How to compare occurences in the same list of tuples
3
I have a list of tuples like this one:
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
Some of the tuples are having exactly the same numbers but in different order. I want to count the occurrences of the tuples and overwrite the ones that have the same values inside. I read several answers in here and I managed to do something using the Counter method. But what I tried doesn't seem to work for me. I am new at python so maybe I don't understand the exact use of Counter method.
L1 = Counter()
for item in L:
for element in item:
if element in item:
L1[tuple(item)] = L1[tuple(item)] + 1
print(L1)
The result I get is:
Counter({(23, 56, 48): 3, (48, 93, 81): 3, (48, 56, 23): 3, (54, 34, 21): 3,
(48, 98, 71): 3, (98, 71, 48): 3, (56, 23, 48): 3})
And the result I want to get is:
Counter({(23, 56, 48): 3, (48, 98, 71): 3, (48, 93, 81): 1, (54, 34, 21): 1})
python list dictionary tuples counter
edited Jan 2 at 13:41
Miraj50
2,7801925
asked Jan 2 at 13:26
immaleeimmalee
225
|
show 1 more comment
3
I have a list of tuples like this one:
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
Some of the tuples are having exactly the same numbers but in different order. I want to count the occurrences of the tuples and overwrite the ones that have the same values inside. I read several answers in here and I managed to do something using the Counter method. But what I tried doesn't seem to work for me. I am new at python so maybe I don't understand the exact use of Counter method.
L1 = Counter()
for item in L:
for element in item:
if element in item:
L1[tuple(item)] = L1[tuple(item)] + 1
print(L1)
The result I get is:
Counter({(23, 56, 48): 3, (48, 93, 81): 3, (48, 56, 23): 3, (54, 34, 21): 3,
(48, 98, 71): 3, (98, 71, 48): 3, (56, 23, 48): 3})
And the result I want to get is:
Counter({(23, 56, 48): 3, (48, 98, 71): 3, (48, 93, 81): 1, (54, 34, 21): 1})
python list dictionary tuples counter
edited Jan 2 at 13:41
Miraj50
2,7801925
asked Jan 2 at 13:26
immaleeimmalee
225
What does "overwrite the ones that have the same values inside" mean?
– DeepSpace
Jan 2 at 13:27
Maybe I cant explain it well, see the actual and the expected results for help, The tuples that contain the same numbers but in different order have to count as the same tuple
– immalee
Jan 2 at 13:28
Use set() instead for comparing tuples
– NEGR KITAEC
Jan 2 at 13:29
no the order doesn't matter, and this is the context, I tried to do it as simple as possible to ask my question...I don't know what set() does, or how to use it, I will try and see how it works
– immalee
Jan 2 at 13:31
Counter is a dictionary at heart and can't use sets as key - it can use frozensets though:Counter(frozenset(t) for t in L)should give you what you want.
– Patrick Artner
Jan 2 at 13:44
|
show 1 more comment
3
3
3
I have a list of tuples like this one:
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
Some of the tuples are having exactly the same numbers but in different order. I want to count the occurrences of the tuples and overwrite the ones that have the same values inside. I read several answers in here and I managed to do something using the Counter method. But what I tried doesn't seem to work for me. I am new at python so maybe I don't understand the exact use of Counter method.
L1 = Counter()
for item in L:
for element in item:
if element in item:
L1[tuple(item)] = L1[tuple(item)] + 1
print(L1)
The result I get is:
Counter({(23, 56, 48): 3, (48, 93, 81): 3, (48, 56, 23): 3, (54, 34, 21): 3,
(48, 98, 71): 3, (98, 71, 48): 3, (56, 23, 48): 3})
And the result I want to get is:
Counter({(23, 56, 48): 3, (48, 98, 71): 3, (48, 93, 81): 1, (54, 34, 21): 1})
python list dictionary tuples counter
edited Jan 2 at 13:41
Miraj50
2,7801925
asked Jan 2 at 13:26
immaleeimmalee
225
I have a list of tuples like this one:
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
Some of the tuples are having exactly the same numbers but in different order. I want to count the occurrences of the tuples and overwrite the ones that have the same values inside. I read several answers in here and I managed to do something using the Counter method. But what I tried doesn't seem to work for me. I am new at python so maybe I don't understand the exact use of Counter method.
