Character escape sequence in javascript
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Just noticed that some strings (taken from an array created from a m3u playlist file) won't work due to a malformed hexadecimal character escape sequence.
var strArray = [
"#EXTM3U",
"C:musicX Marks the Pedwalk - Desolation.mp3", //fine
"#EXTINF:287,Xandria - Ginger Sunset Expire", //fine
"C:musicandria - Ginger Sunset Expire.mp3", //fine
"C:musicxandria - Ginger Sunset Expire.mp3", // FAILS
"C:\music\xandria - Ginger Sunset Expire.mp3" //fine
]
alert (strArray);
I can get around it with escape slashes. But my question is what is actually causing the error. I thought it might be something to do with x but that would mean the first track would also fail. So I'm a little bit confused.
javascript escaping
add a comment |
Just noticed that some strings (taken from an array created from a m3u playlist file) won't work due to a malformed hexadecimal character escape sequence.
var strArray = [
"#EXTM3U",
"C:musicX Marks the Pedwalk - Desolation.mp3", //fine
"#EXTINF:287,Xandria - Ginger Sunset Expire", //fine
"C:musicandria - Ginger Sunset Expire.mp3", //fine
"C:musicxandria - Ginger Sunset Expire.mp3", // FAILS
"C:\music\xandria - Ginger Sunset Expire.mp3" //fine
]
alert (strArray);
I can get around it with escape slashes. But my question is what is actually causing the error. I thought it might be something to do with x but that would mean the first track would also fail. So I'm a little bit confused.
javascript escaping
add a comment |
Just noticed that some strings (taken from an array created from a m3u playlist file) won't work due to a malformed hexadecimal character escape sequence.
var strArray = [
"#EXTM3U",
"C:musicX Marks the Pedwalk - Desolation.mp3", //fine
"#EXTINF:287,Xandria - Ginger Sunset Expire", //fine
"C:musicandria - Ginger Sunset Expire.mp3", //fine
"C:musicxandria - Ginger Sunset Expire.mp3", // FAILS
"C:\music\xandria - Ginger Sunset Expire.mp3" //fine
]
alert (strArray);
I can get around it with escape slashes. But my question is what is actually causing the error. I thought it might be something to do with x but that would mean the first track would also fail. So I'm a little bit confused.
javascript escaping
Just noticed that some strings (taken from an array created from a m3u playlist file) won't work due to a malformed hexadecimal character escape sequence.
var strArray = [
"#EXTM3U",
"C:musicX Marks the Pedwalk - Desolation.mp3", //fine
"#EXTINF:287,Xandria - Ginger Sunset Expire", //fine
"C:musicandria - Ginger Sunset Expire.mp3", //fine
"C:musicxandria - Ginger Sunset Expire.mp3", // FAILS
"C:\music\xandria - Ginger Sunset Expire.mp3" //fine
]
alert (strArray);
I can get around it with escape slashes. But my question is what is actually causing the error. I thought it might be something to do with x but that would mean the first track would also fail. So I'm a little bit confused.
javascript escaping
javascript escaping
edited Jan 27 '13 at 10:25
T.J. Crowder
699k12312441341
699k12312441341
asked Jan 27 '13 at 10:24
Ghoul FoolGhoul Fool
2,34073777
2,34073777
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
I thought it might be something to do with x but that would mean the first track would also fail.
No, because x
and X
are not the same character. :-) x
(with the x
in lower case) is special in string literals, X
(with the X
in upper case) is not.
Best practice is to always escape backslashes that are meant to really be backslashes as opposed to the beginning of an escape sequence. Otherwise, you will trip yourself up.
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
add a comment |
You can replace backslashes with the function str_replace..
<?php
$bodytag = str_replace("%body%", "black", "<body text='%body%'>");
// Produce: <body text='black'>
http://php.net/manual/es/function.str-replace.php
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I thought it might be something to do with x but that would mean the first track would also fail.
No, because x
and X
are not the same character. :-) x
(with the x
in lower case) is special in string literals, X
(with the X
in upper case) is not.
Best practice is to always escape backslashes that are meant to really be backslashes as opposed to the beginning of an escape sequence. Otherwise, you will trip yourself up.
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
add a comment |
I thought it might be something to do with x but that would mean the first track would also fail.
No, because x
and X
are not the same character. :-) x
(with the x
in lower case) is special in string literals, X
(with the X
in upper case) is not.
Best practice is to always escape backslashes that are meant to really be backslashes as opposed to the beginning of an escape sequence. Otherwise, you will trip yourself up.
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
add a comment |
I thought it might be something to do with x but that would mean the first track would also fail.
No, because x
and X
are not the same character. :-) x
(with the x
in lower case) is special in string literals, X
(with the X
in upper case) is not.
Best practice is to always escape backslashes that are meant to really be backslashes as opposed to the beginning of an escape sequence. Otherwise, you will trip yourself up.
I thought it might be something to do with x but that would mean the first track would also fail.
No, because x
and X
are not the same character. :-) x
(with the x
in lower case) is special in string literals, X
(with the X
in upper case) is not.
Best practice is to always escape backslashes that are meant to really be backslashes as opposed to the beginning of an escape sequence. Otherwise, you will trip yourself up.
answered Jan 27 '13 at 10:25
T.J. CrowderT.J. Crowder
699k12312441341
699k12312441341
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
add a comment |
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
Thank you for your swift reply.
– Ghoul Fool
Jan 27 '13 at 10:34
add a comment |
You can replace backslashes with the function str_replace..
<?php
$bodytag = str_replace("%body%", "black", "<body text='%body%'>");
// Produce: <body text='black'>
http://php.net/manual/es/function.str-replace.php
add a comment |
You can replace backslashes with the function str_replace..
<?php
$bodytag = str_replace("%body%", "black", "<body text='%body%'>");
// Produce: <body text='black'>
http://php.net/manual/es/function.str-replace.php
add a comment |
You can replace backslashes with the function str_replace..
<?php
$bodytag = str_replace("%body%", "black", "<body text='%body%'>");
// Produce: <body text='black'>
http://php.net/manual/es/function.str-replace.php
You can replace backslashes with the function str_replace..
<?php
$bodytag = str_replace("%body%", "black", "<body text='%body%'>");
// Produce: <body text='black'>
http://php.net/manual/es/function.str-replace.php
edited Jan 4 at 0:18
Nick
38.9k132443
38.9k132443
answered Jan 3 at 23:59
raulraul
1
1
add a comment |
add a comment |
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