Bdtjtk

I have the following data:

[{'id': ['132605', '132750', '132772', '132773', '133065', '133150', '133185', '133188', '133271', '133298']}, 

 {'number': ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']}, 

 {'id': ['1', '1', '1', '1', '1', '1', '1', '1', '1', '1']}]

What would be the best way to get a list of the keys (as if it was a dict and not an array)? Currently I'm doing:

>>> [list(i.keys())[0] for i in e.original_column_data]

['id', 'number', 'id']

But that feels a bit hackish

What is hacky about it? It's a bit inelegant. You just need to do the following:

>>> keys = 

>>> data = [{'id': ['132605', '132750', '132772', '132773', '133065', '133150', '133185', '133188', '133271', '133298']},

...  {'number': ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']},

...  {'id': ['1', '1', '1', '1', '1', '1', '1', '1', '1', '1']}]

>>> for d in data:

...     keys.extend(d)

...

>>> keys

['id', 'number', 'id']

Or if you prefer one-liners:

>>> [k for d in data for k in d]

['id', 'number', 'id']

This is simpler and does the same thing:

[k for d in e.original_column_data for k in d]

=> ['id', 'number', 'id']

first way

iteration on a dictionary gives u its keys, so a simple

>>> [key for key in dict]

gives u a list of keys and you can get what you want with

>>> [key for dict in dict_list for key in dict]

second way

use .key() (used in your code)
but there is no need to use list() (edit: for python 2)

here's what it will look like:

>>> [dict.keys()[0] for dict in dict_list]

in your code, dictionaries have only one key so these two has the same result.

but I prefer the first one since it gives all keys of all the dictionaries