how to give a custom celery state when it retries
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I have the following celery task and I wanted know how the change the default status when the task retries. I am aware to change the state you would normally give the following line self.update_state(state='MY CUSTOM STATE') however there seems to be something different when the code retries. In the end I would like to change the retry state from RETRY to WAITING.
LOCK_EXPIRE = 60 * 2 # Lock expires in 2 minutes
@contextmanager
def memcache_lock(lock_id, oid):
timeout_at = monotonic() + LOCK_EXPIRE - 3
print('in memcache_lock and timeout_at is {}'.format(timeout_at))
# cache.add fails if the key already exists
status = cache.add(lock_id, oid, LOCK_EXPIRE)
try:
yield status
print('memcache_lock and status is {}'.format(status))
finally:
# memcache delete is very slow, but we have to use it to take
# advantage of using add() for atomic locking
if monotonic() < timeout_at and status:
# don't release the lock if we exceeded the timeout
# to lessen the chance of releasing an expired lock
# owned by someone else
# also don't release the lock if we didn't acquire it
cache.delete(lock_id)
@celery.task(bind=True, name='app.myTask1')
def myTask1(self):
self.update_state(state='IN TASK')
print('dir is {} '.format(dir(self)))
lock_id = self.name
print('lock_id is {}'.format(lock_id))
with memcache_lock(lock_id, self.app.oid) as acquired:
print('in memcache_lock and lock_id is {} self.app.oid is {} and acquired is {}'.format(lock_id, self.app.oid, acquired))
if acquired:
# do work if we got the lock
print('acquired is {}'.format(acquired))
self.update_state(state='DOING WORK')
time.sleep(90)
return 'result'
# otherwise, the lock was already in use
raise self.retry(countdown=60) # redeliver message to the queue, so the work can be done later
python celery django-celery celery-task
asked Jan 4 at 2:42
MattMatt
3082625
add a comment |
0
I have the following celery task and I wanted know how the change the default status when the task retries. I am aware to change the state you would normally give the following line self.update_state(state='MY CUSTOM STATE') however there seems to be something different when the code retries. In the end I would like to change the retry state from RETRY to WAITING.
LOCK_EXPIRE = 60 * 2 # Lock expires in 2 minutes
@contextmanager
def memcache_lock(lock_id, oid):
timeout_at = monotonic() + LOCK_EXPIRE - 3
print('in memcache_lock and timeout_at is {}'.format(timeout_at))
# cache.add fails if the key already exists
status = cache.add(lock_id, oid, LOCK_EXPIRE)
try:
yield status
print('memcache_lock and status is {}'.format(status))
finally:
# memcache delete is very slow, but we have to use it to take
# advantage of using add() for atomic locking
if monotonic() < timeout_at and status:
# don't release the lock if we exceeded the timeout
# to lessen the chance of releasing an expired lock
# owned by someone else
# also don't release the lock if we didn't acquire it
cache.delete(lock_id)
@celery.task(bind=True, name='app.myTask1')
def myTask1(self):
self.update_state(state='IN TASK')
print('dir is {} '.format(dir(self)))
lock_id = self.name
print('lock_id is {}'.format(lock_id))
with memcache_lock(lock_id, self.app.oid) as acquired:
print('in memcache_lock and lock_id is {} self.app.oid is {} and acquired is {}'.format(lock_id, self.app.oid, acquired))
if acquired:
# do work if we got the lock
print('acquired is {}'.format(acquired))
self.update_state(state='DOING WORK')
time.sleep(90)
return 'result'
# otherwise, the lock was already in use
raise self.retry(countdown=60) # redeliver message to the queue, so the work can be done later
python celery django-celery celery-task
asked Jan 4 at 2:42
MattMatt
3082625
add a comment |
0
0
0
I have the following celery task and I wanted know how the change the default status when the task retries. I am aware to change the state you would normally give the following line self.update_state(state='MY CUSTOM STATE') however there seems to be something different when the code retries. In the end I would like to change the retry state from RETRY to WAITING.
LOCK_EXPIRE = 60 * 2 # Lock expires in 2 minutes
@contextmanager
def memcache_lock(lock_id, oid):
timeout_at = monotonic() + LOCK_EXPIRE - 3
print('in memcache_lock and timeout_at is {}'.format(timeout_at))
# cache.add fails if the key already exists
status = cache.add(lock_id, oid, LOCK_EXPIRE)
try:
yield status
print('memcache_lock and status is {}'.format(status))
finally:
# memcache delete is very slow, but we have to use it to take
# advantage of using add() for atomic locking
if monotonic() < timeout_at and status:
# don't release the lock if we exceeded the timeout
# to lessen the chance of releasing an expired lock
# owned by someone else
# also don't release the lock if we didn't acquire it
cache.delete(lock_id)
@celery.task(bind=True, name='app.myTask1')
def myTask1(self):
self.update_state(state='IN TASK')
print('dir is {} '.format(dir(self)))
lock_id = self.name
print('lock_id is {}'.format(lock_id))
with memcache_lock(lock_id, self.app.oid) as acquired:
print('in memcache_lock and lock_id is {} self.app.oid is {} and acquired is {}'.format(lock_id, self.app.oid, acquired))
if acquired:
# do work if we got the lock
print('acquired is {}'.format(acquired))
self.update_state(state='DOING WORK')
time.sleep(90)
return 'result'
# otherwise, the lock was already in use
raise self.retry(countdown=60) # redeliver message to the queue, so the work can be done later
python celery django-celery celery-task
asked Jan 4 at 2:42
MattMatt
3082625
I have the following celery task and I wanted know how the change the default status when the task retries. I am aware to change the state you would normally give the following line self.update_state(state='MY CUSTOM STATE') however there seems to be something different when the code retries. In the end I would like to change the retry state from RETRY to WAITING.
LOCK_EXPIRE = 60 * 2 # Lock expires in 2 minutes
@contextmanager
def memcache_lock(lock_id, oid):
timeout_at = monotonic() + LOCK_EXPIRE - 3
print('in memcache_lock and timeout_at is {}'.format(timeout_at))
# cache.add fails if the key already exists
status = cache.add(lock_id, oid, LOCK_EXPIRE)
try:
yield status
print('memcache_lock and status is {}'.format(status))
finally:
# memcache delete is very slow, but we have to use it to take
# advantage of using add() for atomic locking
if monotonic() < timeout_at and status:
# don't release the lock if we exceeded the timeout
# to lessen the chance of releasing an expired lock
# owned by someone else
# also don't release the lock if we didn't acquire it
cache.delete(lock_id)
@celery.task(bind=True, name='app.myTask1')
def myTask1(self):
self.update_state(state='IN TASK')
print('dir is {} '.format(dir(self)))
lock_id = self.name
print('lock_id is {}'.format(lock_id))
with memcache_lock(lock_id, self.app.oid) as acquired:
print('in memcache_lock and lock_id is {} self.app.oid is {} and acquired is {}'.format(lock_id, self.app.oid, acquired))
if acquired:
# do work if we got the lock
print('acquired is {}'.format(acquired))
self.update_state(state='DOING WORK')
time.sleep(90)
return 'result'
# otherwise, the lock was already in use
raise self.retry(countdown=60) # redeliver message to the queue, so the work can be done later
python celery django-celery celery-task
python celery django-celery celery-task
asked Jan 4 at 2:42
MattMatt
3082625
asked Jan 4 at 2:42
MattMatt
3082625
asked Jan 4 at 2:42
MattMatt
3082625
asked Jan 4 at 2:42
MattMatt
3082625
asked Jan 4 at 2:42
MattMatt
3082625
3082625
add a comment |
add a comment |
0
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