rlocus() - Not enough input arguments in MATLAB 2018a












0














I am following this tutorial on root locus methods and when writing:



syms s
sys = 1/(3*s^2 + 2*s - 1);
rlocus(sys)


I get:




Error using rlocus

Not enough input arguments.




Why is rlocus expecting more input arguments when the documentation states that one input argument is enough?






rlocus(SYS) computes and plots the root locus of the single-input,
single-output LTI model SYS. The root locus plot is used to analyze
the negative feedback loop




Syntax for rlocus:



rlocus(sys)
rlocus(sys1,sys2,...)
[r,k] = rlocus(sys)
r = rlocus(sys,k)









share|improve this question






















  • Did you re-define the function? Type which rlocus and see if the result is a function within the MATLAB toolbox.
    – Cris Luengo
    Dec 27 at 14:31










  • Thanks for your comment. No I did not re-define the function - ...Program FilesMATLABR2018atoolboxcontrolctrlobsoleterlocus.m. Strangely it is in the obsolete folder.
    – Rrz0
    Dec 27 at 14:33










  • Strange indeed. Does which rlocus(sys) return the same thing?
    – Cris Luengo
    Dec 27 at 14:42










  • The documentation link is likely a method of a transfer function object. It may not support symbolic functions. Your call might have reached the obsolete rlocus function which might have operated differently and expects more inputs.
    – Navan
    Dec 27 at 14:52










  • @CrisLuengo, yes it does.
    – Rrz0
    Dec 27 at 14:52
















0














I am following this tutorial on root locus methods and when writing:



syms s
sys = 1/(3*s^2 + 2*s - 1);
rlocus(sys)


I get:




Error using rlocus

Not enough input arguments.




Why is rlocus expecting more input arguments when the documentation states that one input argument is enough?






rlocus(SYS) computes and plots the root locus of the single-input,
single-output LTI model SYS. The root locus plot is used to analyze
the negative feedback loop




Syntax for rlocus:



rlocus(sys)
rlocus(sys1,sys2,...)
[r,k] = rlocus(sys)
r = rlocus(sys,k)









share|improve this question






















  • Did you re-define the function? Type which rlocus and see if the result is a function within the MATLAB toolbox.
    – Cris Luengo
    Dec 27 at 14:31










  • Thanks for your comment. No I did not re-define the function - ...Program FilesMATLABR2018atoolboxcontrolctrlobsoleterlocus.m. Strangely it is in the obsolete folder.
    – Rrz0
    Dec 27 at 14:33










  • Strange indeed. Does which rlocus(sys) return the same thing?
    – Cris Luengo
    Dec 27 at 14:42










  • The documentation link is likely a method of a transfer function object. It may not support symbolic functions. Your call might have reached the obsolete rlocus function which might have operated differently and expects more inputs.
    – Navan
    Dec 27 at 14:52










  • @CrisLuengo, yes it does.
    – Rrz0
    Dec 27 at 14:52














0












0








0







I am following this tutorial on root locus methods and when writing:



syms s
sys = 1/(3*s^2 + 2*s - 1);
rlocus(sys)


I get:




Error using rlocus

Not enough input arguments.




Why is rlocus expecting more input arguments when the documentation states that one input argument is enough?






rlocus(SYS) computes and plots the root locus of the single-input,
single-output LTI model SYS. The root locus plot is used to analyze
the negative feedback loop




Syntax for rlocus:



rlocus(sys)
rlocus(sys1,sys2,...)
[r,k] = rlocus(sys)
r = rlocus(sys,k)









share|improve this question













I am following this tutorial on root locus methods and when writing:



syms s
sys = 1/(3*s^2 + 2*s - 1);
rlocus(sys)


I get:




Error using rlocus

Not enough input arguments.




