Loop object that in the array and in the another object
0
i have the following structure. I need to get Internal value and through in the React. I think i need to get an array of values, for example: ['Bitcoin', 'Etherium'...] and map through it. How can i implement it?
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
]
javascript arrays reactjs object
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
add a comment |
0
i have the following structure. I need to get Internal value and through in the React. I think i need to get an array of values, for example: ['Bitcoin', 'Etherium'...] and map through it. How can i implement it?
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
]
javascript arrays reactjs object
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
add a comment |
0
0
0
i have the following structure. I need to get Internal value and through in the React. I think i need to get an array of values, for example: ['Bitcoin', 'Etherium'...] and map through it. How can i implement it?
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
]
javascript arrays reactjs object
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
i have the following structure. I need to get Internal value and through in the React. I think i need to get an array of values, for example: ['Bitcoin', 'Etherium'...] and map through it. How can i implement it?
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
]
javascript arrays reactjs object
javascript arrays reactjs object
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
edited Dec 30 '18 at 17:27
Jack Bashford
7,09031337
7,09031337
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
asked Dec 30 '18 at 17:19
Sasha ZoriaSasha Zoria
757
757
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
4
Here's how you'd get an array of coin names using Array.prototype.map()
const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
4
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
2
@JackBashford - You need them when you need to lookup a key via a var.const propName = 'Name'; const value = obj[propName];
– Amir Popovich
Dec 30 '18 at 17:30
2
changeletandvartoconstand this answer is perfect
– Pavlo
Dec 30 '18 at 17:31
1
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
1
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
|
show 3 more comments
0
Do it like this
import React from 'react'
export default class YourComponent extends React.Component {
render() {
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
]
let newArr = arr.map((data) => {
return data.CoinInfo.FullName
})
console.log('new array', newArr);
return (
<div>
</div>
)
}
}
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
1
You’re getting downvotes because this is not how you usemap().map()creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.
– Mark Meyer
Dec 30 '18 at 17:36
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
4
Here's how you'd get an array of coin names using Array.prototype.map()
const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
4
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
2
@JackBashford - You need them when you need to lookup a key via a var.const propName = 'Name'; const value = obj[propName];
– Amir Popovich
Dec 30 '18 at 17:30
2
changeletandvartoconstand this answer is perfect
– Pavlo
Dec 30 '18 at 17:31
1
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
1
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
|
show 3 more comments
4
Here's how you'd get an array of coin names using Array.prototype.map()
const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
4
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
2
@JackBashford - You need them when you need to lookup a key via a var.const propName = 'Name'; const value = obj[propName];
– Amir Popovich
Dec 30 '18 at 17:30
2
changeletandvartoconstand this answer is perfect
– Pavlo
Dec 30 '18 at 17:31
1
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
1
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
|
show 3 more comments
4
4
4
Here's how you'd get an array of coin names using Array.prototype.map()
const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
Here's how you'd get an array of coin names using Array.prototype.map()
const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);const arr = [{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
];
const coinNames = arr.map(x => x.CoinInfo.FullName);
console.log(coinNames);answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
edited Dec 30 '18 at 18:54
answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
answered Dec 30 '18 at 17:26
Jack BashfordJack Bashford
7,09031337
7,09031337
4
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
2
@JackBashford - You need them when you need to lookup a key via a var.const propName = 'Name'; const value = obj[propName];
– Amir Popovich
Dec 30 '18 at 17:30
2
changeletandvartoconstand this answer is perfect
– Pavlo
Dec 30 '18 at 17:31
1
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
1
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
|
show 3 more comments
4
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
2
@JackBashford - You need them when you need to lookup a key via a var.const propName = 'Name'; const value = obj[propName];
– Amir Popovich
Dec 30 '18 at 17:30
2
changeletandvartoconstand this answer is perfect
– Pavlo
Dec 30 '18 at 17:31
1
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
1
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
4
4
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
Just use dot notation, no point for brackets
– Ionut Achim
Dec 30 '18 at 17:28
2
2
@JackBashford - You need them when you need to lookup a key via a var.
