Vecrtorized evluation of function defined by matrix over grid












1














I'm looking to plot the value of a function defined by a matrix over a grid of values.



Let S be an invertable 2x2 matrix and let x be a 2-dimensional vector. How can vectorize the evaluation of x@S@x over a two dimensional grid?



Here is how I currently do it. It works, but takes a beat to perform the computation since the grid is so fine.



#Initialize Matrix
S = np.zeros(shape = (2,2))

while np.linalg.matrix_rank(S)<S.shape[1]:
S = np.random.randint(-5,5+1, size = (2,2))


X,Y = [j.ravel() for j in np.meshgrid(np.linspace(-2,2,1001),np.linspace(-2,2,1001))]

Z = np.zeros_like(X)

for i,v in enumerate(zip(X,Y)):
v = np.array(v)
Z[i] = v@S@v

n = int(np.sqrt(X.size))
Z = Z.reshape(n,n)
X = X.reshape(n,n)
Y = Y.reshape(n,n)
plt.contour(X,Y,Z)









share|improve this question



























    1














    I'm looking to plot the value of a function defined by a matrix over a grid of values.



    Let S be an invertable 2x2 matrix and let x be a 2-dimensional vector. How can vectorize the evaluation of x@S@x over a two dimensional grid?



    Here is how I currently do it. It works, but takes a beat to perform the computation since the grid is so fine.



    #Initialize Matrix
    S = np.zeros(shape = (2,2))

    while np.linalg.matrix_rank(S)<S.shape[1]:
    S = np.random.randint(-5,5+1, size = (2,2))


    X,Y = [j.ravel() for j in np.meshgrid(np.linspace(-2,2,1001),np.linspace(-2,2,1001))]

    Z = np.zeros_like(X)

    for i,v in enumerate(zip(X,Y)):
    v = np.array(v)
    Z[i] = v@S@v

    n = int(np.sqrt(X.size))
    Z = Z.reshape(n,n)
    X = X.reshape(n,n)
    Y = Y.reshape(n,n)
    plt.contour(X,Y,Z)









    share|improve this question

























      1












      1








      1







      I'm looking to plot the value of a function defined by a matrix over a grid of values.



      Let S be an invertable 2x2 matrix and let x be a 2-dimensional vector. How can vectorize the evaluation of x@S@x over a two dimensional grid?



      Here is how I currently do it. It works, but takes a beat to perform the computation since the grid is so fine.



      #Initialize Matrix
      S = np.zeros(shape = (2,2))

      while np.linalg.matrix_rank(S)<S.shape[1]:
      S = np.random.randint(-5,5+1, size = (2,2))


      X,Y = [j.ravel() for j in np.meshgrid(np.linspace(-2,2,1001),np.linspace(-2,2,1001))]

      Z = np.zeros_like(X)

      for i,v in enumerate(zip(X,Y)):
      v = np.array(v)
      Z[i] = v@S@v

      n = int(np.sqrt(X.size))
      Z = Z.reshape(n,n)
      X = X.reshape(n,n)
      Y = Y.reshape(n,n)
      plt.contour(X,Y,Z)









      share|improve this question













      I'm looking to plot the value of a function defined by a matrix over a grid of values.



      Let S be an invertable 2x2 matrix and let x be a 2-dimensional vector. How can vectorize the evaluation of x@S@x over a two dimensional grid?



      Here is how I currently do it. It works, but takes a beat to perform the computation since the grid is so fine.



      #Initialize Matrix
      S = np.zeros(shape = (2,2))

      while np.linalg.matrix_rank(S)<S.shape[1]:
      S = np.random.randint(-5,5+1, size = (2,2))


      X,Y = [j.ravel() for j in np.meshgrid(np.linspace(-2,2,1001),np.linspace(-2,2,1001))]

      Z = np.zeros_like(X)

      for i,v in enumerate(zip(X,Y)):
      v = np.array(v)
      Z[i] = v@S@v

      n = int(np.sqrt(X.size))
      Z = Z.reshape(n,n)
      X = X.reshape(n,n)
      Y = Y.reshape(n,n)
      plt.contour(X,Y,Z)






      python numpy






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      asked Dec 27 '18 at 20:08









      Demetri Pananos

      1,9911231




      1,9911231
























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          Simplest would be with stacking those X,Y into a 2-column 2D array and then using np.einsum to replace the loopy matrix-multiplications -



          p = np.column_stack((X,Y)) # or np.stack((X,Y)).T
          Zout = np.einsum('ij,jk,ik->i',p,S,p,optimize=True)





          share|improve this answer























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            Simplest would be with stacking those X,Y into a 2-column 2D array and then using np.einsum to replace the loopy matrix-multiplications -



            p = np.column_stack((X,Y)) # or np.stack((X,Y)).T
            Zout = np.einsum('ij,jk,ik->i',p,S,p,optimize=True)





            share|improve this answer




























              2














              Simplest would be with stacking those X,Y into a 2-column 2D array and then using np.einsum to replace the loopy matrix-multiplications -



              p = np.column_stack((X,Y)) # or np.stack((X,Y)).T
              Zout = np.einsum('ij,jk,ik->i',p,S,p,optimize=True)





              share|improve this answer


























                2












                2








                2






                Simplest would be with stacking those X,Y into a 2-column 2D array and then using np.einsum to replace the loopy matrix-multiplications -



                p = np.column_stack((X,Y)) # or np.stack((X,Y)).T
                Zout = np.einsum('ij,jk,ik->i',p,S,p,optimize=True)





                share|improve this answer














                Simplest would be with stacking those X,Y into a 2-column 2D array and then using np.einsum to replace the loopy matrix-multiplications -



                p = np.column_stack((X,Y)) # or np.stack((X,Y)).T
                Zout = np.einsum('ij,jk,ik->i',p,S,p,optimize=True)






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Dec 27 '18 at 20:42

























                answered Dec 27 '18 at 20:34









                Divakar

                154k1483172




                154k1483172






























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