Python adding “u” to string

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I have a string "E001"
I would like to add "u" to the beginning of that string
So the code would look something like this:



output = add_u("E001")
print(output)
--------------------------
OUTPUT: uE001


There are difficulties with this I keep getting a Unicode error










share|improve this question




















  • 1





    Ok, and what happened when you tried the approaches from your research?

    – roganjosh
    Jan 3 at 22:09






  • 1





    What's your ultimate goal?

    – Felix Kling
    Jan 3 at 22:09











  • It's a simple string concatenation; the only tricky part is that you need to escape the backslash.

    – chepner
    Jan 3 at 22:10













  • The things that kept happening in my research where: it kept adding more then one or gave a Unicode error

    – Quinten Cabo
    Jan 3 at 22:20













  • My ultimate goal is that there is a json file that remaps unicode characters to images so it would be like {"char":"uE001","file":"path/to/image"}

    – Quinten Cabo
    Jan 3 at 22:22


















-2















I have a string "E001"
I would like to add "u" to the beginning of that string
So the code would look something like this:



output = add_u("E001")
print(output)
--------------------------
OUTPUT: uE001


There are difficulties with this I keep getting a Unicode error










share|improve this question




















  • 1





    Ok, and what happened when you tried the approaches from your research?

    – roganjosh
    Jan 3 at 22:09






  • 1





    What's your ultimate goal?

    – Felix Kling
    Jan 3 at 22:09











  • It's a simple string concatenation; the only tricky part is that you need to escape the backslash.

    – chepner
    Jan 3 at 22:10













  • The things that kept happening in my research where: it kept adding more then one or gave a Unicode error

    – Quinten Cabo
    Jan 3 at 22:20













  • My ultimate goal is that there is a json file that remaps unicode characters to images so it would be like {"char":"uE001","file":"path/to/image"}

    – Quinten Cabo
    Jan 3 at 22:22














-2












-2








-2








I have a string "E001"
I would like to add "u" to the beginning of that string
So the code would look something like this:



output = add_u("E001")
print(output)
--------------------------
OUTPUT: uE001


There are difficulties with this I keep getting a Unicode error










share|improve this question
















I have a string "E001"
I would like to add "u" to the beginning of that string
So the code would look something like this:



output = add_u("E001")
print(output)
--------------------------
OUTPUT: uE001


There are difficulties with this I keep getting a Unicode error







python unicode






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 3 at 22:10







Quinten Cabo

















asked Jan 3 at 22:07









Quinten CaboQuinten Cabo

45




45








  • 1





    Ok, and what happened when you tried the approaches from your research?

    – roganjosh
    Jan 3 at 22:09






  • 1





    What's your ultimate goal?

    – Felix Kling
    Jan 3 at 22:09











  • It's a simple string concatenation; the only tricky part is that you need to escape the backslash.

    – chepner
    Jan 3 at 22:10













  • The things that kept happening in my research where: it kept adding more then one or gave a Unicode error

    – Quinten Cabo
    Jan 3 at 22:20













  • My ultimate goal is that there is a json file that remaps unicode characters to images so it would be like {"char":"uE001","file":"path/to/image"}

    – Quinten Cabo
    Jan 3 at 22:22














  • 1





    Ok, and what happened when you tried the approaches from your research?

    – roganjosh
    Jan 3 at 22:09






  • 1





    What's your ultimate goal?

    – Felix Kling
    Jan 3 at 22:09











  • It's a simple string concatenation; the only tricky part is that you need to escape the backslash.

    – chepner
    Jan 3 at 22:10













  • The things that kept happening in my research where: it kept adding more then one or gave a Unicode error

    – Quinten Cabo
    Jan 3 at 22:20













  • My ultimate goal is that there is a json file that remaps unicode characters to images so it would be like {"char":"uE001","file":"path/to/image"}

    – Quinten Cabo
    Jan 3 at 22:22








1




1





Ok, and what happened when you tried the approaches from your research?

