How to find items with multiple different names
I'm having trouble with a very simple sql query. I want to identify all items that have more than one name. Here's what I'm currently doing:
select group_concat(distinct name) names
from table
group by master_id
having names like '%,%'
Unfortunately, a lot of names have a , in it, so the above doesn't work well. What would be the correct way to do this query?
mysql sql
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
asked Jan 1 at 3:53
David LDavid L
25916
add a comment |
I'm having trouble with a very simple sql query. I want to identify all items that have more than one name. Here's what I'm currently doing:
select group_concat(distinct name) names
from table
group by master_id
having names like '%,%'
Unfortunately, a lot of names have a , in it, so the above doesn't work well. What would be the correct way to do this query?
mysql sql
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
asked Jan 1 at 3:53
David LDavid L
25916
Please add sample data to your question.
– Tim Biegeleisen
Jan 1 at 4:00
What does 'doesn't work well' exactly mean?
– Quasimodo's clone
Jan 1 at 4:12
@Quasimodo'sclone It returns rows which correspond to a single name containing a comma.
– duskwuff
Jan 1 at 4:14
Then there's already a correct answer+comment if you are looking for more than one distinct names having the same master_id.
– Quasimodo's clone
Jan 1 at 4:17
@TimBiegeleisen I think you've given the correct answer in your comment below, just doing thehaving count(distinct name) > 1, if you want to put that in an answer I'll go ahead and accept it.
– David L
Jan 1 at 4:41
add a comment |
I'm having trouble with a very simple sql query. I want to identify all items that have more than one name. Here's what I'm currently doing:
select group_concat(distinct name) names
from table
group by master_id
having names like '%,%'
Unfortunately, a lot of names have a , in it, so the above doesn't work well. What would be the correct way to do this query?
mysql sql
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
asked Jan 1 at 3:53
David LDavid L
25916
I'm having trouble with a very simple sql query. I want to identify all items that have more than one name. Here's what I'm currently doing:
select group_concat(distinct name) names
from table
group by master_id
having names like '%,%'
Unfortunately, a lot of names have a , in it, so the above doesn't work well. What would be the correct way to do this query?
mysql sql
mysql sql
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
asked Jan 1 at 3:53
David LDavid L
25916
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
asked Jan 1 at 3:53
David LDavid L
25916
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
edited Jan 1 at 4:47
Tim Biegeleisen
226k1392145
226k1392145
asked Jan 1 at 3:53
David LDavid L
25916
asked Jan 1 at 3:53
David LDavid L
25916
asked Jan 1 at 3:53
David LDavid L
25916
25916
Please add sample data to your question.
– Tim Biegeleisen
Jan 1 at 4:00
What does 'doesn't work well' exactly mean?
– Quasimodo's clone
Jan 1 at 4:12
@Quasimodo'sclone It returns rows which correspond to a single name containing a comma.
– duskwuff
Jan 1 at 4:14
Then there's already a correct answer+comment if you are looking for more than one distinct names having the same master_id.
– Quasimodo's clone
Jan 1 at 4:17
@TimBiegeleisen I think you've given the correct answer in your comment below, just doing thehaving count(distinct name) > 1, if you want to put that in an answer I'll go ahead and accept it.
– David L
Jan 1 at 4:41
add a comment |
Please add sample data to your question.
– Tim Biegeleisen
Jan 1 at 4:00
What does 'doesn't work well' exactly mean?
– Quasimodo's clone
Jan 1 at 4:12
@Quasimodo'sclone It returns rows which correspond to a single name containing a comma.
– duskwuff
Jan 1 at 4:14
Then there's already a correct answer+comment if you are looking for more than one distinct names having the same master_id.
– Quasimodo's clone
Jan 1 at 4:17
@TimBiegeleisen I think you've given the correct answer in your comment below, just doing thehaving count(distinct name) > 1, if you want to put that in an answer I'll go ahead and accept it.
– David L
Jan 1 at 4:41
Please add sample data to your question.
– Tim Biegeleisen
Jan 1 at 4:00
Please add sample data to your question.
– Tim Biegeleisen
Jan 1 at 4:00
What does 'doesn't work well' exactly mean?
– Quasimodo's clone
Jan 1 at 4:12
What does 'doesn't work well' exactly mean?
– Quasimodo's clone
Jan 1 at 4:12
@Quasimodo'sclone It returns rows which correspond to a single name containing a comma.
– duskwuff
Jan 1 at 4:14
@Quasimodo'sclone It returns rows which correspond to a single name containing a comma.
– duskwuff
Jan 1 at 4:14
Then there's already a correct answer+comment if you are looking for more than one distinct names having the same master_id.
– Quasimodo's clone
Jan 1 at 4:17
Then there's already a correct answer+comment if you are looking for more than one distinct names having the same master_id.
