Pace Maker in Select statement not working
Select statement in sqlite3(Python) without pacemaker is working fine but is behaving odd with the pacemaker(?)
In the below code when I'm using "table_column_name" in the select I am getting all the items in my list populated in my list box. but when I am passing it as tuple to select statement with the help of pacemaker my list bosx has only one entry i.e "table_column_name".
class ListObj(tkinter.Listbox):
def __init__(self, window, cname, r, c, rs, cs, sticky, bg,
padx=5, pady=5, ipadx=0, ipady=0, **kwargs):
self = tkinter.Listbox(window)
self.grid(row=r, column=c, rowspan=rs, columnspan=cs,
sticky=sticky, padx=padx, pady=pady,
ipadx=ipadx, ipady=ipady)
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
for x in List:
print(x)
self.insert(tkinter.END, x)
list_box= ListObj(root, 'table_column_name',1,0,2,1,'nsew', 'sky blue')
my expected outcome is that I should get all the items in the column name passed as tuple should populate in the tk list.
python python-3.x sqlite3 pacemaker
add a comment |
Select statement in sqlite3(Python) without pacemaker is working fine but is behaving odd with the pacemaker(?)
In the below code when I'm using "table_column_name" in the select I am getting all the items in my list populated in my list box. but when I am passing it as tuple to select statement with the help of pacemaker my list bosx has only one entry i.e "table_column_name".
class ListObj(tkinter.Listbox):
def __init__(self, window, cname, r, c, rs, cs, sticky, bg,
padx=5, pady=5, ipadx=0, ipady=0, **kwargs):
self = tkinter.Listbox(window)
self.grid(row=r, column=c, rowspan=rs, columnspan=cs,
sticky=sticky, padx=padx, pady=pady,
ipadx=ipadx, ipady=ipady)
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
for x in List:
print(x)
self.insert(tkinter.END, x)
list_box= ListObj(root, 'table_column_name',1,0,2,1,'nsew', 'sky blue')
my expected outcome is that I should get all the items in the column name passed as tuple should populate in the tk list.
python python-3.x sqlite3 pacemaker
nothing in your code uses pacemaker as far as I can see. What relevance has it for an sql-query? how does it help us reproduce your error as a Minimal, Complete, and Verifiable example should?
– Patrick Artner
Dec 28 '18 at 10:14
add a comment |
Select statement in sqlite3(Python) without pacemaker is working fine but is behaving odd with the pacemaker(?)
In the below code when I'm using "table_column_name" in the select I am getting all the items in my list populated in my list box. but when I am passing it as tuple to select statement with the help of pacemaker my list bosx has only one entry i.e "table_column_name".
class ListObj(tkinter.Listbox):
def __init__(self, window, cname, r, c, rs, cs, sticky, bg,
padx=5, pady=5, ipadx=0, ipady=0, **kwargs):
self = tkinter.Listbox(window)
self.grid(row=r, column=c, rowspan=rs, columnspan=cs,
sticky=sticky, padx=padx, pady=pady,
ipadx=ipadx, ipady=ipady)
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
for x in List:
print(x)
self.insert(tkinter.END, x)
list_box= ListObj(root, 'table_column_name',1,0,2,1,'nsew', 'sky blue')
my expected outcome is that I should get all the items in the column name passed as tuple should populate in the tk list.
python python-3.x sqlite3 pacemaker
Select statement in sqlite3(Python) without pacemaker is working fine but is behaving odd with the pacemaker(?)
In the below code when I'm using "table_column_name" in the select I am getting all the items in my list populated in my list box. but when I am passing it as tuple to select statement with the help of pacemaker my list bosx has only one entry i.e "table_column_name".
class ListObj(tkinter.Listbox):
def __init__(self, window, cname, r, c, rs, cs, sticky, bg,
padx=5, pady=5, ipadx=0, ipady=0, **kwargs):
self = tkinter.Listbox(window)
self.grid(row=r, column=c, rowspan=rs, columnspan=cs,
sticky=sticky, padx=padx, pady=pady,
ipadx=ipadx, ipady=ipady)
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
for x in List:
print(x)
self.insert(tkinter.END, x)
list_box= ListObj(root, 'table_column_name',1,0,2,1,'nsew', 'sky blue')
my expected outcome is that I should get all the items in the column name passed as tuple should populate in the tk list.
