Python 3.6 - enumerate files












0















I am trying to loop a series of jpg files in a folder. I found example code of that:



for n, image_file in enumerate(os.scandir(image_folder)):


which will loop through the image files in image_folder. However, it seems like it is not following any sequence. I have my files name like 000001.jpg, 000002.jpg, 000003.jpg,... and so on. But when the code run, it did not follow the sequence:



000213.jpg

000012.jpg

000672.jpg

....


What seems to be the issue here?






python python-3.x







share|improve this question


















  • 3





    Have you read the documentation? If you did, you would know the answer. As for the remedy, have the files sorted before enumerating them.

    – DYZ
    Jan 3 at 16:01











  • ... and, because you want file_9.jpg to come before file_10.jpg, have a look at the natsort module

    – gboffi
    Jan 3 at 16:24


















0















I am trying to loop a series of jpg files in a folder. I found example code of that:



for n, image_file in enumerate(os.scandir(image_folder)):


which will loop through the image files in image_folder. However, it seems like it is not following any sequence. I have my files name like 000001.jpg, 000002.jpg, 000003.jpg,... and so on. But when the code run, it did not follow the sequence:



000213.jpg

000012.jpg

000672.jpg

....


What seems to be the issue here?






python python-3.x







share|improve this question


















  • 3





    Have you read the documentation? If you did, you would know the answer. As for the remedy, have the files sorted before enumerating them.

    – DYZ
    Jan 3 at 16:01











  • ... and, because you want file_9.jpg to come before file_10.jpg, have a look at the natsort module

    – gboffi
    Jan 3 at 16:24
















0












0








0








I am trying to loop a series of jpg files in a folder. I found example code of that:



for n, image_file in enumerate(os.scandir(image_folder)):


which will loop through the image files in image_folder. However, it seems like it is not following any sequence. I have my files name like 000001.jpg, 000002.jpg, 000003.jpg,... and so on. But when the code run, it did not follow the sequence:



000213.jpg

000012.jpg

000672.jpg

....


What seems to be the issue here?






python python-3.x







share|improve this question














I am trying to loop a series of jpg files in a folder. I found example code of that:



for n, image_file in enumerate(os.scandir(image_folder)):


which will loop through the image files in image_folder. However, it seems like it is not following any sequence. I have my files name like 000001.jpg, 000002.jpg, 000003.jpg,... and so on. But when the code run, it did not follow the sequence:



000213.jpg

000012.jpg

000672.jpg

....


What seems to be the issue here?






python python-3.x




python python-3.x






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 3 at 15:57









sooonsooon

1,69633369




1,69633369








  • 3





    Have you read the documentation? If you did, you would know the answer. As for the remedy, have the files sorted before enumerating them.

    – DYZ
    Jan 3 at 16:01











  • ... and, because you want file_9.jpg to come before file_10.jpg, have a look at the natsort module

    – gboffi
    Jan 3 at 16:24
















  • 3





    Have you read the documentation? If you did, you would know the answer. As for the remedy, have the files sorted before enumerating them.

    – DYZ
    Jan 3 at 16:01











  • ... and, because you want file_9.jpg to come before file_10.jpg, have a look at the natsort module

    – gboffi
    Jan 3 at 16:24










3




3





Have you read the documentation? If you did, you would know the answer. As for the remedy, have the files sorted before enumerating them.

– DYZ
Jan 3 at 16:01





Have you read the documentation? If you did, you would know the answer. As for the remedy, have the files sorted before enumerating them.

– DYZ
Jan 3 at 16:01













... and, because you want file_9.jpg to come before file_10.jpg, have a look at the natsort module

– gboffi
Jan 3 at 16:24







... and, because you want file_9.jpg to come before file_10.jpg, have a look at the natsort module

– gboffi
Jan 3 at 16:24














2 Answers
2






active

oldest

votes


















4














Here's the relevant bit on os.scandir():




os.scandir​(path='.')



Return an iterator of os.DirEntry objects
corresponding to the entries in the directory given by path. The
entries are yielded in arbitrary order, and the special entries '.'
and '..' are not included.




