Get a list of non common elements in 2 “different” vectors












0















I'm trying to return a list of items that is not present between vector a and b. But here is the catch



    struct myStruct{
std::shared_ptr<obj> mPtr;
int x;
}

vector<myStruct> listA
vector<std::shared_ptr<obj>> listB
vector<myStruct>result
std::sort(listA.begin(),listA.end());
std::sort<listB.begin(),listB.end());

std::set_difference(listA.begin().listA.end(),listB.begin(),listB.end(),std::back_inserter(result),(vector<myStruct>::value_type &a,vector<std::shared_ptr<obj>>::value_type &b){return a.mPtr != b;});


Sadly the lambda above give me error of C2664 and C2056 even tho I "roughly" understand what it says. I have no idea how to fix it.



Can any1 help?
TIA










share|improve this question























  • Your code in the question has a lot of other errors, and it would be useful to post the full error message that you care about. However: en.cppreference.com/w/cpp/algorithm/set_difference: "The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2." So you're getting C2664 because there's no conversion from std::shared_ptr<obj> to myStruct.

    – Colin Phipps
    Jan 1 at 14:14













  • Hey, thanks for info! Yeah when I read error log that is what he says, he cant convert shared_ptr to myStruct, I though if I would provide a lambda then I could do the comparison myself? In any case, I take there is no way to do this comparison then other than creating 2 matching vectors/maps/other stuff to filter it?

    – Dariusz
    Jan 1 at 14:52
















0















I'm trying to return a list of items that is not present between vector a and b. But here is the catch



    struct myStruct{
std::shared_ptr<obj> mPtr;
int x;
}

vector<myStruct> listA
vector<std::shared_ptr<obj>> listB
vector<myStruct>result
std::sort(listA.begin(),listA.end());
std::sort<listB.begin(),listB.end());

std::set_difference(listA.begin().listA.end(),listB.begin(),listB.end(),std::back_inserter(result),(vector<myStruct>::value_type &a,vector<std::shared_ptr<obj>>::value_type &b){return a.mPtr != b;});


Sadly the lambda above give me error of C2664 and C2056 even tho I "roughly" understand what it says. I have no idea how to fix it.



Can any1 help?
TIA










share|improve this question























  • Your code in the question has a lot of other errors, and it would be useful to post the full error message that you care about. However: en.cppreference.com/w/cpp/algorithm/set_difference: "The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2." So you're getting C2664 because there's no conversion from std::shared_ptr<obj> to myStruct.

    – Colin Phipps
    Jan 1 at 14:14













  • Hey, thanks for info! Yeah when I read error log that is what he says, he cant convert shared_ptr to myStruct, I though if I would provide a lambda then I could do the comparison myself? In any case, I take there is no way to do this comparison then other than creating 2 matching vectors/maps/other stuff to filter it?

    – Dariusz
    Jan 1 at 14:52














0












0








0








I'm trying to return a list of items that is not present between vector a and b. But here is the catch



    struct myStruct{
std::shared_ptr<obj> mPtr;
int x;
}

vector<myStruct> listA
vector<std::shared_ptr<obj>> listB
vector<myStruct>result
std::sort(listA.begin(),listA.end());
std::sort<listB.begin(),listB.end());

std::set_difference(listA.begin().listA.end(),listB.begin(),listB.end(),std::back_inserter(result),(vector<myStruct>::value_type &a,vector<std::shared_ptr<obj>>::value_type &b){return a.mPtr != b;});


Sadly the lambda above give me error of C2664 and C2056 even tho I "roughly" understand what it says. I have no idea how to fix it.



Can any1 help?
TIA










share|improve this question














I'm trying to return a list of items that is not present between vector a and b. But here is the catch



    struct myStruct{
std::shared_ptr<obj> mPtr;
int x;
}

vector<myStruct> listA
vector<std::shared_ptr<obj>> listB
vector<myStruct>result
std::sort(listA.begin(),listA.end());
std::sort<listB.begin(),listB.end());

std::set_difference(listA.begin().listA.end(),listB.begin(),listB.end(),std::back_inserter(result),(vector<myStruct>::value_type &a,vector<std::shared_ptr<obj>>::value_type &b){return a.mPtr != b;});


Sadly the lambda above give me error of C2664 and C2056 even tho I "roughly" understand what it says. I have no idea how to fix it.



Can any1 help?
TIA







std






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 1 at 13:39









DariuszDariusz

167214




167214













  • Your code in the question has a lot of other errors, and it would be useful to post the full error message that you care about. However: en.cppreference.com/w/cpp/algorithm/set_difference: "The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2." So you're getting C2664 because there's no conversion from std::shared_ptr<obj> to myStruct.

    – Colin Phipps
    Jan 1 at 14:14













  • Hey, thanks for info! Yeah when I read error log that is what he says, he cant convert shared_ptr to myStruct, I though if I would provide a lambda then I could do the comparison myself? In any case, I take there is no way to do this comparison then other than creating 2 matching vectors/maps/other stuff to filter it?

    – Dariusz
    Jan 1 at 14:52



















  • Your code in the question has a lot of other errors, and it would be useful to post the full error message that you care about. However: en.cppreference.com/w/cpp/algorithm/set_difference: "The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2." So you're getting C2664 because there's no conversion from std::shared_ptr<obj> to myStruct.

    – Colin Phipps
    Jan 1 at 14:14













  • Hey, thanks for info! Yeah when I read error log that is what he says, he cant convert shared_ptr to myStruct, I though if I would provide a lambda then I could do the comparison myself? In any case, I take there is no way to do this comparison then other than creating 2 matching vectors/maps/other stuff to filter it?

    – Dariusz
    Jan 1 at 14:52

















Your code in the question has a lot of other errors, and it would be useful to post the full error message that you care about. However: en.cppreference.com/w/cpp/algorithm/set_difference: "The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2." So you're getting C2664 because there's no conversion from std::shared_ptr<obj> to myStruct.

– Colin Phipps
Jan 1 at 14:14







Your code in the question has a lot of other errors, and it would be useful to post the full error message that you care about. However: en.cppreference.com/w/cpp/algorithm/set_difference: "The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2." So you're getting C2664 because there's no conversion from std::shared_ptr<obj> to myStruct.

– Colin Phipps
Jan 1 at 14:14















Hey, thanks for info! Yeah when I read error log that is what he says, he cant convert shared_ptr to myStruct, I though if I would provide a lambda then I could do the comparison myself? In any case, I take there is no way to do this comparison then other than creating 2 matching vectors/maps/other stuff to filter it?

– Dariusz
Jan 1 at 14:52





Hey, thanks for info! Yeah when I read error log that is what he says, he cant convert shared_ptr to myStruct, I though if I would provide a lambda then I could do the comparison myself? In any case, I take there is no way to do this comparison then other than creating 2 matching vectors/maps/other stuff to filter it?

– Dariusz
Jan 1 at 14:52












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