why couldnt achieve shared resource in python for twice(thread,timer
this whole script depreciate the NMEA code that i take from serial port. and gave this error(actually give neither error nor desired :
A: b'NX,1,1,2POTR1.01n'
B: b'NX0110,WVR=P 0*6r$GTT000,RVE=80*1r$NTT1002GSGLGALBS7n'
B: b'NX,1,2,BS;IS;S4n'
A: b'GX,0,1,,P;O;;D*7r$GTT0,010SAMEQZS*9r$GTT0002GSST=PSO*7rn'
A: b'X,0012LL=FFFFFFFF-FFF-FFF-FFFFx00*2n'
B: b'NX,1,1,,N OPG;GL3$GNTT1,,0,CFFFF-FFFFFFFFFFFFFFFFFFr$GX,1,,0,ANSPV= DS SEn'
B: b'GT,0,10,NSTTU=O*25n'
B: b'$NX,012,F3F4Bn'
The code:
from threading import Thread
import serial
import time
def runA():
while True:
for line in ser:
print("A: ",line)
def runB():
while True:
for line in ser:
print("B: ",line)
print("hey")
if __name__ == "__main__":
ser=serial.Serial('COM9',9600)
t1 = Thread(target = runA)
t2 = Thread(target = runB)
t1.setDaemon(True)
t2.setDaemon(True)
t1.start()
t2.start()
while True:
pass
expected is:
b'$GNGNS,080647.00,4059.11284,N,02907.92374,E,AA,13,0.84,130.5,37.5,,*6Crn'
b'$GNGGA,080647.00,4059.11284,N,02907.92374,E,1,12,0.84,130.5,M,37.5,M,,*47rn'
b'$GNGSA,A,3,09,22,01,11,17,18,23,03,31,,,,1.51,0.84,1.25*14rn'
b'$GNGSA,A,3,81,76,82,67,,,,,,,,,1.51,0.84,1.25*10rn'
b'$GPGSV,4,1,13,01,57,177,31,03,72,351,24,06,05,322,,09,24,241,30*72rn'
b'$GPGSV,4,2,13,11,28,189,17,14,14,052,,17,23,281,19,18,28,161,22*77rn'
I couldnt get data from same resource. Normally i know how to run two loops simultaneously but why didn't it work properly for this?
Thanks so much.
python multithreading timer wxpython
asked Dec 28 '18 at 5:27
gcsgcs
12
add a comment |
this whole script depreciate the NMEA code that i take from serial port. and gave this error(actually give neither error nor desired :
A: b'NX,1,1,2POTR1.01n'
B: b'NX0110,WVR=P 0*6r$GTT000,RVE=80*1r$NTT1002GSGLGALBS7n'
B: b'NX,1,2,BS;IS;S4n'
A: b'GX,0,1,,P;O;;D*7r$GTT0,010SAMEQZS*9r$GTT0002GSST=PSO*7rn'
A: b'X,0012LL=FFFFFFFF-FFF-FFF-FFFFx00*2n'
B: b'NX,1,1,,N OPG;GL3$GNTT1,,0,CFFFF-FFFFFFFFFFFFFFFFFFr$GX,1,,0,ANSPV= DS SEn'
B: b'GT,0,10,NSTTU=O*25n'
B: b'$NX,012,F3F4Bn'
The code:
from threading import Thread
import serial
import time
def runA():
while True:
for line in ser:
print("A: ",line)
def runB():
while True:
for line in ser:
print("B: ",line)
print("hey")
if __name__ == "__main__":
ser=serial.Serial('COM9',9600)
t1 = Thread(target = runA)
t2 = Thread(target = runB)
t1.setDaemon(True)
t2.setDaemon(True)
t1.start()
t2.start()
while True:
pass
expected is:
b'$GNGNS,080647.00,4059.11284,N,02907.92374,E,AA,13,0.84,130.5,37.5,,*6Crn'
b'$GNGGA,080647.00,4059.11284,N,02907.92374,E,1,12,0.84,130.5,M,37.5,M,,*47rn'
b'$GNGSA,A,3,09,22,01,11,17,18,23,03,31,,,,1.51,0.84,1.25*14rn'
b'$GNGSA,A,3,81,76,82,67,,,,,,,,,1.51,0.84,1.25*10rn'
b'$GPGSV,4,1,13,01,57,177,31,03,72,351,24,06,05,322,,09,24,241,30*72rn'
b'$GPGSV,4,2,13,11,28,189,17,14,14,052,,17,23,281,19,18,28,161,22*77rn'
I couldnt get data from same resource. Normally i know how to run two loops simultaneously but why didn't it work properly for this?