– roganjosh
Jan 3 at 22:09





Ok, and what happened when you tried the approaches from your research?

– roganjosh
Jan 3 at 22:09




1




1





What's your ultimate goal?

– Felix Kling
Jan 3 at 22:09





What's your ultimate goal?

– Felix Kling
Jan 3 at 22:09













It's a simple string concatenation; the only tricky part is that you need to escape the backslash.

– chepner
Jan 3 at 22:10







It's a simple string concatenation; the only tricky part is that you need to escape the backslash.

– chepner
Jan 3 at 22:10















The things that kept happening in my research where: it kept adding more then one or gave a Unicode error

– Quinten Cabo
Jan 3 at 22:20







The things that kept happening in my research where: it kept adding more then one or gave a Unicode error

– Quinten Cabo
Jan 3 at 22:20















My ultimate goal is that there is a json file that remaps unicode characters to images so it would be like {"char":"uE001","file":"path/to/image"}

– Quinten Cabo
Jan 3 at 22:22





My ultimate goal is that there is a json file that remaps unicode characters to images so it would be like {"char":"uE001","file":"path/to/image"}

– Quinten Cabo
Jan 3 at 22:22












2 Answers
2






active

oldest

votes


















0














Try this:



def add_u(s):
return r'u' + s

print(add_u('E001'))


Outputs:



uE001





share|improve this answer
























  • This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

    – Quinten Cabo
    Jan 3 at 22:24













  • The r means raw string literal. stackoverflow.com/questions/2081640/…

    – Luke DeLuccia
    Jan 3 at 22:31













  • So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

    – Quinten Cabo
    Jan 3 at 23:06













  • You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

    – Matthias
    Jan 4 at 8:02



















2














How about just:



output = "\u" + "E001"
print(output)


Or as a function:



def add_u(string):
return "\u" + string

output = add_u("E001")
print(output)


Handles backslash escaping.






share|improve this answer
























  • This won't work I really need there to be one ""

    – Quinten Cabo
    Jan 3 at 22:19






  • 1





    @QuintenCabo There will only be one backslash in the output.

    – mypetlion
    Jan 3 at 22:21













  • I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

    – Quinten Cabo
    Jan 3 at 22:28












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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Try this:



def add_u(s):
return r'u' + s

print(add_u('E001'))


Outputs:



uE001





share|improve this answer
























  • This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

    – Quinten Cabo
    Jan 3 at 22:24













  • The r means raw string literal. stackoverflow.com/questions/2081640/…

    – Luke DeLuccia
    Jan 3 at 22:31













  • So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

    – Quinten Cabo
    Jan 3 at 23:06













  • You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

    – Matthias
    Jan 4 at 8:02
















0














Try this:



def add_u(s):
return r'u' + s

print(add_u('E001'))


Outputs:



uE001





share|improve this answer
























  • This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

    – Quinten Cabo
    Jan 3 at 22:24













  • The r means raw string literal. stackoverflow.com/questions/2081640/…

    – Luke DeLuccia
    Jan 3 at 22:31













  • So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

    – Quinten Cabo
    Jan 3 at 23:06













  • You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

    – Matthias
    Jan 4 at 8:02














0












0








0







Try this:



def add_u(s):
return r'u' + s

print(add_u('E001'))


Outputs:



uE001





share|improve this answer













Try this:



def add_u(s):
return r'u' + s

print(add_u('E001'))


Outputs:



uE001






share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 3 at 22:11









Luke DeLucciaLuke DeLuccia

456212




456212













  • This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

    – Quinten Cabo
    Jan 3 at 22:24













  • The r means raw string literal. stackoverflow.com/questions/2081640/…

    – Luke DeLuccia
    Jan 3 at 22:31













  • So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

    – Quinten Cabo
    Jan 3 at 23:06













  • You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

    – Matthias
    Jan 4 at 8:02



















  • This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

    – Quinten Cabo
    Jan 3 at 22:24













  • The r means raw string literal. stackoverflow.com/questions/2081640/…

    – Luke DeLuccia
    Jan 3 at 22:31













  • So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

    – Quinten Cabo
    Jan 3 at 23:06













  • You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

    – Matthias
    Jan 4 at 8:02

















This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

– Quinten Cabo
Jan 3 at 22:24







This worked! What exactly does the r in front of the string mean? I have come across when I tried to solve this on my own but I find the meaning unclear.

