Measure to count across multiple columns












0















I am new to Power BI - DAX functions.



I have three columns in a table with text in it and I have added a fourth column where I want the count of these three but when I use COUNTA, COUNTX or COUNTAX measure I am getting the count of the entire column.



COUNTA
COUNTAX
COUNTX

Column = COUNTX(Table1, Table1[First_Amendment])
+ COUNTX(Table1, Table1[Second_Amendment])
+ COUNTX(Table1, Table1[Third_Amendment])


Suppose column A, B, C contains three names, apple, mango, oranges respectively so in fourth column I should get count as 3.










share|improve this question

























  • In what cases would you not get 3? Are some of the rows blank?

    – Alexis Olson
    Jan 2 at 18:57
















0















I am new to Power BI - DAX functions.



I have three columns in a table with text in it and I have added a fourth column where I want the count of these three but when I use COUNTA, COUNTX or COUNTAX measure I am getting the count of the entire column.



COUNTA
COUNTAX
COUNTX

Column = COUNTX(Table1, Table1[First_Amendment])
+ COUNTX(Table1, Table1[Second_Amendment])
+ COUNTX(Table1, Table1[Third_Amendment])


Suppose column A, B, C contains three names, apple, mango, oranges respectively so in fourth column I should get count as 3.










share|improve this question

























  • In what cases would you not get 3? Are some of the rows blank?

    – Alexis Olson
    Jan 2 at 18:57














0












0








0








I am new to Power BI - DAX functions.



I have three columns in a table with text in it and I have added a fourth column where I want the count of these three but when I use COUNTA, COUNTX or COUNTAX measure I am getting the count of the entire column.



COUNTA
COUNTAX
COUNTX

Column = COUNTX(Table1, Table1[First_Amendment])
+ COUNTX(Table1, Table1[Second_Amendment])
+ COUNTX(Table1, Table1[Third_Amendment])


Suppose column A, B, C contains three names, apple, mango, oranges respectively so in fourth column I should get count as 3.










share|improve this question
















I am new to Power BI - DAX functions.



I have three columns in a table with text in it and I have added a fourth column where I want the count of these three but when I use COUNTA, COUNTX or COUNTAX measure I am getting the count of the entire column.



COUNTA
COUNTAX
COUNTX

Column = COUNTX(Table1, Table1[First_Amendment])
+ COUNTX(Table1, Table1[Second_Amendment])
+ COUNTX(Table1, Table1[Third_Amendment])


Suppose column A, B, C contains three names, apple, mango, oranges respectively so in fourth column I should get count as 3.







powerbi dax






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 2 at 18:56









Alexis Olson

14.9k21834




14.9k21834










asked Jan 2 at 18:12









Manish YemdeManish Yemde

1




1













  • In what cases would you not get 3? Are some of the rows blank?

    – Alexis Olson
    Jan 2 at 18:57



















  • In what cases would you not get 3? Are some of the rows blank?

    – Alexis Olson
    Jan 2 at 18:57

















In what cases would you not get 3? Are some of the rows blank?

– Alexis Olson
Jan 2 at 18:57





In what cases would you not get 3? Are some of the rows blank?

– Alexis Olson
Jan 2 at 18:57












1 Answer
1






active

oldest

votes


















0














Did you want to count no blank column based on row, right?



If so, you could try to use calculated column like below



Column = if((countaa[a])="",0,1)+if((countaa[b])="",0,1)+if((countaa[c])="",0,1)


enter image description here



You also could refer to this post for details.



Zoe






share|improve this answer
























  • Thank you Zoe very much, it worked.

    – Manish Yemde
    Jan 7 at 15:39











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Did you want to count no blank column based on row, right?



If so, you could try to use calculated column like below



Column = if((countaa[a])="",0,1)+if((countaa[b])="",0,1)+if((countaa[c])="",0,1)


enter image description here



You also could refer to this post for details.



Zoe






share|improve this answer
























  • Thank you Zoe very much, it worked.

    – Manish Yemde
    Jan 7 at 15:39
















0














Did you want to count no blank column based on row, right?



If so, you could try to use calculated column like below



Column = if((countaa[a])="",0,1)+if((countaa[b])="",0,1)+if((countaa[c])="",0,1)


enter image description here



You also could refer to this post for details.



Zoe






share|improve this answer
























  • Thank you Zoe very much, it worked.

    – Manish Yemde
    Jan 7 at 15:39














0












0








0







Did you want to count no blank column based on row, right?



If so, you could try to use calculated column like below



Column = if((countaa[a])="",0,1)+if((countaa[b])="",0,1)+if((countaa[c])="",0,1)


enter image description here



You also could refer to this post for details.



Zoe






share|improve this answer













Did you want to count no blank column based on row, right?



If so, you could try to use calculated column like below



Column = if((countaa[a])="",0,1)+if((countaa[b])="",0,1)+if((countaa[c])="",0,1)


enter image description here



You also could refer to this post for details.



Zoe







share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 3 at 3:01









zoe zhizoe zhi

1193




1193













  • Thank you Zoe very much, it worked.

    – Manish Yemde
    Jan 7 at 15:39



















  • Thank you Zoe very much, it worked.

    – Manish Yemde
    Jan 7 at 15:39

















Thank you Zoe very much, it worked.

– Manish Yemde
Jan 7 at 15:39





Thank you Zoe very much, it worked.

– Manish Yemde
Jan 7 at 15:39




















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