Getting Dict Value from same source at different times and comparing them
I am working on a ceph mgr plugin. I have a dict that I get from self.get('health'). The keys and values in the dict changes depending on the health of the system.
What I want to achieve is to write a function in python that gets the value of self.get('health') every 1 minute and compare it with the previous value i.e. oldDictValue compared to newDictValue where newDictValue is the dict value gotten after 1 minute.
oldDictValue and newDictValue are variables holding values from self.get('health') at different times.
python dictionary ceph
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
add a comment |
I am working on a ceph mgr plugin. I have a dict that I get from self.get('health'). The keys and values in the dict changes depending on the health of the system.
What I want to achieve is to write a function in python that gets the value of self.get('health') every 1 minute and compare it with the previous value i.e. oldDictValue compared to newDictValue where newDictValue is the dict value gotten after 1 minute.
oldDictValue and newDictValue are variables holding values from self.get('health') at different times.
python dictionary ceph
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
I think you can combine those two posts to solve your problem: interval timer and comparing 2 dictionaries
– Ha Bom
Dec 29 '18 at 9:01
@HaBom this [stackoverflow.com/questions/4527942/… will not quite work because the dict lenght will be different if there's a change in status
– Kate Longchi
Dec 29 '18 at 9:13
Yeah, there are so many ways to compare 2 dictionaries in that post, but they're just the ideas. Can you provide a sample of dictionaries?
– Ha Bom
Dec 29 '18 at 9:23
Can you put it in the question for easier understanding?
– Ha Bom
Dec 29 '18 at 9:25
add a comment |
I am working on a ceph mgr plugin. I have a dict that I get from self.get('health'). The keys and values in the dict changes depending on the health of the system.
What I want to achieve is to write a function in python that gets the value of self.get('health') every 1 minute and compare it with the previous value i.e. oldDictValue compared to newDictValue where newDictValue is the dict value gotten after 1 minute.
oldDictValue and newDictValue are variables holding values from self.get('health') at different times.
python dictionary ceph
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
I am working on a ceph mgr plugin. I have a dict that I get from self.get('health'). The keys and values in the dict changes depending on the health of the system.
What I want to achieve is to write a function in python that gets the value of self.get('health') every 1 minute and compare it with the previous value i.e. oldDictValue compared to newDictValue where newDictValue is the dict value gotten after 1 minute.
oldDictValue and newDictValue are variables holding values from self.get('health') at different times.
python dictionary ceph
python dictionary ceph
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
edited Dec 29 '18 at 12:47
Unhandled Exception
1,045159
1,045159
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
asked Dec 29 '18 at 8:54
Kate LongchiKate Longchi
11
11
I think you can combine those two posts to solve your problem: interval timer and comparing 2 dictionaries
– Ha Bom
Dec 29 '18 at 9:01
@HaBom this [stackoverflow.com/questions/4527942/… will not quite work because the dict lenght will be different if there's a change in status
– Kate Longchi
Dec 29 '18 at 9:13
Yeah, there are so many ways to compare 2 dictionaries in that post, but they're just the ideas. Can you provide a sample of dictionaries?
– Ha Bom
Dec 29 '18 at 9:23
Can you put it in the question for easier understanding?
– Ha Bom
Dec 29 '18 at 9:25
add a comment |
I think you can combine those two posts to solve your problem: interval timer and comparing 2 dictionaries
– Ha Bom
Dec 29 '18 at 9:01
@HaBom this [stackoverflow.com/questions/4527942/… will not quite work because the dict lenght will be different if there's a change in status
– Kate Longchi
Dec 29 '18 at 9:13
Yeah, there are so many ways to compare 2 dictionaries in that post, but they're just the ideas. Can you provide a sample of dictionaries?
– Ha Bom
Dec 29 '18 at 9:23
Can you put it in the question for easier understanding?
– Ha Bom
Dec 29 '18 at 9:25
I think you can combine those two posts to solve your problem: interval timer and comparing 2 dictionaries
– Ha Bom
Dec 29 '18 at 9:01
I think you can combine those two posts to solve your problem: interval timer and comparing 2 dictionaries
– Ha Bom
Dec 29 '18 at 9:01
@HaBom this [stackoverflow.com/questions/4527942/… will not quite work because the dict lenght will be different if there's a change in status
– Kate Longchi
Dec 29 '18 at 9:13
@HaBom this [stackoverflow.com/questions/4527942/… will not quite work because the dict lenght will be different if there's a change in status
– Kate Longchi
Dec 29 '18 at 9:13
Yeah, there are so many ways to compare 2 dictionaries in that post, but they're just the ideas. Can you provide a sample of dictionaries?
