
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
add a comment |
0
Assuming that the first property of the object is what you want to sort by, something as simplistic as this should work:
var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
Look at the required output again.
– Andy
Jan 4 at 0:58
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
add a comment |
0
0
0
Assuming that the first property of the object is what you want to sort by, something as simplistic as this should work:
var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
Assuming that the first property of the object is what you want to sort by, something as simplistic as this should work:
var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));var array = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
var sortedArray = array.sort((a, b) => {
var nameKeyA = Object.keys(a)[0];
var nameKeyB = Object.keys(b)[0];
return nameKeyA > nameKeyB;
});
console.log(JSON.stringify(sortedArray));answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
answered Jan 4 at 0:57
Ben BeckBen Beck
1,9731616
1,9731616
Look at the required output again.
– Andy
Jan 4 at 0:58
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
add a comment |
Look at the required output again.
– Andy
Jan 4 at 0:58
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
Look at the required output again.
– Andy
Jan 4 at 0:58
Look at the required output again.
– Andy
Jan 4 at 0:58
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
@Andy interesting... I figured that was just a typo from OP. I'm not entirely sure why one would want that as the output.
– Ben Beck
Jan 4 at 1:01
add a comment |
0
This will provide you with the output you want. It uses the following JS methods/syntax:
mapObject.keys()includes- Template literals
const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);answered Jan 4 at 1:21
AndyAndy
30.4k73565
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
add a comment |
0
This will provide you with the output you want. It uses the following JS methods/syntax:
mapObject.keys()includes- Template literals
const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);answered Jan 4 at 1:21
AndyAndy
30.4k73565
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
add a comment |
0
0
0
This will provide you with the output you want. It uses the following JS methods/syntax:
mapObject.keys()includes- Template literals
const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);answered Jan 4 at 1:21
AndyAndy
30.4k73565
This will provide you with the output you want. It uses the following JS methods/syntax:
mapObject.keys()includes- Template literals
const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);const json = '[{"pos1":"Batterie de préchauffage","attributes":[{"disconnect":"false","disconnectBis":"false"}]},{"pos4":"Batterie haute température","attributes":[{"test":"true","testBis":"false"}]},{"pos3":"free"},{"pos2":"free"}]';
// Parse the JSON
const arr = JSON.parse(json);
// `map` over the array, grabbing the object and index
const out = arr.map((obj, i) => {
// Iterate over the keys from each object
Object.keys(obj).forEach(key => {
// If a key includes the substring "pos"...
if (key.includes('pos')) {
// ...and the new key number doesn't match the current index...
if (key !== `pos${i + 1}`) {
// ...copy it to a new key (starting at pos1)...
obj[`pos${i + 1}`] = obj[key];
// ...then delete the old key
delete obj[key];
}
}
});
// Return the updated object
return obj;
});
console.log(out);answered Jan 4 at 1:21
AndyAndy
30.4k73565
edited Jan 4 at 1:26
answered Jan 4 at 1:21
AndyAndy
30.4k73565
answered Jan 4 at 1:21
AndyAndy
30.4k73565
answered Jan 4 at 1:21
AndyAndy
30.4k73565
30.4k73565
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
add a comment |
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
it's exactly what i want ! thanks a lot, but maybe i will follow your advices, and change my json :)
– Mathieu d.o
Jan 4 at 2:43
add a comment |
-1
If the name is consistently pos[num] this will work.
let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
add a comment |
-1
If the name is consistently pos[num] this will work.
let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
add a comment |
-1
-1
-1
If the name is consistently pos[num] this will work.
let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
If the name is consistently pos[num] this will work.
let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);let data = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
const sortPredicate = (a, b) => {
let aProp = parseInt(Object.getOwnPropertyNames(a)[0].substring(3));
let bProp = parseInt(Object.getOwnPropertyNames(b)[0].substring(3));
return aProp - bProp;
}
let sortedData = data.sort(sortPredicate);
console.log(sortedData);answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
answered Jan 4 at 0:53
BibbertyBibberty
2,3021317
2,3021317
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
add a comment |
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
Please note I agree with the comments above, it would be better to fix the JSON to have a proper key. It looks like you are recording slot allocation and what is in the slot or if its free.
– Bibberty
Jan 4 at 0:57
add a comment |
-1
let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
add a comment |
-1
let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
add a comment |
-1
-1
-1
let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));let x = [
{
"pos1": "Batterie de préchauffage",
"attributes": [
{
"disconnect": "false",
"disconnectBis": "false"
}
]
},
{
"pos4": "Batterie haute température",
"attributes": [
{
"test": "true",
"testBis": "false"
}
]
},
{
"pos3": "free"
},
{
"pos2": "free"
}
];
function getPosKey(obj) {
const firstMatch = Object.keys(obj).find(k => /pos[0-9]+/.test(k));
return firstMatch;
}
const ordered_keys = x.map(o => getPosKey(o)).sort();
x = x.map((o, idx) => {
const k = getPosKey(o);
if(k && ordered_keys[idx] && k !== ordered_keys[idx]) {
o[ordered_keys[idx]] = JSON.parse(JSON.stringify(o[k]));
delete o[k];
}
return o;
});
console.log(JSON.stringify(x, null, 2));answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
edited Jan 4 at 1:15
answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
answered Jan 4 at 0:58
vicatcuvicatcu
4,06832847
4,06832847
add a comment |
add a comment |
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keys are not intended to work like that, it is possible and I will help you if that's what you want, but let me ask you first. Can't you just add a key with name: "id": 0, "id": 1, etc? otherwise we will have to strip the digits from the object.key which isn't very beautiful :P
– joelgullander
Jan 4 at 0:50
Your objects should have a common name for the identifier property.
– Tiny Giant
Jan 4 at 0:51
I know that these keys are not beautiful, but in my program it make like that... I will try to change it :x
– Mathieu d.o
Jan 4 at 0:54