Is it possible to create a list that might look for meeting one of a few specified options?
Are you able to give a value (I would be using an inputted value), and if it is any one of multiple given values, it would meet the "if" statement's criteria. I realize that I could use multiple "if" statements, but multiple "if" statements that all carry out the same function would be cluttered.
tested_value = 1
if tested_value is 1, 2, 3, 4, 5
print("tested_value is an integer between 1 and 5")
else
print("tested_value is not an integer between 1 and 5)
python list
add a comment |
Are you able to give a value (I would be using an inputted value), and if it is any one of multiple given values, it would meet the "if" statement's criteria. I realize that I could use multiple "if" statements, but multiple "if" statements that all carry out the same function would be cluttered.
tested_value = 1
if tested_value is 1, 2, 3, 4, 5
print("tested_value is an integer between 1 and 5")
else
print("tested_value is not an integer between 1 and 5)
python list
add a comment |
Are you able to give a value (I would be using an inputted value), and if it is any one of multiple given values, it would meet the "if" statement's criteria. I realize that I could use multiple "if" statements, but multiple "if" statements that all carry out the same function would be cluttered.
tested_value = 1
if tested_value is 1, 2, 3, 4, 5
print("tested_value is an integer between 1 and 5")
else
print("tested_value is not an integer between 1 and 5)
python list
Are you able to give a value (I would be using an inputted value), and if it is any one of multiple given values, it would meet the "if" statement's criteria. I realize that I could use multiple "if" statements, but multiple "if" statements that all carry out the same function would be cluttered.
tested_value = 1
if tested_value is 1, 2, 3, 4, 5
print("tested_value is an integer between 1 and 5")
else
print("tested_value is not an integer between 1 and 5)
python list
python list
edited Dec 27 '18 at 20:09
Prune
42.5k143456
42.5k143456
asked Dec 27 '18 at 20:07
Mark Zuckerberg
31
31
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The Python keyword is in
, like this:
tested_value = 1
if tested_value in [1, 2, 3, 4, 5]:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5)
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
in python you can check ranges like this:
tested_value = 1
if 1 <= tested_value <= 5:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5")
but if you want to check if its in a list check Adrians answer.
However, checking the range like above will match floats that are between 1 and 5 as well as ints.
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The Python keyword is in
, like this:
tested_value = 1
if tested_value in [1, 2, 3, 4, 5]:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5)
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
The Python keyword is in
, like this:
tested_value = 1
if tested_value in [1, 2, 3, 4, 5]:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5)
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
The Python keyword is in
, like this:
tested_value = 1
if tested_value in [1, 2, 3, 4, 5]:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5)
The Python keyword is in
, like this:
tested_value = 1
if tested_value in [1, 2, 3, 4, 5]:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5)
answered Dec 27 '18 at 20:09
Adrian Tam
1,10812
1,10812
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
Thanks for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
in python you can check ranges like this:
tested_value = 1
if 1 <= tested_value <= 5:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5")
but if you want to check if its in a list check Adrians answer.
However, checking the range like above will match floats that are between 1 and 5 as well as ints.
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
in python you can check ranges like this:
tested_value = 1
if 1 <= tested_value <= 5:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5")
but if you want to check if its in a list check Adrians answer.
However, checking the range like above will match floats that are between 1 and 5 as well as ints.
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
in python you can check ranges like this:
tested_value = 1
if 1 <= tested_value <= 5:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5")
but if you want to check if its in a list check Adrians answer.
However, checking the range like above will match floats that are between 1 and 5 as well as ints.
in python you can check ranges like this:
tested_value = 1
if 1 <= tested_value <= 5:
print("tested_value is an integer between 1 and 5")
else:
print("tested_value is not an integer between 1 and 5")
but if you want to check if its in a list check Adrians answer.
However, checking the range like above will match floats that are between 1 and 5 as well as ints.
answered Dec 27 '18 at 20:12
SimonF
656114
656114
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
Thank you for the help
– Mark Zuckerberg
Dec 27 '18 at 23:06
add a comment |
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