You should not expect it to be in any particular order. The same goes for listdir() if you were considering this as an alternative.



If you strictly need them to be in order, consider sorting them first:



scanned = sorted([f for f in os.scandir(image_folder)], key=lambda f: f.name)

for n, image_file in enumerate(scanned):



# ... rest of your code





share|improve this answer


























  • I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

    – sooon
    Jan 3 at 16:13











  • Try my edit with custom sorted key.

    – Idlehands
    Jan 3 at 16:16



















1














I prefer to use glob:




The glob module finds all the pathnames matching a specified pattern
according to the rules used by the Unix shell, although results are
returned in arbitrary order. No tilde expansion is done, but *, ?, and
character ranges expressed with will be correctly matched.




You will need this if you handle more complex file structures so starting with glob isnt that bad. For your case you also can use os.scandir() as mentioned above.



Reference: glob module



import glob

files = sorted(glob.glob(r"C:UsersFabianDesktopstackimg*.jpg"))

for key, myfile in enumerate(files):

    print(key, myfile)


notice even if there other files like .txt they wont be in your list



Output:



C:UsersFabianDesktopstack>python c:/Users/Fabian/Desktop/stack/img.py

0 C:UsersFabianDesktopstackimgimg0001.jpg

1 C:UsersFabianDesktopstackimgimg0002.jpg

2 C:UsersFabianDesktopstackimgimg0003.jpg

....





share|improve this answer
























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54025747%2fpython-3-6-enumerate-files%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    Here's the relevant bit on os.scandir():




    os.scandir​(path='.')



    Return an iterator of os.DirEntry objects
    corresponding to the entries in the directory given by path. The
    entries are yielded in arbitrary order, and the special entries '.'
    and '..' are not included.




    You should not expect it to be in any particular order. The same goes for listdir() if you were considering this as an alternative.



    If you strictly need them to be in order, consider sorting them first:



    scanned = sorted([f for f in os.scandir(image_folder)], key=lambda f: f.name)
    
for n, image_file in enumerate(scanned):
    

    
# ... rest of your code





    share|improve this answer


























    • I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

      – sooon
      Jan 3 at 16:13











    • Try my edit with custom sorted key.

      – Idlehands
      Jan 3 at 16:16
















    4














    Here's the relevant bit on os.scandir():




    os.scandir​(path='.')



    Return an iterator of os.DirEntry objects
    corresponding to the entries in the directory given by path. The
    entries are yielded in arbitrary order, and the special entries '.'
    and '..' are not included.




    You should not expect it to be in any particular order. The same goes for listdir() if you were considering this as an alternative.



    If you strictly need them to be in order, consider sorting them first:



    scanned = sorted([f for f in os.scandir(image_folder)], key=lambda f: f.name)
    
for n, image_file in enumerate(scanned):
    

    
# ... rest of your code





    share|improve this answer


























    • I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

      – sooon
      Jan 3 at 16:13











    • Try my edit with custom sorted key.

      – Idlehands
      Jan 3 at 16:16














    4












    4








    4







    Here's the relevant bit on os.scandir():




    os.scandir​(path='.')



    Return an iterator of os.DirEntry objects
    corresponding to the entries in the directory given by path. The
    entries are yielded in arbitrary order, and the special entries '.'
    and '..' are not included.




    You should not expect it to be in any particular order. The same goes for listdir() if you were considering this as an alternative.



    If you strictly need them to be in order, consider sorting them first:



    scanned = sorted([f for f in os.scandir(image_folder)], key=lambda f: f.name)
    
for n, image_file in enumerate(scanned):
    

    
# ... rest of your code





    share|improve this answer















    Here's the relevant bit on os.scandir():




    os.scandir​(path='.')



    Return an iterator of os.DirEntry objects
    corresponding to the entries in the directory given by path. The
    entries are yielded in arbitrary order, and the special entries '.'
    and '..' are not included.




    You should not expect it to be in any particular order. The same goes for listdir() if you were considering this as an alternative.