L1 = Counter()
for item in L:
for element in item:
if element in item:
L1[tuple(item)] = L1[tuple(item)] + 1
print(L1)
The result I get is:
Counter({(23, 56, 48): 3, (48, 93, 81): 3, (48, 56, 23): 3, (54, 34, 21): 3,
(48, 98, 71): 3, (98, 71, 48): 3, (56, 23, 48): 3})
And the result I want to get is:
Counter({(23, 56, 48): 3, (48, 98, 71): 3, (48, 93, 81): 1, (54, 34, 21): 1})
python list dictionary tuples counter
python list dictionary tuples counter
edited Jan 2 at 13:41
Miraj50
2,7801925
asked Jan 2 at 13:26
immaleeimmalee
225
edited Jan 2 at 13:41
Miraj50
2,7801925
asked Jan 2 at 13:26
immaleeimmalee
225
edited Jan 2 at 13:41
Miraj50
2,7801925
edited Jan 2 at 13:41
Miraj50
2,7801925
edited Jan 2 at 13:41
Miraj50
2,7801925
2,7801925
asked Jan 2 at 13:26
immaleeimmalee
225
asked Jan 2 at 13:26
immaleeimmalee
225
asked Jan 2 at 13:26
immaleeimmalee
225
225
What does "overwrite the ones that have the same values inside" mean?
– DeepSpace
Jan 2 at 13:27
Maybe I cant explain it well, see the actual and the expected results for help, The tuples that contain the same numbers but in different order have to count as the same tuple
– immalee
Jan 2 at 13:28
Use set() instead for comparing tuples
– NEGR KITAEC
Jan 2 at 13:29
no the order doesn't matter, and this is the context, I tried to do it as simple as possible to ask my question...I don't know what set() does, or how to use it, I will try and see how it works
– immalee
Jan 2 at 13:31
Counter is a dictionary at heart and can't use sets as key - it can use frozensets though:Counter(frozenset(t) for t in L)should give you what you want.
– Patrick Artner
Jan 2 at 13:44
|
show 1 more comment
What does "overwrite the ones that have the same values inside" mean?
– DeepSpace
Jan 2 at 13:27
Maybe I cant explain it well, see the actual and the expected results for help, The tuples that contain the same numbers but in different order have to count as the same tuple
– immalee
Jan 2 at 13:28
Use set() instead for comparing tuples
– NEGR KITAEC
Jan 2 at 13:29
no the order doesn't matter, and this is the context, I tried to do it as simple as possible to ask my question...I don't know what set() does, or how to use it, I will try and see how it works
– immalee
Jan 2 at 13:31
Counter is a dictionary at heart and can't use sets as key - it can use frozensets though:Counter(frozenset(t) for t in L)should give you what you want.
– Patrick Artner
Jan 2 at 13:44
What does "overwrite the ones that have the same values inside" mean?
– DeepSpace
Jan 2 at 13:27
What does "overwrite the ones that have the same values inside" mean?
