Exception Unhandled












0















In Visual Studio the fscanf gives me this error:



Unhandled exception at 0x6080D4EC (ucrtbased.dll) in Programação Imperativa.exe: 0xC0000005: Access violation writing location 0x00D0B000.



    #define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <locale.h>
#include <stdlib.h>
#include <string.h>


struct estrutura
{
char nome[100];
float no1;
float no2;
float valor;
}v1, r1, r2, r3, r4;

int main(void)
{
FILE *circuito;
int x;
setlocale(LC_ALL, "Portuguese");
circuito = fopen("circuito.cir", "r");


if (circuito == NULL)
{
printf("Erro na abertura do ficheiro");
}
else
{
while ((x = fgetc(circuito)) != 'n');

fscanf_s(circuito, "%s %f %f %fn", v1.nome, &v1.no1, &v1.no2, &v1.valor);
printf("%s %lf %lf %lf n", v1.nome, v1.no1, v1.no2, v1.valor);

fscanf_s(circuito, "%s %f %f %fn", r1.nome, &r1.no1, &r1.no2, &r1.valor);
printf("%s %f %f %f n", r1.nome, r1.no1, r1.no2, r1.valor);
}





return 0;
}









share|improve this question

























  • OT: regarding: printf("Erro na abertura do ficheiro"); error messages should be output to stderr, not stdout and when the error indication is from a C library function, then should also output to stderr the text reason the system thinks the error occurred. The function: perror() properly handles all of this. After handling an unrecoverable error, then should call exit( EXIT_FAILURE ); (from stdlib.h) For one reason, typically a return of 0 indicates 'success', but the code was NOT successful.

    – user3629249
    Jan 1 at 1:25













  • what input are you giving it? how much does it print out?

    – Tom Tanner
    Jan 1 at 17:24
















0















In Visual Studio the fscanf gives me this error:



Unhandled exception at 0x6080D4EC (ucrtbased.dll) in Programação Imperativa.exe: 0xC0000005: Access violation writing location 0x00D0B000.



    #define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <locale.h>
#include <stdlib.h>
#include <string.h>


struct estrutura
{
char nome[100];
float no1;
float no2;
float valor;
}v1, r1, r2, r3, r4;

int main(void)
{
FILE *circuito;
int x;
setlocale(LC_ALL, "Portuguese");
circuito = fopen("circuito.cir", "r");


if (circuito == NULL)
{
printf("Erro na abertura do ficheiro");
}
else
{
while ((x = fgetc(circuito)) != 'n');

fscanf_s(circuito, "%s %f %f %fn", v1.nome, &v1.no1, &v1.no2, &v1.valor);
printf("%s %lf %lf %lf n", v1.nome, v1.no1, v1.no2, v1.valor);

fscanf_s(circuito, "%s %f %f %fn", r1.nome, &r1.no1, &r1.no2, &r1.valor);
printf("%s %f %f %f n", r1.nome, r1.no1, r1.no2, r1.valor);
}





return 0;
}









share|improve this question

























  • OT: regarding: printf("Erro na abertura do ficheiro"); error messages should be output to stderr, not stdout and when the error indication is from a C library function, then should also output to stderr the text reason the system thinks the error occurred. The function: perror() properly handles all of this. After handling an unrecoverable error, then should call exit( EXIT_FAILURE ); (from stdlib.h) For one reason, typically a return of 0 indicates 'success', but the code was NOT successful.

    – user3629249
    Jan 1 at 1:25













  • what input are you giving it? how much does it print out?

    – Tom Tanner
    Jan 1 at 17:24














0












0








0








In Visual Studio the fscanf gives me this error:



Unhandled exception at 0x6080D4EC (ucrtbased.dll) in Programação Imperativa.exe: 0xC0000005: Access violation writing location 0x00D0B000.



