Convert timestamp to datetime instance
I am having the following PHP setup:
$ php --version
PHP 7.1.8 (cli) (built: Aug 1 2017 21:10:46) ( ZTS MSVC14 (Visual C++ 2015) x86
)
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2017 Zend Technologies
with Xdebug v2.6.1, Copyright (c) 2002-2018, by Derick Rethans
I am using xampp, so I am running a 32-bit version on my 64-bit windows 8.1 machine.
I would like to convert the following timestamp into a Datetime instance:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
echo $t;
However, I get the following exception:
Catchable fatal error: Object of class DateTime could not be converted to string
I was thinking that my 32-bit PHP version might cause some issues. Any suggestions what I am doing wrong?
Thx in advance for your reply!
UPDATE
After using var_dump() I get the following:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
Output:
class DateTime#1 (3) {
public $date =>
string(20) "50974-09-09 05:30:30"
public $timezone_type =>
int(1)
public $timezone =>
string(6) "+00:00"
}
As you can see the wrong timestamp is converted?
Any suggestions why?
UPDATE
After trying several things I found the following solution:
$timestamp = 1546438627830;
$result = date ('c', (int) round ($timestamp / 1000));
$msec = (int) $timestamp % 1000;
$t = strtotime(str_replace ('+00:00', sprintf (".%03dZ", $msec), $result));
$finalTime = DateTime::createFromFormat('U', $t);
var_dump($finalTime);
php datetime
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
add a comment |
I am having the following PHP setup:
$ php --version
PHP 7.1.8 (cli) (built: Aug 1 2017 21:10:46) ( ZTS MSVC14 (Visual C++ 2015) x86
)
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2017 Zend Technologies
with Xdebug v2.6.1, Copyright (c) 2002-2018, by Derick Rethans
I am using xampp, so I am running a 32-bit version on my 64-bit windows 8.1 machine.
I would like to convert the following timestamp into a Datetime instance:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
echo $t;
However, I get the following exception:
Catchable fatal error: Object of class DateTime could not be converted to string
I was thinking that my 32-bit PHP version might cause some issues. Any suggestions what I am doing wrong?
Thx in advance for your reply!
UPDATE
After using var_dump() I get the following:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
Output:
class DateTime#1 (3) {
public $date =>
string(20) "50974-09-09 05:30:30"
public $timezone_type =>
int(1)
public $timezone =>
string(6) "+00:00"
}
As you can see the wrong timestamp is converted?
Any suggestions why?
UPDATE
After trying several things I found the following solution:
$timestamp = 1546438627830;
$result = date ('c', (int) round ($timestamp / 1000));
$msec = (int) $timestamp % 1000;
$t = strtotime(str_replace ('+00:00', sprintf (".%03dZ", $msec), $result));
$finalTime = DateTime::createFromFormat('U', $t);
var_dump($finalTime);
php datetime
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
Why do you think it is wrong?
– Alex
Jan 2 at 14:45
@Alex I printed thevar_dumpoutput, however I still get the wrong value for the timestamp. Any suggestions why?
– Anna.Klee
Jan 2 at 14:46
year value equal to50974technically it is not wrong, it is just weird and you just don't expect it. Once you can explain why you expect different result - you will be able to answer your question yourself next time and will realize why it is obvious for some people.
– Alex
Jan 2 at 14:53
add a comment |
I am having the following PHP setup:
$ php --version
PHP 7.1.8 (cli) (built: Aug 1 2017 21:10:46) ( ZTS MSVC14 (Visual C++ 2015) x86
)
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2017 Zend Technologies
with Xdebug v2.6.1, Copyright (c) 2002-2018, by Derick Rethans
I am using xampp, so I am running a 32-bit version on my 64-bit windows 8.1 machine.
I would like to convert the following timestamp into a Datetime instance:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
echo $t;
However, I get the following exception:
Catchable fatal error: Object of class DateTime could not be converted to string
I was thinking that my 32-bit PHP version might cause some issues. Any suggestions what I am doing wrong?
Thx in advance for your reply!
UPDATE
After using var_dump() I get the following:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
Output:
class DateTime#1 (3) {
public $date =>
string(20) "50974-09-09 05:30:30"
public $timezone_type =>
int(1)
public $timezone =>
string(6) "+00:00"
}
As you can see the wrong timestamp is converted?
Any suggestions why?
