The division of a city in terms of the driving distance to two places.
For a research project I would like to divide the travel times within a city between two places. Specifically: It is about the question in which of two hospitals an ambulance within the city limits of Munich, Germany should drive best, i.e. what has the shortest travel time. Is there a way to calculate this? I have to say that I am a doctor and unfortunately have no programming knowledge. So I need a lot of support ;-) Many thanks already
routing traffic-simulation
asked 1 hour ago
Benjamin Friedrich
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For a research project I would like to divide the travel times within a city between two places. Specifically: It is about the question in which of two hospitals an ambulance within the city limits of Munich, Germany should drive best, i.e. what has the shortest travel time. Is there a way to calculate this? I have to say that I am a doctor and unfortunately have no programming knowledge. So I need a lot of support ;-) Many thanks already
routing traffic-simulation
asked 1 hour ago
Benjamin Friedrich
1
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
For a research project I would like to divide the travel times within a city between two places. Specifically: It is about the question in which of two hospitals an ambulance within the city limits of Munich, Germany should drive best, i.e. what has the shortest travel time. Is there a way to calculate this? I have to say that I am a doctor and unfortunately have no programming knowledge. So I need a lot of support ;-) Many thanks already
routing traffic-simulation
asked 1 hour ago
Benjamin Friedrich
1
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
For a research project I would like to divide the travel times within a city between two places. Specifically: It is about the question in which of two hospitals an ambulance within the city limits of Munich, Germany should drive best, i.e. what has the shortest travel time. Is there a way to calculate this? I have to say that I am a doctor and unfortunately have no programming knowledge. So I need a lot of support ;-) Many thanks already
routing traffic-simulation
routing traffic-simulation
asked 1 hour ago
Benjamin Friedrich
1
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Benjamin Friedrich
1
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Benjamin Friedrich
1
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
Benjamin Friedrich
1
asked 1 hour ago
Benjamin Friedrich
1
1
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Benjamin Friedrich is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
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The best and the easiest way i can suggest is you can calculate the Arial distance between source and destination using Latitude and longitude and which ever is short you can take that in consideration. Because to determine the minimum time there are loads of dimension facts are involved. eg. Number of traffic,Is any short curt available, Road conditions, Avg. vehicle moving speed etc.
Sample code in JAVASCRIPT
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
i am attaching alink from where you can get the details.
link1
Link2
answered 1 hour ago
smn_onrocks
1,05411024
add a comment |
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1 Answer
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1 Answer
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oldest
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The best and the easiest way i can suggest is you can calculate the Arial distance between source and destination using Latitude and longitude and which ever is short you can take that in consideration. Because to determine the minimum time there are loads of dimension facts are involved. eg. Number of traffic,Is any short curt available, Road conditions, Avg. vehicle moving speed etc.
Sample code in JAVASCRIPT
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
i am attaching alink from where you can get the details.
link1
Link2
answered 1 hour ago
smn_onrocks
1,05411024
add a comment |
The best and the easiest way i can suggest is you can calculate the Arial distance between source and destination using Latitude and longitude and which ever is short you can take that in consideration. Because to determine the minimum time there are loads of dimension facts are involved. eg. Number of traffic,Is any short curt available, Road conditions, Avg. vehicle moving speed etc.
Sample code in JAVASCRIPT
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
i am attaching alink from where you can get the details.
link1
Link2
answered 1 hour ago
smn_onrocks
1,05411024
add a comment |
The best and the easiest way i can suggest is you can calculate the Arial distance between source and destination using Latitude and longitude and which ever is short you can take that in consideration. Because to determine the minimum time there are loads of dimension facts are involved. eg. Number of traffic,Is any short curt available, Road conditions, Avg. vehicle moving speed etc.
Sample code in JAVASCRIPT
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
i am attaching alink from where you can get the details.
link1
Link2
answered 1 hour ago
smn_onrocks
1,05411024
The best and the easiest way i can suggest is you can calculate the Arial distance between source and destination using Latitude and longitude and which ever is short you can take that in consideration. Because to determine the minimum time there are loads of dimension facts are involved. eg. Number of traffic,Is any short curt available, Road conditions, Avg. vehicle moving speed etc.
Sample code in JAVASCRIPT
function getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a =
Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2)
;
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
i am attaching alink from where you can get the details.
link1
Link2
answered 1 hour ago
smn_onrocks
1,05411024
answered 1 hour ago
smn_onrocks
1,05411024
answered 1 hour ago
smn_onrocks
1,05411024
answered 1 hour ago
smn_onrocks
1,05411024
1,05411024
add a comment |
add a comment |
Benjamin Friedrich is a new contributor. Be nice, and check out our Code of Conduct.
Benjamin Friedrich is a new contributor. Be nice, and check out our Code of Conduct.
Benjamin Friedrich is a new contributor. Be nice, and check out our Code of Conduct.
Benjamin Friedrich is a new contributor. Be nice, and check out our Code of Conduct.
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