Showing a loading screen with a spinner on a separate thread while working, ShowDialog works but Show doesn't
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I am trying to show a form with a spinner in the middle as a loading screen (not a progress indicator) while doing some long work and finally showing a form with the results, i am letting another thread handle the loading screen but when i use show() it just shows a black window (like its stuck) and sometimes it just flashes the window, while using ShowDialog() works perfectly but it blocks the thread and now i have to use Thread.Abort() and Thread.ResetAbort() to kill the thread, which i think you agree its not a good way to handle this. so my question is why ShowDialog() works but Show() doesn't.
I tried using async and await methods that i found here but it always comes back to ShowDialog(), what am i missing? and is there a safe way to exit the thread here?
public void button1_Click(object sender, EventArgs e)
{
t1 = new Thread(() =>
{
Loading l = new Loading();
l.Show(); //Doesn't work
l.ShowDialog(); //Works but thread will be blocked
while (!ThreadExitFlag)
{
}
l.Close();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
}
c# multithreading winforms
edited Jan 4 at 12:10
R Pelzer
696926
asked Jan 4 at 11:53
HMZHMZ
46
add a comment |
I am trying to show a form with a spinner in the middle as a loading screen (not a progress indicator) while doing some long work and finally showing a form with the results, i am letting another thread handle the loading screen but when i use show() it just shows a black window (like its stuck) and sometimes it just flashes the window, while using ShowDialog() works perfectly but it blocks the thread and now i have to use Thread.Abort() and Thread.ResetAbort() to kill the thread, which i think you agree its not a good way to handle this. so my question is why ShowDialog() works but Show() doesn't.
I tried using async and await methods that i found here but it always comes back to ShowDialog(), what am i missing? and is there a safe way to exit the thread here?
public void button1_Click(object sender, EventArgs e)
{
t1 = new Thread(() =>
{
Loading l = new Loading();
l.Show(); //Doesn't work
l.ShowDialog(); //Works but thread will be blocked
while (!ThreadExitFlag)
{
}
l.Close();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
}
c# multithreading winforms
edited Jan 4 at 12:10
R Pelzer
696926
asked Jan 4 at 11:53
HMZHMZ
46
1
You should not do UI operations outside the UI thread. Maybe this will help you.
– heap1
Jan 4 at 11:59
To wit, flip things around and doLongWork()in a separate thread while you keep your UI in the main thread.
– IceGlasses
Jan 4 at 13:18
add a comment |
I am trying to show a form with a spinner in the middle as a loading screen (not a progress indicator) while doing some long work and finally showing a form with the results, i am letting another thread handle the loading screen but when i use show() it just shows a black window (like its stuck) and sometimes it just flashes the window, while using ShowDialog() works perfectly but it blocks the thread and now i have to use Thread.Abort() and Thread.ResetAbort() to kill the thread, which i think you agree its not a good way to handle this. so my question is why ShowDialog() works but Show() doesn't.
I tried using async and await methods that i found here but it always comes back to ShowDialog(), what am i missing? and is there a safe way to exit the thread here?
public void button1_Click(object sender, EventArgs e)
{
t1 = new Thread(() =>
{
Loading l = new Loading();
l.Show(); //Doesn't work
l.ShowDialog(); //Works but thread will be blocked
while (!ThreadExitFlag)
{
}
l.Close();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
}
c# multithreading winforms
edited Jan 4 at 12:10
R Pelzer
696926
asked Jan 4 at 11:53
HMZHMZ
46
I am trying to show a form with a spinner in the middle as a loading screen (not a progress indicator) while doing some long work and finally showing a form with the results, i am letting another thread handle the loading screen but when i use show() it just shows a black window (like its stuck) and sometimes it just flashes the window, while using ShowDialog() works perfectly but it blocks the thread and now i have to use Thread.Abort() and Thread.ResetAbort() to kill the thread, which i think you agree its not a good way to handle this. so my question is why ShowDialog() works but Show() doesn't.