    #define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <locale.h>
#include <stdlib.h>
#include <string.h>


struct estrutura
{
char nome[100];
float no1;
float no2;
float valor;
}v1, r1, r2, r3, r4;

int main(void)
{
FILE *circuito;
int x;
setlocale(LC_ALL, "Portuguese");
circuito = fopen("circuito.cir", "r");


if (circuito == NULL)
{
printf("Erro na abertura do ficheiro");
}
else
{
while ((x = fgetc(circuito)) != 'n');

fscanf_s(circuito, "%s %f %f %fn", v1.nome, &v1.no1, &v1.no2, &v1.valor);
printf("%s %lf %lf %lf n", v1.nome, v1.no1, v1.no2, v1.valor);

fscanf_s(circuito, "%s %f %f %fn", r1.nome, &r1.no1, &r1.no2, &r1.valor);
printf("%s %f %f %f n", r1.nome, r1.no1, r1.no2, r1.valor);
}





return 0;
}









share|improve this question
















In Visual Studio the fscanf gives me this error:



Unhandled exception at 0x6080D4EC (ucrtbased.dll) in Programação Imperativa.exe: 0xC0000005: Access violation writing location 0x00D0B000.



    #define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <locale.h>
#include <stdlib.h>
#include <string.h>


struct estrutura
{
char nome[100];
float no1;
float no2;
float valor;
}v1, r1, r2, r3, r4;

int main(void)
{
FILE *circuito;
int x;
setlocale(LC_ALL, "Portuguese");
circuito = fopen("circuito.cir", "r");


if (circuito == NULL)
{
printf("Erro na abertura do ficheiro");
}
else
{
while ((x = fgetc(circuito)) != 'n');

fscanf_s(circuito, "%s %f %f %fn", v1.nome, &v1.no1, &v1.no2, &v1.valor);
printf("%s %lf %lf %lf n", v1.nome, v1.no1, v1.no2, v1.valor);

fscanf_s(circuito, "%s %f %f %fn", r1.nome, &r1.no1, &r1.no2, &r1.valor);
printf("%s %f %f %f n", r1.nome, r1.no1, r1.no2, r1.valor);
}





return 0;
}






c exception-handling






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edited Jan 1 at 3:14









Shahnewaz

392311




392311










asked Dec 31 '18 at 18:59









rui gomesrui gomes

21




21













  • OT: regarding: printf("Erro na abertura do ficheiro"); error messages should be output to stderr, not stdout and when the error indication is from a C library function, then should also output to stderr the text reason the system thinks the error occurred. The function: perror() properly handles all of this. After handling an unrecoverable error, then should call exit( EXIT_FAILURE ); (from stdlib.h) For one reason, typically a return of 0 indicates 'success', but the code was NOT successful.

    – user3629249
    Jan 1 at 1:25













  • what input are you giving it? how much does it print out?

    – Tom Tanner
    Jan 1 at 17:24



















  • OT: regarding: printf("Erro na abertura do ficheiro"); error messages should be output to stderr, not stdout and when the error indication is from a C library function, then should also output to stderr the text reason the system thinks the error occurred. The function: perror() properly handles all of this. After handling an unrecoverable error, then should call exit( EXIT_FAILURE ); (from stdlib.h) For one reason, typically a return of 0 indicates 'success', but the code was NOT successful.

    – user3629249
    Jan 1 at 1:25













  • what input are you giving it? how much does it print out?

    – Tom Tanner
    Jan 1 at 17:24

















OT: regarding: printf("Erro na abertura do ficheiro"); error messages should be output to stderr, not stdout and when the error indication is from a C library function, then should also output to stderr the text reason the system thinks the error occurred. The function: perror() properly handles all of this. After handling an unrecoverable error, then should call exit( EXIT_FAILURE ); (from stdlib.h) For one reason, typically a return of 0 indicates 'success', but the code was NOT successful.

– user3629249
Jan 1 at 1:25







OT: regarding: printf("Erro na abertura do ficheiro"); error messages should be output to stderr, not stdout and when the error indication is from a C library function, then should also output to stderr the text reason the system thinks the error occurred. The function: perror() properly handles all of this. After handling an unrecoverable error, then should call exit( EXIT_FAILURE ); (from stdlib.h) For one reason, typically a return of 0 indicates 'success', but the code was NOT successful.

– user3629249
Jan 1 at 1:25















what input are you giving it? how much does it print out?

– Tom Tanner
Jan 1 at 17:24





what input are you giving it? how much does it print out?

– Tom Tanner
Jan 1 at 17:24












1 Answer
1






active

oldest

votes


















5














You are using fscanf_s with %s specifier incorrectly.




Unlike fscanf ... fscanf_s ... requires the buffer size to be
specified for all input parameters of type c, C, s, S, or string
control sets that are enclosed in . The buffer size in characters is
passed as an additional parameter immediately following the pointer to
the buffer or variable.




Because there is one too few arguments passed, the address passed to accept a value for the final %f is undefined.