– Quasimodo's clone
Jan 1 at 4:17
@TimBiegeleisen I think you've given the correct answer in your comment below, just doing the
having count(distinct name) > 1, if you want to put that in an answer I'll go ahead and accept it.– David L
Jan 1 at 4:41
@TimBiegeleisen I think you've given the correct answer in your comment below, just doing the
having count(distinct name) > 1, if you want to put that in an answer I'll go ahead and accept it.– David L
Jan 1 at 4:41
add a comment |
2 Answers
2
active
oldest
votes
Here is a correct version of your query:
SELECT
master_id,
GROUP_CONCAT(DISTINCT name) names
FROM yourTable
GROUP BY master_id
HAVING COUNT(DISTINCT name) > 1;
The reason we need to count distinct in the HAVING clause is that a logical item in the aggregated string is a distinct name.
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
add a comment |
The correct solution would be:
… HAVING COUNT(name) > 1
In a query using GROUP BY, aggregate functions like COUNT(), MIN(), and MAX() (as well as GROUP_CONCAT(), as well as a few others) can be used to operate on all values of a column in the grouped rows.
You could also include COUNT(name) in the columns to return the number of names for the master_id.
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
2
It should beHAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.
– Tim Biegeleisen
Jan 1 at 4:01
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here is a correct version of your query:
SELECT
master_id,
GROUP_CONCAT(DISTINCT name) names
FROM yourTable
GROUP BY master_id
HAVING COUNT(DISTINCT name) > 1;
The reason we need to count distinct in the HAVING clause is that a logical item in the aggregated string is a distinct name.
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
add a comment |
Here is a correct version of your query:
SELECT
master_id,
GROUP_CONCAT(DISTINCT name) names
FROM yourTable
GROUP BY master_id
HAVING COUNT(DISTINCT name) > 1;
The reason we need to count distinct in the HAVING clause is that a logical item in the aggregated string is a distinct name.
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
add a comment |
Here is a correct version of your query:
SELECT
master_id,
GROUP_CONCAT(DISTINCT name) names
FROM yourTable
GROUP BY master_id
HAVING COUNT(DISTINCT name) > 1;
The reason we need to count distinct in the HAVING clause is that a logical item in the aggregated string is a distinct name.
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
Here is a correct version of your query:
SELECT
master_id,
GROUP_CONCAT(DISTINCT name) names
FROM yourTable
GROUP BY master_id
HAVING COUNT(DISTINCT name) > 1;
The reason we need to count distinct in the HAVING clause is that a logical item in the aggregated string is a distinct name.
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
edited Jan 1 at 4:47
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
answered Jan 1 at 4:46
Tim BiegeleisenTim Biegeleisen
226k1392145
226k1392145
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
add a comment |
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
looks good, thank you for the solution.
– David L
Jan 1 at 4:46
add a comment |
The correct solution would be:
… HAVING COUNT(name) > 1
In a query using GROUP BY, aggregate functions like COUNT(), MIN(), and MAX() (as well as GROUP_CONCAT(), as well as a few others) can be used to operate on all values of a column in the grouped rows.
You could also include COUNT(name) in the columns to return the number of names for the master_id.
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
2
It should beHAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.
– Tim Biegeleisen
Jan 1 at 4:01
add a comment |
The correct solution would be:
… HAVING COUNT(name) > 1
In a query using GROUP BY, aggregate functions like COUNT(), MIN(), and MAX() (as well as GROUP_CONCAT(), as well as a few others) can be used to operate on all values of a column in the grouped rows.
You could also include COUNT(name) in the columns to return the number of names for the master_id.
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
2
It should beHAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.
– Tim Biegeleisen
Jan 1 at 4:01
add a comment |
The correct solution would be:
… HAVING COUNT(name) > 1
In a query using GROUP BY, aggregate functions like COUNT(), MIN(), and MAX() (as well as GROUP_CONCAT(), as well as a few others) can be used to operate on all values of a column in the grouped rows.
You could also include COUNT(name) in the columns to return the number of names for the master_id.
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
The correct solution would be:
… HAVING COUNT(name) > 1
In a query using GROUP BY, aggregate functions like COUNT(), MIN(), and MAX() (as well as GROUP_CONCAT(), as well as a few others) can be used to operate on all values of a column in the grouped rows.
You could also include COUNT(name) in the columns to return the number of names for the master_id.
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
answered Jan 1 at 3:57
duskwuffduskwuff
148k19177234
148k19177234
2
It should beHAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.
– Tim Biegeleisen
Jan 1 at 4:01
add a comment |
2
It should beHAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.
– Tim Biegeleisen
Jan 1 at 4:01
2
2
It should be
HAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.– Tim Biegeleisen
Jan 1 at 4:01
It should be
HAVING COUNT(DISTINCT name), but let's see the data the OP might add to the question.– Tim Biegeleisen
Jan 1 at 4:01
add a comment |
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Please add sample data to your question.
– Tim Biegeleisen
Jan 1 at 4:00
What does 'doesn't work well' exactly mean?
– Quasimodo's clone
Jan 1 at 4:12
@Quasimodo'sclone It returns rows which correspond to a single name containing a comma.
– duskwuff
Jan 1 at 4:14
Then there's already a correct answer+comment if you are looking for more than one distinct names having the same master_id.
– Quasimodo's clone
Jan 1 at 4:17
@TimBiegeleisen I think you've given the correct answer in your comment below, just doing the
having count(distinct name) > 1, if you want to put that in an answer I'll go ahead and accept it.– David L
Jan 1 at 4:41