Count categorical values in DataFrame












1














I have DataFrame only with Categorical Values



    Col1 | Col2| ... | ColM
Row
1 X | Y | ... | X
2 Z | X | ... | Y
3 Y | Z | ... | X
.
.
.
N X | Z | ... | Z


I would like to count how many times each category appeared in database
So example result:



X - 100 times
Y - 30 times
Z = 210 times


Thank You for help










share|improve this question


















  • 3




    df.stack().value_counts()?
    – coldspeed
    Dec 27 '18 at 18:23
















1














I have DataFrame only with Categorical Values



    Col1 | Col2| ... | ColM
Row
1 X | Y | ... | X
2 Z | X | ... | Y
3 Y | Z | ... | X
.
.
.
N X | Z | ... | Z


I would like to count how many times each category appeared in database
So example result:



X - 100 times
Y - 30 times
Z = 210 times


Thank You for help










share|improve this question


















  • 3




    df.stack().value_counts()?
    – coldspeed
    Dec 27 '18 at 18:23














1












1








1







I have DataFrame only with Categorical Values



    Col1 | Col2| ... | ColM
Row
1 X | Y | ... | X
2 Z | X | ... | Y
3 Y | Z | ... | X
.
.
.
N X | Z | ... | Z


I would like to count how many times each category appeared in database
So example result:



X - 100 times
Y - 30 times
Z = 210 times


Thank You for help










share|improve this question













I have DataFrame only with Categorical Values



    Col1 | Col2| ... | ColM
Row
1 X | Y | ... | X
2 Z | X | ... | Y
3 Y | Z | ... | X
.
.
.
N X | Z | ... | Z


I would like to count how many times each category appeared in database
So example result:



X - 100 times
Y - 30 times
Z = 210 times


Thank You for help







python-3.x pandas dataframe






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share|improve this question











share|improve this question




share|improve this question










asked Dec 27 '18 at 18:22









goskan

528




528








  • 3




    df.stack().value_counts()?
    – coldspeed
    Dec 27 '18 at 18:23














  • 3




    df.stack().value_counts()?
    – coldspeed
    Dec 27 '18 at 18:23








3




3




df.stack().value_counts()?
– coldspeed
Dec 27 '18 at 18:23




df.stack().value_counts()?
– coldspeed
Dec 27 '18 at 18:23












1 Answer
1






active

oldest

votes


















2














The most performant option is to use np.unique with the return_counts flag set:



u, c = np.unique(df, return_counts=True)
pd.Series(c, index=u)


There's also stack and value_counts, which is much slower, but simple and intuitive:



df.stack().value_counts()





share|improve this answer

















  • 1




    That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
    – goskan
    Dec 27 '18 at 18:28













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














The most performant option is to use np.unique with the return_counts flag set:



u, c = np.unique(df, return_counts=True)
pd.Series(c, index=u)


There's also stack and value_counts, which is much slower, but simple and intuitive:



df.stack().value_counts()





share|improve this answer

















  • 1




    That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
    – goskan
    Dec 27 '18 at 18:28


















2














The most performant option is to use np.unique with the return_counts flag set:



u, c = np.unique(df, return_counts=True)
pd.Series(c, index=u)


There's also stack and value_counts, which is much slower, but simple and intuitive:



df.stack().value_counts()





share|improve this answer

















  • 1




    That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
    – goskan
    Dec 27 '18 at 18:28
















2












2








2






The most performant option is to use np.unique with the return_counts flag set:



u, c = np.unique(df, return_counts=True)
pd.Series(c, index=u)


There's also stack and value_counts, which is much slower, but simple and intuitive:



df.stack().value_counts()





share|improve this answer












The most performant option is to use np.unique with the return_counts flag set:



u, c = np.unique(df, return_counts=True)
pd.Series(c, index=u)


There's also stack and value_counts, which is much slower, but simple and intuitive:



df.stack().value_counts()






share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 27 '18 at 18:25









coldspeed

120k20119195




120k20119195








  • 1




    That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
    – goskan
    Dec 27 '18 at 18:28
















  • 1




    That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
    – goskan
    Dec 27 '18 at 18:28










1




1




That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
– goskan
Dec 27 '18 at 18:28






That's the answer, I was thinking about value_counts() but completely didn't think about stack(). Thank You!
– goskan
Dec 27 '18 at 18:28




















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