Detect inline elements with cheerio?
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Multi tool use
Is it possible to detect inline elements with cheerio? For example:
<div>
Hello
<strong>there</strong>
John!
</div>
This is an example of an inline element I would like to detect, because to a reader, the strong
tag is very clearly a continuation of the rest of the phrase. However, compared to something like this:
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
These aren't exactly inline, because to a reader, they are clearly separated.
I guess what I'm asking is, is it possible to use cheerio to detect if an element is sandwiched between the text of its parent?
javascript html css node.js cheerio
add a comment |
Is it possible to detect inline elements with cheerio? For example:
<div>
Hello
<strong>there</strong>
John!
</div>
This is an example of an inline element I would like to detect, because to a reader, the strong
tag is very clearly a continuation of the rest of the phrase. However, compared to something like this:
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
These aren't exactly inline, because to a reader, they are clearly separated.
I guess what I'm asking is, is it possible to use cheerio to detect if an element is sandwiched between the text of its parent?
javascript html css node.js cheerio
add a comment |
Is it possible to detect inline elements with cheerio? For example:
<div>
Hello
<strong>there</strong>
John!
</div>
This is an example of an inline element I would like to detect, because to a reader, the strong
tag is very clearly a continuation of the rest of the phrase. However, compared to something like this:
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
These aren't exactly inline, because to a reader, they are clearly separated.
I guess what I'm asking is, is it possible to use cheerio to detect if an element is sandwiched between the text of its parent?
javascript html css node.js cheerio
Is it possible to detect inline elements with cheerio? For example:
<div>
Hello
<strong>there</strong>
John!
</div>
This is an example of an inline element I would like to detect, because to a reader, the strong
tag is very clearly a continuation of the rest of the phrase. However, compared to something like this:
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
These aren't exactly inline, because to a reader, they are clearly separated.
I guess what I'm asking is, is it possible to use cheerio to detect if an element is sandwiched between the text of its parent?
javascript html css node.js cheerio
javascript html css node.js cheerio
asked Jan 3 at 3:58
Luke TanLuke Tan
4701415
4701415
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Note: The term inline elements
might not be the best to describe what you are trying to achieve.
The basic steps I would take are:
- use childNodes to get a nodelist of child text and
html elements. - Then use nodeType or similar to figure out if the node is an
element or text. - Then check if the text elements have more than just white space characters in their respective
textContent
or data.
Working with js, one way this could be accomplished is like so:
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
So by applying a very similar approach, this could be achieved in cheerio like so:
const cheerio = require('cheerio')
const $ = cheerio.load(`
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
`)
const divs = $('div')
divs.toArray().forEach(div => {
div.childNodes.forEach(child => {
if (
child.type === 'tag' &&
child.prev.type === 'text' &&
child.prev.data.trim() !== '' &&
child.next.type === 'text' &&
child.next.data.trim() !== ''
) {
console.log(child)
}
})
})
stackblitz
1
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Note: The term inline elements
might not be the best to describe what you are trying to achieve.
The basic steps I would take are:
- use childNodes to get a nodelist of child text and
html elements. - Then use nodeType or similar to figure out if the node is an
element or text. - Then check if the text elements have more than just white space characters in their respective
textContent
or data.
Working with js, one way this could be accomplished is like so:
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
So by applying a very similar approach, this could be achieved in cheerio like so:
const cheerio = require('cheerio')
const $ = cheerio.load(`
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
`)
const divs = $('div')
divs.toArray().forEach(div => {
div.childNodes.forEach(child => {
if (
child.type === 'tag' &&
child.prev.type === 'text' &&
child.prev.data.trim() !== '' &&
child.next.type === 'text' &&
child.next.data.trim() !== ''
) {
console.log(child)
}
})
})
stackblitz
1
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
add a comment |
Note: The term inline elements
might not be the best to describe what you are trying to achieve.
The basic steps I would take are:
- use childNodes to get a nodelist of child text and
html elements. - Then use nodeType or similar to figure out if the node is an
element or text. - Then check if the text elements have more than just white space characters in their respective
textContent
or data.
Working with js, one way this could be accomplished is like so:
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
So by applying a very similar approach, this could be achieved in cheerio like so:
const cheerio = require('cheerio')
const $ = cheerio.load(`
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
`)
const divs = $('div')
divs.toArray().forEach(div => {
div.childNodes.forEach(child => {
if (
child.type === 'tag' &&
child.prev.type === 'text' &&
child.prev.data.trim() !== '' &&
child.next.type === 'text' &&
child.next.data.trim() !== ''
) {
console.log(child)
}
})
})
stackblitz
1
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
add a comment |
Note: The term inline elements
might not be the best to describe what you are trying to achieve.
The basic steps I would take are:
- use childNodes to get a nodelist of child text and
html elements. - Then use nodeType or similar to figure out if the node is an
element or text. - Then check if the text elements have more than just white space characters in their respective
textContent
or data.
Working with js, one way this could be accomplished is like so:
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
So by applying a very similar approach, this could be achieved in cheerio like so:
const cheerio = require('cheerio')
const $ = cheerio.load(`
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
`)
const divs = $('div')
divs.toArray().forEach(div => {
div.childNodes.forEach(child => {
if (
child.type === 'tag' &&
child.prev.type === 'text' &&
child.prev.data.trim() !== '' &&
child.next.type === 'text' &&
child.next.data.trim() !== ''
) {
console.log(child)
}
})
})
stackblitz
Note: The term inline elements
might not be the best to describe what you are trying to achieve.
The basic steps I would take are:
- use childNodes to get a nodelist of child text and
html elements. - Then use nodeType or similar to figure out if the node is an
element or text. - Then check if the text elements have more than just white space characters in their respective
textContent
or data.
Working with js, one way this could be accomplished is like so:
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
So by applying a very similar approach, this could be achieved in cheerio like so:
const cheerio = require('cheerio')
const $ = cheerio.load(`
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
`)
const divs = $('div')
divs.toArray().forEach(div => {
div.childNodes.forEach(child => {
if (
child.type === 'tag' &&
child.prev.type === 'text' &&
child.prev.data.trim() !== '' &&
child.next.type === 'text' &&
child.next.data.trim() !== ''
) {
console.log(child)
}
})
})
stackblitz
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
function markSandwichedEls(parent) {
var children = parent.childNodes;
for (let i = 0; i < children.length; i++) {
if (
children[i].nodeType === 1 &&
children[i - 1].nodeType === 3 &&
children[i - 1].textContent.replace(/s/g, "").length &&
children[i + 1].nodeType === 3 &&
children[i + 1].textContent.replace(/s/g, "").length
) {
children[i].style.backgroundColor = "red";
}
}
}
document.querySelectorAll("div").forEach(div => {
markSandwichedEls(div);
});
<div>
Hello
<strong>there</strong> John!
</div>
<div>
Jobs
<span>Cleaner</span>
<span>Artist</span>
</div>
edited Jan 4 at 17:46
answered Jan 3 at 8:30


ksavksav
5,38721432
5,38721432
1
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
add a comment |
1
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
1
1
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
thanks a bunch! exactly what I was looking for :)
– Luke Tan
Jan 5 at 7:05
add a comment |
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