python python-3.x sqlite3 pacemaker
python python-3.x sqlite3 pacemaker
edited Dec 28 '18 at 10:37
Patrick Artner
22.2k62143
22.2k62143
asked Dec 28 '18 at 9:38
user9977436user9977436
135
135
nothing in your code uses pacemaker as far as I can see. What relevance has it for an sql-query? how does it help us reproduce your error as a Minimal, Complete, and Verifiable example should?
– Patrick Artner
Dec 28 '18 at 10:14
add a comment |
nothing in your code uses pacemaker as far as I can see. What relevance has it for an sql-query? how does it help us reproduce your error as a Minimal, Complete, and Verifiable example should?
– Patrick Artner
Dec 28 '18 at 10:14
nothing in your code uses pacemaker as far as I can see. What relevance has it for an sql-query? how does it help us reproduce your error as a Minimal, Complete, and Verifiable example should?
– Patrick Artner
Dec 28 '18 at 10:14
nothing in your code uses pacemaker as far as I can see. What relevance has it for an sql-query? how does it help us reproduce your error as a Minimal, Complete, and Verifiable example should?
– Patrick Artner
Dec 28 '18 at 10:14
add a comment |
1 Answer
1
active
oldest
votes
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
Looks like you're trying to pass a column name as a bound parameter. You can't do that; table and column names have to be present in the SQL statement when it's compiled, not passed at execution time. The cname
variable is being bound as a string, and that string returned. Because it's a SELECT DISTINCT
, and every row of the table ends up selecting the same 'table_column_name'
string, only one row with that value is being returned. That whole query basically can be reduced to SELECT ?
where the question mark is replaced by the string in cname
.
add a comment |
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List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
Looks like you're trying to pass a column name as a bound parameter. You can't do that; table and column names have to be present in the SQL statement when it's compiled, not passed at execution time. The cname
variable is being bound as a string, and that string returned. Because it's a SELECT DISTINCT
, and every row of the table ends up selecting the same 'table_column_name'
string, only one row with that value is being returned. That whole query basically can be reduced to SELECT ?
where the question mark is replaced by the string in cname
.
add a comment |
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
Looks like you're trying to pass a column name as a bound parameter. You can't do that; table and column names have to be present in the SQL statement when it's compiled, not passed at execution time. The cname
variable is being bound as a string, and that string returned. Because it's a SELECT DISTINCT
, and every row of the table ends up selecting the same 'table_column_name'
string, only one row with that value is being returned. That whole query basically can be reduced to SELECT ?
where the question mark is replaced by the string in cname
.
add a comment |
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
Looks like you're trying to pass a column name as a bound parameter. You can't do that; table and column names have to be present in the SQL statement when it's compiled, not passed at execution time. The cname
variable is being bound as a string, and that string returned. Because it's a SELECT DISTINCT
, and every row of the table ends up selecting the same 'table_column_name'
string, only one row with that value is being returned. That whole query basically can be reduced to SELECT ?
where the question mark is replaced by the string in cname
.
List = cursor.execute(f"SELECT DISTINCT ? FROM juke_box",
(cname,))
Looks like you're trying to pass a column name as a bound parameter. You can't do that; table and column names have to be present in the SQL statement when it's compiled, not passed at execution time. The cname
variable is being bound as a string, and that string returned. Because it's a SELECT DISTINCT
, and every row of the table ends up selecting the same 'table_column_name'
string, only one row with that value is being returned. That whole query basically can be reduced to SELECT ?
where the question mark is replaced by the string in cname
.
answered Dec 28 '18 at 11:52
ShawnShawn
3,5731613
3,5731613
add a comment |
add a comment |
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nothing in your code uses pacemaker as far as I can see. What relevance has it for an sql-query? how does it help us reproduce your error as a Minimal, Complete, and Verifiable example should?
– Patrick Artner
Dec 28 '18 at 10:14