    If you strictly need them to be in order, consider sorting them first:



    scanned = sorted([f for f in os.scandir(image_folder)], key=lambda f: f.name)
    
for n, image_file in enumerate(scanned):
    

    
# ... rest of your code






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 3 at 16:13

























    answered Jan 3 at 16:01









    IdlehandsIdlehands

    6,1631923




    6,1631923













    • I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

      – sooon
      Jan 3 at 16:13











    • Try my edit with custom sorted key.

      – Idlehands
      Jan 3 at 16:16



















    • I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

      – sooon
      Jan 3 at 16:13











    • Try my edit with custom sorted key.

      – Idlehands
      Jan 3 at 16:16

















    I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

    – sooon
    Jan 3 at 16:13





    I added scanned = sorted([f for f in os.scandir(image_folder)]) and getting error:TypeError: '<' not supported between instances of 'posix.DirEntry' and 'posix.DirEntry'

    – sooon
    Jan 3 at 16:13













    Try my edit with custom sorted key.

    – Idlehands
    Jan 3 at 16:16





    Try my edit with custom sorted key.

    – Idlehands
    Jan 3 at 16:16













    1














    I prefer to use glob:




    The glob module finds all the pathnames matching a specified pattern
    according to the rules used by the Unix shell, although results are
    returned in arbitrary order. No tilde expansion is done, but *, ?, and
    character ranges expressed with will be correctly matched.




    You will need this if you handle more complex file structures so starting with glob isnt that bad. For your case you also can use os.scandir() as mentioned above.



    Reference: glob module



    import glob
    
files = sorted(glob.glob(r"C:UsersFabianDesktopstackimg*.jpg"))
    
for key, myfile in enumerate(files):
    
    print(key, myfile)


    notice even if there other files like .txt they wont be in your list



    Output:



    C:UsersFabianDesktopstack>python c:/Users/Fabian/Desktop/stack/img.py
    
0 C:UsersFabianDesktopstackimgimg0001.jpg
    
1 C:UsersFabianDesktopstackimgimg0002.jpg
    
2 C:UsersFabianDesktopstackimgimg0003.jpg
    
....





    share|improve this answer




























      1














      I prefer to use glob:




      The glob module finds all the pathnames matching a specified pattern
      according to the rules used by the Unix shell, although results are
      returned in arbitrary order. No tilde expansion is done, but *, ?, and
      character ranges expressed with will be correctly matched.




      You will need this if you handle more complex file structures so starting with glob isnt that bad. For your case you also can use os.scandir() as mentioned above.



      Reference: glob module



      import glob
      
files = sorted(glob.glob(r"C:UsersFabianDesktopstackimg*.jpg"))
      
for key, myfile in enumerate(files):
      
    print(key, myfile)


      notice even if there other files like .txt they wont be in your list



      Output:



      C:UsersFabianDesktopstack>python c:/Users/Fabian/Desktop/stack/img.py
      
0 C:UsersFabianDesktopstackimgimg0001.jpg
      
1 C:UsersFabianDesktopstackimgimg0002.jpg
      
2 C:UsersFabianDesktopstackimgimg0003.jpg
      
....





      share|improve this answer


























        1












        1








        1







        I prefer to use glob:




        The glob module finds all the pathnames matching a specified pattern
        according to the rules used by the Unix shell, although results are
        returned in arbitrary order. No tilde expansion is done, but *, ?, and
        character ranges expressed with will be correctly matched.




        You will need this if you handle more complex file structures so starting with glob isnt that bad. For your case you also can use os.scandir() as mentioned above.



        Reference: glob module



        import glob
        
files = sorted(glob.glob(r"C:UsersFabianDesktopstackimg*.jpg"))
        
for key, myfile in enumerate(files):
        
    print(key, myfile)


        notice even if there other files like .txt they wont be in your list



        Output:



        C:UsersFabianDesktopstack>python c:/Users/Fabian/Desktop/stack/img.py
        
0 C:UsersFabianDesktopstackimgimg0001.jpg
        
1 C:UsersFabianDesktopstackimgimg0002.jpg
        
2 C:UsersFabianDesktopstackimgimg0003.jpg
        
....





        share|improve this answer













        I prefer to use glob:




        The glob module finds all the pathnames matching a specified pattern
        according to the rules used by the Unix shell, although results are
        returned in arbitrary order. No tilde expansion is done, but *, ?, and
        character ranges expressed with will be correctly matched.




