Need a date from an array DateTimeObject
-1
I need formatted date-time from php array, I received it from mysql like this:
Array(
[0] => Array
(
[Holidays] => DateTime Object
(
[date] => 2018-01-01 00:00:00.000000
[timezone_type] => 3
[timezone] => Europe/Berlin
)
) )
But I need the new array like this:
Array
(
[0] => 2018-12-31
[1] => 2018-12-07
)
Saw a post like this but it doesn't have datetimeobject
php mysql datetime
asked Dec 27 '18 at 21:49
Victor
31
add a comment |
-1
I need formatted date-time from php array, I received it from mysql like this:
Array(
[0] => Array
(
[Holidays] => DateTime Object
(
[date] => 2018-01-01 00:00:00.000000
[timezone_type] => 3
[timezone] => Europe/Berlin
)
) )
But I need the new array like this:
Array
(
[0] => 2018-12-31
[1] => 2018-12-07
)
Saw a post like this but it doesn't have datetimeobject
php mysql datetime
asked Dec 27 '18 at 21:49
Victor
31
You could always ask mysql for a DATE built from the DATETIME. I prefer keeping data operations in the database whenever my ORM etc makes that possible; after all, it's a database and it's way faster at mass data operations than php will ever be ( ignoring the decrease in network overhead for sending time data you don't want).
– Dan Farrell
Dec 27 '18 at 22:01
add a comment |
-1
-1
-1
I need formatted date-time from php array, I received it from mysql like this:
Array(
[0] => Array
(
[Holidays] => DateTime Object
(
[date] => 2018-01-01 00:00:00.000000
[timezone_type] => 3
[timezone] => Europe/Berlin
)
) )
But I need the new array like this:
Array
(
[0] => 2018-12-31
[1] => 2018-12-07
)
Saw a post like this but it doesn't have datetimeobject
php mysql datetime
asked Dec 27 '18 at 21:49
Victor
31
I need formatted date-time from php array, I received it from mysql like this:
Array(
[0] => Array
(
[Holidays] => DateTime Object
(
[date] => 2018-01-01 00:00:00.000000
[timezone_type] => 3
[timezone] => Europe/Berlin
)
) )
But I need the new array like this:
Array
(
[0] => 2018-12-31
[1] => 2018-12-07
)
Saw a post like this but it doesn't have datetimeobject
php mysql datetime
php mysql datetime
asked Dec 27 '18 at 21:49
Victor
31
asked Dec 27 '18 at 21:49
Victor
31
asked Dec 27 '18 at 21:49
Victor
31
asked Dec 27 '18 at 21:49
Victor
31
asked Dec 27 '18 at 21:49
Victor
31
31
You could always ask mysql for a DATE built from the DATETIME. I prefer keeping data operations in the database whenever my ORM etc makes that possible; after all, it's a database and it's way faster at mass data operations than php will ever be ( ignoring the decrease in network overhead for sending time data you don't want).
– Dan Farrell
Dec 27 '18 at 22:01
add a comment |
You could always ask mysql for a DATE built from the DATETIME. I prefer keeping data operations in the database whenever my ORM etc makes that possible; after all, it's a database and it's way faster at mass data operations than php will ever be ( ignoring the decrease in network overhead for sending time data you don't want).
– Dan Farrell
Dec 27 '18 at 22:01
You could always ask mysql for a DATE built from the DATETIME. I prefer keeping data operations in the database whenever my ORM etc makes that possible; after all, it's a database and it's way faster at mass data operations than php will ever be ( ignoring the decrease in network overhead for sending time data you don't want).
– Dan Farrell
Dec 27 '18 at 22:01
You could always ask mysql for a DATE built from the DATETIME. I prefer keeping data operations in the database whenever my ORM etc makes that possible; after all, it's a database and it's way faster at mass data operations than php will ever be ( ignoring the decrease in network overhead for sending time data you don't want).
– Dan Farrell
Dec 27 '18 at 22:01
add a comment |
3 Answers
3
active
oldest
votes
0
Assuming all the elements in your array are as you show in your question, you can just use array_map to translate the array. For example:
$a = array(array('Holidays' => new DateTime('2018-01-01', new DateTimeZone('Europe/Berlin'))),
array('Holidays' => new DateTime('2018-01-26', new DateTimeZone('Australia/Sydney'))));
print_r($a);
$a = array_map(function ($v) { return $v['Holidays']->format('Y-m-d'); }, $a);
print_r($a);
Output:
Array (
[0] => 2018-01-01
[1] => 2018-01-26
)
Demo on 3v4l.org
answered Dec 27 '18 at 22:41
Nick
24k91635
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
add a comment |
0
Assuming your array is this:
$array=array("2018-01-01 00:00:00.000000","2018-02-01 06:10:59.000000");
You could try formatting your data using Date and strtotime
foreach($array as $date){
echo "Date Format: ".Date('Y-m-d',strtotime($date))."<br>";
echo "Datetime Format: ".Date('Y-m-d H:i:s',strtotime($date))."<br>";
}
I hope it helps C:
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
add a comment |
0
Try to use this http://php.net/manual/en/datetime.format.php
foreach ($dates as $date) {
echo $date->format('Y-m-d');
}
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
2
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Assuming all the elements in your array are as you show in your question, you can just use array_map to translate the array. For example:
$a = array(array('Holidays' => new DateTime('2018-01-01', new DateTimeZone('Europe/Berlin'))),
array('Holidays' => new DateTime('2018-01-26', new DateTimeZone('Australia/Sydney'))));
print_r($a);
$a = array_map(function ($v) { return $v['Holidays']->format('Y-m-d'); }, $a);
print_r($a);
Output:
Array (
[0] => 2018-01-01
[1] => 2018-01-26
)
Demo on 3v4l.org
answered Dec 27 '18 at 22:41
Nick
24k91635