UPDATE
After trying several things I found the following solution:
$timestamp = 1546438627830;
$result = date ('c', (int) round ($timestamp / 1000));
$msec = (int) $timestamp % 1000;
$t = strtotime(str_replace ('+00:00', sprintf (".%03dZ", $msec), $result));
$finalTime = DateTime::createFromFormat('U', $t);
var_dump($finalTime);
php datetime
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
I am having the following PHP setup:
$ php --version
PHP 7.1.8 (cli) (built: Aug 1 2017 21:10:46) ( ZTS MSVC14 (Visual C++ 2015) x86
)
Copyright (c) 1997-2017 The PHP Group
Zend Engine v3.1.0, Copyright (c) 1998-2017 Zend Technologies
with Xdebug v2.6.1, Copyright (c) 2002-2018, by Derick Rethans
I am using xampp, so I am running a 32-bit version on my 64-bit windows 8.1 machine.
I would like to convert the following timestamp into a Datetime instance:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
echo $t;
However, I get the following exception:
Catchable fatal error: Object of class DateTime could not be converted to string
I was thinking that my 32-bit PHP version might cause some issues. Any suggestions what I am doing wrong?
Thx in advance for your reply!
UPDATE
After using var_dump() I get the following:
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
Output:
class DateTime#1 (3) {
public $date =>
string(20) "50974-09-09 05:30:30"
public $timezone_type =>
int(1)
public $timezone =>
string(6) "+00:00"
}
As you can see the wrong timestamp is converted?
Any suggestions why?
UPDATE
After trying several things I found the following solution:
$timestamp = 1546438627830;
$result = date ('c', (int) round ($timestamp / 1000));
$msec = (int) $timestamp % 1000;
$t = strtotime(str_replace ('+00:00', sprintf (".%03dZ", $msec), $result));
$finalTime = DateTime::createFromFormat('U', $t);
var_dump($finalTime);
php datetime
php datetime
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
edited Jan 2 at 14:54
Anna.Klee
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
asked Jan 2 at 14:36
Anna.KleeAnna.Klee
1,2531165135
1,2531165135
Why do you think it is wrong?
– Alex
Jan 2 at 14:45
@Alex I printed thevar_dumpoutput, however I still get the wrong value for the timestamp. Any suggestions why?
– Anna.Klee
Jan 2 at 14:46
year value equal to50974technically it is not wrong, it is just weird and you just don't expect it. Once you can explain why you expect different result - you will be able to answer your question yourself next time and will realize why it is obvious for some people.
– Alex
Jan 2 at 14:53
add a comment |
Why do you think it is wrong?
– Alex
Jan 2 at 14:45
@Alex I printed thevar_dumpoutput, however I still get the wrong value for the timestamp. Any suggestions why?
– Anna.Klee
Jan 2 at 14:46
year value equal to50974technically it is not wrong, it is just weird and you just don't expect it. Once you can explain why you expect different result - you will be able to answer your question yourself next time and will realize why it is obvious for some people.
– Alex
Jan 2 at 14:53
Why do you think it is wrong?
– Alex
Jan 2 at 14:45
Why do you think it is wrong?
– Alex
Jan 2 at 14:45
@Alex I printed the
var_dump output, however I still get the wrong value for the timestamp. Any suggestions why?– Anna.Klee
Jan 2 at 14:46
@Alex I printed the
var_dump output, however I still get the wrong value for the timestamp. Any suggestions why?– Anna.Klee
Jan 2 at 14:46
year value equal to
50974 technically it is not wrong, it is just weird and you just don't expect it. Once you can explain why you expect different result - you will be able to answer your question yourself next time and will realize why it is obvious for some people.– Alex
Jan 2 at 14:53
year value equal to
50974 technically it is not wrong, it is just weird and you just don't expect it. Once you can explain why you expect different result - you will be able to answer your question yourself next time and will realize why it is obvious for some people.– Alex
Jan 2 at 14:53
add a comment |
1 Answer
1
active
oldest
votes
When using echo on an object, PHP tries to call the magic __toString() method on that object. If it can't do that, it will throw the error you get. I recommend using var_dump() to debug objects.
https://3v4l.org/GlJaW
<?php
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
References:
http://php.net/manual/en/function.var-dump.php
http://php.net/manual/en/function.echo.php
http://php.net/manual/en/language.oop5.magic.php
http://php.net/manual/de/datetime.createfromformat.php
EDIT: Handling milliseconds
<?php
$timestamp = (int)(1546438627830 / 1000);
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
Thx for your reply! I usedvar_dumpto "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?
– Anna.Klee
Jan 2 at 14:45
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page toDateTime::createFromFormat. TheUmodifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.
