How to GET a different page of bulk responses for my python-based SurveyMonkey data retriever?
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I'm working with the Surveymonkey API, and I have at long last retrieved the kind of information that I need from SurveyMonkey in Python using the requests module and can successfully export that data into a lovely Excel file. The only problem is, I'm not quite getting ALL the survey response data. I'm getting 50 of the several hundered survey responses.
Now, according to the SurveyMonkey API docs, there's a simple solution to this:
"Fetch the next page of 100 responses using the resource url returned in the links.next field."
I also read this part of the docs which tries to explain it further:
https://api.surveymonkey.net/v3/docs?python#pagination
I've tried adding 'links.next' into every place I can think of within the url I've been using to access the data, but every time I do, I just get an error.
Clearly I'm missing something.
HOST = "https://api.surveymonkey.com/v3/surveys/%s/responses/bulk" %
(survey_id)
data = s.get(HOST)
That is the HOST address I'm using, and I gather that links.next is supposed to interact with it in SOME way (right?)
Is there some formatting that I don't understand?
python api python-requests surveymonkey
add a comment |
I'm working with the Surveymonkey API, and I have at long last retrieved the kind of information that I need from SurveyMonkey in Python using the requests module and can successfully export that data into a lovely Excel file. The only problem is, I'm not quite getting ALL the survey response data. I'm getting 50 of the several hundered survey responses.
Now, according to the SurveyMonkey API docs, there's a simple solution to this:
"Fetch the next page of 100 responses using the resource url returned in the links.next field."
I also read this part of the docs which tries to explain it further:
https://api.surveymonkey.net/v3/docs?python#pagination
I've tried adding 'links.next' into every place I can think of within the url I've been using to access the data, but every time I do, I just get an error.
Clearly I'm missing something.
HOST = "https://api.surveymonkey.com/v3/surveys/%s/responses/bulk" %
(survey_id)
data = s.get(HOST)
That is the HOST address I'm using, and I gather that links.next is supposed to interact with it in SOME way (right?)
Is there some formatting that I don't understand?
python api python-requests surveymonkey
1
links.next is just the full URL with the pagination params for the next page of data ex. api.surveymonkey.net/v3/surveys/12345678/responses/…
– Adam Klockars
Jan 3 at 18:29
add a comment |
I'm working with the Surveymonkey API, and I have at long last retrieved the kind of information that I need from SurveyMonkey in Python using the requests module and can successfully export that data into a lovely Excel file. The only problem is, I'm not quite getting ALL the survey response data. I'm getting 50 of the several hundered survey responses.
Now, according to the SurveyMonkey API docs, there's a simple solution to this:
"Fetch the next page of 100 responses using the resource url returned in the links.next field."
I also read this part of the docs which tries to explain it further:
https://api.surveymonkey.net/v3/docs?python#pagination
I've tried adding 'links.next' into every place I can think of within the url I've been using to access the data, but every time I do, I just get an error.
Clearly I'm missing something.
HOST = "https://api.surveymonkey.com/v3/surveys/%s/responses/bulk" %
(survey_id)
data = s.get(HOST)
That is the HOST address I'm using, and I gather that links.next is supposed to interact with it in SOME way (right?)
Is there some formatting that I don't understand?
python api python-requests surveymonkey
I'm working with the Surveymonkey API, and I have at long last retrieved the kind of information that I need from SurveyMonkey in Python using the requests module and can successfully export that data into a lovely Excel file. The only problem is, I'm not quite getting ALL the survey response data. I'm getting 50 of the several hundered survey responses.
Now, according to the SurveyMonkey API docs, there's a simple solution to this:
"Fetch the next page of 100 responses using the resource url returned in the links.next field."
I also read this part of the docs which tries to explain it further:
https://api.surveymonkey.net/v3/docs?python#pagination
I've tried adding 'links.next' into every place I can think of within the url I've been using to access the data, but every time I do, I just get an error.
Clearly I'm missing something.
HOST = "https://api.surveymonkey.com/v3/surveys/%s/responses/bulk" %
(survey_id)
data = s.get(HOST)
That is the HOST address I'm using, and I gather that links.next is supposed to interact with it in SOME way (right?)
Is there some formatting that I don't understand?
python api python-requests surveymonkey
python api python-requests surveymonkey
asked Jan 3 at 4:10
jeepers mcfacejeepers mcface
90110
90110
1
links.next is just the full URL with the pagination params for the next page of data ex. api.surveymonkey.net/v3/surveys/12345678/responses/…
– Adam Klockars
Jan 3 at 18:29
add a comment |
1
links.next is just the full URL with the pagination params for the next page of data ex. api.surveymonkey.net/v3/surveys/12345678/responses/…
– Adam Klockars
Jan 3 at 18:29
1
1
links.next is just the full URL with the pagination params for the next page of data ex. api.surveymonkey.net/v3/surveys/12345678/responses/…
– Adam Klockars
Jan 3 at 18:29
links.next is just the full URL with the pagination params for the next page of data ex. api.surveymonkey.net/v3/surveys/12345678/responses/…
– Adam Klockars
Jan 3 at 18:29
add a comment |
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links.next is just the full URL with the pagination params for the next page of data ex. api.surveymonkey.net/v3/surveys/12345678/responses/…
– Adam Klockars
Jan 3 at 18:29