In MongoDB, how do you retrieve a set of results where Field X is greater than Field Y by Value N?
I'm trying to query my local MongoDB for documents where Field X is greater than Field Y by Value N (in this case, Value N = 0.25).
I currently have:
db.getCollection('collection1').find({ $expr: { $gt: [ "$field1" , "$field2" ] }}).sort({"dateAdded" : -1})
But this only returns results where field1 is greater than field2. I need field1 to be greater than field2 by 0.25.
I can't find this in the documentation anywhere, i'm sure i'm missing something easy...
Thanks for your help.
database mongodb expression robo3t
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
add a comment |
I'm trying to query my local MongoDB for documents where Field X is greater than Field Y by Value N (in this case, Value N = 0.25).
I currently have:
db.getCollection('collection1').find({ $expr: { $gt: [ "$field1" , "$field2" ] }}).sort({"dateAdded" : -1})
But this only returns results where field1 is greater than field2. I need field1 to be greater than field2 by 0.25.
I can't find this in the documentation anywhere, i'm sure i'm missing something easy...
Thanks for your help.
database mongodb expression robo3t
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
add a comment |
I'm trying to query my local MongoDB for documents where Field X is greater than Field Y by Value N (in this case, Value N = 0.25).
I currently have:
db.getCollection('collection1').find({ $expr: { $gt: [ "$field1" , "$field2" ] }}).sort({"dateAdded" : -1})
But this only returns results where field1 is greater than field2. I need field1 to be greater than field2 by 0.25.
I can't find this in the documentation anywhere, i'm sure i'm missing something easy...
Thanks for your help.
database mongodb expression robo3t
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
I'm trying to query my local MongoDB for documents where Field X is greater than Field Y by Value N (in this case, Value N = 0.25).
I currently have:
db.getCollection('collection1').find({ $expr: { $gt: [ "$field1" , "$field2" ] }}).sort({"dateAdded" : -1})
But this only returns results where field1 is greater than field2. I need field1 to be greater than field2 by 0.25.
I can't find this in the documentation anywhere, i'm sure i'm missing something easy...
Thanks for your help.
database mongodb expression robo3t
database mongodb expression robo3t
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
asked Dec 28 '18 at 9:36
Ruben MurrayRuben Murray
61
61
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Create an expression that calculates the difference first and then you can do the greater than comparison.
Take for instance this query which uses the $subtract operator to get the difference:
db.getCollection('collection1').find(
{ "$expr": {
"$gt": [
{ "$subtract": ["$field1", "$field2"] },
0.25
]
}}
).sort({"dateAdded" : -1})
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Create an expression that calculates the difference first and then you can do the greater than comparison.
Take for instance this query which uses the $subtract operator to get the difference:
db.getCollection('collection1').find(
{ "$expr": {
"$gt": [
{ "$subtract": ["$field1", "$field2"] },
0.25
]
}}
).sort({"dateAdded" : -1})
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
add a comment |
Create an expression that calculates the difference first and then you can do the greater than comparison.
Take for instance this query which uses the $subtract operator to get the difference:
db.getCollection('collection1').find(
{ "$expr": {
"$gt": [
{ "$subtract": ["$field1", "$field2"] },
0.25
]
}}
).sort({"dateAdded" : -1})
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
add a comment |
Create an expression that calculates the difference first and then you can do the greater than comparison.
Take for instance this query which uses the $subtract operator to get the difference:
db.getCollection('collection1').find(
{ "$expr": {
"$gt": [
{ "$subtract": ["$field1", "$field2"] },
0.25
]
}}
).sort({"dateAdded" : -1})
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
Create an expression that calculates the difference first and then you can do the greater than comparison.
Take for instance this query which uses the $subtract operator to get the difference:
db.getCollection('collection1').find(
{ "$expr": {
"$gt": [
{ "$subtract": ["$field1", "$field2"] },
0.25
]
}}
).sort({"dateAdded" : -1})
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
answered Dec 28 '18 at 10:05
chridamchridam
66.3k13105138
66.3k13105138
add a comment |
add a comment |
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