– Quinten Cabo
Jan 3 at 22:24















The r means raw string literal. stackoverflow.com/questions/2081640/…

– Luke DeLuccia
Jan 3 at 22:31







The r means raw string literal. stackoverflow.com/questions/2081640/…

– Luke DeLuccia
Jan 3 at 22:31















So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

– Quinten Cabo
Jan 3 at 23:06







So when I add this string to a list it adds a second "", a_list = ["uE001"] becomes ["\uE001"] is there any way to prevent this? I have the string in a variable if you do this literally nothing will happen but if you return a variable from a function and put that in a list then this happens

– Quinten Cabo
Jan 3 at 23:06















You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

– Matthias
Jan 4 at 8:02





You're looking at the representation of the string, not at the string content. If you have x = '` in your code then x` will be a string with one character, the backslash. See the difference with print(x, repr(x)).

– Matthias
Jan 4 at 8:02













2














How about just:



output = "\u" + "E001"
print(output)


Or as a function:



def add_u(string):
return "\u" + string

output = add_u("E001")
print(output)


Handles backslash escaping.






share|improve this answer
























  • This won't work I really need there to be one ""

    – Quinten Cabo
    Jan 3 at 22:19






  • 1





    @QuintenCabo There will only be one backslash in the output.

    – mypetlion
    Jan 3 at 22:21













  • I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

    – Quinten Cabo
    Jan 3 at 22:28
















2














How about just:



output = "\u" + "E001"
print(output)


Or as a function:



def add_u(string):
return "\u" + string

output = add_u("E001")
print(output)


Handles backslash escaping.






share|improve this answer
























  • This won't work I really need there to be one ""

    – Quinten Cabo
    Jan 3 at 22:19






  • 1





    @QuintenCabo There will only be one backslash in the output.

    – mypetlion
    Jan 3 at 22:21













  • I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

    – Quinten Cabo
    Jan 3 at 22:28














2












2








2







How about just:



output = "\u" + "E001"
print(output)


Or as a function:



def add_u(string):
return "\u" + string

output = add_u("E001")
print(output)


Handles backslash escaping.






share|improve this answer













How about just:



output = "\u" + "E001"
print(output)


Or as a function:



def add_u(string):
return "\u" + string

output = add_u("E001")
print(output)


Handles backslash escaping.







share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 3 at 22:11









connectyourchargerconnectyourcharger

599424




599424













  • This won't work I really need there to be one ""

    – Quinten Cabo
    Jan 3 at 22:19






  • 1





    @QuintenCabo There will only be one backslash in the output.

    – mypetlion
    Jan 3 at 22:21













  • I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

    – Quinten Cabo
    Jan 3 at 22:28



















  • This won't work I really need there to be one ""

    – Quinten Cabo
    Jan 3 at 22:19






  • 1





    @QuintenCabo There will only be one backslash in the output.

    – mypetlion
    Jan 3 at 22:21













  • I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

    – Quinten Cabo
    Jan 3 at 22:28

















This won't work I really need there to be one ""

– Quinten Cabo
Jan 3 at 22:19





This won't work I really need there to be one ""

– Quinten Cabo
Jan 3 at 22:19




1




1





@QuintenCabo There will only be one backslash in the output.

– mypetlion
Jan 3 at 22:21







@QuintenCabo There will only be one backslash in the output.

– mypetlion
Jan 3 at 22:21















I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

– Quinten Cabo
Jan 3 at 22:28





I was testing this in a console and there it did 2 but running it from a script it indeed had 1 ""

– Quinten Cabo
Jan 3 at 22:28


















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