Sorting nested lists with jquery

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I am trying to sort nested lists. I came across this link: Sorting <li> elements of a <Ul> according to text in <span> inside <li>

It gets me most of the way there, however, it assumes you do not have lists like

<ul>

  <li><span>sortable text a</span>

    <ul>

      <li><span>sortable subtext</span></li>

    </ul>

  </li>

<ul>

Whenever I use the code suggested above, any nested list gets appended to the first <li> in the nested list. I need it to go to the original list item.

My code:

$(document).ready(function() {

  // for each ul separately

  $('#rootUl ul, ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li').children('span');



    // extract the text

    var values = $toSort.get().map(function(span) {

      return span.textContent;

    });



    // sort the text

    values.sort();



    // shove reordered texts back into the original elements

    values.forEach(function(value, index) {

      $toSort[index].textContent = value;

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

I would expect the following:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>qq rrr</span></li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

    </ul>

  </li>

  <li>

    <span>zzz</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

</ul>

But instead, I get this:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li><span>zzz</span>

    <ul>

      <li>

        <span>qq rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span></li>

    </ul>

  </li>

</ul>

edited Jan 3 at 21:47

Andreas

16.7k52842

asked Jan 3 at 21:34

Jonathan M Roe

You're just sorting the text of each span at the same level, you're not moving the rest of the li with it.

– Barmar
Jan 3 at 22:29

Thanks for the information, but I'm not having any luck moving the rest of the li to its original <ul> tag. Can you tell me how?

– Jonathan M Roe
Jan 4 at 14:50

add a comment |

I am trying to sort nested lists. I came across this link: Sorting <li> elements of a <Ul> according to text in <span> inside <li>

It gets me most of the way there, however, it assumes you do not have lists like

<ul>

  <li><span>sortable text a</span>

    <ul>

      <li><span>sortable subtext</span></li>

    </ul>

  </li>

<ul>

Whenever I use the code suggested above, any nested list gets appended to the first <li> in the nested list. I need it to go to the original list item.

My code:

$(document).ready(function() {

  // for each ul separately

  $('#rootUl ul, ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li').children('span');



    // extract the text

    var values = $toSort.get().map(function(span) {

      return span.textContent;

    });



    // sort the text

    values.sort();



    // shove reordered texts back into the original elements

    values.forEach(function(value, index) {

      $toSort[index].textContent = value;

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

I would expect the following:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>qq rrr</span></li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

    </ul>

  </li>

  <li>

    <span>zzz</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

</ul>

But instead, I get this:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li><span>zzz</span>

    <ul>

      <li>

        <span>qq rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span></li>

    </ul>

  </li>

</ul>

edited Jan 3 at 21:47

Andreas

16.7k52842

asked Jan 3 at 21:34

Jonathan M Roe

You're just sorting the text of each span at the same level, you're not moving the rest of the li with it.

– Barmar
Jan 3 at 22:29

Thanks for the information, but I'm not having any luck moving the rest of the li to its original <ul> tag. Can you tell me how?

– Jonathan M Roe
Jan 4 at 14:50

add a comment |

I am trying to sort nested lists. I came across this link: Sorting <li> elements of a <Ul> according to text in <span> inside <li>

It gets me most of the way there, however, it assumes you do not have lists like

<ul>

  <li><span>sortable text a</span>

    <ul>

      <li><span>sortable subtext</span></li>

    </ul>

  </li>

<ul>

Whenever I use the code suggested above, any nested list gets appended to the first <li> in the nested list. I need it to go to the original list item.