The compiler should have warned you about the missing buffer size argument.






share|improve this answer
























  • The compiler is not required to report errors in varargs. A lot of the time it can't.

    – Mad Physicist
    Jan 1 at 3:20













  • @MadPhysicist OP's Visual Studio warns about this.

    – Weather Vane
    Jan 1 at 17:26











  • TIL. I mostly use gcc.

    – Mad Physicist
    Jan 1 at 17:31











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5














You are using fscanf_s with %s specifier incorrectly.




Unlike fscanf ... fscanf_s ... requires the buffer size to be
specified for all input parameters of type c, C, s, S, or string
control sets that are enclosed in . The buffer size in characters is
passed as an additional parameter immediately following the pointer to
the buffer or variable.




Because there is one too few arguments passed, the address passed to accept a value for the final %f is undefined.



The compiler should have warned you about the missing buffer size argument.






share|improve this answer
























  • The compiler is not required to report errors in varargs. A lot of the time it can't.

    – Mad Physicist
    Jan 1 at 3:20













  • @MadPhysicist OP's Visual Studio warns about this.

    – Weather Vane
    Jan 1 at 17:26











  • TIL. I mostly use gcc.

    – Mad Physicist
    Jan 1 at 17:31
















5














You are using fscanf_s with %s specifier incorrectly.




Unlike fscanf ... fscanf_s ... requires the buffer size to be
specified for all input parameters of type c, C, s, S, or string
control sets that are enclosed in . The buffer size in characters is
passed as an additional parameter immediately following the pointer to
the buffer or variable.




Because there is one too few arguments passed, the address passed to accept a value for the final %f is undefined.



The compiler should have warned you about the missing buffer size argument.






share|improve this answer
























  • The compiler is not required to report errors in varargs. A lot of the time it can't.

    – Mad Physicist
    Jan 1 at 3:20













  • @MadPhysicist OP's Visual Studio warns about this.

    – Weather Vane
    Jan 1 at 17:26











  • TIL. I mostly use gcc.

    – Mad Physicist
    Jan 1 at 17:31














5












5








5







You are using fscanf_s with %s specifier incorrectly.




Unlike fscanf ... fscanf_s ... requires the buffer size to be
specified for all input parameters of type c, C, s, S, or string
control sets that are enclosed in . The buffer size in characters is
passed as an additional parameter immediately following the pointer to
the buffer or variable.




Because there is one too few arguments passed, the address passed to accept a value for the final %f is undefined.



The compiler should have warned you about the missing buffer size argument.






share|improve this answer













You are using fscanf_s with %s specifier incorrectly.




Unlike fscanf ... fscanf_s ... requires the buffer size to be
specified for all input parameters of type c, C, s, S, or string
control sets that are enclosed in . The buffer size in characters is
passed as an additional parameter immediately following the pointer to
the buffer or variable.




Because there is one too few arguments passed, the address passed to accept a value for the final %f is undefined.



The compiler should have warned you about the missing buffer size argument.







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 31 '18 at 19:11









Weather VaneWeather Vane

26k52138




26k52138













  • The compiler is not required to report errors in varargs. A lot of the time it can't.

    – Mad Physicist
    Jan 1 at 3:20













  • @MadPhysicist OP's Visual Studio warns about this.

    – Weather Vane
    Jan 1 at 17:26











  • TIL. I mostly use gcc.

    – Mad Physicist
    Jan 1 at 17:31



















  • The compiler is not required to report errors in varargs. A lot of the time it can't.

    – Mad Physicist
    Jan 1 at 3:20













  • @MadPhysicist OP's Visual Studio warns about this.

    – Weather Vane
    Jan 1 at 17:26











  • TIL. I mostly use gcc.

    – Mad Physicist
    Jan 1 at 17:31

















The compiler is not required to report errors in varargs. A lot of the time it can't.

– Mad Physicist
Jan 1 at 3:20







The compiler is not required to report errors in varargs. A lot of the time it can't.

– Mad Physicist
Jan 1 at 3:20















@MadPhysicist OP's Visual Studio warns about this.

– Weather Vane
Jan 1 at 17:26





@MadPhysicist OP's Visual Studio warns about this.

– Weather Vane
Jan 1 at 17:26













TIL. I mostly use gcc.

– Mad Physicist
Jan 1 at 17:31





TIL. I mostly use gcc.

– Mad Physicist
Jan 1 at 17:31




















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