– Xatenev
Jan 2 at 14:50
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
When using echo on an object, PHP tries to call the magic __toString() method on that object. If it can't do that, it will throw the error you get. I recommend using var_dump() to debug objects.
https://3v4l.org/GlJaW
<?php
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
References:
http://php.net/manual/en/function.var-dump.php
http://php.net/manual/en/function.echo.php
http://php.net/manual/en/language.oop5.magic.php
http://php.net/manual/de/datetime.createfromformat.php
EDIT: Handling milliseconds
<?php
$timestamp = (int)(1546438627830 / 1000);
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
Thx for your reply! I usedvar_dumpto "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?
– Anna.Klee
Jan 2 at 14:45
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page toDateTime::createFromFormat. TheUmodifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.
– Xatenev
Jan 2 at 14:50
add a comment |
When using echo on an object, PHP tries to call the magic __toString() method on that object. If it can't do that, it will throw the error you get. I recommend using var_dump() to debug objects.
https://3v4l.org/GlJaW
<?php
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
References:
http://php.net/manual/en/function.var-dump.php
http://php.net/manual/en/function.echo.php
http://php.net/manual/en/language.oop5.magic.php
http://php.net/manual/de/datetime.createfromformat.php
EDIT: Handling milliseconds
<?php
$timestamp = (int)(1546438627830 / 1000);
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
Thx for your reply! I usedvar_dumpto "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?
– Anna.Klee
Jan 2 at 14:45
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page toDateTime::createFromFormat. TheUmodifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.
– Xatenev
Jan 2 at 14:50
add a comment |
When using echo on an object, PHP tries to call the magic __toString() method on that object. If it can't do that, it will throw the error you get. I recommend using var_dump() to debug objects.
https://3v4l.org/GlJaW
<?php
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
References:
http://php.net/manual/en/function.var-dump.php
http://php.net/manual/en/function.echo.php
http://php.net/manual/en/language.oop5.magic.php
http://php.net/manual/de/datetime.createfromformat.php
EDIT: Handling milliseconds
<?php
$timestamp = (int)(1546438627830 / 1000);
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
When using echo on an object, PHP tries to call the magic __toString() method on that object. If it can't do that, it will throw the error you get. I recommend using var_dump() to debug objects.
https://3v4l.org/GlJaW
<?php
$timestamp = 1546438627830;
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
References:
http://php.net/manual/en/function.var-dump.php
http://php.net/manual/en/function.echo.php
http://php.net/manual/en/language.oop5.magic.php
http://php.net/manual/de/datetime.createfromformat.php
EDIT: Handling milliseconds
<?php
$timestamp = (int)(1546438627830 / 1000);
$t = DateTime::createFromFormat('U',$timestamp);
var_dump($t);
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
edited Jan 2 at 14:50
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
answered Jan 2 at 14:42
XatenevXatenev
5,76921235
5,76921235
Thx for your reply! I usedvar_dumpto "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?
– Anna.Klee
Jan 2 at 14:45
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page toDateTime::createFromFormat. TheUmodifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.
– Xatenev
Jan 2 at 14:50
add a comment |
Thx for your reply! I usedvar_dumpto "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?
– Anna.Klee
Jan 2 at 14:45
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page toDateTime::createFromFormat. TheUmodifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.
– Xatenev
Jan 2 at 14:50
Thx for your reply! I used
var_dump to "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?– Anna.Klee
Jan 2 at 14:45
Thx for your reply! I used
var_dump to "debug" the timestamp. However, still I get the wrong output? I kindly ask for your opinion what might be the reason for this? How to correctly parse it?– Anna.Klee
Jan 2 at 14:45
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page to
DateTime::createFromFormat. The U modifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.– Xatenev
Jan 2 at 14:50
@Anna.Klee Well your timestamp is in milliseconds. Try the edit. Make sure to read the documentation page to
DateTime::createFromFormat. The U modifier means seconds since the unix epoch, not milliseconds. Thus the weird behavior.– Xatenev
Jan 2 at 14:50
add a comment |
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Why do you think it is wrong?
– Alex
Jan 2 at 14:45
@Alex I printed the
var_dumpoutput, however I still get the wrong value for the timestamp. Any suggestions why?– Anna.Klee
Jan 2 at 14:46
year value equal to
50974technically it is not wrong, it is just weird and you just don't expect it. Once you can explain why you expect different result - you will be able to answer your question yourself next time and will realize why it is obvious for some people.– Alex
Jan 2 at 14:53