Expected an indented block Exception

After running this code, i get this exception and i didn't found any place to fix it properly

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

in_degrees = G.in_degree()

in_degrees=dict(in_degrees)

in_values = sorted(set(in_degrees.values()))

in_hist = [in_degrees.values().count(x) for x in in_values]

plt.figure() 

plt.grid(True)

plt.loglog(in_values, in_hist, 'ro-') 

plt.plot(out_values, out_hist, 'bv-') 

plt.legend(['In-degree', 'Out-degree'])

plt.xlabel('Degree')

plt.ylabel('Number of nodes')

plt.title('network of places in Cambridge')

#plt.xlim([0, 2*10**2])

I expect to receive a proper graph but all i get is this warning

  File "<ipython-input-32-f89b896484d7>", line 2

    in_degrees = G.in_degree()

             ^

IndentationError: expected an indented block

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

add a comment |

After running this code, i get this exception and i didn't found any place to fix it properly

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

in_degrees = G.in_degree()

in_degrees=dict(in_degrees)

in_values = sorted(set(in_degrees.values()))

in_hist = [in_degrees.values().count(x) for x in in_values]

plt.figure() 

plt.grid(True)

plt.loglog(in_values, in_hist, 'ro-') 

plt.plot(out_values, out_hist, 'bv-') 

plt.legend(['In-degree', 'Out-degree'])

plt.xlabel('Degree')

plt.ylabel('Number of nodes')

plt.title('network of places in Cambridge')

#plt.xlim([0, 2*10**2])

I expect to receive a proper graph but all i get is this warning

  File "<ipython-input-32-f89b896484d7>", line 2

    in_degrees = G.in_degree()

             ^

IndentationError: expected an indented block

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

add a comment |

After running this code, i get this exception and i didn't found any place to fix it properly

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

in_degrees = G.in_degree()

in_degrees=dict(in_degrees)

in_values = sorted(set(in_degrees.values()))

in_hist = [in_degrees.values().count(x) for x in in_values]

plt.figure() 

plt.grid(True)

plt.loglog(in_values, in_hist, 'ro-') 

plt.plot(out_values, out_hist, 'bv-') 

plt.legend(['In-degree', 'Out-degree'])

plt.xlabel('Degree')

plt.ylabel('Number of nodes')

plt.title('network of places in Cambridge')

#plt.xlim([0, 2*10**2])

I expect to receive a proper graph but all i get is this warning

  File "<ipython-input-32-f89b896484d7>", line 2

    in_degrees = G.in_degree()

             ^

IndentationError: expected an indented block

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

After running this code, i get this exception and i didn't found any place to fix it properly

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

in_degrees = G.in_degree()

in_degrees=dict(in_degrees)

in_values = sorted(set(in_degrees.values()))

in_hist = [in_degrees.values().count(x) for x in in_values]

plt.figure() 

plt.grid(True)

plt.loglog(in_values, in_hist, 'ro-') 

plt.plot(out_values, out_hist, 'bv-') 

plt.legend(['In-degree', 'Out-degree'])

plt.xlabel('Degree')

plt.ylabel('Number of nodes')

plt.title('network of places in Cambridge')

#plt.xlim([0, 2*10**2])

I expect to receive a proper graph but all i get is this warning

  File "<ipython-input-32-f89b896484d7>", line 2

    in_degrees = G.in_degree()

             ^

IndentationError: expected an indented block

csv graph jupyter-notebook pyhook

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

asked Dec 27 '18 at 18:21

Amit Mek

asked Dec 27 '18 at 18:21

Amit Mek

New contributor

Amit Mek is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment |

1 Answer
1

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votes

Python relies on proper indentation to identify function blocks. This code should work:

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

    in_degrees = G.in_degree()

    in_degrees=dict(in_degrees)

    in_values = sorted(set(in_degrees.values()))

    in_hist = [in_degrees.values().count(x) for x in in_values]

    plt.figure() 

    plt.grid(True)

    plt.loglog(in_values, in_hist, 'ro-') 

    plt.plot(out_values, out_hist, 'bv-') 

    plt.legend(['In-degree', 'Out-degree'])

    plt.xlabel('Degree')

    plt.ylabel('Number of nodes')

    plt.title('network of places in Cambridge')

    #plt.xlim([0, 2*10**2])