Thanks so much.
python multithreading timer wxpython
asked Dec 28 '18 at 5:27
gcsgcs
12
add a comment |
this whole script depreciate the NMEA code that i take from serial port. and gave this error(actually give neither error nor desired :
A: b'NX,1,1,2POTR1.01n'
B: b'NX0110,WVR=P 0*6r$GTT000,RVE=80*1r$NTT1002GSGLGALBS7n'
B: b'NX,1,2,BS;IS;S4n'
A: b'GX,0,1,,P;O;;D*7r$GTT0,010SAMEQZS*9r$GTT0002GSST=PSO*7rn'
A: b'X,0012LL=FFFFFFFF-FFF-FFF-FFFFx00*2n'
B: b'NX,1,1,,N OPG;GL3$GNTT1,,0,CFFFF-FFFFFFFFFFFFFFFFFFr$GX,1,,0,ANSPV= DS SEn'
B: b'GT,0,10,NSTTU=O*25n'
B: b'$NX,012,F3F4Bn'
The code:
from threading import Thread
import serial
import time
def runA():
while True:
for line in ser:
print("A: ",line)
def runB():
while True:
for line in ser:
print("B: ",line)
print("hey")
if __name__ == "__main__":
ser=serial.Serial('COM9',9600)
t1 = Thread(target = runA)
t2 = Thread(target = runB)
t1.setDaemon(True)
t2.setDaemon(True)
t1.start()
t2.start()
while True:
pass
expected is:
b'$GNGNS,080647.00,4059.11284,N,02907.92374,E,AA,13,0.84,130.5,37.5,,*6Crn'
b'$GNGGA,080647.00,4059.11284,N,02907.92374,E,1,12,0.84,130.5,M,37.5,M,,*47rn'
b'$GNGSA,A,3,09,22,01,11,17,18,23,03,31,,,,1.51,0.84,1.25*14rn'
b'$GNGSA,A,3,81,76,82,67,,,,,,,,,1.51,0.84,1.25*10rn'
b'$GPGSV,4,1,13,01,57,177,31,03,72,351,24,06,05,322,,09,24,241,30*72rn'
b'$GPGSV,4,2,13,11,28,189,17,14,14,052,,17,23,281,19,18,28,161,22*77rn'
I couldnt get data from same resource. Normally i know how to run two loops simultaneously but why didn't it work properly for this?
Thanks so much.
python multithreading timer wxpython
asked Dec 28 '18 at 5:27
gcsgcs
12
this whole script depreciate the NMEA code that i take from serial port. and gave this error(actually give neither error nor desired :
A: b'NX,1,1,2POTR1.01n'
B: b'NX0110,WVR=P 0*6r$GTT000,RVE=80*1r$NTT1002GSGLGALBS7n'
B: b'NX,1,2,BS;IS;S4n'
A: b'GX,0,1,,P;O;;D*7r$GTT0,010SAMEQZS*9r$GTT0002GSST=PSO*7rn'
A: b'X,0012LL=FFFFFFFF-FFF-FFF-FFFFx00*2n'
B: b'NX,1,1,,N OPG;GL3$GNTT1,,0,CFFFF-FFFFFFFFFFFFFFFFFFr$GX,1,,0,ANSPV= DS SEn'
B: b'GT,0,10,NSTTU=O*25n'
B: b'$NX,012,F3F4Bn'
The code:
from threading import Thread
import serial
import time
def runA():
while True:
for line in ser:
print("A: ",line)
def runB():
while True:
for line in ser:
print("B: ",line)
print("hey")
if __name__ == "__main__":
ser=serial.Serial('COM9',9600)
t1 = Thread(target = runA)
t2 = Thread(target = runB)
t1.setDaemon(True)
t2.setDaemon(True)
t1.start()
t2.start()
while True:
pass
expected is:
b'$GNGNS,080647.00,4059.11284,N,02907.92374,E,AA,13,0.84,130.5,37.5,,*6Crn'
b'$GNGGA,080647.00,4059.11284,N,02907.92374,E,1,12,0.84,130.5,M,37.5,M,,*47rn'
b'$GNGSA,A,3,09,22,01,11,17,18,23,03,31,,,,1.51,0.84,1.25*14rn'
b'$GNGSA,A,3,81,76,82,67,,,,,,,,,1.51,0.84,1.25*10rn'
b'$GPGSV,4,1,13,01,57,177,31,03,72,351,24,06,05,322,,09,24,241,30*72rn'
b'$GPGSV,4,2,13,11,28,189,17,14,14,052,,17,23,281,19,18,28,161,22*77rn'
I couldnt get data from same resource. Normally i know how to run two loops simultaneously but why didn't it work properly for this?