– DeepSpace
Jan 2 at 13:27
Maybe I cant explain it well, see the actual and the expected results for help, The tuples that contain the same numbers but in different order have to count as the same tuple
– immalee
Jan 2 at 13:28
Maybe I cant explain it well, see the actual and the expected results for help, The tuples that contain the same numbers but in different order have to count as the same tuple
– immalee
Jan 2 at 13:28
Use set() instead for comparing tuples
– NEGR KITAEC
Jan 2 at 13:29
Use set() instead for comparing tuples
– NEGR KITAEC
Jan 2 at 13:29
no the order doesn't matter, and this is the context, I tried to do it as simple as possible to ask my question...I don't know what set() does, or how to use it, I will try and see how it works
– immalee
Jan 2 at 13:31
no the order doesn't matter, and this is the context, I tried to do it as simple as possible to ask my question...I don't know what set() does, or how to use it, I will try and see how it works
– immalee
Jan 2 at 13:31
Counter is a dictionary at heart and can't use sets as key - it can use frozensets though:
Counter(frozenset(t) for t in L)should give you what you want.– Patrick Artner
Jan 2 at 13:44
Counter is a dictionary at heart and can't use sets as key - it can use frozensets though:
Counter(frozenset(t) for t in L)should give you what you want.– Patrick Artner
Jan 2 at 13:44
|
show 1 more comment
1 Answer
1
active
oldest
votes
2
You need to map the tuples with the same values to the same key, one way is sorting the tuples (using sorted):
from collections import Counter
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
result = Counter(tuple(e) for e in map(sorted, L))
print(result)
Output
Counter({(23, 48, 56): 3, (48, 71, 98): 2, (21, 34, 54): 1, (48, 81, 93): 1})
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
1
MaybeCounter(frozenset(t) for t in L)? Not sure what would be more performant
– DeepSpace
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You need to map the tuples with the same values to the same key, one way is sorting the tuples (using sorted):
from collections import Counter
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
result = Counter(tuple(e) for e in map(sorted, L))
print(result)
Output
Counter({(23, 48, 56): 3, (48, 71, 98): 2, (21, 34, 54): 1, (48, 81, 93): 1})
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
1
MaybeCounter(frozenset(t) for t in L)? Not sure what would be more performant
– DeepSpace
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
add a comment |
2
You need to map the tuples with the same values to the same key, one way is sorting the tuples (using sorted):
from collections import Counter
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
result = Counter(tuple(e) for e in map(sorted, L))
print(result)
Output
Counter({(23, 48, 56): 3, (48, 71, 98): 2, (21, 34, 54): 1, (48, 81, 93): 1})
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
1
MaybeCounter(frozenset(t) for t in L)? Not sure what would be more performant
– DeepSpace
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
add a comment |
2
2
2
You need to map the tuples with the same values to the same key, one way is sorting the tuples (using sorted):
from collections import Counter
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
result = Counter(tuple(e) for e in map(sorted, L))
print(result)
Output
Counter({(23, 48, 56): 3, (48, 71, 98): 2, (21, 34, 54): 1, (48, 81, 93): 1})
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
You need to map the tuples with the same values to the same key, one way is sorting the tuples (using sorted):
from collections import Counter
L = [(23,56,48),(48,93,81),(48,56,23),(54,34,21),(48,98,71),(98,71,48),(56,23,48)]
result = Counter(tuple(e) for e in map(sorted, L))
print(result)
Output
Counter({(23, 48, 56): 3, (48, 71, 98): 2, (21, 34, 54): 1, (48, 81, 93): 1})
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
edited Jan 2 at 13:36
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
answered Jan 2 at 13:31
Daniel MesejoDaniel Mesejo
18.7k21433
18.7k21433
1
MaybeCounter(frozenset(t) for t in L)? Not sure what would be more performant
– DeepSpace
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
add a comment |
1
MaybeCounter(frozenset(t) for t in L)? Not sure what would be more performant
– DeepSpace
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
1
1
Maybe
Counter(frozenset(t) for t in L)? Not sure what would be more performant– DeepSpace
Jan 2 at 13:32
Maybe
Counter(frozenset(t) for t in L)? Not sure what would be more performant– DeepSpace
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Yes that could be another option too
– Daniel Mesejo
Jan 2 at 13:32
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
Again as I said being new to python is the problem, I didn't think about using something like map at all. Thank you I will see how it works and try to understand it.
– immalee
Jan 2 at 13:33
add a comment |
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What does "overwrite the ones that have the same values inside" mean?
– DeepSpace
Jan 2 at 13:27
Maybe I cant explain it well, see the actual and the expected results for help, The tuples that contain the same numbers but in different order have to count as the same tuple
– immalee
Jan 2 at 13:28
Use set() instead for comparing tuples
– NEGR KITAEC
Jan 2 at 13:29
no the order doesn't matter, and this is the context, I tried to do it as simple as possible to ask my question...I don't know what set() does, or how to use it, I will try and see how it works
– immalee
Jan 2 at 13:31
Counter is a dictionary at heart and can't use sets as key - it can use frozensets though:
Counter(frozenset(t) for t in L)should give you what you want.– Patrick Artner
Jan 2 at 13:44