Basically just indent it by 2 or 4 spaces as per your style requirements.

answered Dec 27 '18 at 18:31

Sashi

6832617

Thanks a lot, it worked! No i got another Exception .. AttributeError: 'dict_values' object has no attribute 'count'
– Amit Mek
Dec 27 '18 at 18:34

Great. Please feel free to mark my answer as correct so it can be useful for future users who have similar problems!
– Sashi
Dec 27 '18 at 18:35

Just did! :) Think you know what could be the solution of the new exception ?
– Amit Mek
Dec 27 '18 at 18:37

Which line are you getting it on? I'm having trouble finding dict_values object. Would it be possible to create a new question for this and also share the error message? Official stackoverflow policy is that each question should only contain one problem! :)
– Sashi
Dec 27 '18 at 18:39

Yes of course, that what i will do in a minute!
– Amit Mek
Dec 27 '18 at 18:41

|
show 2 more comments

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Python relies on proper indentation to identify function blocks. This code should work:

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

    in_degrees = G.in_degree()

    in_degrees=dict(in_degrees)

    in_values = sorted(set(in_degrees.values()))

    in_hist = [in_degrees.values().count(x) for x in in_values]

    plt.figure() 

    plt.grid(True)

    plt.loglog(in_values, in_hist, 'ro-') 

    plt.plot(out_values, out_hist, 'bv-') 

    plt.legend(['In-degree', 'Out-degree'])

    plt.xlabel('Degree')

    plt.ylabel('Number of nodes')

    plt.title('network of places in Cambridge')

    #plt.xlim([0, 2*10**2])

Basically just indent it by 2 or 4 spaces as per your style requirements.

answered Dec 27 '18 at 18:31

Sashi

6832617

Thanks a lot, it worked! No i got another Exception .. AttributeError: 'dict_values' object has no attribute 'count'
– Amit Mek
Dec 27 '18 at 18:34

Great. Please feel free to mark my answer as correct so it can be useful for future users who have similar problems!
– Sashi
Dec 27 '18 at 18:35

Just did! :) Think you know what could be the solution of the new exception ?
– Amit Mek
Dec 27 '18 at 18:37

Which line are you getting it on? I'm having trouble finding dict_values object. Would it be possible to create a new question for this and also share the error message? Official stackoverflow policy is that each question should only contain one problem! :)
– Sashi
Dec 27 '18 at 18:39

Yes of course, that what i will do in a minute!
– Amit Mek
Dec 27 '18 at 18:41

|
show 2 more comments

Python relies on proper indentation to identify function blocks. This code should work:

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

    in_degrees = G.in_degree()

    in_degrees=dict(in_degrees)

    in_values = sorted(set(in_degrees.values()))

    in_hist = [in_degrees.values().count(x) for x in in_values]

    plt.figure() 

    plt.grid(True)

    plt.loglog(in_values, in_hist, 'ro-') 

    plt.plot(out_values, out_hist, 'bv-') 

    plt.legend(['In-degree', 'Out-degree'])

    plt.xlabel('Degree')

    plt.ylabel('Number of nodes')

    plt.title('network of places in Cambridge')

    #plt.xlim([0, 2*10**2])

Basically just indent it by 2 or 4 spaces as per your style requirements.

answered Dec 27 '18 at 18:31

Sashi

6832617

Thanks a lot, it worked! No i got another Exception .. AttributeError: 'dict_values' object has no attribute 'count'
– Amit Mek
Dec 27 '18 at 18:34

Great. Please feel free to mark my answer as correct so it can be useful for future users who have similar problems!
– Sashi
Dec 27 '18 at 18:35

Just did! :) Think you know what could be the solution of the new exception ?
– Amit Mek
Dec 27 '18 at 18:37

Which line are you getting it on? I'm having trouble finding dict_values object. Would it be possible to create a new question for this and also share the error message? Official stackoverflow policy is that each question should only contain one problem! :)
– Sashi
Dec 27 '18 at 18:39

Yes of course, that what i will do in a minute!
– Amit Mek
Dec 27 '18 at 18:41

|
show 2 more comments

Python relies on proper indentation to identify function blocks. This code should work:

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

    in_degrees = G.in_degree()

    in_degrees=dict(in_degrees)

    in_values = sorted(set(in_degrees.values()))

    in_hist = [in_degrees.values().count(x) for x in in_values]

    plt.figure() 

    plt.grid(True)

    plt.loglog(in_values, in_hist, 'ro-') 

    plt.plot(out_values, out_hist, 'bv-') 

    plt.legend(['In-degree', 'Out-degree'])

    plt.xlabel('Degree')

    plt.ylabel('Number of nodes')

    plt.title('network of places in Cambridge')

    #plt.xlim([0, 2*10**2])

Basically just indent it by 2 or 4 spaces as per your style requirements.

answered Dec 27 '18 at 18:31

Sashi

6832617

Python relies on proper indentation to identify function blocks. This code should work:

import networkx as nx

from networkx.algorithms import bipartite

import numpy as np

from pandas import DataFrame, concat

import pandas as pd

import matplotlib.pyplot as plt

from scipy.optimize import curve_fit 

import ast

import csv

import sys



def plot_degree_dist(G):

    in_degrees = G.in_degree()

    in_degrees=dict(in_degrees)

    in_values = sorted(set(in_degrees.values()))

    in_hist = [in_degrees.values().count(x) for x in in_values]

    plt.figure() 

    plt.grid(True)

    plt.loglog(in_values, in_hist, 'ro-') 

    plt.plot(out_values, out_hist, 'bv-') 

    plt.legend(['In-degree', 'Out-degree'])

    plt.xlabel('Degree')

    plt.ylabel('Number of nodes')

    plt.title('network of places in Cambridge')

    #plt.xlim([0, 2*10**2])

Basically just indent it by 2 or 4 spaces as per your style requirements.

answered Dec 27 '18 at 18:31

Sashi

6832617

answered Dec 27 '18 at 18:31

Sashi

6832617

answered Dec 27 '18 at 18:31

Sashi

6832617

answered Dec 27 '18 at 18:31

Sashi

6832617

Thanks a lot, it worked! No i got another Exception .. AttributeError: 'dict_values' object has no attribute 'count'
– Amit Mek
Dec 27 '18 at 18:34

Great. Please feel free to mark my answer as correct so it can be useful for future users who have similar problems!
– Sashi
Dec 27 '18 at 18:35

Just did! :) Think you know what could be the solution of the new exception ?
– Amit Mek
Dec 27 '18 at 18:37

Which line are you getting it on? I'm having trouble finding dict_values object. Would it be possible to create a new question for this and also share the error message? Official stackoverflow policy is that each question should only contain one problem! :)
– Sashi
Dec 27 '18 at 18:39

Yes of course, that what i will do in a minute!
– Amit Mek
Dec 27 '18 at 18:41

|
show 2 more comments

Thanks a lot, it worked! No i got another Exception .. AttributeError: 'dict_values' object has no attribute 'count'
– Amit Mek
Dec 27 '18 at 18:34

Great. Please feel free to mark my answer as correct so it can be useful for future users who have similar problems!
– Sashi
Dec 27 '18 at 18:35

Just did! :) Think you know what could be the solution of the new exception ?
– Amit Mek
Dec 27 '18 at 18:37

Which line are you getting it on? I'm having trouble finding dict_values object. Would it be possible to create a new question for this and also share the error message? Official stackoverflow policy is that each question should only contain one problem! :)
– Sashi
Dec 27 '18 at 18:39

Yes of course, that what i will do in a minute!
– Amit Mek
Dec 27 '18 at 18:41

Thanks a lot, it worked! No i got another Exception .. AttributeError: 'dict_values' object has no attribute 'count'
– Amit Mek
Dec 27 '18 at 18:34

Great. Please feel free to mark my answer as correct so it can be useful for future users who have similar problems!
– Sashi
Dec 27 '18 at 18:35

Just did! :) Think you know what could be the solution of the new exception ?
– Amit Mek
Dec 27 '18 at 18:37

Which line are you getting it on? I'm having trouble finding dict_values object. Would it be possible to create a new question for this and also share the error message? Official stackoverflow policy is that each question should only contain one problem! :)
– Sashi
Dec 27 '18 at 18:39

Yes of course, that what i will do in a minute!
– Amit Mek
Dec 27 '18 at 18:41

|
show 2 more comments

Amit Mek is a new contributor. Be nice, and check out our Code of Conduct.

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