– Ha Bom
Dec 29 '18 at 9:23
Yeah, there are so many ways to compare 2 dictionaries in that post, but they're just the ideas. Can you provide a sample of dictionaries?
– Ha Bom
Dec 29 '18 at 9:23
Can you put it in the question for easier understanding?
– Ha Bom
Dec 29 '18 at 9:25
Can you put it in the question for easier understanding?
– Ha Bom
Dec 29 '18 at 9:25
add a comment |
1 Answer
1
active
oldest
votes
Here is a proposed pseudo code for what I wish to achieve. I am finding it difficult to covert this to a working solution
```
fun diff_health(old_health, new_health):
old = {}
new = {}
updated = {}
for code, item in new_health['checks'].iteritems():
if code not in old_health['checks']:
# it's a new alert
new[code] = item
else:
old_item = old_health['checks'][code]
if item['severity'] != old_item['severity'] or item['summary']['message'] != old_item['usmmary']['message']:
# changed
updated[code] = item
for code, item in old_health['checks'].iteritems():
if code not in new_health['checks']:
# health alert has resolved
...
return old, new, updated
```
new_health and old_health are values from self.get('heatth') at diffrent times
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here is a proposed pseudo code for what I wish to achieve. I am finding it difficult to covert this to a working solution
```
fun diff_health(old_health, new_health):
old = {}
new = {}
updated = {}
for code, item in new_health['checks'].iteritems():
if code not in old_health['checks']:
# it's a new alert
new[code] = item
else:
old_item = old_health['checks'][code]
if item['severity'] != old_item['severity'] or item['summary']['message'] != old_item['usmmary']['message']:
# changed
updated[code] = item
for code, item in old_health['checks'].iteritems():
if code not in new_health['checks']:
# health alert has resolved
...
return old, new, updated
```
new_health and old_health are values from self.get('heatth') at diffrent times
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
add a comment |
Here is a proposed pseudo code for what I wish to achieve. I am finding it difficult to covert this to a working solution
```
fun diff_health(old_health, new_health):
old = {}
new = {}
updated = {}
for code, item in new_health['checks'].iteritems():
if code not in old_health['checks']:
# it's a new alert
new[code] = item
else:
old_item = old_health['checks'][code]
if item['severity'] != old_item['severity'] or item['summary']['message'] != old_item['usmmary']['message']:
# changed
updated[code] = item
for code, item in old_health['checks'].iteritems():
if code not in new_health['checks']:
# health alert has resolved
...
return old, new, updated
```
new_health and old_health are values from self.get('heatth') at diffrent times
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
add a comment |
Here is a proposed pseudo code for what I wish to achieve. I am finding it difficult to covert this to a working solution
```
fun diff_health(old_health, new_health):
old = {}
new = {}
updated = {}
for code, item in new_health['checks'].iteritems():
if code not in old_health['checks']:
# it's a new alert
new[code] = item
else:
old_item = old_health['checks'][code]
if item['severity'] != old_item['severity'] or item['summary']['message'] != old_item['usmmary']['message']:
# changed
updated[code] = item
for code, item in old_health['checks'].iteritems():
if code not in new_health['checks']:
# health alert has resolved
...
return old, new, updated
```
new_health and old_health are values from self.get('heatth') at diffrent times
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
Here is a proposed pseudo code for what I wish to achieve. I am finding it difficult to covert this to a working solution
```
fun diff_health(old_health, new_health):
old = {}
new = {}
updated = {}
for code, item in new_health['checks'].iteritems():
if code not in old_health['checks']:
# it's a new alert
new[code] = item
else:
old_item = old_health['checks'][code]
if item['severity'] != old_item['severity'] or item['summary']['message'] != old_item['usmmary']['message']:
# changed
updated[code] = item
for code, item in old_health['checks'].iteritems():
if code not in new_health['checks']:
# health alert has resolved
...
return old, new, updated
```
new_health and old_health are values from self.get('heatth') at diffrent times
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
edited Dec 29 '18 at 9:40
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
answered Dec 29 '18 at 9:34
Kate LongchiKate Longchi
11
11
add a comment |
add a comment |
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I think you can combine those two posts to solve your problem: interval timer and comparing 2 dictionaries
– Ha Bom
Dec 29 '18 at 9:01
@HaBom this [stackoverflow.com/questions/4527942/… will not quite work because the dict lenght will be different if there's a change in status
– Kate Longchi
Dec 29 '18 at 9:13
Yeah, there are so many ways to compare 2 dictionaries in that post, but they're just the ideas. Can you provide a sample of dictionaries?
– Ha Bom
Dec 29 '18 at 9:23
Can you put it in the question for easier understanding?
– Ha Bom
Dec 29 '18 at 9:25