My code:

$(document).ready(function() {

  // for each ul separately

  $('#rootUl ul, ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li').children('span');



    // extract the text

    var values = $toSort.get().map(function(span) {

      return span.textContent;

    });



    // sort the text

    values.sort();



    // shove reordered texts back into the original elements

    values.forEach(function(value, index) {

      $toSort[index].textContent = value;

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

I would expect the following:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>qq rrr</span></li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

    </ul>

  </li>

  <li>

    <span>zzz</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

</ul>

But instead, I get this:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li><span>zzz</span>

    <ul>

      <li>

        <span>qq rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span></li>

    </ul>

  </li>

</ul>

edited Jan 3 at 21:47

Andreas

16.7k52842

asked Jan 3 at 21:34

Jonathan M Roe

I am trying to sort nested lists. I came across this link: Sorting <li> elements of a <Ul> according to text in <span> inside <li>

It gets me most of the way there, however, it assumes you do not have lists like

<ul>

  <li><span>sortable text a</span>

    <ul>

      <li><span>sortable subtext</span></li>

    </ul>

  </li>

<ul>

Whenever I use the code suggested above, any nested list gets appended to the first <li> in the nested list. I need it to go to the original list item.

My code:

$(document).ready(function() {

  // for each ul separately

  $('#rootUl ul, ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li').children('span');



    // extract the text

    var values = $toSort.get().map(function(span) {

      return span.textContent;

    });



    // sort the text

    values.sort();



    // shove reordered texts back into the original elements

    values.forEach(function(value, index) {

      $toSort[index].textContent = value;

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

I would expect the following:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>qq rrr</span></li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

    </ul>

  </li>

  <li>

    <span>zzz</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

</ul>

But instead, I get this:

<ul id="rootUl">

  <li>

    <span>ccc</span>

    <ul>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

      <li><span>dd zzz</span></li>

    </ul>

  </li>

  <li>

    <span>rrr</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>mm ccc</span></li>

      <li><span>nn ccc</span></li>

    </ul>

  </li>

  <li><span>zzz</span>

    <ul>

      <li>

        <span>qq rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>ss rrr</span></li>

    </ul>

  </li>

</ul>

$(document).ready(function() {

  // for each ul separately

  $('#rootUl ul, ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li').children('span');



    // extract the text

    var values = $toSort.get().map(function(span) {

      return span.textContent;

    });



    // sort the text

    values.sort();



    // shove reordered texts back into the original elements

    values.forEach(function(value, index) {

      $toSort[index].textContent = value;

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

$(document).ready(function() {

  // for each ul separately

  $('#rootUl ul, ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li').children('span');



    // extract the text

    var values = $toSort.get().map(function(span) {

      return span.textContent;

    });



    // sort the text

    values.sort();



    // shove reordered texts back into the original elements

    values.forEach(function(value, index) {

      $toSort[index].textContent = value;

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

jquery list nested

edited Jan 3 at 21:47

Andreas

16.7k52842

asked Jan 3 at 21:34

Jonathan M Roe

edited Jan 3 at 21:47

Andreas

16.7k52842

asked Jan 3 at 21:34

Jonathan M Roe

edited Jan 3 at 21:47

Andreas

16.7k52842

edited Jan 3 at 21:47

Andreas

16.7k52842

edited Jan 3 at 21:47

Andreas

16.7k52842

asked Jan 3 at 21:34

Jonathan M Roe

asked Jan 3 at 21:34

Jonathan M Roe

asked Jan 3 at 21:34

Jonathan M Roe

You're just sorting the text of each span at the same level, you're not moving the rest of the li with it.

– Barmar
Jan 3 at 22:29

Thanks for the information, but I'm not having any luck moving the rest of the li to its original <ul> tag. Can you tell me how?

– Jonathan M Roe
Jan 4 at 14:50

add a comment |

You're just sorting the text of each span at the same level, you're not moving the rest of the li with it.

– Barmar
Jan 3 at 22:29

Thanks for the information, but I'm not having any luck moving the rest of the li to its original <ul> tag. Can you tell me how?

– Jonathan M Roe
Jan 4 at 14:50

You're just sorting the text of each span at the same level, you're not moving the rest of the li with it.

– Barmar
Jan 3 at 22:29

Thanks for the information, but I'm not having any luck moving the rest of the li to its original <ul> tag. Can you tell me how?