Thanks so much.
python multithreading timer wxpython
python multithreading timer wxpython
asked Dec 28 '18 at 5:27
gcsgcs
12
asked Dec 28 '18 at 5:27
gcsgcs
12
asked Dec 28 '18 at 5:27
gcsgcs
12
asked Dec 28 '18 at 5:27
gcsgcs
12
asked Dec 28 '18 at 5:27
gcsgcs
12
12
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
there are a bunch of problems with this ... its not starved for resources ...
probably the main one is though that
for line in serialPort is not part of the serial interface
I think you mean to do
for line in iter(ser.readline,''): which will blockingly wait for a newline
but i expect you will get garbled output trying to consume from the same port in both threads ... but it wont block
this assumes that you can even access ser inside of your functions ... since its scope is the if __name__ == "__main__" and i think python3 fixes some leaky scope issues
I actually am pretty sure both your threads are just crashing out... and your main loop is just spinning
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
your code is doingfor line in ser... not what I put, or what you put ... you need to dofor line in iter(ser.readline,''):...
– Joran Beasley
Dec 28 '18 at 6:10
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
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oldest
votes
active
oldest
votes
there are a bunch of problems with this ... its not starved for resources ...
probably the main one is though that
for line in serialPort is not part of the serial interface
I think you mean to do
for line in iter(ser.readline,''): which will blockingly wait for a newline
but i expect you will get garbled output trying to consume from the same port in both threads ... but it wont block
this assumes that you can even access ser inside of your functions ... since its scope is the if __name__ == "__main__" and i think python3 fixes some leaky scope issues
I actually am pretty sure both your threads are just crashing out... and your main loop is just spinning
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
your code is doingfor line in ser... not what I put, or what you put ... you need to dofor line in iter(ser.readline,''):...
– Joran Beasley
Dec 28 '18 at 6:10
add a comment |
there are a bunch of problems with this ... its not starved for resources ...
probably the main one is though that
for line in serialPort is not part of the serial interface
I think you mean to do
for line in iter(ser.readline,''): which will blockingly wait for a newline
but i expect you will get garbled output trying to consume from the same port in both threads ... but it wont block
this assumes that you can even access ser inside of your functions ... since its scope is the if __name__ == "__main__" and i think python3 fixes some leaky scope issues
I actually am pretty sure both your threads are just crashing out... and your main loop is just spinning
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
your code is doingfor line in ser... not what I put, or what you put ... you need to dofor line in iter(ser.readline,''):...
– Joran Beasley
Dec 28 '18 at 6:10
add a comment |
there are a bunch of problems with this ... its not starved for resources ...
probably the main one is though that
for line in serialPort is not part of the serial interface
I think you mean to do
for line in iter(ser.readline,''): which will blockingly wait for a newline
but i expect you will get garbled output trying to consume from the same port in both threads ... but it wont block
this assumes that you can even access ser inside of your functions ... since its scope is the if __name__ == "__main__" and i think python3 fixes some leaky scope issues
I actually am pretty sure both your threads are just crashing out... and your main loop is just spinning
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
there are a bunch of problems with this ... its not starved for resources ...
probably the main one is though that
for line in serialPort is not part of the serial interface
I think you mean to do
for line in iter(ser.readline,''): which will blockingly wait for a newline
but i expect you will get garbled output trying to consume from the same port in both threads ... but it wont block
this assumes that you can even access ser inside of your functions ... since its scope is the if __name__ == "__main__" and i think python3 fixes some leaky scope issues
I actually am pretty sure both your threads are just crashing out... and your main loop is just spinning
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
answered Dec 28 '18 at 5:35
Joran BeasleyJoran Beasley
72.4k677117
72.4k677117
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
your code is doingfor line in ser... not what I put, or what you put ... you need to dofor line in iter(ser.readline,''):...
– Joran Beasley
Dec 28 '18 at 6:10
add a comment |
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
your code is doingfor line in ser... not what I put, or what you put ... you need to dofor line in iter(ser.readline,''):...
– Joran Beasley
Dec 28 '18 at 6:10
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
def runA(): ser=serial.Serial('COM9',9600) while True: for line in iter(ser.readline,''): print("A: ",line) runA() this works. ı dont have any problem with serial, my problem is using shared resource with thread. Thanks for your effort btw
– gcs
Dec 28 '18 at 6:06
your code is doing
for line in ser ... not what I put, or what you put ... you need to do for line in iter(ser.readline,''): ...– Joran Beasley
Dec 28 '18 at 6:10
your code is doing
for line in ser ... not what I put, or what you put ... you need to do for line in iter(ser.readline,''): ...– Joran Beasley
Dec 28 '18 at 6:10
add a comment |
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