Using sed with command-substitution text in the replacement part is not working












1














I have a CFN with cfn-init to deploy a Apache web server with specified virtual hosts. In the template, I use a AWS::CloudFormation::Init configset to replace local IPs with the Instance's private IP.



  config:
packages:...
files:...
services:...
commands:
replacePrivateIP:
cwd: "/etc/httpd/conf"
command: !Sub |
sed -i 's@127.0.0.1@$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)@g' httpd.conf


The sed command works fine outside the CFN template. But in the CFN-init process, it simply replace "127.0.0.1" with the whole $(curl -s http://...) string.



How can I feed the instance private IP correctly into the httpd.conf file through cfn-init?










share|improve this question





























    1














    I have a CFN with cfn-init to deploy a Apache web server with specified virtual hosts. In the template, I use a AWS::CloudFormation::Init configset to replace local IPs with the Instance's private IP.



      config:
    packages:...
    files:...
    services:...
    commands:
    replacePrivateIP:
    cwd: "/etc/httpd/conf"
    command: !Sub |
    sed -i 's@127.0.0.1@$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)@g' httpd.conf


    The sed command works fine outside the CFN template. But in the CFN-init process, it simply replace "127.0.0.1" with the whole $(curl -s http://...) string.



    How can I feed the instance private IP correctly into the httpd.conf file through cfn-init?










    share|improve this question



























      1












      1








      1







      I have a CFN with cfn-init to deploy a Apache web server with specified virtual hosts. In the template, I use a AWS::CloudFormation::Init configset to replace local IPs with the Instance's private IP.



        config:
      packages:...
      files:...
      services:...
      commands:
      replacePrivateIP:
      cwd: "/etc/httpd/conf"
      command: !Sub |
      sed -i 's@127.0.0.1@$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)@g' httpd.conf


      The sed command works fine outside the CFN template. But in the CFN-init process, it simply replace "127.0.0.1" with the whole $(curl -s http://...) string.



      How can I feed the instance private IP correctly into the httpd.conf file through cfn-init?










      share|improve this question















      I have a CFN with cfn-init to deploy a Apache web server with specified virtual hosts. In the template, I use a AWS::CloudFormation::Init configset to replace local IPs with the Instance's private IP.



        config:
      packages:...
      files:...
      services:...
      commands:
      replacePrivateIP:
      cwd: "/etc/httpd/conf"
      command: !Sub |
      sed -i 's@127.0.0.1@$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)@g' httpd.conf


      The sed command works fine outside the CFN template. But in the CFN-init process, it simply replace "127.0.0.1" with the whole $(curl -s http://...) string.



      How can I feed the instance private IP correctly into the httpd.conf file through cfn-init?







      sed






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Dec 28 '18 at 12:19









      Inian

      38.9k63770




      38.9k63770










      asked Dec 28 '18 at 11:11









      Tomking ChenTomking Chen

      327




      327
























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          The command-substitution syntax $(..) does not work when wrapped in single quotes which is as expected in bash or most other shells as they preserve the literal value present inside. For your substitution to happen, put it inside double-quotes as



          sed -i 's@127.0.0.1@'"$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)"'@g' httpd.conf


          Compare the outputs of echo '$(date)' and echo "$(date)" for a simple example of your case.






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            1 Answer
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            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            1














            The command-substitution syntax $(..) does not work when wrapped in single quotes which is as expected in bash or most other shells as they preserve the literal value present inside. For your substitution to happen, put it inside double-quotes as



            sed -i 's@127.0.0.1@'"$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)"'@g' httpd.conf


            Compare the outputs of echo '$(date)' and echo "$(date)" for a simple example of your case.






            share|improve this answer




























              1














              The command-substitution syntax $(..) does not work when wrapped in single quotes which is as expected in bash or most other shells as they preserve the literal value present inside. For your substitution to happen, put it inside double-quotes as



              sed -i 's@127.0.0.1@'"$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)"'@g' httpd.conf


              Compare the outputs of echo '$(date)' and echo "$(date)" for a simple example of your case.






              share|improve this answer


























                1












                1








                1






                The command-substitution syntax $(..) does not work when wrapped in single quotes which is as expected in bash or most other shells as they preserve the literal value present inside. For your substitution to happen, put it inside double-quotes as



                sed -i 's@127.0.0.1@'"$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)"'@g' httpd.conf


                Compare the outputs of echo '$(date)' and echo "$(date)" for a simple example of your case.






                share|improve this answer














                The command-substitution syntax $(..) does not work when wrapped in single quotes which is as expected in bash or most other shells as they preserve the literal value present inside. For your substitution to happen, put it inside double-quotes as



                sed -i 's@127.0.0.1@'"$(curl -s http://169.254.169.254/latest/meta-data/local-ipv4)"'@g' httpd.conf


                Compare the outputs of echo '$(date)' and echo "$(date)" for a simple example of your case.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Dec 28 '18 at 12:23

























                answered Dec 28 '18 at 12:18









                InianInian

                38.9k63770




                38.9k63770






























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