– Jonathan M Roe
Jan 4 at 14:50

add a comment |

1 Answer
1

active

oldest

votes

You need to sort the li elements within their parent lists, not just move the text contents of the spans. Use a callback function in sort() that compares the text of the span.

Once you've sorted the lis, you can append them to their parent ul to rearrange them in the DOM.

It's also not necessary to specify both #rootUl ul and ul in the selector, since ul will match #rootUl ul.

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

answered Jan 4 at 18:36

Barmar

435k36260363

That's got it! Thank you!

– Jonathan M Roe
Jan 4 at 19:41

add a comment |

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You need to sort the li elements within their parent lists, not just move the text contents of the spans. Use a callback function in sort() that compares the text of the span.

Once you've sorted the lis, you can append them to their parent ul to rearrange them in the DOM.

It's also not necessary to specify both #rootUl ul and ul in the selector, since ul will match #rootUl ul.

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

answered Jan 4 at 18:36

Barmar

435k36260363

That's got it! Thank you!

– Jonathan M Roe
Jan 4 at 19:41

add a comment |

You need to sort the li elements within their parent lists, not just move the text contents of the spans. Use a callback function in sort() that compares the text of the span.

Once you've sorted the lis, you can append them to their parent ul to rearrange them in the DOM.

It's also not necessary to specify both #rootUl ul and ul in the selector, since ul will match #rootUl ul.

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

answered Jan 4 at 18:36

Barmar

435k36260363

That's got it! Thank you!

– Jonathan M Roe
Jan 4 at 19:41

add a comment |

You need to sort the li elements within their parent lists, not just move the text contents of the spans. Use a callback function in sort() that compares the text of the span.

Once you've sorted the lis, you can append them to their parent ul to rearrange them in the DOM.

It's also not necessary to specify both #rootUl ul and ul in the selector, since ul will match #rootUl ul.

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

answered Jan 4 at 18:36

Barmar

435k36260363

You need to sort the li elements within their parent lists, not just move the text contents of the spans. Use a callback function in sort() that compares the text of the span.

Once you've sorted the lis, you can append them to their parent ul to rearrange them in the DOM.

It's also not necessary to specify both #rootUl ul and ul in the selector, since ul will match #rootUl ul.

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

$(document).ready(function() {

  // for each ul separately

  $('ul').each(function(_, ul) {

    // get all the nodes to be sorted

    var $toSort = $(ul).children('li');

    $toSort.sort((li1, li2) => $(li1).children("span").text().localeCompare($(li2).children("span").text()));

    $toSort.each(function() {

      $(this).appendTo(ul);

    });

  });

});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul id="rootUl">

  <li><span>zzz</span>

    <ul>

      <li><span>dd zzz</span></li>

      <li><span>aa zzz</span></li>

      <li><span>bb zzz</span></li>

    </ul>

  </li>

  <li><span>ccc</span>

    <ul>

      <li><span>ll ccc</span></li>

      <li><span>nn ccc</span></li>

      <li><span>mm ccc</span></li>

    </ul>

  </li>

  <li><span>rrr</span>

    <ul>

      <li><span>ss rrr</span>

        <ul>

          <li><span>dd ss rrr</span></li>

          <li><span>ff ss rrr</span></li>

          <li><span>ee ss rrr</span></li>

        </ul>

      </li>

      <li><span>rr rrr</span></li>

      <li><span>qq rrr</span></li>

    </ul>

  </li>

</ul>

answered Jan 4 at 18:36

Barmar

435k36260363

answered Jan 4 at 18:36

Barmar

435k36260363

answered Jan 4 at 18:36

Barmar

435k36260363

answered Jan 4 at 18:36

Barmar

435k36260363

That's got it! Thank you!

– Jonathan M Roe
Jan 4 at 19:41

add a comment |

That's got it! Thank you!

– Jonathan M Roe
Jan 4 at 19:41

That's got it! Thank you!

– Jonathan M Roe
Jan 4 at 19:41

add a comment |

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