Can not debounce action within other action in Vuex

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2















I'm trying to debounce anything within an Action, it gets swallowed in one way or another...



Take this (pseudo) code:



import { debounce } from "lodash";

const actions = {
debounceSomeLogging ({ dispatch }, text) {
console.log("Outside debounced function.");
debounce(function() {
console.log("Inside debounced function.");
dispatch("doRealThing");
}, 1000);
},

doRealThing({ commit }) {
// Whatever
}
}


When I call the action, I see the Outside debounced function, but I can not see the other logging and the other action does not get triggered.



Anyone have experience with this and can point me in the right direction?










share|improve this question


















  • 1





    debounce does not run your function but creates a new one which is when called delays the invoking of your inner function. So you need to assign the return value of debounce and call it from somewhere...

    – nemesv
    Dec 30 '18 at 11:42













  • Okay, that seemed to be the problem. Thank you a lot, I will add it as an answer.

    – Titulum
    Dec 30 '18 at 12:08
















2















I'm trying to debounce anything within an Action, it gets swallowed in one way or another...



Take this (pseudo) code:



import { debounce } from "lodash";

const actions = {
debounceSomeLogging ({ dispatch }, text) {
console.log("Outside debounced function.");
debounce(function() {
console.log("Inside debounced function.");
dispatch("doRealThing");
}, 1000);
},

doRealThing({ commit }) {
// Whatever
}
}


When I call the action, I see the Outside debounced function, but I can not see the other logging and the other action does not get triggered.



Anyone have experience with this and can point me in the right direction?










share|improve this question


















  • 1





    debounce does not run your function but creates a new one which is when called delays the invoking of your inner function. So you need to assign the return value of debounce and call it from somewhere...

    – nemesv
    Dec 30 '18 at 11:42













  • Okay, that seemed to be the problem. Thank you a lot, I will add it as an answer.

    – Titulum
    Dec 30 '18 at 12:08














2












2








2








I'm trying to debounce anything within an Action, it gets swallowed in one way or another...



Take this (pseudo) code:



import { debounce } from "lodash";

const actions = {
debounceSomeLogging ({ dispatch }, text) {
console.log("Outside debounced function.");
debounce(function() {
console.log("Inside debounced function.");
dispatch("doRealThing");
}, 1000);
},

doRealThing({ commit }) {
// Whatever
}
}


When I call the action, I see the Outside debounced function, but I can not see the other logging and the other action does not get triggered.



Anyone have experience with this and can point me in the right direction?










share|improve this question














I'm trying to debounce anything within an Action, it gets swallowed in one way or another...



Take this (pseudo) code:



import { debounce } from "lodash";

const actions = {
debounceSomeLogging ({ dispatch }, text) {
console.log("Outside debounced function.");
debounce(function() {
console.log("Inside debounced function.");
dispatch("doRealThing");
}, 1000);
},

doRealThing({ commit }) {
// Whatever
}
}


When I call the action, I see the Outside debounced function, but I can not see the other logging and the other action does not get triggered.



Anyone have experience with this and can point me in the right direction?







vue.js vuejs2 lodash vuex vuex-modules






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 30 '18 at 11:31









TitulumTitulum

6401516




6401516








  • 1





    debounce does not run your function but creates a new one which is when called delays the invoking of your inner function. So you need to assign the return value of debounce and call it from somewhere...

    – nemesv
    Dec 30 '18 at 11:42













  • Okay, that seemed to be the problem. Thank you a lot, I will add it as an answer.

    – Titulum
    Dec 30 '18 at 12:08














  • 1





    debounce does not run your function but creates a new one which is when called delays the invoking of your inner function. So you need to assign the return value of debounce and call it from somewhere...

    – nemesv
    Dec 30 '18 at 11:42













  • Okay, that seemed to be the problem. Thank you a lot, I will add it as an answer.

    – Titulum
    Dec 30 '18 at 12:08








1




1





debounce does not run your function but creates a new one which is when called delays the invoking of your inner function. So you need to assign the return value of debounce and call it from somewhere...

– nemesv
Dec 30 '18 at 11:42







debounce does not run your function but creates a new one which is when called delays the invoking of your inner function. So you need to assign the return value of debounce and call it from somewhere...

– nemesv
Dec 30 '18 at 11:42















Okay, that seemed to be the problem. Thank you a lot, I will add it as an answer.

– Titulum
Dec 30 '18 at 12:08





Okay, that seemed to be the problem. Thank you a lot, I will add it as an answer.

– Titulum
Dec 30 '18 at 12:08












1 Answer
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oldest

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As nemesv pointed out in a comment, the debounce function does not call the inner function. So you need to call the debounce again, like so:



debounce(function() {
console.log("Inside debounced function.");
dispatch("doRealThing");
}, 1000)();


So, in short, it should look like this:



debounce(...)() instead of like this debounce(...).






share|improve this answer























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    1 Answer
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    0














    As nemesv pointed out in a comment, the debounce function does not call the inner function. So you need to call the debounce again, like so:



    debounce(function() {
    console.log("Inside debounced function.");
    dispatch("doRealThing");
    }, 1000)();


    So, in short, it should look like this:



    debounce(...)() instead of like this debounce(...).






    share|improve this answer




























      0














      As nemesv pointed out in a comment, the debounce function does not call the inner function. So you need to call the debounce again, like so:



      debounce(function() {
      console.log("Inside debounced function.");
      dispatch("doRealThing");
      }, 1000)();


      So, in short, it should look like this:



      debounce(...)() instead of like this debounce(...).






      share|improve this answer


























        0












        0








        0







        As nemesv pointed out in a comment, the debounce function does not call the inner function. So you need to call the debounce again, like so:



        debounce(function() {
        console.log("Inside debounced function.");
        dispatch("doRealThing");
        }, 1000)();


        So, in short, it should look like this:



        debounce(...)() instead of like this debounce(...).






        share|improve this answer













        As nemesv pointed out in a comment, the debounce function does not call the inner function. So you need to call the debounce again, like so:



        debounce(function() {
        console.log("Inside debounced function.");
        dispatch("doRealThing");
        }, 1000)();


        So, in short, it should look like this:



        debounce(...)() instead of like this debounce(...).







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 30 '18 at 12:11









        TitulumTitulum

        6401516




        6401516






























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