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
add a comment |
0
Assuming all the elements in your array are as you show in your question, you can just use array_map to translate the array. For example:
$a = array(array('Holidays' => new DateTime('2018-01-01', new DateTimeZone('Europe/Berlin'))),
array('Holidays' => new DateTime('2018-01-26', new DateTimeZone('Australia/Sydney'))));
print_r($a);
$a = array_map(function ($v) { return $v['Holidays']->format('Y-m-d'); }, $a);
print_r($a);
Output:
Array (
[0] => 2018-01-01
[1] => 2018-01-26
)
Demo on 3v4l.org
answered Dec 27 '18 at 22:41
Nick
24k91635
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
add a comment |
0
0
0
Assuming all the elements in your array are as you show in your question, you can just use array_map to translate the array. For example:
$a = array(array('Holidays' => new DateTime('2018-01-01', new DateTimeZone('Europe/Berlin'))),
array('Holidays' => new DateTime('2018-01-26', new DateTimeZone('Australia/Sydney'))));
print_r($a);
$a = array_map(function ($v) { return $v['Holidays']->format('Y-m-d'); }, $a);
print_r($a);
Output:
Array (
[0] => 2018-01-01
[1] => 2018-01-26
)
Demo on 3v4l.org
answered Dec 27 '18 at 22:41
Nick
24k91635
Assuming all the elements in your array are as you show in your question, you can just use array_map to translate the array. For example:
$a = array(array('Holidays' => new DateTime('2018-01-01', new DateTimeZone('Europe/Berlin'))),
array('Holidays' => new DateTime('2018-01-26', new DateTimeZone('Australia/Sydney'))));
print_r($a);
$a = array_map(function ($v) { return $v['Holidays']->format('Y-m-d'); }, $a);
print_r($a);
Output:
Array (
[0] => 2018-01-01
[1] => 2018-01-26
)
Demo on 3v4l.org
answered Dec 27 '18 at 22:41
Nick
24k91635
edited Dec 27 '18 at 23:32
answered Dec 27 '18 at 22:41
Nick
24k91635
answered Dec 27 '18 at 22:41
Nick
24k91635
answered Dec 27 '18 at 22:41
Nick
24k91635
24k91635
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
add a comment |
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
Thank you so much, guess I need to read about array map. Really this helped me as I want.
– Victor
Dec 28 '18 at 14:53
add a comment |
0
Assuming your array is this:
$array=array("2018-01-01 00:00:00.000000","2018-02-01 06:10:59.000000");
You could try formatting your data using Date and strtotime
foreach($array as $date){
echo "Date Format: ".Date('Y-m-d',strtotime($date))."<br>";
echo "Datetime Format: ".Date('Y-m-d H:i:s',strtotime($date))."<br>";
}
I hope it helps C:
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
add a comment |
0
Assuming your array is this:
$array=array("2018-01-01 00:00:00.000000","2018-02-01 06:10:59.000000");
You could try formatting your data using Date and strtotime
foreach($array as $date){
echo "Date Format: ".Date('Y-m-d',strtotime($date))."<br>";
echo "Datetime Format: ".Date('Y-m-d H:i:s',strtotime($date))."<br>";
}
I hope it helps C:
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
add a comment |
0
0
0
Assuming your array is this:
$array=array("2018-01-01 00:00:00.000000","2018-02-01 06:10:59.000000");
You could try formatting your data using Date and strtotime
foreach($array as $date){
echo "Date Format: ".Date('Y-m-d',strtotime($date))."<br>";
echo "Datetime Format: ".Date('Y-m-d H:i:s',strtotime($date))."<br>";
}
I hope it helps C:
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
Assuming your array is this:
$array=array("2018-01-01 00:00:00.000000","2018-02-01 06:10:59.000000");
You could try formatting your data using Date and strtotime
foreach($array as $date){
echo "Date Format: ".Date('Y-m-d',strtotime($date))."<br>";
echo "Datetime Format: ".Date('Y-m-d H:i:s',strtotime($date))."<br>";
}
I hope it helps C:
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
answered Dec 27 '18 at 22:34
ricardosalazarfullstack
524
524
add a comment |
add a comment |
0
Try to use this http://php.net/manual/en/datetime.format.php
foreach ($dates as $date) {
echo $date->format('Y-m-d');
}
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
2
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
add a comment |
0
Try to use this http://php.net/manual/en/datetime.format.php
foreach ($dates as $date) {
echo $date->format('Y-m-d');
}
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
2
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
add a comment |
0
0
0
Try to use this http://php.net/manual/en/datetime.format.php
foreach ($dates as $date) {
echo $date->format('Y-m-d');
}
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
Try to use this http://php.net/manual/en/datetime.format.php
foreach ($dates as $date) {
echo $date->format('Y-m-d');
}
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
edited Dec 27 '18 at 22:38
Funk Forty Niner
80.5k1247101
80.5k1247101
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
answered Dec 27 '18 at 21:58
Maxim Shubin
1,20110
1,20110
2
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
add a comment |
2
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
2
2
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
Always use English as an external reference; I've edited this.
– Funk Forty Niner
Dec 27 '18 at 22:38
add a comment |
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You could always ask mysql for a DATE built from the DATETIME. I prefer keeping data operations in the database whenever my ORM etc makes that possible; after all, it's a database and it's way faster at mass data operations than php will ever be ( ignoring the decrease in network overhead for sending time data you don't want).
– Dan Farrell
Dec 27 '18 at 22:01