const propName = 'Name'; const value = obj[propName];– Amir Popovich
Dec 30 '18 at 17:30
@JackBashford - You need them when you need to lookup a key via a var.
const propName = 'Name'; const value = obj[propName];– Amir Popovich
Dec 30 '18 at 17:30
2
2
change
let and var to const and this answer is perfect– Pavlo
Dec 30 '18 at 17:31
change
let and var to const and this answer is perfect– Pavlo
Dec 30 '18 at 17:31
1
1
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
Ah, of course @AmirPopovich That makes sense - if you used dots in that example, it would create a property literally named propName. Thanks for clarifying that.
– Jack Bashford
Dec 30 '18 at 17:32
1
1
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
Object property names are always strings. You only wrap them in quotes when they are the same as reserved words or are not valid J's identifiers (e.g. contain a space, hyphen or starts with a number).
– Ionut Achim
Dec 30 '18 at 17:36
|
show 3 more comments
0
Do it like this
import React from 'react'
export default class YourComponent extends React.Component {
render() {
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
]
let newArr = arr.map((data) => {
return data.CoinInfo.FullName
})
console.log('new array', newArr);
return (
<div>
</div>
)
}
}
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
1
You’re getting downvotes because this is not how you usemap().map()creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.
– Mark Meyer
Dec 30 '18 at 17:36
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
add a comment |
0
Do it like this
import React from 'react'
export default class YourComponent extends React.Component {
render() {
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
]
let newArr = arr.map((data) => {
return data.CoinInfo.FullName
})
console.log('new array', newArr);
return (
<div>
</div>
)
}
}
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
1
You’re getting downvotes because this is not how you usemap().map()creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.
– Mark Meyer
Dec 30 '18 at 17:36
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
add a comment |
0
0
0
Do it like this
import React from 'react'
export default class YourComponent extends React.Component {
render() {
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
]
let newArr = arr.map((data) => {
return data.CoinInfo.FullName
})
console.log('new array', newArr);
return (
<div>
</div>
)
}
}
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
Do it like this
import React from 'react'
export default class YourComponent extends React.Component {
render() {
let arr = [
{
"CoinInfo": {
"Id": "1182",
"Name": "BTC",
"FullName": "Bitcoin",
"Internal": "BTC",
"ImageUrl": "/media/19633/btc.png",
"Url": "/coins/btc/overview"
}
},
{
"CoinInfo": {
"Id": "7605",
"Name": "ETH",
"FullName": "Ethereum",
"Internal": "ETH",
"ImageUrl": "/media/20646/eth_logo.png",
"Url": "/coins/eth/overview"
}
}
]
let newArr = arr.map((data) => {
return data.CoinInfo.FullName
})
console.log('new array', newArr);
return (
<div>
</div>
)
}
}
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
edited Dec 30 '18 at 17:41
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
answered Dec 30 '18 at 17:26
Vikas SinghVikas Singh
482514
482514
1
You’re getting downvotes because this is not how you usemap().map()creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.
– Mark Meyer
Dec 30 '18 at 17:36
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
add a comment |
1
You’re getting downvotes because this is not how you usemap().map()creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.
– Mark Meyer
Dec 30 '18 at 17:36
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
1
1
You’re getting downvotes because this is not how you use
map(). map() creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.– Mark Meyer
Dec 30 '18 at 17:36
You’re getting downvotes because this is not how you use
map(). map() creates and returns an array. Using it to loop over and push into another array is redundant. See the answers above for examples.– Mark Meyer
Dec 30 '18 at 17:36
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer Thank you so much for the help! I did the mistake and later I have corrected it.
– Vikas Singh
Dec 30 '18 at 17:51
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
@MarkMeyer I could have done it but I thought this is the best lesson I got.
– Vikas Singh
Dec 30 '18 at 18:01
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