$match stage is not giving any output in MongoDB aggregation
2
I need to print the documents with more than the average of one field in the same collection.
In the aggregation pipeline, I am not getting the avg_pmnt parameter available to $match stage (next stage)
For the following code
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
])
I am getting the following output:
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14191 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 32642 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 33348 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 45864 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 82261 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 7565 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 44895 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 19502 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 47924 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 49524 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 50219 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 1491 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 17876 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 34638 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 101245 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 85411 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 11044 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 83598 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 6067 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14571 }
Type "it" for more
But I want to filter them
so, I tried this:
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: "$avg_pmnt"} }}
])
For which I am not getting any documents (empty set).
I also tried
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: 1} }}
])
for which I am getting all the documents as the condition satisfies for every document.
mongodb aggregation-framework
edited 19 hours ago
mickl
11.4k51535
asked 19 hours ago
Anjan Kailash
287
add a comment |
2
I need to print the documents with more than the average of one field in the same collection.
In the aggregation pipeline, I am not getting the avg_pmnt parameter available to $match stage (next stage)
For the following code
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
])
I am getting the following output:
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14191 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 32642 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 33348 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 45864 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 82261 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 7565 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 44895 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 19502 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 47924 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 49524 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 50219 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 1491 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 17876 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 34638 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 101245 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 85411 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 11044 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 83598 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 6067 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14571 }
Type "it" for more
But I want to filter them
so, I tried this:
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: "$avg_pmnt"} }}
])
For which I am not getting any documents (empty set).
I also tried
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: 1} }}
])
for which I am getting all the documents as the condition satisfies for every document.
mongodb aggregation-framework
edited 19 hours ago
mickl
11.4k51535
asked 19 hours ago
Anjan Kailash
287
add a comment |
2
2
2
I need to print the documents with more than the average of one field in the same collection.
In the aggregation pipeline, I am not getting the avg_pmnt parameter available to $match stage (next stage)
For the following code
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
])
I am getting the following output:
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14191 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 32642 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 33348 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 45864 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 82261 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 7565 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 44895 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 19502 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 47924 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 49524 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 50219 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 1491 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 17876 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 34638 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 101245 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 85411 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 11044 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 83598 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 6067 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14571 }
Type "it" for more
But I want to filter them
so, I tried this:
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: "$avg_pmnt"} }}
])
For which I am not getting any documents (empty set).
I also tried
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: 1} }}
])
for which I am getting all the documents as the condition satisfies for every document.
mongodb aggregation-framework
edited 19 hours ago
mickl
11.4k51535
asked 19 hours ago
Anjan Kailash
287
I need to print the documents with more than the average of one field in the same collection.
In the aggregation pipeline, I am not getting the avg_pmnt parameter available to $match stage (next stage)
For the following code
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
])
I am getting the following output:
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14191 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 32642 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 33348 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 45864 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 82261 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 7565 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 44895 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 19502 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 47924 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 49524 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 50219 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 1491 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 17876 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 34638 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 101245 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 85411 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 11044 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 83598 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 6067 }
{ "_id" : 1, "avg_pmnt" : 32431.65567765568, "AMNT" : 14571 }
Type "it" for more
But I want to filter them
so, I tried this:
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: "$avg_pmnt"} }}
])
For which I am not getting any documents (empty set).
I also tried
db.payments.aggregate([
{$group: {
"_id":1,
"avg_pmnt": {$avg: "$AMOUNT"},
"AMNT": {$push: "$AMOUNT"}
} },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: {AMNT: {$gt: 1} }}
])
for which I am getting all the documents as the condition satisfies for every document.
mongodb aggregation-framework
mongodb aggregation-framework
edited 19 hours ago
mickl
11.4k51535
asked 19 hours ago
Anjan Kailash
287
edited 19 hours ago
mickl
11.4k51535
asked 19 hours ago
Anjan Kailash
287
edited 19 hours ago
mickl
11.4k51535
edited 19 hours ago
mickl
11.4k51535
edited 19 hours ago
mickl
11.4k51535
11.4k51535
asked 19 hours ago
Anjan Kailash
287
asked 19 hours ago
Anjan Kailash
287
asked 19 hours ago
Anjan Kailash
287
287
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
you can also use $redact to compare within the same document fields and filter the documents
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$redact :{$cond : [{$gt: ["$AMNT", "$avg_pmnt" ]},"$$DESCEND","$$PRUNE"]}}
])
answered 13 hours ago
Saravana
7,53421633
add a comment |
2
You should use $expr as you're trying to compare two fields inside of $match stage
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: { $expr: { $gt: [ "$AMNT", "$avg_pmnt" ] } } }
])
answered 19 hours ago
mickl
11.4k51535
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
you can also use $redact to compare within the same document fields and filter the documents
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$redact :{$cond : [{$gt: ["$AMNT", "$avg_pmnt" ]},"$$DESCEND","$$PRUNE"]}}
])
answered 13 hours ago
Saravana
7,53421633
add a comment |
1
you can also use $redact to compare within the same document fields and filter the documents
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$redact :{$cond : [{$gt: ["$AMNT", "$avg_pmnt" ]},"$$DESCEND","$$PRUNE"]}}
])
answered 13 hours ago
Saravana
7,53421633
add a comment |
1
1
1
you can also use $redact to compare within the same document fields and filter the documents
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$redact :{$cond : [{$gt: ["$AMNT", "$avg_pmnt" ]},"$$DESCEND","$$PRUNE"]}}
])
answered 13 hours ago
Saravana
7,53421633
you can also use $redact to compare within the same document fields and filter the documents
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$redact :{$cond : [{$gt: ["$AMNT", "$avg_pmnt" ]},"$$DESCEND","$$PRUNE"]}}
])
answered 13 hours ago
Saravana
7,53421633
answered 13 hours ago
Saravana
7,53421633
answered 13 hours ago
Saravana
7,53421633
answered 13 hours ago
Saravana
7,53421633
7,53421633
add a comment |
add a comment |
2
You should use $expr as you're trying to compare two fields inside of $match stage
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: { $expr: { $gt: [ "$AMNT", "$avg_pmnt" ] } } }
])
answered 19 hours ago
mickl
11.4k51535
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
add a comment |
2
You should use $expr as you're trying to compare two fields inside of $match stage
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: { $expr: { $gt: [ "$AMNT", "$avg_pmnt" ] } } }
])
answered 19 hours ago
mickl
11.4k51535
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
add a comment |
2
2
2
You should use $expr as you're trying to compare two fields inside of $match stage
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: { $expr: { $gt: [ "$AMNT", "$avg_pmnt" ] } } }
])
answered 19 hours ago
mickl
11.4k51535
You should use $expr as you're trying to compare two fields inside of $match stage
db.payments.aggregate([
{$group: { "_id":1, "avg_pmnt": {$avg: "$AMOUNT"}, "AMNT": {$push: "$AMOUNT"} } },
{$unwind: "$AMNT"},
{$project: {avg_pmnt: "$avg_pmnt", AMNT: "$AMNT"}},
{$match: { $expr: { $gt: [ "$AMNT", "$avg_pmnt" ] } } }
])
answered 19 hours ago
mickl
11.4k51535
answered 19 hours ago
mickl
11.4k51535
answered 19 hours ago
mickl
11.4k51535
answered 19 hours ago
mickl
11.4k51535
11.4k51535
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
add a comment |
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
Thank you. Actually, I am new to MongoDB.
– Anjan Kailash
19 hours ago
add a comment |
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