Why is rlocus expecting more input arguments when the documentation states that one input argument is enough?






rlocus(SYS) computes and plots the root locus of the single-input,
single-output LTI model SYS. The root locus plot is used to analyze
the negative feedback loop




Syntax for rlocus:



rlocus(sys)
rlocus(sys1,sys2,...)
[r,k] = rlocus(sys)
r = rlocus(sys,k)






matlab






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 27 at 14:19









Rrz0

485518




485518












  • Did you re-define the function? Type which rlocus and see if the result is a function within the MATLAB toolbox.
    – Cris Luengo
    Dec 27 at 14:31










  • Thanks for your comment. No I did not re-define the function - ...Program FilesMATLABR2018atoolboxcontrolctrlobsoleterlocus.m. Strangely it is in the obsolete folder.
    – Rrz0
    Dec 27 at 14:33










  • Strange indeed. Does which rlocus(sys) return the same thing?
    – Cris Luengo
    Dec 27 at 14:42










  • The documentation link is likely a method of a transfer function object. It may not support symbolic functions. Your call might have reached the obsolete rlocus function which might have operated differently and expects more inputs.
    – Navan
    Dec 27 at 14:52










  • @CrisLuengo, yes it does.
    – Rrz0
    Dec 27 at 14:52


















  • Did you re-define the function? Type which rlocus and see if the result is a function within the MATLAB toolbox.
    – Cris Luengo
    Dec 27 at 14:31










  • Thanks for your comment. No I did not re-define the function - ...Program FilesMATLABR2018atoolboxcontrolctrlobsoleterlocus.m. Strangely it is in the obsolete folder.
    – Rrz0
    Dec 27 at 14:33










  • Strange indeed. Does which rlocus(sys) return the same thing?
    – Cris Luengo
    Dec 27 at 14:42










  • The documentation link is likely a method of a transfer function object. It may not support symbolic functions. Your call might have reached the obsolete rlocus function which might have operated differently and expects more inputs.
    – Navan
    Dec 27 at 14:52










  • @CrisLuengo, yes it does.
    – Rrz0
    Dec 27 at 14:52
















Did you re-define the function? Type which rlocus and see if the result is a function within the MATLAB toolbox.
– Cris Luengo
Dec 27 at 14:31




Did you re-define the function? Type which rlocus and see if the result is a function within the MATLAB toolbox.
– Cris Luengo
Dec 27 at 14:31












Thanks for your comment. No I did not re-define the function - ...Program FilesMATLABR2018atoolboxcontrolctrlobsoleterlocus.m. Strangely it is in the obsolete folder.
– Rrz0
Dec 27 at 14:33




Thanks for your comment. No I did not re-define the function - ...Program FilesMATLABR2018atoolboxcontrolctrlobsoleterlocus.m. Strangely it is in the obsolete folder.
– Rrz0
Dec 27 at 14:33












Strange indeed. Does which rlocus(sys) return the same thing?
– Cris Luengo
Dec 27 at 14:42




Strange indeed. Does which rlocus(sys) return the same thing?
– Cris Luengo
Dec 27 at 14:42












The documentation link is likely a method of a transfer function object. It may not support symbolic functions. Your call might have reached the obsolete rlocus function which might have operated differently and expects more inputs.
– Navan
Dec 27 at 14:52




The documentation link is likely a method of a transfer function object. It may not support symbolic functions. Your call might have reached the obsolete rlocus function which might have operated differently and expects more inputs.
– Navan
Dec 27 at 14:52












@CrisLuengo, yes it does.
– Rrz0
Dec 27 at 14:52




@CrisLuengo, yes it does.
– Rrz0
Dec 27 at 14:52












1 Answer
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You are supposed to input a transfer function to rlocus not a symbolic variable. The code you provided gave me the same error but this worked just fine



s=tf('s');
sys = 1/(3*s^2 + 2*s - 1);
rlocus(sys);





share|improve this answer





















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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You are supposed to input a transfer function to rlocus not a symbolic variable. The code you provided gave me the same error but this worked just fine



    s=tf('s');
    sys = 1/(3*s^2 + 2*s - 1);
    rlocus(sys);





    share|improve this answer


























      0














      You are supposed to input a transfer function to rlocus not a symbolic variable. The code you provided gave me the same error but this worked just fine



      s=tf('s');
      sys = 1/(3*s^2 + 2*s - 1);
      rlocus(sys);





      share|improve this answer
























        0












        0








        0






        You are supposed to input a transfer function to rlocus not a symbolic variable. The code you provided gave me the same error but this worked just fine



        s=tf('s');
        sys = 1/(3*s^2 + 2*s - 1);
        rlocus(sys);





        share|improve this answer












        You are supposed to input a transfer function to rlocus not a symbolic variable. The code you provided gave me the same error but this worked just fine



        s=tf('s');
        sys = 1/(3*s^2 + 2*s - 1);
        rlocus(sys);






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 27 at 17:54









        Nirvedh Meshram

        329112




        329112






























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