        You will need this if you handle more complex file structures so starting with glob isnt that bad. For your case you also can use os.scandir() as mentioned above.



        Reference: glob module



        import glob
        
files = sorted(glob.glob(r"C:UsersFabianDesktopstackimg*.jpg"))
        
for key, myfile in enumerate(files):
        
    print(key, myfile)


        notice even if there other files like .txt they wont be in your list



        Output:



        C:UsersFabianDesktopstack>python c:/Users/Fabian/Desktop/stack/img.py
        
0 C:UsersFabianDesktopstackimgimg0001.jpg
        
1 C:UsersFabianDesktopstackimgimg0002.jpg
        
2 C:UsersFabianDesktopstackimgimg0003.jpg
        
....






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 3 at 16:26









        FabianFabian

        18211




        18211






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54025747%2fpython-3-6-enumerate-files%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            Popular posts from this blog

            Monofisismo

            Image
            Monofisismo (do grego: monos - "único, singular" e physis - "natureza") é o ponto de vista cristológico que defende que, depois da união do divino e do humano na encarnação histórica, Jesus Cristo, como encarnação do Filho ou Verbo ( Logos ) de Deus, teria apenas uma única "natureza", a divina, e não uma síntese de ambas. O monofisismo é contraposto pelo diofisismo (ou "diafisismo"), que defende que Jesus preservou em si as duas naturezas. Historicamente, o monofisismo se refere primordialmente à posição dos que (especialmente no Egito e, em menor grau, na Síria) rejeitaram as decisões do Concílio de Calcedônia em 451 (o quarto concílio ecumênico). Os membros mais moderados entre eles, porém, defendem a teologia "miafisita", que se tornou a oficial para as Igrejas Ortodoxas Orientais. Muitos ortodoxos orientais, porém, rejeitam essa classificação, mesmo como um termo genérico, mas ele é amplamente utilizado na literatura históri
            Read more

            Angular Downloading a file using contenturl with Basic Authentication

            Image
            0 I have a contentUrl when user clicks on that,file should be downloaded. If I try to browse the contentUrl in the browser it asks for Userid and password.I believe this is Basic Authentication.I dont want user to enter UserId and Password so I am passing it Authorization(Please see below code). Url looks some thing like this: http://XXX.XXX.XX.XXX:8080/flowable-rest/service/runtime/tasks/90875/attachments/90555/content let username : string = 'admin'; let pwd : string = 'test'; let headers = new Headers(); headers.set('Accept', 'text/json'); headers.append('Content-Type', 'application/json'); headers.set('Access-Control-Allow-Origin', '*'); headers.set('Access-Control-Allow-Methods','POST, GET, OPTIONS, PUT, DELETE'); head
            Read more

            Olmecas

            Image
            Monumento 1, uma das quatro cabeças colossais encontradas em La Venta, com altura aproximada de 3 metros Olmecas é a designação do povo e da civilização que estiveram na origem da antiga cultura pré-colombiana da Mesoamérica e que se desenvolveram nas regiões tropicais do centro-sul do atual México durante o pré-clássico, próximo de onde hoje estão localizados os estados mexicanos de Veracruz e Tabasco, no Istmo de Tehuantepec, numa zona designada área nuclear olmeca. A cultura olmeca floresceu nesta região aproximadamente entre 1500 e 400 a.C., [ 1 ] e crê-se que tenha sido a civilização-mãe de todas as civilizações mesoamericanas que se desenvolveram posteriormente. [ 2 ] No entanto, desconhece-se a sua exacta filiação étnica, ainda que existam numerosas hipóteses colocadas para tentar resolver esta questão. O etnónimo olmeca foi cunhado pelos arqueólogos do século XX, e não devem confundir-se com os muito posteriores olmecas-xicalancas que ocuparam vários locais do México
            Read more