I tried using async and await methods that i found here but it always comes back to ShowDialog(), what am i missing? and is there a safe way to exit the thread here?
public void button1_Click(object sender, EventArgs e)
{
t1 = new Thread(() =>
{
Loading l = new Loading();
l.Show(); //Doesn't work
l.ShowDialog(); //Works but thread will be blocked
while (!ThreadExitFlag)
{
}
l.Close();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
}
c# multithreading winforms
c# multithreading winforms
edited Jan 4 at 12:10
R Pelzer
696926
asked Jan 4 at 11:53
HMZHMZ
46
edited Jan 4 at 12:10
R Pelzer
696926
asked Jan 4 at 11:53
HMZHMZ
46
edited Jan 4 at 12:10
R Pelzer
696926
edited Jan 4 at 12:10
R Pelzer
696926
edited Jan 4 at 12:10
R Pelzer
696926
696926
asked Jan 4 at 11:53
HMZHMZ
46
asked Jan 4 at 11:53
HMZHMZ
46
asked Jan 4 at 11:53
HMZHMZ
46
46
1
You should not do UI operations outside the UI thread. Maybe this will help you.
– heap1
Jan 4 at 11:59
To wit, flip things around and doLongWork()in a separate thread while you keep your UI in the main thread.
– IceGlasses
Jan 4 at 13:18
add a comment |
1
You should not do UI operations outside the UI thread. Maybe this will help you.
– heap1
Jan 4 at 11:59
To wit, flip things around and doLongWork()in a separate thread while you keep your UI in the main thread.
– IceGlasses
Jan 4 at 13:18
1
1
You should not do UI operations outside the UI thread. Maybe this will help you.
– heap1
Jan 4 at 11:59
You should not do UI operations outside the UI thread. Maybe this will help you.
– heap1
Jan 4 at 11:59
To wit, flip things around and do
LongWork() in a separate thread while you keep your UI in the main thread.– IceGlasses
Jan 4 at 13:18
To wit, flip things around and do
LongWork() in a separate thread while you keep your UI in the main thread.– IceGlasses
Jan 4 at 13:18
add a comment |
1 Answer
1
active
oldest
votes
Finally, this worked for me, I am not sure if this is the right approach but it does the job perfectly. Code:
Thread t1 = new Thread(() =>
{
Loading l = new Loading();
Thread t2 = new Thread(() => {
while (!ThreadExitFlag)
{
}
l.Invoke(new Action(() => { l.Close(); }));
});
t2.Start();
l.ShowDialog();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
answered Jan 5 at 0:16
HMZHMZ
46
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Finally, this worked for me, I am not sure if this is the right approach but it does the job perfectly. Code:
Thread t1 = new Thread(() =>
{
Loading l = new Loading();
Thread t2 = new Thread(() => {
while (!ThreadExitFlag)
{
}
l.Invoke(new Action(() => { l.Close(); }));
});
t2.Start();
l.ShowDialog();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
answered Jan 5 at 0:16
HMZHMZ
46
add a comment |
Finally, this worked for me, I am not sure if this is the right approach but it does the job perfectly. Code:
Thread t1 = new Thread(() =>
{
Loading l = new Loading();
Thread t2 = new Thread(() => {
while (!ThreadExitFlag)
{
}
l.Invoke(new Action(() => { l.Close(); }));
});
t2.Start();
l.ShowDialog();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
answered Jan 5 at 0:16
HMZHMZ
46
add a comment |
Finally, this worked for me, I am not sure if this is the right approach but it does the job perfectly. Code:
Thread t1 = new Thread(() =>
{
Loading l = new Loading();
Thread t2 = new Thread(() => {
while (!ThreadExitFlag)
{
}
l.Invoke(new Action(() => { l.Close(); }));
});
t2.Start();
l.ShowDialog();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
answered Jan 5 at 0:16
HMZHMZ
46
Finally, this worked for me, I am not sure if this is the right approach but it does the job perfectly. Code:
Thread t1 = new Thread(() =>
{
Loading l = new Loading();
Thread t2 = new Thread(() => {
while (!ThreadExitFlag)
{
}
l.Invoke(new Action(() => { l.Close(); }));
});
t2.Start();
l.ShowDialog();
});
t1.Start();
LongWork(); //this will trigger the ThreadExitFlag by the end
answered Jan 5 at 0:16
HMZHMZ
46
answered Jan 5 at 0:16
HMZHMZ
46
answered Jan 5 at 0:16
HMZHMZ
46
answered Jan 5 at 0:16
HMZHMZ
46
46
add a comment |
add a comment |
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1
You should not do UI operations outside the UI thread. Maybe this will help you.
– heap1
Jan 4 at 11:59
To wit, flip things around and do
LongWork()in a separate thread while you keep your UI in the main thread.– IceGlasses
Jan 4 at 13:18