Within the TensorFlow C API, is there a way to directly replace the buffer in a tensor with using memcpy?
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I'm coding an interface between a Fortran application and TensorFlow using the C API. I have successfully passed my data to C and run the session and returned the results and it works as expected. However I wanted to improve the performance and reduce memory overhead by replacing the buffer pointer in the Tensor without needing to create a copy (not using memcpy). I have initialized the Tensor (and its underlying buffer) to the proper size. I wanted to do something like this:
TF_TensorData(tensor) = pointerToExistingData;
Of course that's not permitted in C. So I wrote a function that would take the 2 pointers and do the assignment.
void* ptrcopy(void* ptr1, const void* ptr2)
{
ptr1 = ptr2;
return ptr1;
}
ptrcopy(TF_TensorData(tensor), pointerToExistingData);
While this is at best an improper way to achieve my goal, I thought that would work. However if I call TF_TensorData() afterwards the value of the pointer remains the same.
I can't access the buffer directly and don't want to use the C++ API. Does anyone have any ideas of a workaround or an alternative solution that doesn't require created a copy?
c tensorflow
asked Jan 3 at 20:25
jordanjordan
11
add a comment |
I'm coding an interface between a Fortran application and TensorFlow using the C API. I have successfully passed my data to C and run the session and returned the results and it works as expected. However I wanted to improve the performance and reduce memory overhead by replacing the buffer pointer in the Tensor without needing to create a copy (not using memcpy). I have initialized the Tensor (and its underlying buffer) to the proper size. I wanted to do something like this:
TF_TensorData(tensor) = pointerToExistingData;
Of course that's not permitted in C. So I wrote a function that would take the 2 pointers and do the assignment.
void* ptrcopy(void* ptr1, const void* ptr2)
{
ptr1 = ptr2;
return ptr1;
}
ptrcopy(TF_TensorData(tensor), pointerToExistingData);
While this is at best an improper way to achieve my goal, I thought that would work. However if I call TF_TensorData() afterwards the value of the pointer remains the same.
I can't access the buffer directly and don't want to use the C++ API. Does anyone have any ideas of a workaround or an alternative solution that doesn't require created a copy?
c tensorflow
asked Jan 3 at 20:25
jordanjordan
11
add a comment |
I'm coding an interface between a Fortran application and TensorFlow using the C API. I have successfully passed my data to C and run the session and returned the results and it works as expected. However I wanted to improve the performance and reduce memory overhead by replacing the buffer pointer in the Tensor without needing to create a copy (not using memcpy). I have initialized the Tensor (and its underlying buffer) to the proper size. I wanted to do something like this:
TF_TensorData(tensor) = pointerToExistingData;
Of course that's not permitted in C. So I wrote a function that would take the 2 pointers and do the assignment.
void* ptrcopy(void* ptr1, const void* ptr2)
{
ptr1 = ptr2;
return ptr1;
}
ptrcopy(TF_TensorData(tensor), pointerToExistingData);
While this is at best an improper way to achieve my goal, I thought that would work. However if I call TF_TensorData() afterwards the value of the pointer remains the same.
I can't access the buffer directly and don't want to use the C++ API. Does anyone have any ideas of a workaround or an alternative solution that doesn't require created a copy?
c tensorflow
asked Jan 3 at 20:25
jordanjordan
11
I'm coding an interface between a Fortran application and TensorFlow using the C API. I have successfully passed my data to C and run the session and returned the results and it works as expected. However I wanted to improve the performance and reduce memory overhead by replacing the buffer pointer in the Tensor without needing to create a copy (not using memcpy). I have initialized the Tensor (and its underlying buffer) to the proper size. I wanted to do something like this:
TF_TensorData(tensor) = pointerToExistingData;
Of course that's not permitted in C. So I wrote a function that would take the 2 pointers and do the assignment.
void* ptrcopy(void* ptr1, const void* ptr2)
{
ptr1 = ptr2;
return ptr1;
}
ptrcopy(TF_TensorData(tensor), pointerToExistingData);
While this is at best an improper way to achieve my goal, I thought that would work. However if I call TF_TensorData() afterwards the value of the pointer remains the same.
I can't access the buffer directly and don't want to use the C++ API. Does anyone have any ideas of a workaround or an alternative solution that doesn't require created a copy?
c tensorflow
c tensorflow
asked Jan 3 at 20:25
jordanjordan
11
asked Jan 3 at 20:25
jordanjordan
11
asked Jan 3 at 20:25
jordanjordan
11
asked Jan 3 at 20:25
jordanjordan
11
asked Jan 3 at 20:25
jordanjordan
11
11
add a comment |
add a comment |
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